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Nuclear Rotation
Experimental evidences for collective modes
Deformed Nuclei, shell model
Indicators for rotational collectivity: moment of inertia, electric quadrupole moment, lifetime measurements
The energy spectra shope different structuresdepending on the number n of nucleons outside the closed shell
shell modelstates:
n = ± 1, ± 2 …middle shell:
simple spectra
Even-even Nuclei: how can one interprete the energies of the 2+ states?
E [M
eV]
A
2 MeV
100 keV
energy forbreaking a pair
Energy of 2+ state decreases with A
0+ (ground state): all nucleons are coupled to spin 0
2+ (first excited state): in middle shells the nucleus realizes anintrinsic configuration energetically
more favoured than the breaking of a pair
even-even Nuclei: how to explain E(4+)/E(2+) and Q(2+) ?E(
4+)/
E(2
+ ) [M
eV]
A
3.3
2
A<150: E(4+)/E(2+) ~ 2150<A<190 e A>230: E(4+)/E(2+) ~ 3.3
Q(2
+ ) [b] A
Q ∝ <r2>
E(4+)/E(2+) ratio
A<150 Q(2+) ~ 0150<A<190 e A>230: Q(2+) grande
electric quadrupole Q(2+)
Two different collective behaviour : A<150 vibration of a stable spherical nucleus
150<A<190 rotation of a stable deformed nucleus
Collective Vibrations and Rotations
Vibrational Nucleus
120Te
I Energy [keV]0+
2+
4+
6+
0
560.6
1161.9
1776.6ωh⋅= nE n
ωh
E(4+)/E(2+) ~ 2
Rotational Nucleus
168Yb
I Energy [keV]087285.8584.5
969.1
1424.5
1935.1
0+2+4+6+
8+
10+
12+1)(
2
2
+ℑ
= IIE h
E(4+)/E(2+) ~ 3.3
Rotational Motion: It can be observed only in nucleiwith stable equilibrium deformation
deformed nuclei
[ ]),(1),( 20 φθβφθ YRR av +=
The shape of the nucleus isrepresented byan ellipsoid of revolution:
deformation parameter β(ellipsoid eccentricity):
3/10
534
ARR
RR
av
av
=
∆=
πβ
50 100 150 2000
50
100
150
0
Number of neutrons N
Num
bero
f pro
tons
P
β0.450.400.350.300.250.200.150.100.05
ground statequadrupole deformation
β>0 prolate β<0 oblate
Nuclear Shapes
the deformed potential givesthe nuclear shape
(Bohr & Mottelson, 1950)
deformed harmonic oscillator
f7/2 [n,l,j,mj]εΩ
appearance of new magic numbers:• superdeformed nuclei (2:1)• hyperdeformed nuclei (3:1)
1:2 2:1 3:1
the energy levels loosethe (2j+1) degeneracy
Nilsson diagram for neutrons in a prolate deformed potentialen
ergy
/hω
β
[N,l,j,mj]π = (-1)N
Ω = mj
±1/2 ±3/2±5/2
±7/2
at ω=0 the energy levels show a 2 fold degeneracy: ±mj
f7/2
New magic numbersNew minima at larger deformations
Rotation removes the time-reversal invariance
ωr
Hω=Ho-hωjx
The Coriolis interaction gives rise to forces of opposite sign,
depending whether a nucleon moves clockwise or anti-clockwise
⇒ splitting of ±mj energy levels
⇒ changes of shell structureswith rotation Appearance of favorite deformed
minima at high spins
la rotazione provoca una rottura nella degenerazione in mj
Nilsson pairingcranking
[N,l,j,±mj][N,l,j,±mj]
[N,l,j,+mj][N,l,j,-mj]
±1/2 ±3/2
±5/2
±7/2
ad ω=0 i livelli hanno degenerazione 2
Yrast
projectilenucleus
targetnucleus
fusionfast
fission10-22 seccompound nucleus
formation
hω ∼ 0.75 MeV∼ 2×1020 Hzrotation
10-19sec
10-15sec
10-9 sec
groundstateI
E* E1
E2
compound nucleusγ−decay
Heavy ion reactionsallow to populatenuclear states
at high angular momenta( ≥40 h)
A
l(h)
Angular momentum limits(liquid drop calculations)
Bf=8 MeV
Bf= 0triaxial
oblate
Eγ1 Eγ2
γ spectrum
1
24
5
36
Eγ2
Eγ1
10-15 sec
γ detector∆t ∼ 10-8 sec
Eγ2
Eγ1
γ cascade
Eγ [keV]200 400 600
rotational energy of a body withmoment of inerzia ℑangular velocity ω = I/ ℑ
Eγ
rotationalband
12+
10+
8+
6+4+2+0+
1)(222
1 222 +
ℑ→
ℑ=ℑ= IIIE hω
even-even nuclei: 0+, 2+, 4+, 6+, …
E(4+)/E(2+) ~ 3.3
γE∆
ℑ=−+=∆
ℑ=−+=
+ℑ
=
2
2
2
4)()2(
42
)()2()(
1)(2
)(
h
h
h
IEIEE
IIEIEIE
IIIE
γγγ
γ
Channel number
The nucleus is NON a rigid body, is NON an irrotational fluid
)31.01(52 2 β+=ℑ avrigid MR
βπ
2
89
avfluid MR=ℑ
rigidexpfluid ℑ<ℑ<ℑ
this is a consequence of the short range nature of the nuclear force:strong forces exist only among close nucleons→ The nucleus does not show the long range structure typical of rigid bodies
Additional evidence for lack of rigididy:
2'0
0 1)(
ωkIIk
+ℑ=ℑ
++ℑ=ℑ
back-bending
ℑ increases with the rotation(as it happens in fluids, but not in rigid bodies)
“centrifugal stretching”
ℑ is NON constant with I
1)(2
)(2
+ℑ
= IIIE h
ℑ changes with I
back-bending takes places whenthe rotational energy exceeds the energyrequired to break a pair of nucleons
Unpaired nucleons go to different orbitsand change the momet of inertia
The nucleus can constract the rotation in two different ways:
)(1)(2
)(2
iERRIE ++ℑ
=h
iiRI +ℑ=+= ω
collective motion single particlemotion
158Er 147Gd
Deformed nucleus quasi-spherical nucleus
Indicator of collectivity of the nuclear system: the quadrupole moment Q0
Q0 measures the deviation from a symmetric distributionof the nuclear charge distribution
[ ][ ]
000
)(3
)(32222
2222
<>=
><+><+><−><=
++−= ∫zyxzZ
dzyxzQ τρ
spherical shape <z2> = <x2>=<y2>prolate: elongation along z <z2> > <x2>=<y2>oblate: flattening along z <z2> < <x2>=<y2>
oblate
z
prolatez
Large electric quadrupole moments indicate a stable deformation :
measured quadrupole moment+−= 2
72
0 forQQ
)16.01(53 2
0 ββπ
+= ZRQ av
intrinsec quadrupole momenti (osservable only in the intrinsic reference frame)
Q0 can be obtained from the B(E2) reduced transition probability: 22
02 0020
165):2( fifi JJQeJJEBπ
=→
220
2
165)02:2( βπ
∝=→ ++ QeEB
225 )1(08156.0
)2( beE
BEB
totατγ
γ
+=
s13103.0−≈
≈
τ
β
s111005.0−≈
≈
τ
β
γ decay probability=
=
tot
Bα
γ
probability for internal conversion
High Spin limit: 0,1 == totB αγ
sEEB
125 10
)2(08156.0 −×=
γ
τ
in W.U.
γEEB )2(
in MeV
423/40594.01 fmeAWU =expected intensity for 1 transitioninvolving only 1 nucleon
Measurement of nuclear lifetimes τ
τ > 10−3 sdirect measure
10−3 < τ < 10−11 sDelayed coincidence technique
teNtN λ−= 0)(
10−10 < τ < 10−12 sDoppler-recoil method
plunger setupthe produced nuclei escape from the taget
with a velocity v/c
they decay emitting γ’s which are Doppler shifted
the nuclei qre finally completely stoppedinto a stopper, therefore decaying with v/c=0
two peaks are observed:shifted → in flight decaystopped → decay at rest
)cos1(' θγγ cvEE +=
γγ EE ='
Tipical values:v/c ~ 0.1, τ ~ 10-12 s → d ~ 0.03 mm
The ratio of the peak intensities depends on the lifetime τ of the state
10−15 s <τ < 10−12 sDoppler-shift attenuation method(DSAM)the produced nuclei immediately penetrate into a solid backing (Pb o Au)
they immediately start to slow down and at the end they stop
0 < v/c < (v/c)max
the γ emission varies continously in energyEγ < Eγ
‘ < Eγ(1+ v/c cos θ)
from the shape of the peak one extractv/c and therefore τ(once the dE/dx energy loss nechanism is known)
vdxdEE
vxt 1
/∆
=∆
=∆
stopping power
inte
nsit
y time
EγEγ+(∆Eγ)max
DSAM technique
400 800 1200 1600E γ (keV)
0.0
0.2
0.4
0.6
0.8
1.0
F(τ) 10
753
13eb
SD YrastRidgesTriaxial
143Eu: lifetime analysis
5.2+0.4-0.5
MAXcvcv
F)/(
)/()( =τ