introduction to mechanics-i

24
Prof. Ramesh Singh What is Bulk Deformation? Imparting changes in material (dM~0): – Geometry • Force • Die – Material properties and Mechanics • Strength • Hardness • Toughness Yield Criteria Theory of plasticity

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Page 1: Introduction to Mechanics-I

Prof. Ramesh Singh

What is Bulk Deformation?

• Imparting changes in material (dM~0):– Geometry

• Force• Die

– Material properties and Mechanics• Strength• Hardness• Toughness• Yield Criteria• Theory of plasticity

Page 2: Introduction to Mechanics-I

Prof. Ramesh Singh

Part 1- Mechanics Review• Concept of stress and strain, True and engineering• Stresses in 2D/3D, Mohr’s circle (stress and strain) for

2D/3D• Elements of Plasticity• Material Models• Yielding criteria, Tresca and Von Mises• Invariants of stress and strain• Levy-Mises equations• Strengthening mechanisms• Basic formulation of slip line in plane strain

Page 3: Introduction to Mechanics-I

Prof. Ramesh Singh

Part 2- Bulk Deformation

• Process description, videos and first order mathematical analysis– Plane strain forging– Cylindrical forging– Closed die forging– Rolling– Drawing– Tube drawing– Extrusion

Page 4: Introduction to Mechanics-I

Prof. Ramesh Singh

Outline

• Stress and strain– Engineering stresses/strain– True stresses/strain

• Stress tensors and strain tensors– Stresses/strains in 3D– Plane stress and plane strain

• Principal stresses• Mohr’s circle in 2D/3D

Page 5: Introduction to Mechanics-I

Prof. Ramesh Singh

#1 - Match

a) Force equilibriumb) Compatibility of

deformationc) Constitutive

equation

1) δT = δ1 + δ2

2) ΣF=0; ΣM=0

3) σ = E e

Page 6: Introduction to Mechanics-I

Prof. Ramesh Singh

Steps of a Mechanics Problem

• O Read and understand problem• 1 Free body diagram• 2 Equilibrium of forces

– e.g. ΣF=0, ΣM=0.• 3 Compatibility of deformations

– e.g. δT = δ1 + δ2

• 4 Constitutive equations– e.g. σ = E e

• 5 Solve

F F

A

Page 7: Introduction to Mechanics-I

Prof. Ramesh Singh

Key ConceptsLoad (Force), P, acting over area,

A, gives rise to stress, σ.

Engineering stress: σ = P/Ao

(Ao = original area)

True stress: σt = P/A(A = actual area)

P PA

Page 8: Introduction to Mechanics-I

Prof. Ramesh Singh

Deformation

• Quantified by strain, e or ε

• Engineering strain: e = (lf-li)/li

• True Strain: ε = ln(lf/li)

• Shear strain: γ = a/b

lilf

a

b

Page 9: Introduction to Mechanics-I

Prof. Ramesh Singh

True and Engineering strains

e = (lf-li)/lie = (lf/li) – 1(lf/li) = e + 1ln(lf/li) = ln(e + 1)ε = ln(e + 1)

Page 10: Introduction to Mechanics-I

Prof. Ramesh Singh

3-D Stress State in Cartesian Plane

There are two subscripts in any stress component:

Direction of normal vector of the plane (first subscript)

σ x x and τ x y

Courtesy: http://www.jwave.vt.edu/crcd/kriz/lectures/Anisotropy.html

Direction of action (second subscript)

Page 11: Introduction to Mechanics-I

Prof. Ramesh Singh

Stress Tensor

zzzyzx

yzyyyx

xzxyxx

στττστττσ

333231

232221

131211

σσσσσσσσσ

Mechanics Notation Expanded Tensorial Notation

It can also be written as σij in condensed form and is a second order tensor, where i and j are indicesThe number of components to specify a tensor

• 3n , where n is the order of matrix

Page 12: Introduction to Mechanics-I

Prof. Ramesh Singh

Symmetry in Shear Stress • Ideally, there has to be nine components• For small faces with no change in stresses• Moment about z-axis,

• Tensor becomes symmetric and have only six components, 3 normal and 3 shear stresses

xzzx

zyyz

yxxy

yxxy

Similarly

yzxxzy

ττ

ττ

ττ

ττ

=

=

=

∆∆∆=∆∆∆

,

)()(

Page 13: Introduction to Mechanics-I

Prof. Ramesh Singh

Plane Stress

00

===

zxyx

zz

ττσ

Only three components of stress

http://www.shodor.org/~jingersoll/weave4/tutorial/Figures/sc.jpg

Page 14: Introduction to Mechanics-I

Prof. Ramesh Singh

2-D Stresses at an Angle

Page 15: Introduction to Mechanics-I

Prof. Ramesh Singh

Shear Stress on Inclined Plane

Page 16: Introduction to Mechanics-I

Prof. Ramesh Singh

Transformation Equations

Use θ and 90 +θ for x and y directions, respectively

Page 17: Introduction to Mechanics-I

Prof. Ramesh Singh

Principal StressesFor principal stresses τxy=0

= 0

22

22

2

22cos

2

2sin

2

2tan

xyyx

yx

p

xyyx

xyp

yx

xyp

τσσ

σσ

θ

τσσ

τθ

σστ

θ

+

±=

+

−±=

−=

Page 18: Introduction to Mechanics-I

Prof. Ramesh Singh

Principal Stresses• Substituting values of sin2θp and cos2θp in

transformation equation we get principal stresses

2

2tan

plane, stress principal maximum The

22tan

02cos2sin2

stress,shear maximum of Angle

222

2

2,1

yx

xyp

xy

yx

s

xyxyxy

s

xyyxyx

dd

dd

σστ

θ

τ

σσ

θ

θτϑσσ

ϑϑτ

θ

τσσσσ

σ

−=

−=

=

+

−=

+

−±

+=

Page 19: Introduction to Mechanics-I

Prof. Ramesh Singh

Maximum Shear Stresses

22

max 2

in of valuengsubstituti

45

9022

2cot2tan

xyyx

xys

ps

ps

ps

τσσ

τ

τθ

θθ

θθ

θθ

+

−=

±=

±=

−=

Page 20: Introduction to Mechanics-I

Prof. Ramesh Singh

Equations of Mohr’s Circle

Page 21: Introduction to Mechanics-I

Prof. Ramesh Singh

Mohr’s Circle

Page 22: Introduction to Mechanics-I

Prof. Ramesh Singh

Page 23: Introduction to Mechanics-I

Prof. Ramesh Singh

Page 24: Introduction to Mechanics-I

Prof. Ramesh Singh