ic in one shot
TRANSCRIPT
with
ABHISHEK K RB.Tech - Aerospace, Alliance University
CBSE Expert | Inventor of RocketPro6+ Years Teaching Exp | Mentored more than 5000 studentsHelped 1000s of students get 10 CGPA in CBSE X
Force and Laws of Motion In One Shot
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Balanced & Unbalanced Forces
Momentum & Second law of Motion
Inertia & 1st law of motion
Third law of motion & Conservation of momentum
For
ce &
law
s of
Mot
ion
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
Force is a Push or Pull
To push or pull heavy objects more force is required. Thus force has Magnitude
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
Force is a Push or Pull
To push or pull heavy objects more force is required. Thus force has Magnitude
Force has direction tooForce is a vector Quantity
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
Balanced Forces
In a system, when net force is equal to zero, it is called Balanced Force system
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
Unbalanced Forces
In this system, the net force is towards the left and it will cause the box move towards left.
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
Unbalanced Forces
In a system, when net force is not equal to zero, it is called Unbalanced Force system
Q1. Find the value of x if system is a unbalanced force system with net force equal to 10 units towards left.
12 14
9 15
A B
C D
Q1. Find the value of x if system is a unbalanced force system with net force equal to 10 units towards left.
12 14
9 15
A B
C D
Q1. Find the value of x if system is a unbalanced force system with net force equal to 10 units towards left.
As the friction force is zero, there is no force applying on the ball to decrease its speed.
The ball will continue to move with the same constant speed.
Newton’s first law
An object remains in a state of rest or in uniform motion in a straight line unless an external unbalanced force is applied on it.
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
The property of maintaining state of rest or to keep moving with uniform velocity is called inertia of the body.
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
https://www.stickmanphysics.com/stickman-physics-home/forces/
Heavy objects tends to resist more towards change in state of motion.
Objects with greater mass has greater INERTIA.
To decrease its speed
To increase its speed
To resist any change in its state of motion
To decelerate due to friction
A B
C D
Q2. The inertia of an object tends to cause the object
To decrease its speed
To increase its speed
To resist any change in its state of motion
To decelerate due to friction
A B
C D
Q2. The inertia of an object tends to cause the object
Move forward Move backward
Be unaffected Rise upwards
A B
C D
Q3. A water tanker filled up to 2/3 of its height is moving with a uniform speed. On sudden application of the brake, the water in the tank would
Move forward Move backward
Be unaffected Rise upwards
A B
C D
Q3. A water tanker filled up to 2/3 of its height is moving with a uniform speed. On sudden application of the brake, the water in the tank would
F ∝ Velocity (v)
F ∝ Mass (m)
We can say that there is a quantity relating mass and velocity affecting force
This Quantity is called Momentum
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
SI Unit of momentum is Kgm/s
It is denoted by P.P= mv
Momentum is the product of mass and velocity.
Momentum is a vector Quantity .Its direction is same as direction of velocity
Unchanged Zero
Quadrupled Doubled
A B
C D
Q4. A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but with twice the mass then its momentum would be
Q4. A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but with twice the mass then its momentum would be
Unchanged Zero
Quadrupled Doubled
A B
C D
Q4. A freight train rolls along a track with considerable momentum. If it were to roll at the same speed but with twice the mass then its momentum would be
15000 Kg m/s 15000 Kg Km/hr
54000 Kg m/s 54000 g m/s
A B
C D
Q5. The speed of a car weighing 1500 kg increases from 36 km/h to 72 km/h uniformly. What will be the change in momentum of the car?
Q5. The speed of a car weighing 1500 kg increases from 36 km/h to 72 km/h uniformly. What will be the change in momentum of the car?
15000 Kg m/s 15000 Kg Km/hr
54000 Kg m/s 54000 g m/s
A B
C D
Q5. The speed of a car weighing 1500 kg increases from 36 km/h to 72 km/h uniformly. What will be the change in momentum of the car?
Change in momentum is directly proportional to force
the force is inversely proportional to the time taken for change of momentum
F ∝ p2― p1
F ∝ 1/t
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
F = ma
DERIVATION
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
Newton’s second law of motion gives the measure of force acting on an object as the product of its mass and acceleration
Force applied on an object is the rate of change of momentum
50 N 100 N
200 N 10 N
A B
C D
Q6. An object of 50 kg gets the speed of 10m/s in 5 second from zero velocity. Calculate the required force applied by engine of the car.
Q6. An object of 50 kg gets the speed of 10m/s in 5 second from zero velocity. Calculate the required force applied by engine of the car.
50 N 100 N
200 N 10 N
A B
C D
Q6. An object of 50 kg gets the speed of 10m/s in 5 second from zero velocity. Calculate the required force applied by engine of the car.
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6 subjects = 8 classes/day (You can have UNLIMITED!)
1 week = 48 classes or 50 classes(Rounding off since I hate maths)
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Let’s do the Tabahi Math!!
Coupon CodeAKPRO ₹ 2294 /- ₹ 5949 /- ₹ 9774 /-
6 subjects = 8 classes/day (You can have UNLIMITED!)
1 week = 48 classes or 50 classes(Rounding off since I hate maths)
1 month = 50 x 4 weeks = 200 classes(Aur kitna padhoge?)
Per Class Price ₹ 2294 /- ₹ 5949 /- ₹ 9774 /-
200 600 1200
Per Class Price ₹ 11.47 /- ₹ 9.19 /- ₹ 8.145 /-
(Ya I know Decimals!!)
Lesser than Your
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
While swimming
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
Action and reaction force are equal in magnitude and opposite in direction. But acceleration of the objects depends upon their masses.
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
In simple terms, “EVERY ACTION HAS AN EQUAL AND OPPOSITE REACTION.”
Weight of the arrow
Arrow pushing against bow string
Air resistance against the bow
Grip of the archers hand on the bow
A B
C D
Q7. An archer shoots an arrow. Consider the action force to be the bowstring against the arrow. What will be the reaction force?
Weight of the arrow
Arrow pushing against bow string
Air resistance against the bow
Grip of the archers hand on the bow
A B
C D
Q7. An archer shoots an arrow. Consider the action force to be the bowstring against the arrow. What will be the reaction force?
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
By newton’s third law
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
Force applied by ball a on ball b (Fab) will be
Force applied by ball b on ball a (Fba) will be
FAB = -FBA
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
FAB = -FBA
Solving further, We get
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
We can see that,
The total momentum before collision and total momentum after collision remains same provided no external force acts. This is called Law of Conservation of Momentum.
Source: https://giphy.com/gifs/light-road-speed-3oGRFrD8HqAUe5CXIc
We can see that,
The total momentum before collision and total momentum after collision remains same provided no external force acts. This is called Law of Conservation of Momentum.
For an ideal collision, no external force acts on the system.
0.1 m/s 1 m/s
0.01 m/s 0
A B
C D
Q8. A man wearing a bullet-proof vest stands on roller skates. The total mass is 80 kg. A bullet of mass 20 g is fired at 400 m/s. It is stopped by the vest and falls to the ground. What is then the velocity of the man?
Q8. A man wearing a bullet-proof vest stands on roller skates. The total mass is 80 kg. A bullet of mass 20 g is fired at 400 m/s. It is stopped by the vest and falls to the ground. What is then the velocity of the man?
0.1 m/s 1 m/s
0.01 m/s 0
A B
C D
Q8. A man wearing a bullet-proof vest stands on roller skates. The total mass is 80 kg. A bullet of mass 20 g is fired at 400 m/s. It is stopped by the vest and falls to the ground. What is then the velocity of the man?
0.1 m/s 2.5 m/s
5 m/s 0
A B
C D
Q9. Two objects each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m/s before the collision during which they stick together. What will be the velocity of the combined object after the collision?
Q9. Two objects each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m/s before the collision during which they stick together. What will be the velocity of the combined object after the collision?
0.1 m/s 2.5 m/s
5 m/s 0
A B
C D
Q9. Two objects each of mass 1.5 kg are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 m/s before the collision during which they stick together. What will be the velocity of the combined object after the collision?
Q10. A bullet of mass 25 g is horizontally fired with a velocity 200 ms-1 from a pistol of mass 2.5 kg. What is the recoil velocity of pistol?