introduction to vectors - umass...
TRANSCRIPT
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 3
Course website:
http://faculty.uml.edu/Andriy_Danylov/Teaching/PhysicsI
Lecture Capture:
http://echo360.uml.edu/danylov2013/physics1fall.html
Lecture 4
Introduction to
vectors
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Chapter 3. Section 3.1 – 3.5
• Vectors and Scalars
• Addition of Vectors
• Subtraction of Vectors
• Multiplication of a Vector by a Scalar
• Adding Vectors by Components
• Unit Vectors
Outline
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Vector and Scalars
e.g. distance, speed, temperature, mass, time, density, volume
r,v ,a
e.g. displacement, velocity, acceleration, force, momentum
has only magnitude
(no need in direction)
Vector quantity Scalar quantity
r
has both direction and magnitude
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Addition of Vectors (1D)
If the vectors are in
opposite directions
If the vectors are in the
same direction
For vectors in one dimension, simple addition and subtraction are all that is needed. Easy!!!!
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Addition of Vectors (2D). Graphical Methods
Triangle method.
• “Tail-to-Tip” method
• Draw first vector
• Draw second vector, placing tail at tip of first vector
• Arrow from tail of 1st vector to tip of 2nd vector: resultant
𝑨 𝑩
If the motion is in two dimensions, the situation is somewhat
more complicated.
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Addition of Vectors (2D). Graphical Methods
Parallelogram method.
• “Parallelogram” method
• The two vectors, 𝐴 𝑎𝑛𝑑 𝐵, are drawn as the sides of the
parallelogram and the resultant, 𝐶 = 𝐴 + 𝐵, is its
diagonal
𝑨
𝑩
Commutative property of vectors 𝑪 = 𝑨 + 𝑩 = 𝑩 + 𝑨
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Subtraction of vectors
is a vector with the same magnitude as but in the
opposite direction. So we can rewrite subtraction as addition
B
BA
= A
AB
B
B
𝑪 = 𝑨 − 𝑩
B
So, we add the negative vector.
)( BA
ConcepTest 1 Vector Addition
You are adding vectors of length
20 and 40 units. What is the only
possible resultant magnitude that
you can obtain out of the
following choices?
A) 0
B) 18
C) 37
D) 64
E) 100
ConcepTest 1 Vector Addition
You are adding vectors of length
20 and 40 units. What is the only
possible resultant magnitude that
you can obtain out of the
following choices?
A) 0
B) 18
C) 37
D) 64
E) 100
The minimum resultant occurs when the vectors
are opposite, giving 20 units. The maximum resultant
occurs when the vectors are aligned, giving 60 units.
Anything in between is also possible for angles
between 0° and 180°.
40 20
Min=40-20=20 Max=40+20=60
Resultant is between 20 and 60
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Multiplication of a Vector by a Scalar
𝐴
𝐵 = 1.5 𝐴 𝐶 = −2.0 𝐴
A vector can be multiplied by a scalar b(positive); the result is a
vector that has the same direction but a magnitude .
𝐴 𝐵 𝑏𝐴
If b is negative, the resultant vector points in the opposite direction.
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Addition of three or more vectors
Can use “tip to tail” for more than 2 vectors
+ + = 𝑨
𝑩
𝑪 𝑨 𝑩
𝑪
𝑫 = 𝑨 + 𝑩 + 𝑪
Order of addition does not matter
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Vector components
It is customary to resolve a vector into components along mutually
perpendicular directions.
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Determining vector components Given V and θ, we can find Vx, Vy
• In 2D, we can always write any vector as the sum of a
vector in the x-direction, and one in the y-direction.
• Given V, θ (magnitude, direction), we can find Vx and Vy
V =Vx +Vy
cos so cos VVV
Vx
x V
Vx
Vy
q sin so sin VV
V
Vy
y
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
x
y
V
Vtan
Given Vx and Vy, we can find V, θ
• Vx, Vy are the legs of the right triangle and are therefore perpendicular
• Vector 𝑽 as the hypotenuse.
• So, the magnitudes of the vectors satisfy the Pythagorean Theorem.
V
Vx
Vy
q
Vy
222
yx VVV
22
yx VVVV
x
y
V
V1tan so
x
y
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Example 1
mV 10
• A vector is given by its magnitude and direction (V,)
• What is the x, y-component
of the vector?
axisxabove 30
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Example 2
• A vector is given by its vector components:
• Write the vector in terms of magnitude and direction.
4,2 yx VV
47.42042 22 V
x
y
-1
4
2
-2
4yV
2xV
22
yx VVV
x
y
V
Vtan 2
2
4tan
magnitude
axisxfrom 11763180180
632tan 1
axisxfrom
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Adding vectors by components
Given and , how can we find ?
21 VVV
V1
V2 V
V1x
V1y
V2x
V2y
V1 V2 V1 +V2
x
y
𝑽𝒙 =𝑽𝟏𝒙 + 𝑽𝟐𝒙
𝑽𝒚 =𝑽𝟏𝒚+𝑽𝟐𝒚
yx VVV ,
yx VVV 111 ,
yx VVV 222 ,
yyxx VVVV 2121 ,
Adding corresponding
components
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Unit Vectors (1)
• As we said before, a vector has both magnitude and direction.
• Now, it’s time to simplify a notation of direction:
Let’s introduce unit vectors
vectorsunitasknownkji ˆ,ˆ,ˆ
x
y
z
𝒌
𝒋
𝒊
• They point along major axes of our
coordinate system
𝑖 = 𝑗 = 𝑘 =1
• Unit vectors have a magnitude of 1
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Unit Vectors (2)
Writing a vector with unit vectors is equivalent to
multiplying each unit vector by a scalar
jVViVV yyxxˆ;ˆ
• If a vector has components:
• In unit vector notation, we write
3,4 yx VV
jiV ˆ3ˆ4
jViVV yxˆˆ
x
y
𝒋 𝒊
xV
),( yx VV
)3,4(
iVxˆ
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Example: Vector Addition/Subtraction
A hiker traces her movement along a trail.
D1 = (2500m)i + (500m) j
D2 = (500m)i + (700m) j + (700m)k
D3 = (600m) j
D4 = -(500m)k
D = (3000m)i + (1800m) j + (200m)k
D =D1 +D2 +D3 +D4
= (2500m)i + (500m) j
+ (500m)i + (700m) j + (700m)k
+ (600m) j
- (500m)k
What is the hiker’s final displacement?
The first leg is a flat hike to the foot of the mountain: ----------------------------
On the second leg, she climbs the mountain:----------------------------------
On the third, she walks along a plateau: -----
Then she falls off a cliff: --------------------------
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Relative Velocity
• So far we have just added/subtracted displacement vectors
• May find situations to add or subtract other types of
vectors, say velocity vectors
• Can only add or subtract the same type of vectors
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Relative Velocity
5m/s
25m/s
• A train moves at 25 m/s relative to the ground
• Your velocity relative to the train is 5 m/s
• So your velocity relative to the ground is: 20 m/s
x
- +
+
-
+ +25 m/s – 5m/s=
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Boat in the river. Derivation of the relative velocity equation 3-15
𝑽𝑩𝑾 means “velocity of the boat relative to water”
𝑽𝑩𝑺 = 𝑽𝑩𝑾 + 𝑽𝑾𝑺
B Boat
W Water
S Shore
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Relative Velocity - 2D
A boat’s speed in still water is 1.85m/s.
The river flows with a 1.20m/s current.
If we want to directly cross the stream at what upstream angle (see diagram) should the boat be pointed?
hypotenuse
oppositesin
River current
θ 𝑽𝑩𝑾
𝑽𝑾𝑺
𝑽𝑩𝑺
𝑽𝑩𝑾 means “velocity of the boat relative to water”
B Boat
W Water
S Shore
4.40)6486.0(sin 1
6486.085.1
20.1sin
𝑽𝑩𝑺 = 𝑽𝑩𝑾 + 𝑽𝑾𝑺 =1.85m/s
=1.20m/s
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Summary
• Vectors
• Graphical Methods
• Addition and Subtraction
• Multiplication by a scalar
• Components
• Unit vectors
• Displacement & velocity vectors
• Relative Velocity
Department of Physics and Applied Physics 95.141, Fall 2013, Lecture 4
Thank you
See you on Wednesday
If two vectors are given
such that A + B = 0,
what can you say about
the magnitude and
direction of vectors
A and B?
A) same magnitude, but can be in any
direction
B) same magnitude, but must be in the same
direction
C) different magnitudes, but must be in the
same direction
D) same magnitude, but must be in opposite
directions
E) different magnitudes, but must be in
opposite directions
ConcepTest 1 Vectors I
If two vectors are given
such that A + B = 0, what
can you say about the
magnitude and direction of
vectors A and B?
A) same magnitude, but can be in any
direction
B) same magnitude, but must be in the same
direction
C) different magnitudes, but must be in the same
direction
D) same magnitude, but must be in opposite
directions
E) different magnitudes, but must be in
opposite directions
The magnitudes must be the same, but one vector must be pointing in the
opposite direction of the other in order for the sum to come out to zero. You
can prove this with the tip-to-tail method.
ConcepTest 1 Vectors I
𝑨 𝑩
Given that A + B = C, and
that lAl 2 + lBl 2 = lCl 2,
how are vectors A and B
oriented with respect to
each other?
1) they are perpendicular to each other
2) they are parallel and in the same direction
3) they are parallel but in the opposite
direction
4) they are at 45° to each other
5) they can be at any angle to each other
Note that the magnitudes of the vectors satisfy the Pythagorean Theorem.
This suggests that they form a right triangle, with vector C as the hypotenuse.
Thus, A and B are the legs of the right triangle and are therefore perpendicular.
ConcepTest 2 Vectors II
𝑨 𝑩
Pythagorean Theorem