fourier
TRANSCRIPT
Math for CS Lecture 11 1
Lecture 11
Fourier Transforms
Math for CS Lecture 11 2
Fourier Series in exponential form
Consider the Fourier series of the 2T periodic function:
Due to the Euler formula
It can be rewritten as
With the decomposition coefficients calculated as:
(1)
1
0 )sincos(2
)(~
nnn T
nxb
T
nxa
axf
sincos ie i
n
inxnecxf )(
~
T
T
tT
in
n tfeT
c )(2
1
(2)
Math for CS Lecture 11 3
Fourier transform
The frequencies are and
Therefore (1) and (2) are represented as
Since, on one hand the function with period T has also the periods kT for any integer k, and
on the other hand any non-periodic function can be considered as a function with infinite
period, we can run the T to infinity, and obtain the Riemann sum with ∆w→∞, converging to
the integral:
(3)
T
nwn
wdttfeexfn
T
T
iwtiwx
)(2
1)(
~
Tw
dwdttfeexf
T
T
iwtiwx )(2
1)(
~
(4)
Math for CS Lecture 11 4
Fourier transform definition
The integral (4) suggests the formal definition:
The funciotn F(w) is called a Fourier Transform of function f(x) if:
The function
Is called an inverse Fourier transform of F(w).
dttfetfFwF iwt )(:)}({:)(
dwwFewFF iwx )(2
1:)}({1
(6)
(5)
Math for CS Lecture 11 5
Example 1
The Fourier transform of
is
The inverse Fourier transform is
1||
1||
0
1:)(
t
ttf
02
0sin
2)}({1
1 w
ww
wdtetfF iwt
00
0
10
12/1
1||1))1(sin(1))1(sin(1
sincos
2sin
2
2
x
x
x
dww
xwdw
w
xw
dww
wwxdw
w
we iwx
Math for CS Lecture 11 6
Fourier Integral
If f(x) and f’(x) are piecewise continuous in every finite interval, and f(x) is absolutely
integrable on R, i.e.
converges, then
Remark: the above conditions are sufficient, but not necessary.
dwdttfeexfxf iwtiwx )(
2
1)]()([
2
1
Math for CS Lecture 11 7
Properties of Fourier transform
1 Linearity:
For any constants a, b the following equality holds:
Proof is by substitution into (5).
2 Scaling:
For any constant c, the following equality holds:
)()()}({)}({)}()({ wbGwaFtgbFtfaFtbgtafF
)(||
1)}({
c
wF
cctfF
Math for CS Lecture 11 8
Properties of Fourier transform 2
3 Time shifting:
Proof:
4. Frequency shifting:
Proof:
)()}({ 00 wFettfF iwt
dueufedtettfttfF iwuiwtiwt
)()()}({ 0
00
)()}({ 00 wwFtfeF iwt
)()()}({ 000 wwFdtetfetfeF iwtiwttiw
Math for CS Lecture 11 9
Properties of Fourier transform 3
5. Symmetry:
Proof:
The inverse Fourier transform is
therefore
dwewFwfFtf iwt)(2
1)}({)( 1
)(2)}({ wftFF
)}({)(2
1)(2 tFFdtetFwf itw
Math for CS Lecture 11 10
Properties of Fourier transform 4
6. Modulation:
Proof:
Using Euler formula, properties 1 (linearity) and 4 (frequency shifting):
)]()([2
1)}sin()({
)]()([2
1)}cos()({
000
000
wwFwwFtwtfF
wwFwwFtwtfF
)]()([2
1
)}]({)}({[2
1)}cos()({
00
000
wwFwwF
tfeFtfeFtwtfF tiwtiw
Math for CS Lecture 11 11
Differentiation in time
7. Transform of derivatives
Suppose that f(n) is piecewise continuous, and absolutely integrable on R. Then
In particular
and
Proof:
From the definition of F{f(n)(t)} via integrating by parts.
)()()}({ )( wFiwtfF nn
)()}({ ' wiwFtfF )()}({ 2'' wFwtfF
Math for CS Lecture 11 12
Example 2
The property of Fourier transform of derivatives can be used for solution of differential
equations:
Setting F{y(t)}=Y(w), we have
tetHyy 4)(4
01
00)(
t
ttH
iwetHFyFyF t
4
1})({}{4}{ 4
iwwYwiwY
4
1)(4)(
Math for CS Lecture 11 13
Example 2
Then
Therefore
216
1
)4)(4(
1)(
wiwiwwY
||41
8
1)}({)( tewYFwy
Math for CS Lecture 11 14
Frequency Differentiation
In particular and
Which can be proved from the definition of F{f(t)}.
)()}({ )( wFitftF nnn
)()}({ wFittfF )()}({ 2 wFtftF
Math for CS Lecture 11 15
ConvolutionThe convolution of two functions f(t) and g(t) is defined as:
Theorem:
Proof:
duutgufgf )()(*
)](*[2
1)}()({
}{}{}*{
wGFtgtfF
gFfFgfF
}{}{)()()(
)()(}*{
)( gFfFduutdutgeufe
dtduutgufegfF
utiwiwu
iwt