go.roguecc.edugo.roguecc.edu/sites/go.roguecc.edu/files/users/cmul... · web viewfind the...

Section 1.2: Measurement

1. = 1 1 } over {4¿, B = 2 5} over {8¿, C = 3 11} over {16 ¿, D = 4 7 } over {8¿, E = 5 15} over {16¿

2. A = 1 3 } over {32¿, B = 2 15 } over {32¿, C = 3 19} over {32¿, D = 4 23 } over {32¿, E = 5 29 } over {32¿

3. A = 1.8 cm, B = 4.1 cm, C = 7.6 cm, D = 11.9 cm4. A = 25 mm, B = 52 mm, C = 76 mm, D = 108 mm,

E = 139 mm5. A = 35, B = 25, C = 32, D = 13, E = 36, F = 16, G =

20, H = 53, I = 19, J = 19, K = 20, L = 26, M = 51, N = 21, P = 19, Q = 33, R = 26, S = 12 *Note: copy machines will have an effect on the measurements (all in millimeters).

6. A = 1 5} over {8¿, B = 1 1} over {8¿, C = 1 15 } over {32¿, D = 5} over {8¿, E = 1 5} over {8¿, F = 23 } over {32¿, G = 29 } over {32¿, H = 2 7 } over {16 ¿, I = 7} over {8¿, J = 7 } over {8¿, K = 29 } over {32¿, L = 1 5} over {32¿, M = 2 5} over {16¿, N = 15} over {16¿, P = 7} over {8¿, Q = 1 15 } over {32¿, R = 1 5} over {32¿, S = 9 } over {16 ¿ *Note: copy machines will have an effect on the measurements.

7. 3 } over {8¿8. 26 boards, spacing = 1 } over {8¿9. a) .025” ≈ 1 } over {32¿

b) .041” ≈ 1} over {32¿c) .065” ≈ 1 } over {16¿

10. Loose pilot holes: 1} over {8¿, 5 } over {32¿, 7 } over {32¿, 1 } over {4¿Tight pilot holes: 3 } over {32¿, 1} over {8¿, 3 } over {16¿, 7 } over {32¿

11. Width = Height = 1 11} over {16 ¿12. 7 9} over {16 ¿13. 15 Rises, Rise height = 7 1} over {16¿14. Number of rises Rise height

20 6 1 } over {16¿ 19 6 3 } over {8¿ 18 6 3} over {4 ¿ 17 7 1 } over {8¿

16 7 9 } over {16 ¿

15.

16.

of 21

X-Coordinate Y - CoordinateP2 0.000 1.875P4 1.250 3.750P6 3.750 0.000P9 1.375 3.000H3 0.625 2.500H6 2.500 2.750H8 1.875 2.250H9 3.000 0.750

X-Coordinate Y - Coordinate

P1−14

−34

P3 -112 2

38

P5 214 3

P7 112 1

14

P8 112 2

14

P10−18 1

14

H1 0 0

H2−78 1

18

H4−78 2

38

H538 2

116

H7 1 1716


17. 41} over {2¿18. 45} over {8¿19.

of 21

Working Depth Clearance Tooth

Thickness.253 in .020 in .199 in

1.687 cm .133 cm 1.325 cm.358 in .028 in .281 in.300 in .024 in .236 in


1. Find the measurements indicated by the arrows on the standard ruler.

A = 1-1/4 in

2. Find the measurements indicated by the arrows on the standard ruler. All measurements fall between 16 ths, answer to the nearest 32nd of an inch.

A = 1-3/32 in

3. Find the measurements indicated by the arrows on the metric ruler in centimeters.

of 21


Answers may vary by 1/10 cm.

A = 1.8 cm B = 4.1 cm C = 7.6 cm D = 11.9 cm

4. Find the measurements indicated by the arrows on the metric ruler in millimeters.

Answers may vary by 1 mm.

A = 25 mm B = 52 mm C = 76 mm D = 108 mm E = 139 mm

5. Measure the dimensions A-S on the part to the nearest millimeter.

Answers may vary by 1 mm.

A = 35 mm D = 13 mm G = 20 mm J = 19 mm M = 51 mm Q = 33 mm

B = 25 mm E = 36 mm H = 53 mm K = 20 mm N = 21 mm R = 26 mm

C = 32 mm F = 16 mm I = 19 mm L = 26 mm P = 19 mm S = 12 mm of 21


of 21


6. Measure the dimensions A-S on the part to the nearest 32nd of an inch.

Answers may vary by

A = 1 J =

B = 1 K =

C = 1 L = 1

D = M = 2

E = 1 N =

F = P =

G = Q = 1

H = 2 R =

I = S =

of 21


7. A fence is to have 11 boards between two posts so that the space between each board is the same. Calculate the distance between each board rounded to the nearest 16th of an inch.

Approach:1. Multiply the number of boards (11) times the width of each board (5-1/4 in).2. Subtract the result from step 1 from the total length (62-1/8 in).3. Divide the result from step 2 by the number of spaces (number of boards plus 1) to get the width of one space

(S).

of 21

Change the answer to 16ths and simplify if possible.

The distance between each board is 3/8 in.


8. A fence is to have 3- 1/2” wide boards between two posts that are 94-1/4” apart so that the space between each board is the same. Calculate the number of boards and the spacing so that the spacing between the boards is as small as possible. Round your answer for the spacing to the nearest 16th of an inch.

Approach:

1. Find the maximum number of boards (N) possible by dividing the space available (94-1/4 in) by the width of one board (3-1/2 in). If the answer does not turn out to be a whole number, round down to the nearest whole number.

2. Multiply the answer from step 1 (N) by the width of one board (3-1/2 in), then subtract the answer from the space available. This will give the total distance available for the spacing between the boards (D).

3. Divide the answer from step 2 by the number of spaces required (you need one more space than the number of boards) to get the space between the boards (S).

To get the spacing between the boards as small as possible, you can have 26 boards with 1/8 in spacing.

of 21


9. Copper pipe is manufactured in three types according to wall thickness. Use the outside and inside diameter measurements from the chart to calculate the wall thickness as a decimal rounded to three places and as a fraction rounded to the nearest 32nd of an inch. All measurements are in inches.

a) Size 3/8 Type Mb) Size 5/8 Type Lc) Size 1-1/4 Type K

Approach:

a) Size 3/8 Type M b) Size 5/8 Type L c) Size 1-1/4 Type K

10. Fill in the missing columns in the pilot hole size chart below. Loose pilot holes

of 21

Wood Screw Pilot Hole SizesScrew

Size

Thread

Diameter

Loose Pilot Hole

Tight Pilot Hole

4 .112

6 .138

11 .203

14 .242


should be fractions rounded up to the nearest 32nd of an inch so that the screw can slide through. Tight pilot holes should be rounded down to the nearest 32nd of an inch so the screw threads have wood to grip.

Approach:

1. Change each diameter to a 32nd of an inch by multiplying by 32/32.2. Round up for loose pilot holes, round down for tight pilot holes.

of 21

Diameter 0.112 (A) Diameter 0.138 (B) Diameter 0.203 (C) Diameter 0.242 (D)


11. If the first aid sign below is scaled down by a factor of nine, find the new dimensions for the overall width and height rounded to the nearest 16th of an inch. Assume the shape to be symmetrical and all dimensions to be in inches.

Approach:Step 1. Divide the current overall width by 9 to get the scaled down width (W).Step 2. Divide the current overall length by 9 to get the scaled down length (L).

Scaled down width (W) Scaled down length (L)

of 21


12. A stair stringer is to be cut with nine rises to reach a deck that is 68 inches above the ground. Construction code stipulates that each rise must be equal so that the stair case will not be a trip hazard. Calculate the height of each rise rounded to the nearest 16th of an inch.

Approach: Find the height of each rise (R) by dividing the total rise (68 in) by the number of rises (9), then round to the nearest 16th of an inch.

of 21


13. A stair stringer is to be cut to reach a 2nd story floor that is 106 inches above the ground floor. Construction code stipulates that each rise must be equal so that the stair case will not be a trip hazard. Calculate the whole number of rises so the height of each rise is as near the ideal of seven inches as possible. Next, use the whole number of rises to calculate the height of each rise rounded to the nearest 16 th of an inch.

Approach:Step 1. Determine the number of rises (N) by dividing the total rise (106 in) by the ideal rise

height (7 in), then round to the nearest whole number.Step 2. Determine the actual rise height (H) by dividing the total rise (106 in) by the number of

rises found in step 1 (N). Round to the nearest 16th in.

Step 1 Step 2

of 21


14. A stair stringer is to be cut to reach a 2nd story floor in a house with nine foot ceilings. The distance from the 1st

to the 2nd floor can be calculated by adding up the height of each material. Bottom plate , stud , two

top plates each, ceiling joist , and subfloor . Construction code stipulates that each rise cannot exceed eight inches and must be equal so that the stair case will not be a trip hazard. Calculate the number of rises and the height of each rise (rounded to the nearest 16 th of an inch) for all possible designs where the rise is between six and eight inches.

Approach:Step 1. Calculate the total rise (R) by adding the height of each material.Step 2a. Find the number of rises (N) for a rise height maximum of 8 in by dividing the answer from step 2 by 8.Step 2b. Find the actual rise height (H) for the number of rises found in step 2a.

Step 1 Step 2a Step 2b

of 21

Note: In step 2a, you must round up in order to maintain a maximum rise height of 8 in. If you rounded own to 15, the rise height would be over 8 in.


In order to answer the remainder of the question, we must consider other designs where the number of rises is less than 8 in but a minimum of 6 in. Therefore increase the number of steps by 1 (17, 18, 19, and so on) until we reach a rise less than 6 in.

Approach: Calculate the rise height (H) for the following number of rises.

17 rises 18 rises 19 rises

20 rises 21 rises

of 21


15. A manufacturer must describe a dimensioned part according to its x & y coordinates for a CNC (computer numerically controlled) machine to produce it. These coordinates are measured relative to a datum. The x-coordinate is the horizontal distance from the datum and the y-coordinate is the vertical distance from the datum. Fill in the chart that locates the holes and points that define the part.

X - Coordinate Y - Coordinate

P2

0 No work required.

1.8750 No work required.

P4

P6

0 No work required.

of 21


P2

P4

P6

P9

H3

H6

H8

H9


P9

H3 0.625 No work required.

H6

H8

H9 0.750 No work required.

Approach: In most cases, there is more than one way to find the correct ordered pair.

To find the x-coordinate, add and/or subtract horizontal measures in order to arrive at the desired point.

To find the y-coordinate, add and/or subtract vertical measures in order to arrive at the desire point.

of 21


16. A manufacturer must describe a dimensioned part according to its x & y coordinates for a CNC (computer numerically controlled) machine to produce it. These coordinates are measured relative to a datum. The x-coordinate is the horizontal distance from the datum, right is positive and left is negative. The y-coordinate is the vertical distance from the datum, up is positive and down is negative. Fill in the chart that locates the holes and points that define the part.

of 21


P1

P3

P5

P7

P8

P10

H1

H2

H4

H5

H7


of 21


P1 No work is required. No work is required.

P3

P5

P7

P8Same as P7.

P10Same as P7.

H1 0 No work is required. 0 No work is required.

H2No work is required. No work is required.

H4Same as H2.

H5

H7


17. Four pieces of equal length are cut from the 20 inch length of round stock. If the saw takes 3/16”, calculate the length of the left over piece as a fraction. All dimensions are in inches.

Approach:

Step 1:Find the total length of the four cut pieces.Step 2: Find the total

amount of kerf taken with four cuts.Step 3: Subtract the total of steps 1 and 2 from the original length of the stock.

18. A length of round stock is to be cut into six equal lengths using a saw that removes 3/8” with each cut. Calculate the length of the equal piece. All dimensions are in inches.

Approach:Step 1: Find the total amount of kerf taken

with five cuts.Step 2: Subtract the answer from step 1 from the starting length.Step 3: Divide the answer from step 2 by 6 pieces.

of 21


19. A section of a gear is shown. Given the formulas below and the circular pitch in the chart, determine the working depth, clearance, and tooth thickness. Answer as decimals rounded to 3 decimal places.

Working Depth = .6366 x Circular PitchClearance = .05 x Circular PitchTooth Thickness = .5 x Circular Pitch

of 21

Circular Pitch Working Depth Clearance Tooth Thickness

.398 inches

2.65 cm

916 inches

4721000 of an inch

go.roguecc.edugo.roguecc.edu/sites/go.roguecc.edu/files/users/cmul... · web viewfind the...

Documents