industrial electronics 2 controlled rectifiers
DESCRIPTION
electronics Circuit AnalysisTRANSCRIPT
HALF CONTROLLED RECTIFIERS
With a Resistive Load:
SITUATION NO. 1:A half wave controlled rectifier is supplied from a 120V source. If the load resistance is 10Ω,
1. Find the load voltage and power to the load for a 0o delay angleA. 45V , 200WB. 54V , 293W * C. 35V , 150W D. 53V , 300W
2. Find the load voltage and power to the load for a 45 o delay angleA. 45V , 200WB. 35V , 150WC. 46.2V , 213W*D. 53V , 300W
3. Find the load voltage and power to the load for a 90o delay angleA. 27.1V , 73.2W*B. 45V , 200WC. 35V , 150WD. 53V , 300W
4. Find the load voltage and power to the load for a 135o delay angleA. 53V , 300WB. 7.72V , 6.3W*C. 35V , 150WD. 53V , 300W
5. Find the load voltage and power to the load for a 180o delay angleA. 35V , 150WB. 53V , 300WC. 35V , 250WD. 0V , 0 W*
+Vo -
R
K
G
A i
Average Value of the output voltage :Voave = ( Vop / 2π ) ( 1 + cos α )
RMS Value of the output voltage :Vorms = ( Vop / 2 ) [ 1 – α/π + (sin 2α ) / 2π ]1/2
For an input voltage ofvin = Vinp sin wt
0 α π 2π
SITUATION NO.2:A half-wave controlled rectifier connected to a 150V, 60hz source is supplyng a resistive loadof 10Ω. If the delay angle is 300
6. Calculate the maximum load currentA. 12.2AB. 21.2A*C. 22.1AD. 20.2A
7. Calculate the average load voltageA. 63V*B. 64VC. 65VD. 66V
8. Calculate the average load currentA. 6.0AB. 6.1AC. 6.2AD. 6.3A*
9. Calculate the rms load currentA. 10.4AB. 10.5A*C. 10.6AD. 10.7A
10. Calculate the power supplied to the loadA. 1904WB. 1094W*C. 9140WD. 1940W
11. Calculate the conduction angleA. 90O
B. 150O*C. 45O
D. 35O
12. Calculate the ripple frequencyA. 60hzB. 120hzC. 240hzD. 480hz
13. Calculate the power power factorA. 0.8B. 0.75C. 0.65D. 0.69*
14. A half-wave controlled rectifier is connected to a 120V source. Calculate the firing angle necessary to deliver 150W of power to a load of 10Ω A. 90O
B. 150O*C. 45O
D. nota
With an Inductive ( RL) Load:
With a freewheeling diode:
L +
Vo
R -
G
KA
For an input voltage ofvin = Vinp sin wt
Average Value of the output voltage :Voave = ( Vop / 2π ) ( cos α - cosβ )
RMS Value of the output voltage :Vorms = ( Vop / 2 ) [ β/π – α/π + (sin2α – sin2β ) / 2π ]1/2
0 α π 2π β
i
i0 α π 2π
Average Value of the output voltage :Voave = ( Vop / 2π ) ( 1 + cos α )
RMS Value of the output voltage :Vorms = ( Vop / 2 ) [ 1 – α/π + (sin 2α ) / 2π ]1/2For an input voltage of
vin = Vm sin wt
FULL WAVE CONTROLLED CENTER TAPPED RECTIFIERS
With a Resistive Load:
With an Inductive ( RL) Load:
With a freewheeling diode:
G
A K
A K
G
For an input voltage ofvin = Vinp sin wt
0 α π (π+α) 2π
Average Value of the output voltage :Voave = ( Vop /π ) ( 1 + cos α )
RMS Value of the output voltage :Vorms = ( Vop / √2 ) [ 1 – α/π + (sin 2α ) / 2π ]1/2
For an input voltage ofvin = Vinp sin wt
Average Value of the output voltage :Voave = ( 2Vop /π ) cos α
RMS Value of the output voltage :Vorms = Vinrms
For an input voltage ofvin = Vinp sin wt
Average Value of the output voltage :Voave = ( Vop /π ) ( 1 + cos α )
RMS Value of the output voltage :Vorms = ( Vop / √2 ) [ 1 – α/π + (sin 2α ) / 2π ]1/2
FULL WAVE CONTROLLED BRIDGE RECTIFIERS
With a Resistive Load:
SITUATION NO. 3:A fulll wave bridge controlled rectifier is supplied from a 150 V source with a load resistance of 10Ω . If the firing angle α is 30o
15. Calculate the average load voltageA. 126V*B. 216VC. 612VD. 162V
16. Calculate the average load currentA. 12.6V*B. 21.6VC. 61.2VD. 16.2V
17. Calculate the maximum load currentA. 12.2AB. 21.2A*C. 31.2AD. 13.2A
18. Calculate the RMS load currentA. 12.2AB. 14.8A*C. 31.2AD. 13.2A
19. Calculate the power supply to the loadA. 2182W*B. 1282WC. 8212WD. 8128W
SCR 1 SCR 2
SCR 3 SCR 4
i
+
Vo
-
R 0 α π (π+α) 2π
Average Value of the output voltage :Voave = ( Vop /π ) ( 1 + cos α )
RMS Value of the output voltage :Vorms = ( Vop / √2 ) [ 1 – α/π + (sin 2α ) / 2π ]1/2
For an input voltage ofvin = Vinp sin wt
20. Calculate the ripple frequencyA. 60HzB. 120Hz*C. 240HzD. 480Hz
21. Calculate the power factorA. 0.707B 0.6.C. 0.8D. 0.98*
With an Inductive ( RL ) Load:
With a free wheeling diode:
TAKE HOME EXAM
For an input voltage ofvin = Vinp sin wt
Average Value of the output voltage :Voave = ( Vop /π ) ( cos α – cos β )
Average Value of the output voltage :Voave = ( Vop /π ) ( 1 + cos α )
RMS Value of the output voltage :Vorms = ( Vop / √2 ) [ 1 – α/π + (sin 2α ) / 2π ]1/2
For an input voltage ofvin = Vinp sin wt