from last lesson we found… vol = distance x area = speed x time x area
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From last lesson we found… VOL = distance x Area = speed x time x Area # ELECTRONS = charge/charge of 1 electron = current x time / e NUMBER DENSITY, n = # electrons/ vol n = (I x t) n = I/ evA e x v x t x A nAve = I. The big question: What did Kirchoff say? - PowerPoint PPT PresentationTRANSCRIPT
From last lesson we found…
VOL = distance x Area = speed x time x Area# ELECTRONS = charge/charge of 1 electron = current x time / e
NUMBER DENSITY, n = # electrons/vol
n = (I x t) n = I/evA e x v x t x A
nAve = I
The big question: What did Kirchoff say?
Why are we learning this?Supermax (super maximum security) prisonse.g. Alcatraz
Learning Objective: To evaluate Kirchoff’s first law
The big question: What does Kirchoff say?
A – B –C –D -
Calculate velocity
A copper wire has cross-sectional area 3.0 mm2 and current 5.0A. Copper’s number density is 6.0x1028 m-3.
A brass wire has cross-sectional area 6.0mm2 and current 9.0A. Assume Brass’s number density is 9.0x1028 m-3.
A brass wire has radius ½ that of the previous question, with the same current.
On a whiteboard:
(b) A silver wire has cross-sectional area 3.0 mm2 and current 2.0A. Copper’s number density is 4.0x1028 m-3.
(A) If the radius was ¼ as small, then the number of electrons will be what factor smaller?
Learning Objective: To combine knowledge on density and electricity to calculate velocity
The big question: How do we combine density with velocity?
A – Predict insulator number densitiesB – Analyse how number density changes drift velocityC – Create a formula for drift velocity and CurrentD – Calculate drift velocity
Calculate mean drift velocity:
A copper wire has cross-sectional area 4.0 mm2 and current 5.0A. Copper’s number density is 8.0x1028 m-3.
A brass wire has cross-sectional area 6.0mm2 and current 15.0A. Assume Brass’s number density is 9.0x1028 m-3.
(C) Using letters n for number density, I for current, e for charge of 1 electron and A for cross-sectional area, write an expression for v
What do they do?
A – Predict insulator number densities, using your expression from C and B
B – Analyse how number density (n) changes drift velocity. Keep all other numbers the same and change n up and down, to see the effect on velocity
C – Create a formula for drift velocity, v and rearrange it for current, I
Current, I =
nA/ve ve/nA
n/vAe nAve
If the wire had a high number densityV is velocity
v would increase v would stay thesame
v would decrease
If the wire was an insulator
number density number density would increase would decrease
number density would stay same
Learning Objective: To combine knowledge on density and electricity to calculate velocity
The big question: How do we combine density with velocity?
A – Predict insulator number densitiesB – Analyse how number density changes drift velocityC – Create a formula for drift velocity and CurrentD – Calculate drift velocity
Learning Objective: To combine knowledge on density and electricity to calculate velocity
The big question: How do we combine density with velocity?
A – Predict insulator number densitiesB – Analyse how number density changes drift velocityC – Create a formula for drift velocity and CurrentD – Calculate drift velocity