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Geometry Chapter 13 Review

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Page 1: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

Geometry

Chapter 13 Review

Page 2: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

1 1( , )x y 2 2( , )x y

2 22 1 2 1( ) ( )d x x y y

The distance d between points and is:

Example 2Find the distance between (–3, 4) and (1, –4).

Why? Let’s try an example to find out!

22 )4(413

6416

8054

(-3, 4).

. (1, -4)

4

8

Pythagorean Theorem!

4√5

Page 3: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

2 2 2( ) ( )x a y b r An equation of the circle with center (a, b) and radius r is:

Let’s analyze (x – 0)2 + (y – 0)2 = 81 to see if it really is a circle!!

How could this be a circle?

Page 4: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

2 2( 2) ( 4) 9x y

Find the center and radius of each circle. Sketch the graph.

4. 5.

Center: (2, -4)Radius = 3

.

Page 5: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

Example 1b: Find the slope of the line.Example 1b: Find the slope of the line.

-5 – (-2)=

3 – (- 1) x

y

.

.(-1 , -2)

(3 , -5)

y2 – y1=

x2 – x1

slope

- 3=

4

The slope of the line is3

4- __

Page 6: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

Positive SlopeGreater than 1

Uphill

Steep

Positive SlopeLess than 1

Uphill

Flatter

Negative SlopeGreater than 1

Downhill

Steep

Negative SlopeLess than 1

Downhill

Flatter

Slope = 0

Undefined Slope

Running up the hill is undefined!

Page 7: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

A line with slope 4/3 passes through points (4, -5) and (-2, __ ).

Use the slope formula to find the missing y coordinate.

43

=y – (-5)

-2 – 4

43

=y + 5

-6

Simplify and solve as a proportion

-24 = 3y + 15

-39 = 3yy = -13

-13 y

Page 8: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

• Parallel lines have slopes that are equal.

• Perpendicular lines have slopes that are opposite inverses(change the sign and flip).

Page 9: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

The Midpoint Formula

The midpoint of the segment that joins points (x1,y1) and (x2,y2) is the point

2yy

,2

xx 2121

(-4,2)

(6,8)

282

,2

64- •(1,5)

Page 10: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

Exercises

3. M (3,5) A (0,1) B (x,y)

(6,9)

This is the midpoint

To find the coordinates of B:

x-coordinate:

3 = 0 + x2

6 = 0 + xx = 6

y-coordinate:

5 = 1 + y2

10 = 1 + yy = 9

Page 11: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

II. Standard Form: (Ax + By = C)II. Standard Form: (Ax + By = C). Getting x and y intercepts: (x, 0) . Getting x and y intercepts: (x, 0) and (0, y)and (0, y)

1) 2x + 3y = 61) 2x + 3y = 6

20

3 0

Try the cover up method!!!

.(0, 2)

.(3, 0)

yx

Page 12: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

14

2y x

II. Slope-Intercept Form (y = mx + b): m = slope; b = y-intercept

y = 2

.(0, 4). ..

..

yorizontal

Why?

Thus y=2!!

.(-1, 2) .(6, 2).(-6, 2)

Page 13: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

III. Finding Slope-Intercept Form: (y = mx + b)

3x – 4y = 10

m = _____ b = _____

-3x -3x

-4y = -3x + 10-4 -4 -4

y = 3/4x – 5/2

3/4 -5/2

Page 14: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

IV. Systems of Equations: Two lines in a coordinate plane can do two things: (1) intersect (perpendicular or not) (2) not intersect

(parallel)

Systems Algebraic Graph

By Substitution2x + y = 8y = 2x

Isolate a variable first.This is already done.Then substitute.

( )( ) 2x + (2x) = 8

4x = 8x = 2

Substitute 2 back in for x in the easier equation!!

y = 2x

y = 2(2)

y = 4

The solution to the system is (2, 4)

Graph 2x + y = 8 -2x -2x

y = -2x + 8

y = -2x + 8

Graph y = 2x

y =

2x

.(2,4)

Page 15: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

IV. Systems of Equations: Two lines in a coordinate plane can do two things: (1) intersect (perpendicular or not) (2) not intersect

(parallel)

Systems Algebraic GraphBy Addition w/Multiplication

2x + y = 63x – 2y = 2

Graph 2x + y = 6 -2x -2x

y = -2x + 6

y =

3/2x

– 1

Graph 3x – 2y = 2

y = -2x + 6

.(2,2)

7x = 14

x = 2Substitute 2 back in for x in the easier equation!!

4(2) + 2y = 12

8 + 2y = 12

2y = 4

y = 2

The solution to the system is (2, 2)

-8 -8

-3x -3x -2y = -3x + 2 -2 -2 -2

y = 3/2x – 1

( )24x + 2y = 12

Page 16: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

Given x and y intercepts:

1. x-int: 2 y-int: -3

(2,0) (0,-3)

Notice that the slope is

rise 3

run 2or

(2,0)

(0,-3)

(-3)

2

or y-int

x-int.

The y intercept (b) of -3 is given

The equation in slope intercept form isy = 3

2x - 3

-

opposite

Page 17: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

Given InterceptsTo write the equation in slope-intercept form use the pattern :

y = y-intercept

x-interceptx + y-intercept

slope m b

Page 18: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

7 2 5

4 1 3m

52 ( 1)

3y x

Step 1: Compute slope

Step 2: Use PS Form

Step 3: Simplify to SI Form

+2y = 5/3x + 1/3

Using (1, 2)

Part IV #1: Given 2 points. (1,2) and (4,7)

5 52

3 3y x

6

3

You can check with other point:

7 = 5/3(4) + 1/3

7 = 20/3 + 1/3

7 = 21/3

7 = 7 check!

Page 19: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

x = 8

Part VI #5:

(8,7) and parallel to x = -2

x = 2

Part VI #6:

(2,2) and perpendicular to y = 3

All vertical lines are parallel

A vertical line is perpendicular to a horizontal line

Page 20: Geometry Chapter 13 Review. The distance d between points and is: Example 2 Find the distance between (–3, 4) and (1, –4). Why? Let’s try an example to

• Chapter 13 WS• How can you get 100% on your final?

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