geometry: similar triangles. ma.912.g.4.5 apply theorems involving segments divided proportionally...

16
Geometry: Similar Triangles

Upload: harriet-powers

Post on 18-Jan-2018

225 views

Category:

Documents


1 download

DESCRIPTION

Similar triangles Definition: Two triangles are similar if and only if their corresponding angles are congruent and corresponding sides are proportional.

TRANSCRIPT

Page 1: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Geometry: Similar Triangles

Page 2: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

MA.912.G.4.5 Apply theorems involving segments divided

proportionallyBlock 28

Page 3: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Similar triangles

Definition: Two triangles are similar if and only if their

corresponding angles are congruent and corresponding sides are proportional.

Page 4: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Tests for similarity of triangles

(AA Similarity) If two angles of one triangles are congruent to two angles of another triangle, then the triangles are similar.

Page 5: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

There is a lot of situations where similar triangles naturally arise

Page 6: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Tests for similarity of triangles cont.

• Side-Side-Side (SSS) Similarity: If the corresponding side lengths of two triangles are proportional, then triangles are similar

• SAS (SAS) Similarity: It the lengths of two sides of one triangle are proportional to the lengths of two corresponding sides of another triangle and the included angles are congruent then the triangles are similar

Page 7: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Proofs using similar triangles

Page 8: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Segments of chords theorem

Theorem: Given AB and CD chords of a circle intersect at point F then AF*FB=CF*FD.

Page 9: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Two-column proof:

• Refer to the following picture:

Page 10: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Two-column proof:Statements:• AB and CD intersect at F• Angle A is congruent to

angle D

• Triangles AFC and DFB are similar

• AF/FD=CF/FB

• AF*FB=CF*FD

Reasoning:• Given• Inscribed angles, and that

intercept the same arc are congruent

• AA similarity principle

• Definition of similar triangles

• Cross products

Page 11: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Secant segments theorem

Theorem: If two secants intersect in an exterior of a circle, then the product of the measures of one secant and its external secant segment is equal to the product of the measures of the other secant and its external secant segment so: AC*AB=AE*DE

Page 12: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Secant segments theorem

Theorem: AB*AC=AD*AE

Page 13: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

First we form two triangles: ACD and AEB to help in the proof.

Page 14: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Paragraph proof:

AC and AE are secant segments. By the Reflective Property angles BAD and DAB are congruent.

Inscribed angles that intercept the same arcs are congruent. So ACD is congruent to AEB. By the definition of similar triangles, AB/AD=AE/AC.

Since the cross products of a proportion are similar , AB*AC=AD*AE.

Page 15: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Proportional Perimeter Theorem

• If two triangles are similar, then the perimeters are proportional to the measures of the corresponding sides

Page 16: Geometry: Similar Triangles. MA.912.G.4.5 Apply theorems involving segments divided proportionally Block 28

Creating illustrations in GeoGebra as aid in proofs

• Discuss how creating the illustrations can help to understand the problem and help in the proof