Honors ChemistryHonors ChemistryFinal Exam ReviewFinal Exam Review

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Convert 15.2 m/s to km/hrConvert 15.2 m/s to km/hr

1. 54.7 km/hr

2. 0.912 km/hr

3. 4.22 km/hr

4. 5.47 x 107

5. not listed

Converting Word Equations into Converting Word Equations into Chemical EquationsChemical Equations

Converting Word Equations into Converting Word Equations into Chemical EquationsChemical Equations

Strontium iodide + Lead (II) phosphate Strontium phosphate + lead (II) iodide

SrI2 + Pb3(PO4)2 ---->

Sr3(PO4)2 + PbI2

3

3

Practice Quiz Practice Quiz Net Ionic EquationsNet Ionic Equations

Write the molecular, complete ionic, and net ionic equations for this reaction: Silver nitrate reacts with calcium chloride

Molecular:

2AgNO3 + CaCl2 2AgCl + Ca(NO3)2

Complete Ionic:

2Ag+ + 2NO3-+ Ca2+ + 2Cl- 2AgCl + Ca2+ +

2NO3-

Net Ionic:

2Ag+ + 2Cl- 2AgCl

Mixed PracticeMixed Practice

• State the type, predict the products, and balance the following reactions:

1. BaCl2 + H2SO4

2. C6H12 + O2

3. Zn + CuSO4

4. Cs + Br2

5. FeCO3

Double Displacement

Combustion

Single Displacement

Synthesis

Decomposition

Try This…Try This…

• Predict the products, balance the following reactions and show the change in oxidation numbers :

• Zinc reacts with aqueous copper (II) sulfate• Zinc is higher relative activity so…

Zn + CuSO4 Cu + ZnSO4

Each Zn loses 2e- oxidation, reducing agent

Each Cu(II) gains 2e- reduction, oxidizing agent

Review Mass-Mole-Molecules: Review Mass-Mole-Molecules: Determine the number of molecules in Determine the number of molecules in

73 g of water73 g of water

73 g H2O

# H2O molecules =

x 1 mol H2O

18.02 g H2O

= 2.4 x 1024 molecules H2O

x 6.02x1023 molecules

1 mol H2O

Try this one:Try this one:

Calculate the mass in grams of iodine required to react completely with 0.50 moles of aluminum.

Al + I2 AlI32 Al + 3 I2 2 AlI3

= 190 g I2

0.50 mol Al x 3 mol I2 2 mol Al

x 253.80 g I2

1 mol I2

0.50 g Al

Try this one:Try this one:

Calculate the mass in grams of iodine required to react completely with 0.50 g of aluminum.

Al + I2 AlI32 Al + 3 I2 2 AlI3

= 7.1 g I2

x 3 mol I2 2 mol Al

x 253.80 g I2

1 mol I2

x 1 mol Al

26.98 g Al

x 3 mol Zn

2 mol MoO3

What mass of ZnO is formed when 20.0 g of MoO3 is reacted with 10.0 g of Zn?

20.0 g MoO3 x 1 mol MoO3

143.94 g MoO3

3 Zn + 2 MoO3 Mo2O3 + 3 ZnO

x 65.39 g Zn

1 mol Zn

= 13.6 g Zn

x 3 mol ZnO

3 mol Zn

What mass of ZnO is formed when 20.0 g of MoO3 is reacted with 10.0 g of Zn?We need 13.6 g of Zn so Zn is limiting!

10.0 g Zn x 1 mol Zn

65.39 g Zn

3 Zn + 2 MoO3 Mo2O3 + 3 ZnO

x 81.39 g ZnO

1 mol ZnO

= 12.4 g ZnO

x 118.00 g SbI3

130.1 g SbI3

Determine the percent yield if 118.00 g of antimony (III) iodide is produced.

130.1 g of Sbl3 should have been produced. What is the percent yield?

2 Sb + 3 I2 2 SbI3

= 90.70 % Yield

x 100

Empirical Formulas:

72% iron and 28% oxygenDetermine the formula for this substance.

moles of Fe 72 g Fe

55.85 g/mole

= 1.29 moles Fe

moles of O = 28 g O

16.00 g/mole

= 1.75 moles O

Formula:

1.29 1.75 Fe O 1.29 1.75 1.36

1.29 1.29

Fe FeOO

Empirical Formulas #9:

72% iron and 28% oxygenDetermine the formula for this substance.

Multiply subscripts by 3 to get

1.29 1.75 Fe O 1 1.36 3/3 4/3Fe Fe OO

3 4 Fe O

How much water do I need to add to 250 How much water do I need to add to 250 mL of 3.0 M HCl to dilute it to 1.0 M HCl?mL of 3.0 M HCl to dilute it to 1.0 M HCl?How much water do I need to add to 250 How much water do I need to add to 250 mL of 3.0 M HCl to dilute it to 1.0 M HCl?mL of 3.0 M HCl to dilute it to 1.0 M HCl?

= 0.75 L Total, therefore 0.50 L

3.0 M HCl x 0.250 L

= 1.0 M HCl x L

Name HCl.Name HCl.

1. Hydrogen chloride

2. Hydrochloric acid

3. Chloric acid

4. Perchloric acid

5. Chlorous acid

6. Hypochlorus acid

7. I have no idea!!

8. Who cares??1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

21 22 23 24 25 26 27 28 29 30

Name HClOName HClO44..

1. Hydrogen chloride

2. Hydrochloric acid

3. Chloric acid

4. Perchloric acid

5. Chlorous acid

6. Hypochlorus acid

7. I have no idea!!

8. Who cares??1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

21 22 23 24 25 26 27 28 29 30

Name Fe(OH)Name Fe(OH)33

1. Iron (III) Hydroxide

2. Iron Hydroxide

3. Ironic Acid

4. Iron (I) Hydroxide

5. Iron Oxyhydride

6. Not listed

Which of the following definitions of Which of the following definitions of an acid includes conjugate acids?an acid includes conjugate acids?

1. Arrhenius

2. Bronsted-Lowry

3. Lewis

4. Kenzig

5. Woods

6. Toburen

7. Sabol

8. Sanson

Identify the conjugate base in the Identify the conjugate base in the following equation.following equation.

1. NH3

2. H2O

3. NH4+

4. OH-

HH22O + COO + CO332-2- OH OH-- + HCO + HCO33

According to Bronsted-Lowry theory, in According to Bronsted-Lowry theory, in the above reaction, Hthe above reaction, H22O is a(n)O is a(n)

1. Acid

2. Base

3. Conjugate acid

4. Conjugate base

According to Lewis theory, PClAccording to Lewis theory, PCl33 is a(n) is a(n)

1. Acid

2. Base

3. Salt

4. Conjugate Acid

5. Conjugate Base

The pOH of a 0.0030M solution of The pOH of a 0.0030M solution of HH22SOSO44 is: is:

1. 2.52

2. 11.48

3. 2.22

4. 11.78

5. 0.99

6. 13.01

100.0 mL of 3.000 M nitric acid 100.0 mL of 3.000 M nitric acid neutralizes 3.000 M of aluminum neutralizes 3.000 M of aluminum

hydroxide. How many mL of the base hydroxide. How many mL of the base did you use?did you use?

1. 100.0 mL

2. 50.00 mL

3. 33.33 mL

4. 16.67 mL

5. 8.333 mL

6. Not listed

Learning CheckLearning Check

A gas has a volume of 675 mL at 35°C and 0.850 atm pressure. What is the temperature in °C when the gas has a volume of 0.315 L and a pressure of 802 mm Hg?

CalculationCalculation

P1 = 0.850 atm V1 = 675 mL T1 = 308 K

P2 = 1.06 atm V2 = 315 mL T2 = ??

P1 V1 P2 V2

= P1 V1 T2 = P2 V2 T1

T1 T2

T2 = 1.06 atm x 315 mL x 308 K

0.850 atm x 675 mL

T2 = 179 K - 273 = -94 °C

= 179 K

Zinc will react with hydrochloric acid. The Zinc will react with hydrochloric acid. The hydrogen gas is collected through water at hydrogen gas is collected through water at

30.030.0ooC and 782 mm Hg. The vapor C and 782 mm Hg. The vapor

pressure of water at 30.0pressure of water at 30.0ooC is 32.0 mm Hg. C is 32.0 mm Hg. What is the partial pressure of H What is the partial pressure of H22??

1. 250 atm

2. 314 atm

3. 0.329 atm

4. 0.987 atm

5. Not listed

Zinc ( 65.39 g/mole) will react with Zinc ( 65.39 g/mole) will react with hydrochloric acid. Determine the grams of hydrochloric acid. Determine the grams of zinc that must be reacted to produce this zinc that must be reacted to produce this quantity of hydrogen if the volume is 142 quantity of hydrogen if the volume is 142

mL . (P = 0.987 atm, T = 30.0mL . (P = 0.987 atm, T = 30.0ooC) C)

1. 0.112 g

2. 1.18 g

3. 628 g

4. 0.000 628 g

5. 0.369 g

When a gas forms a liquid, which process is taking place?

1. freezing

2. condensation

3. boiling

4. evaporation

Chemical or Physical

Based on the melting points shown in the table, which

material would still be a solid at 400°C?

1. beeswax

2. gold

3. lead

4. oxygen

Based on the melting points shown in the table, which

material would still be a solid at 400°C?

1. beeswax

2. gold

3. lead

4. oxygen

Substance Melting Point (°C)

Beeswax 62

Gold 1,063

Lead 327

Oxygen –218

Substance Melting Point (°C)

Beeswax 62

Gold 1,063

Lead 327

Oxygen –218

Chemical or Physical

A chemical change for a piece of metal would be

1. being bent in half.

2. getting cut into two pieces.

3. being painted.

4. getting rusty.

States of Matter States of Matter List the Location of Each List the Location of Each

Change of StateChange of State

Solid

Liquid

Gas

Energy

Melting

Deposition Freezing Sublimation

Condensation Boiling

Energy

Energy

List the Location of Each List the Location of Each Enthapy Used to Change StateEnthapy Used to Change State

Solid

Liquid

Gas

Energy

Heat of Fusion

Heat of Vaporization

Energy

Energy

Determine the energy released in Determine the energy released in joules as a 152.00 g sample of metal joules as a 152.00 g sample of metal

(0.0335 cal/g(0.0335 cal/gooC cools 51.5C cools 51.5ooCC

q = cp x m x t:

q = x Jcp = 0.0335 cal/goC (4.184 J/cal)

m = 152.00 g t = -51.5oC

x = (0.140164 J/goC )(152.00 g)(-51.5 oC)

= -1.10 x 103 J

Zinc will react with hydrochloric acid. Zinc will react with hydrochloric acid. What are the 2 products for this What are the 2 products for this

reaction? reaction?

1. ZnCl + H

2. ZnCl + H2

3. Zn2Cl + H2

4. ZnCl2 + H2

5. Not listed

Zinc will react with hydrochloric acid. Zinc will react with hydrochloric acid. What kind of reaction is this? What kind of reaction is this?

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

21 22 23 24 25 26 27 28 29 30

1. DD

2. SD

3. Synthesis

4. Decomposition

5. Not listed

Zinc will react with hydrochloric acid. This Zinc will react with hydrochloric acid. This reaction will form reaction will form ZnCl ZnCl22 + H + H22. What are the . What are the

4 coefficients for the balanced chemical 4 coefficients for the balanced chemical equation?equation?

1. 1,2,1,2

2. 2,1,2,1

3. 1,1,1,1

4. 2,2,1,2

5. Not listed

As you leave Chemistry always

remember:

You may not be perfect...

but parts of you are

excellent!!!

The End!!!