glencoe algebra 2brine divided by the total solution. percentage of brine in solution. mixture...
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![Page 1: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/1.jpg)
![Page 2: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/2.jpg)
• rational equation
• weighted average
• rational inequality
![Page 3: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/3.jpg)
Solve a Rational Equation
The LCD for the terms is 24(3 – x).
Original equation
Solve . Check your solution.
Multiply each side by 24(3 – x).
![Page 4: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/4.jpg)
Solve a Rational Equation
Distributive Property
Simplify.
Simplify.
Add 6x and –63 to each side.
![Page 5: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/5.jpg)
Solve a Rational Equation
Original equationCheck
x = –45
Simplify.
Simplify.
The solution is correct.
![Page 6: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/6.jpg)
Solve a Rational Equation
Answer: The solution is –45.
![Page 7: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/7.jpg)
A. A
B. B
C. C
D. D A B C D
0% 0%0%0%
Solve .
A. –2
B.
C.
D. 2
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Solve a Rational Equation
The LCD is (p + 1)(p – 1).
Original equation
Solve Check your solution.
Multiply by the LCD.
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Solve a Rational Equation
(p – 1)(p2 – p – 5) = (p2 – 7)(p + 1) + p(p + 1)(p – 1)
p3 – p2 – 5p – p2 + p + 5 = p3 + p2 – 7p – 7 + p3 – p
p3 – 2p2 – 4p + 5 = 2p3 + p2 – 8p – 7
0 = p3 + 3p2 – 4p – 12
Divide commonfactors.
DistributiveProperty
Simplify.
Subtract p3 – 2p2 – 4p + 5from each side.
![Page 10: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/10.jpg)
Solve a Rational Equation
Zero Product
Property
0 = (p + 3)(p + 2)(p – 2)
Factor.
0 = p + 3 or 0 = p + 2 or 0 = p – 2
Original equation
Check Try p = –3.
p = –3
![Page 11: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/11.jpg)
Solve a Rational Equation
Simplify.
Simplify.
Original equation
Try p = –2.
![Page 12: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/12.jpg)
Solve a Rational Equation
Simplify.
p = –2
Simplify.
![Page 13: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/13.jpg)
Solve a Rational Equation
Answer: The solutions are –3, –2 and 2.
Try p = 2.
Original equation
Simplify.
p = 2
Simplify.
![Page 14: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/14.jpg)
A. A
B. B
C. C
D. D A B C D
0% 0%0%0%
A. 4
B. –2
C. 2
D. –4
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Mixture Problem
BRINE Aaron adds an 80% brine (salt and water) solution to 16 ounces of solution that is 10% brine. How much of the solution should be added to create a solution that is 50% brine?
Understand Aaron needs to know how much of asolution needs to be added to anoriginal solution to create a newsolution.
![Page 16: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/16.jpg)
Mixture Problem
Plan Each solution has a certainpercentage that is salt. Thepercentage of brine in the finalsolution must equal the amount ofbrine divided by the total solution.
Percentage of brine in solution
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Mixture Problem
Substitute.
Simplify numerator.
LCD is 100(10 + x).
Solve Write a proportion.
![Page 18: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/18.jpg)
Mixture Problem
Distribute.
Subtract 50x and160.
Divide each side by 30.
Answer: Aaron needs to add ounces of 80% brine solution.
Simplify.
Divide common factors.
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Mixture Problem
Simplify.
Check Originalequation
?
?
0.5 = 0.5 Simplify.
![Page 20: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/20.jpg)
A. A
B. B
C. C
D. D A B C D
0% 0%0%0%
A. 9.6 ounces
B. 10.4 ounces
C. 11.8 ounces
D. 12.3 ounces
BRINE Janna adds a 65% base solution to 13 ounces of solution that is 20% base. How much of the solution should be added to create a solution that is 40% base?
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Distance Problem
SWIMMING Lilia swims for 5 hours in a stream that has a current of 1 mile per hour. She leaves her dock and swims upstream for 2 miles and then back to her dock. What is her swimming speed in still water?
Understand We are given the speed of the current,the distance she swims upstream, andthe total time.
Plan She swam 2 miles upstream against the
current and 2 miles back to the dock with
the current. The formula that relates
distance, time, and rate is d = rt or
![Page 22: Glencoe Algebra 2brine divided by the total solution. Percentage of brine in solution. Mixture Problem Substitute. Simplify numerator. LCD is 100(10 + x). Solve Write a proportion](https://reader031.vdocuments.mx/reader031/viewer/2022040603/5ea06022d0700b529d798c11/html5/thumbnails/22.jpg)
Distance Problem
Solve
Original equation
Time going withthe current plus
time going againstthe current equals
totaltime.
5
Let r equal her speed in still water. Thenher speed with the current is r + 1, andher speed against the current is r – 1.
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Distance Problem
Divide Common Factors
Distribute.
Simplify.
Subtract 4rfrom each side.
(r + 1)2 + (r – 1)2 = 5(r2 – 1) Simplify.
Multiply each side by r2 – 1.
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Distance Problem
Use the Quadratic Formula to solve for r.
Quadratic Formula
x = r, a = 5, b = – 4, and c = –5
Simplify.
Simplify.
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Distance Problem
Answer: Since speed must be positive, the answer is about 1.5 miles per hour.
Check Original equation
r ≈ 1.5 or –0.7 Use a calculator.
r = 1.5?
Simplify.
Simplify.?
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A. A
B. B
C. C
D. D A B C D
0% 0%0%0%
A. about 0.6 mph
B. about 2.0 mph
C. about 4.6 mph
D. about 6.6 mph
SWIMMING Lynne swims for 1 hour in a stream that has a current of 2 miles per hour. She leaves her dock and swims upstream for 3 miles and then back to her dock. What is her swimming speed in still water?
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Work Problems
MOWING LAWNS Wuyi and Uima mow lawns together. Wuyi working alone could complete a particular job in 4.5 hours, and Uima could complete it alone in 3.7 hours. How long does it take to complete the job when they work together?
Understand We are given how long it takes Wuyiand Uima working alone to mow aparticular lawn. We need to determinehow long it would take them together.
Plan Wuyi can mow the lawn in 4.5 hours,
so the rate of mowing is of a
lawn per hour.
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Work Problems
Uima can mow the lawn in 3.7 hours,
so the rate of mowing is of a lawn
per hour.
The combined rate is
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Work Problems
Multiply both sidesby x.
Solve
Write the equation.
Add
Answer: It would take Wuyi and Uima about 2 hours to mow the lawn together.
x ≈ 2.0304 Multiply 1 by
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Work Problems
x ≈ 2
Simplify.
Check
Originalequation
?
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A. A
B. B
C. C
D. D A B C D
0% 0%0%0%
A. about 2 hours and 28 minutes
B. about 2 hours and 36 minutes
C. about 2 hours and 45 minutes
D. about 2 hours and 56 minutes
PAINTING Adriana and Monique paint rooms together. Adriana working alone could complete a particular job in 6.4 hours, and Monique could complete it alone in 4.8 hours. How long does it take to complete the job when they work together?
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Solve a Rational Inequality
Step 1 Values that make the denominator equal to 0 are excluded from the denominator. For this inequality the excluded value is 0.
Related equation
Step 2 Solve the related equation.
Solve
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Solve a Rational Inequality
Multiply each side by 9k.
Simplify.
Add.
Divide each side by 6.
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Solve a Rational Inequality
Step 3 Draw vertical lines at the excluded value and at the solution to separate the number line into regions.
Now test a sample value in each region to determine if the values in the region satisfy the inequality.
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Solve a Rational Inequality
Test k = –1.
k < 0 is a solution.
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Solve a Rational Inequality
Test k = .
0 < k < is not a solution.
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Solve a Rational Inequality
Test k = 1.
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A. A
B. B
C. C
D. D A B C D
0% 0%0%0%
A. x < 0
B. x > 0
C. x < 0 or x > 4
D. 0 < x < 4
Solve .