inverse operations (x&/) by: me math period 2. benchmark: topic #22: benchmark:ma.7.2.3: apply...

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Inverse Operations (x&/) By: Me Math Period 2

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Page 1: Inverse Operations (x&/) By: Me Math Period 2. Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction,

Inverse Operations (x&/)

By: Me

Math Period 2

Page 2: Inverse Operations (x&/) By: Me Math Period 2. Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction,

Benchmark:

Topic #22:Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction, and multiplication and division, to solve one- step problems.

Page 3: Inverse Operations (x&/) By: Me Math Period 2. Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction,

Definition:

Operations that “undo” each other. Multiplying and dividing are inverse operations and so are addition and subtraction.

Page 4: Inverse Operations (x&/) By: Me Math Period 2. Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction,

Example/ Drawing/ Formula:First you do the inverse of multiplying 3 which is dividing

3. That cancels out. Then I do 6/3, which equals 2. Next, you take the 9x and divide by 9 which now means you are left with x. Now you bring the 2

down and divide 2 and 9 (2/9). Therefore, x= 2/9.

Equation: 9x * 3 = 6 9x * 3 = 6

/3 /3 9x 9x = 2 /9 /9

x = 2/9

Page 5: Inverse Operations (x&/) By: Me Math Period 2. Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction,

Create A Question:

Can you solve this equation?

Page 6: Inverse Operations (x&/) By: Me Math Period 2. Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction,

My Question:

14x / 4 = 7

Page 7: Inverse Operations (x&/) By: Me Math Period 2. Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction,

Solution to question:

x= 2

How did I get 2? Here… look at this

Page 8: Inverse Operations (x&/) By: Me Math Period 2. Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction,

Explanation To Question:

What you have to do is do the inverse of dividing 4 which is multiplying 4. That cancels out. Then you do the same to the other side. 7x4=28. Bring that down(28). Next, 14x/14equals it canceling out. X is left over. So, 28/14=2. Therefore, x=2.

14x / 4 = 7

Page 9: Inverse Operations (x&/) By: Me Math Period 2. Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction,

Credits:

I would like to thank:

Google (for the images)Mr. Imamura (for the math)Kahiki ( for helping me to put the image as the background)Mom( for letting me use the computer)

Page 10: Inverse Operations (x&/) By: Me Math Period 2. Benchmark: Topic #22: Benchmark:MA.7.2.3: Apply inverse relationships between addition and subtraction,

Thank you for watching!!!