(g) altitude-intercept method 1

Upload: bernard-mamora

Post on 02-Jun-2018

223 views

Category:

Documents


0 download

TRANSCRIPT

  • 8/10/2019 (G) Altitude-Intercept Method 1

    1/39

    One way of fixing position is by means of altitude-

    intercept method and the Navigator must be familiar on

    identifying the celestial body, starsin particular..

  • 8/10/2019 (G) Altitude-Intercept Method 1

    2/39

    Identification of Stars

    Although no formal star identification tables are

    included in Pub. No. 229, a simple approach to star

    identification is to scan the pagesof the appropriate

    latitudes, and observe the combination of arguments

    which give the altitudeand azimuth angleof the observation.

    Thus the declinationand LHA of Ariesare determined directly.

    The stars SHA is found from:

    SHA of the star = LHA of the star LHA of the Aries.

    From these quantities the star can be identified from the

    Nautical Almanac.

  • 8/10/2019 (G) Altitude-Intercept Method 1

    3/39

    Altitude-Intercept Method

    Learning Objectives:

    Comprehend the concept of the circle of equal

    altitude as a line of position.

    Become familiar with the concepts of the

    circle of equal altitude.

    Know the altitude-intercept method of plottinga celestial LOP.

  • 8/10/2019 (G) Altitude-Intercept Method 1

    4/39

    Circle of Equal Altitude

    Imagine a pole attached to a flat surface, with

    a wire suspended from the pole.

    If the wire is held at a constant angle to thepole, and rotated about the pole, it inscribes a

    circle.

    This scenario is depicted on the next slide...

  • 8/10/2019 (G) Altitude-Intercept Method 1

    5/39

  • 8/10/2019 (G) Altitude-Intercept Method 1

    6/39

    Circle of Equal Altitude

    Now, lets make two changes to oursituation:

    make the pole infinitely tall make our surface spherical

    Now we have something similar to the

    earth and the navigational stars. Now our circles look like this...

  • 8/10/2019 (G) Altitude-Intercept Method 1

    7/39

  • 8/10/2019 (G) Altitude-Intercept Method 1

    8/39

    Circle of Equal Altitude

    Now, weneed torelate this

    concept tothenavigation

    triangle:

  • 8/10/2019 (G) Altitude-Intercept Method 1

    9/39

  • 8/10/2019 (G) Altitude-Intercept Method 1

    10/39

  • 8/10/2019 (G) Altitude-Intercept Method 1

    11/39

    Circle of Equal Altitude

    Thus, if we know the altitude of aparticular star, and its location relative tothe earth (which we can determine from

    the NauticalAlmanac),we know that ourposition must lie somewhere on this circleof equal altitude.

    Therefore, the circle of equal altitude is aline of position (LOP).

  • 8/10/2019 (G) Altitude-Intercept Method 1

    12/39

    Circle of Equal Altitude

    Here is a more realistic scenario, where

    our assumed position does not lie exactly

    on the circle of equal altitude...

  • 8/10/2019 (G) Altitude-Intercept Method 1

    13/39

  • 8/10/2019 (G) Altitude-Intercept Method 1

    14/39

    Circle of Equal Altitude

    If we know the altitude of two or more stars, wecan cross the LOPs and arrive at acelestial fix.

    Note that these circles cross at two points;

    however, these points are usually several

    hundred miles apart, and we can therefore rule

    one out. If not, a third star can be used to

    resolve the ambiguity.

  • 8/10/2019 (G) Altitude-Intercept Method 1

    15/39

  • 8/10/2019 (G) Altitude-Intercept Method 1

    16/39

    Circle of Equal Altitude

    Consider a problem with this idea:

    For Ho=60o, the radius of the circle of equal

    altitude is 1800 miles! To plot this with any

    degree of accuracy would require a chart larger

    than this room.

    Instead, we only plot a small portion of thiscircle; this is the basis of theAltitude-Intercept

    Method.

  • 8/10/2019 (G) Altitude-Intercept Method 1

    17/39

    Altitude-Intercept Method

    If we are near the GP, a portion of the

    circle would plot as an arc...

  • 8/10/2019 (G) Altitude-Intercept Method 1

    18/39

  • 8/10/2019 (G) Altitude-Intercept Method 1

    19/39

    Altitude-Intercept Method

    Now, if the distance to the GP is very

    large, the arc becomes a straight line...

  • 8/10/2019 (G) Altitude-Intercept Method 1

    20/39

  • 8/10/2019 (G) Altitude-Intercept Method 1

    21/39

    Altitude-Intercept Method

    Dont forget, we are still essentially drawing a

    circle.

    But were no longer using the radius(determined from the stars altitude) so how do

    we know where, or for that matter, at what

    angle, to draw the line?

  • 8/10/2019 (G) Altitude-Intercept Method 1

    22/39

    Altitude-Intercept Method

    1. First, assume a position based on the ships

    DR plot, and we modify the numbers slightly (for

    ease of calculation).

    2. Select navigational stars to shoot, and

    calculate what the altitude should be (Hc,

    computed altitude), given ourAPand the timeof observation.

  • 8/10/2019 (G) Altitude-Intercept Method 1

    23/39

    Altitude-Intercept Method

    3. Observe the stars altitude using a marinesextant, and determine the observed altitude

    (Ho).

    4. The difference between Hc and Ho,combined with Zn (which we can calculate using

    the Nautical Almanacand Pub 229) is used to

    plot a celestial LOP.

  • 8/10/2019 (G) Altitude-Intercept Method 1

    24/39

    Altitude-Intercept Method

    The difference between Hc and Hois

    known as the intercept distance (a).

  • 8/10/2019 (G) Altitude-Intercept Method 1

    25/39

    Altitude-Intercept Method

    If Ho>Hc, we move towardthe star (alongZn) to plot our celestial LOP.

    Ho Mo To

    If Hc>Ho, we move awayfrom the star,along the reciprocal bearing of Zn, to plotour celestial LOP.

    Computed Greater Away

    Coast Guard Academy

  • 8/10/2019 (G) Altitude-Intercept Method 1

    26/39

    Altitude-Intercept Method

    A picture clearly illustrates the idea...

  • 8/10/2019 (G) Altitude-Intercept Method 1

    27/39

  • 8/10/2019 (G) Altitude-Intercept Method 1

    28/39

    Example

    Now lets try an example to illustrate theconcept:

    A star is observed, and we determine thatHo is 45o00.0

    Based on our AP at the time of

    observation, Hc is 44o45.5

  • 8/10/2019 (G) Altitude-Intercept Method 1

    29/39

    Example

    First, we calculate the intercept distance,a, using a= Ho-Hc

    The result is:Ho 45o00.0

    -Hc 44o45.5

    a 14.5

  • 8/10/2019 (G) Altitude-Intercept Method 1

    30/39

    Computed Altitude Formula

    sin hc = sin L sin d + cos L cos d cos LHA

    Where: hc = Computed Altitude

    L = Latitude

    d = declinationLHA = Local hour angle

    Note: For both same and contrary name cases, the sine and

    cosine functions of latitude are positive. In the contrary name

    case, declination is considered as a negativeangle.

  • 8/10/2019 (G) Altitude-Intercept Method 1

    31/39

    Example

    So our intercept distance is 14.5 nm, andsince Ho>Hc, we must move towardthe

    star to plot our LOP.

    Lets examine again the angular

    relationships, and show how the LOP is

    plotted...

  • 8/10/2019 (G) Altitude-Intercept Method 1

    32/39

    Example

  • 8/10/2019 (G) Altitude-Intercept Method 1

    33/39

    Plotting the Celestial LOP

    Lets assume we made an observation ofVenus, and came up with

    a = 14.8 nm towards Zn=091.5oT

    The plotted LOP is shown on the next

    slide...

  • 8/10/2019 (G) Altitude-Intercept Method 1

    34/39

    Finding Azimuth Formula

    Solution by ABC

    A =Tan Lat x Cot Ha A = Tan Lat / Tan Ha

    B = Tan Dec x Cosec Ha B = Tan Dec / Sin Ha

    C = A + B

    Cot Z = C x Cos Lat.

    NOTE: A is named opposite to Lat except when

    Hour angle is between 90oand 270o.B is always named the same as declination.

  • 8/10/2019 (G) Altitude-Intercept Method 1

    35/39

    How to Solve and Plot the Line of

  • 8/10/2019 (G) Altitude-Intercept Method 1

    36/39

    How to Solve and Plot the Line ofPosition

    Arguments Needed:

    1) Assumed Latitude = 20oN

    2) Assumed Longitude= 067oW

    3) LHA or t = 56oE = 304o

    4) Declination = 12o

    24.3S

    Ho = 26o31.4

    Hc = 26o04.9

    Int = 26.5 towards

    Zn = 115.6oT

    Where: Assumed latitudeis taken asthe nearest whole degree of latitude tothe DR and the assumed longitudeis

    selected so that the local hour angle isa whole degree.

    How to Solve and Plot the Line of

  • 8/10/2019 (G) Altitude-Intercept Method 1

    37/39

    How to Solve and Plot the Line ofPosition

    GHA = 11o32.1

    Assumed longitude = 67o32.1 W

    LHA or t =304oor 56oE

    Arguments to plot (LOP)

    1) Assumed latitude = 20oN

    2) Assumed longitude = 67o32.1W

    3) Intercept = 26.5 towards4) Azimuth = 115.6o

    How to Solve and Plot the Line of

  • 8/10/2019 (G) Altitude-Intercept Method 1

    38/39

    How to Solve and Plot the Line ofPosition

    Note: To remember in West longitude, the minute of your

    Longitude is equal to the minutes of your GHA. (See example).

    In East longitude, do not copy the minutes of your GHA, but

    instead add a number to make it into 1oand carry it to your

    GHA degrees adding to your longitude.

    Example: GHA = 11o32.1

    Assumed long. = 67o27.9 East

  • 8/10/2019 (G) Altitude-Intercept Method 1

    39/39

    Plotting the Celestial LOP

    Note that celestial plotting is usually done

    on a plotting sheet, and once a fix is

    established, the latitude and longitude are

    used to transfer it to thechart.