introduction to projectile motion mr. chin-sung lin

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Introduction to Projectile Motion Mr. Chin-Sung Lin

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Page 1: Introduction to Projectile Motion Mr. Chin-Sung Lin

Introduction to

Projectile Motion

Mr. Chin-Sung Lin

Page 2: Introduction to Projectile Motion Mr. Chin-Sung Lin

Introduction to Projectile Motion

What is Projectile Motion?

Trajectory of a Projectile

Calculation of Projectile Motion

Page 3: Introduction to Projectile Motion Mr. Chin-Sung Lin

Introduction to Projectile Motion

What is Projectile Motion?

Trajectory of a Projectile

Calculation of Projectile Motion

Page 4: Introduction to Projectile Motion Mr. Chin-Sung Lin

What is Projectile Motion?

Page 5: Introduction to Projectile Motion Mr. Chin-Sung Lin

Features of Projectile Motion?

2-D Motion

Parabolic Path

Affected by Gravity

Thrown into the Air

Determined by Initial Velocity

Page 6: Introduction to Projectile Motion Mr. Chin-Sung Lin

Definition: Projectile Motion

Projectile motion refers to the 2-D motion of

an object that is given an initial velocity and

projected into the air at an angle.

The only force acting upon the object is

gravity. It follows a parabolic path

determined by the effect of the initial

velocity and gravitational acceleration.

Page 7: Introduction to Projectile Motion Mr. Chin-Sung Lin

Definition: Projectile Motion

Projectile motion refers to the 2-D motion of

an object that is given an initial velocity and

projected into the air at an angle.

The only force acting upon the object is

gravity. It follows a parabolic path

determined by the effect of the initial

velocity and gravitational acceleration.

Page 8: Introduction to Projectile Motion Mr. Chin-Sung Lin

Introduction to Projectile Motion

What is Projectile Motion?

Trajectory of a Projectile

Calculation of Projectile Motion

Page 9: Introduction to Projectile Motion Mr. Chin-Sung Lin

Trajectory (Path) of a Projectile

Page 10: Introduction to Projectile Motion Mr. Chin-Sung Lin

Trajectory (Path) of a Projectile

Page 11: Introduction to Projectile Motion Mr. Chin-Sung Lin

v0

x

y

Page 12: Introduction to Projectile Motion Mr. Chin-Sung Lin

x

y

Page 13: Introduction to Projectile Motion Mr. Chin-Sung Lin

x

y

Page 14: Introduction to Projectile Motion Mr. Chin-Sung Lin

x

y

Page 15: Introduction to Projectile Motion Mr. Chin-Sung Lin

x

y

Velocity is changing and the motion is accelerated

The horizontal component of velocity (vx) is constant

Acceleration from the vertical component of velocity (vy)

Acceleration due to gravity is constant, and downward

a = - g = - 9.81m/s2

g = 9.81m/s2

Page 16: Introduction to Projectile Motion Mr. Chin-Sung Lin

x

y

The horizontal and vertical motions are independent of each other

Both motions share the same time (t)

The horizontal velocity ....vx = v0

The horizontal distance .... dx = vx t

The vertical velocity .... .... vy = - g t

The vertical distance .... .... dy = 1/2 g t2

g = 9.81m/s2

Page 17: Introduction to Projectile Motion Mr. Chin-Sung Lin

Trajectory (Path) of a Projectile

The path of a projectile is the result of the simultaneous effect of the H & V components of its motion

V component accelerated downward motion

H component constant velocity motion

H & V motions are independent

H & V motions share the same time t

The projectile flight time t is determined by the V component of its motion

Page 18: Introduction to Projectile Motion Mr. Chin-Sung Lin

Trajectory (Path) of a Projectile

H velocity is constant vx = v0

V velocity is changing vy = - g t

H range: dx = v0 t

V distance: dy = 1/2 g t2

Page 19: Introduction to Projectile Motion Mr. Chin-Sung Lin

Introduction to Projectile Motion

What is Projectile Motion?

Trajectory of a Projectile

Calculation of Projectile Motion

Page 20: Introduction to Projectile Motion Mr. Chin-Sung Lin

Calculation of Projectile Motion

Example: A projectile was fired with initial velocity v0 horizontally from a cliff d meters above the ground. Calculate the horizontal range R of the projectile.

g

R

d

v0

t

Page 21: Introduction to Projectile Motion Mr. Chin-Sung Lin

Strategies of Solving Projectile Problems

H & V motions can be calculated independently H & V kinematics equations share the same

variable t

g

R

d

v0

t

Page 22: Introduction to Projectile Motion Mr. Chin-Sung Lin

Strategies of Solving Projectile Problems

H motion: dx = vx t R = v0 t

V motion: dy = d = 1/2 g t2 t = sqrt(2d/g)

So, R = v0 t = v0 * sqrt(2d/g)

g

R

d

v0

t

Page 23: Introduction to Projectile Motion Mr. Chin-Sung Lin

Numerical Example of Projectile Motion

H motion: dx = vx t R = v0 t = 10 t

V motion: dy = d = 1/2 g t2 t = sqrt(2 *19.62/9.81) = 2 s

So, R = v0 t = v0 * sqrt(2d/g) = 10 * 2 = 20 m

g = 9.81 m/s2

R

19.62 m

V0 = 10 m/s

t

Page 24: Introduction to Projectile Motion Mr. Chin-Sung Lin

Exercise 1: Projectile Problem

A projectile was fired with initial velocity 10 m/s horizontally from a cliff. If the horizontal range of the projectile is 20 m, calculate the height d of the cliff.

g = 9.81 m/s2

20 m

d

V0 = 10 m/s

t

Page 25: Introduction to Projectile Motion Mr. Chin-Sung Lin

Exercise 1: Projectile Problem

H motion: dx = vx t 20 = v0 t = 10 t t = 2 s

V motion: dy = d = 1/2 g t2 = 1/2 (9.81) 22 = 19.62 m

So, d = 19.62 m

g = 9.81 m/s2

20 m

d

V0 = 10 m/s

t

Page 26: Introduction to Projectile Motion Mr. Chin-Sung Lin

Exercise 2: Projectile Problem

A projectile was fired horizontally from a cliff 19.62 m above the ground. If the horizontal range of the projectile is 20 m, calculate the initial velocity v0 of the projectile.

g = 9.81 m/s2

20 m

19.62 m

V0

t

Page 27: Introduction to Projectile Motion Mr. Chin-Sung Lin

Exercise 2: Projectile Problem

H motion: dx = vx t 20 = v0 t

V motion: dy = d = 1/2 g t2 t = sqrt(2 *19.62/9.81) = 2 s

So, 20 = v0 t = 2 v0 v0 = 20/2 = 10 m/s

g = 9.81 m/s2

20 m

19.62 m

V0

t

Page 28: Introduction to Projectile Motion Mr. Chin-Sung Lin

Summary of Projectile Motion

What is Projectile Motion?

Trajectory of a Projectile

Calculation of Projectile Motion

Page 29: Introduction to Projectile Motion Mr. Chin-Sung Lin

Projectile Motion with Angles

Mr. Chin-Sung Lin

Page 30: Introduction to Projectile Motion Mr. Chin-Sung Lin

Example: Projectile Problem – H & V

A projectile was fired from ground with 20 m/s initial velocity at 60-degree angle. What’s the horizontal and vertical components of the initial velocity?

g = 9.81 m/s2

20 m/s

60o

vx

vy

Page 31: Introduction to Projectile Motion Mr. Chin-Sung Lin

Example: Projectile Problem – At the Top

A projectile was fired from ground with 20 m/s initial velocity at 60-degree angle. What’s the velocity of the projectile at the top of its trajectory?

g = 9.81 m/s2

R

v

t

20 m/s

60o

vy

vx

Page 32: Introduction to Projectile Motion Mr. Chin-Sung Lin

Example: Projectile Problem – Height

A projectile was fired from ground with 20 m/s initial velocity at 60-degree angle. What’s the maximum height that the ball can reach?

g = 9.81 m/s2

h

20 m/s

60o

vy

vx

Page 33: Introduction to Projectile Motion Mr. Chin-Sung Lin

Example: Projectile Problem - Time

A projectile was fired from ground with 20 m/s initial velocity at 60-degree angle. How long will the ball travel before hitting the ground?

g = 9.81 m/s2

t

20 m/s

60o

vy

vx

Page 34: Introduction to Projectile Motion Mr. Chin-Sung Lin

Example: Projectile Problem – H Range

A projectile was fired from ground with 20 m/s initial velocity at 60-degree angle. How far will the ball reach horizontally?

g = 9.81 m/s2

R

20 m/s

60o

vy

vx

Page 35: Introduction to Projectile Motion Mr. Chin-Sung Lin

Example: Projectile Problem – Final V

A projectile was fired from ground with 20 m/s initial velocity at 60-degree angle. What’s the final velocity of the projectile right before hitting the ground?

g = 9.81 m/s2

20 m/s

60o

vy

vx

vfx

vfy vf

Page 36: Introduction to Projectile Motion Mr. Chin-Sung Lin

Example: Projectile Problem – Max R

A projectile was fired from ground with 20 m/s initial velocity. How can the projectile reach the maximum horizontal range? What’s the maximum horizontal range it can reach?

g = 9.81 m/s2

R

20 m/s