foundation design of heavy oil cooler
TRANSCRIPT
1 The moments Mx and Mz on the fixed support is considered as 500 kgm
2 The frictional load on sliding support is considered as 0.3 times the vertical load
3 The SBC of soil at 1.5m depth is considered as 15 t/m2
LL
Y
LB
X X X
LY
LF
Fixed supportSliding support
LL LX LR
Y
LB
X x X
LY
LF
Y
Sliding
INPUT DATA (GENERAL) Load case (1) Normal 1.00
SAEF BEARING CAPACITY (NET SBC) SBC 15.00t/m2
Plt
Plb
PrtPlt
PrbPlb
FOUNDING DEPTH FROM GRADED LEVEL H m 1.50
PEDESTAL HEIGHT ABOVE GRADED LEVEL m 0.30
GRADE OF CONCRETE fck N/sqmm 30.00
GRADE OF STEEL fy N/sqmm 500.00
TOTAL WEIGHT (FULL OF WATER) W 25.42
Y-DIRECTION PARAMETERS
CENTER TO CENTER DISTANCE OF PEDESTALS m 0.00
FRONT CANTILEVER DISTANCE FROM CENTER LINE OF PED m 1.00
BACK CANTILEVER DISTANCE FROM CENTER LINE OF PED m 1.00
X-DIRECTION PARAMETERS
CENTER TO CENTER DISTANCE OF PEDESTALS m 0.00
RIGHT CANTILEVER DISTANCE FROM CENTER LINE OF PED m 0.90
LEFT CANTILEVER DISTANCE FROM CENTER LINE OF PED m 0.90
VERTICAL LOAD tonne 0.00
HORIZONTAL SHEAR IN X -DIRECTION X1 tonne 0.00
HORIZONTAL SHEAR IN Y-DIRECTION Y1 tonne 0.00
MOMENT ABOUT Y-Y DUE TO HOR SHEAR IN X-DIR t-m 0.00
MOMENT ABOUT X-X DUE TO HOR SHEAR IN Y-DIR t-m 0.00
VERTICAL LOAD tonne 0.00
HORIZONTAL SHEAR IN X -DIRECTION X2 tonne 0.00
HORIZONTAL SHEAR IN Y-DIRECTION Y2 tonne 0.00
MOMENT ABOUT Y-Y DUE TO HOR SHEAR IN X-DIR t-m 0.00
MOMENT ABOUT X-X DUE TO HOR SHEAR IN Y-DIR t-m 0.00
VERTICAL LOAD W/2 tonne 12.71
HORIZONTAL SHEAR IN X -DIRECTION x3 tonne 3.81
HORIZONTAL SHEAR IN Y-DIRECTION y3 tonne 0.00
MOMENT ABOUT Y-Y DUE TO HOR SHEAR IN X-DIR x3 * (Ht+H) t-m 6.86
MOMENT ABOUT X-X DUE TO HOR SHEAR IN Y-DIR t-m 0.00
Ht
LY
LF
LB
LX
LR
LL
INPUT LOAD DATA (RIGHT TOP PEDESTAL) AT BASE PLATE LEVEL
prt
MyRt
MxRt
INPUT LOAD DATA (RIGHT BOT PEDESTAL) AT BASE PLATE LEVEL
prb
MyRb
MxRb
INPUT LOAD DATA (LEFT TOP PEDESTAL) AT BASE PLATE LEVEL
pLt
MyLt
MxLt
INPUT LOAD DATA (LEFT BOT PEDESTAL) AT BASE PLATE LEVEL
VERTICAL LOAD tonne 0.00
HORIZONTAL SHEAR IN X -DIRECTION x4 tonne 0.00
HORIZONTAL SHEAR IN Y-DIRECTION y4 tonne 0.00
MOMENT ABOUT Y-Y DUE TO HOR SHEAR IN X-DIR t-m 0.00
MOMENT ABOUT X-X DUE TO HOR SHEAR IN Y-DIR t-m 0.00
INPUT WATER TABLE HEIGHT FROM FGL(Assumed) Hw m 4.00
CALCULATIONS:
LENGTH OF MAT L m 1.80
WIDTH OF MAT B m 2.00
AREA OF MAT A L*B 3.60
THICKNESS OF THE RAFT T m 0.45
TOTAL VERTICAL LOAD Wapp t 12.71
SELFWEIGHT OF RAFT A*T*2.5 t 4.05
PEDESTAL WIDTH (top right) pw1 m 0.00
PEDESTAL DEPTH (top right) pd1 m 0.00
PEDESTAL WIDTH (bot right) pw2 m 0.00
PEDESTAL DEPTH (bot right) pd2 m 0.00
PEDESTAL WIDTH (top left) pw3 m 0.30
PEDESTAL DEPTH (top left) pd3 m 0.90
PEDESTAL WIDTH (bot left) pw4 m 0.00
PEDESTAL DEPTH (bot left) pd4 m 0.00
SELFWEIGHT OF PEDESTALS t 0.91
UNIT WEIGHT OF SOIL s 1.80
SOIL WEIGHT (A-(4xPWxPD))x(H-T)xs t 6.29
TOTAL WEIGHT t 23.96
CG OF APPLIED LOAD
TOTAL APPILED MOMENT ABOUT Y-Y t-m 6.86
TOTAL APPILED MOMENT ABOUT X-X t-m 0.00
Weight of top right pedestal Wp1 pw1xpd1*(H-T+Ht)*2.5 t 0.00
Weight of bottom right pedestal Wp2 pw2xpd2*(H-T+Ht)*2.5 t 0.00
Weight of top left pedestal Wp3 pw3xpd3*(H-T+Ht)*2.5 t 0.91
Weight of bottom left pedestal Wp4 pw4xpd4*(H-T+Ht)*2.5 t 0.00
Weight of soil at top right pedestal Ws1 pw1xpd1*(H-T)*s t 0.00
Weight of soil at bottom right pedestal Ws2 pw2xpd2*(H-T)*s t 0.00
Weight of soil at top left pedestal Ws3 pw3xpd3*(H-T)*s t 0.51
Weight of soil at bottom left pedestal Ws4 pw4xpd4*(H-T)*s t 0.00
pLb
MyLb
MxLb
Lx+LL+LR
Ly+LF+LB
m2
prt+prb+pLt+pLb
WR
WP
(sum area ped)(H-
T+Ht)*2.5
t/m3
WS
WT Wapp+WR+WP+WS
Mapp-y MyRt+MyRb+MyLt+MyLb
Mapp-x MxRt+MxRb+MXLt+MXLb
Moment of soil weight about Y-Y Msx tm 5.66
Moment of soil weight about X-X Msy tm 6.29
TAKING MOMENT ABT LOWER LEFT CORNER-CG..
X-BAR X-bar m 0.90
Y-BAR Y-bar m 1.00
Ex Ex L/2-X-bar m 0.00
Ey Ey B/2-Y-bar m 0.00
MOMENT DUE TO Ex (about Y-Y) t-m 0.00
MOMENT DUE TO Ey (about X-X) t-m 0.00
TOTAL Moment about X-X Mx t-m 0.00
TOTAL Moment about Y-Y My t-m 6.86
Zxx Zxx 1/6(B*B*L) 1.20
Zyy Zyy 1/6(L*L*B) 1.08
Mx/Zx Mx/Zx Mx/Zx 0.00
My/Zy My/Zy My/Zy 6.35
P/A P/A 6.66
pressure at bottom left - 1 P1 P/A+ Mx/Zx+My/Zy 13.01
Pressure at top right - 3 P2 P/A- Mx/Zx-My/Zy 0.30
pressure at top left -2 P3 P/A- Mx/Zx+My/Zy 13.01
pressure at right bottom -4 P4 P/A+ Mx/Zx-My/Zy 0.30
LxBx(H-T)sxL/2-Ws1xLx+LL-Ws2xLx+LL-
Ws3xLL-Ws4xLL
LxBx(H-T)sxB/2-Ws1xLf+Ly-
Ws2xLf-Ws3xLf+Ly-Ws4xLf
((prt*Lx+LL)+
(prb*LX+LL)+(pLt*LL)
+(pLb*LL)+(WR)*L/
2)+(Wp1*Lx+LL)+
(Wp2*Lx*LL)+
(Wp3*LL)+
(Wp4*LL)+Msx/WT
((prt*Ly+LF)+(pLT*Ly+LF)+
(pLB*LF)+(pRb*LF)+(WR)*B/2+
(Wp1*Lf+Ly)+(Wp2*Lf)+
(Wp3*Lf+Ly)+(Wp4*Ly)+Msy)/WT
Mey Ex*WT
Mex Ey*WT
Mapp-x+Mex
Mapp-y+Mey
m3
m3
t/m2
t/m2
WT/A t/m2
t/m2
t/m2
t/m2
t/m2
CHECK FOR BEARINGAllowable bearing SBC + (H*1 OR 1.25)s 17.70
SAFE
Contact area of footing with soil b'n 1&2 100.00
Contact area of footing with soil b'n 2&3 100.00
Contact area of footing with soil b'n 3&4 100.00
Contact area of footing with soil b'n 1&4 100.00
Average contact area 100.00
For wind contact area is increased by 20% 100.00
Check for 80% contact area SAFE
e in X direction ex My / WT 0.286393
e in Y direction ey Mx / WT 0
k factor for redistribution of pressure in X direction 1
k factor for redistribution of pressure in Y direction 1.000
Maximum base Pressure max(P1,P2,P3,P4) 13.01
Check for allowable pressure SBC + (H*1 OR 1.25)s 17.70
SAFE
CHECK FOR FACTOR OF SAFETY ABT X-X
OVERTURNING MOMENT OTM Mx t-m 0.00
RESISTING MOMENT RTM t-m 23.96
FOS #DIV/0!
SAFE
CHECK FOR FACTOR OF SAFETY ABT Y-Y
OVERTURNING MOMENT OTM My t-m 6.86
RESISTING MOMENT RTM t-m 21.57
FOS 3
SAFE
CHECK FOR UPLIFT PRESSURE
Total uplift pressure Pw (H-Hw)*1*A tonne -9.00
Total Reisting pressure tonne 23.96
FOS WT/Pw -2.66
SAFE
CHECK FOR SLIDING X DIRECTION
Distributing force Px X1+X2+X3+X4 tonne 3.81
Restoring force including uplift Prx 0.3(Wr-Pw) tonne 9.89
NO TENSIO
N
WT x (B/2+EY)
WT x (L/2 + Ex)
WT
FOS Prx/Px 3
SAFE
CHECK FOR SLIDING Y DIRECTION
Distributing force Py Y1+Y2+Y3+Y4 tonne 0.00
Restoring force including uplift Pry 0.3(Wr-Pw) tonne 9.89
FOS Pry/Py #DIV/0!
SAFE
CHECK FOR PUNCHING STRESSLTP
Allowable shear stress under limit state SS Ks x tc 1.14
min of pw3/pd3 or pd3/pw3 0.33
0.5 + Beeta c 0.83
1.37
Depth required D (Plt - BP*pw3*pd3)/(2pw mm 33.58
check SAFE
DESIGN OF FOOTING REINFORCEMENTS
Maximum base pressure under normal condition = 13.0119306 1 19.518 13.0119MAXIMUM BASE PRESSURE (1) (under limit state) 13.0119306 t/m2 Hence condition iUplift due to water pressure (2) 0 t/m2self weight of soil and base raft (3) 2.87325 t/m2
Design base pressure = (1)+(2)-(3) 10.1386806 t/m2
DESIGN BASE PRESSURE 10.1386806 t/m2
Calculation of Bending moment and Shear Force
Moment on left cantilever Mlc BP x LL X LL / 2 t-m 4.106166
Moment on Right cantilever Mrc BP x LR X LR / 2 t-m 4.106166
Moment at middle of X direction Mx (BP*(L/2)*(L/2))/2 - t-m 4.106166
Shear force at d/2 from left face of cantilever Vlc BP*(LL-pw3/2-d/2) t 5.652314
shear force at d/2 from L.col towards middle Vxl BP*(LL+pw3/2+d/2))-t 3.472498
Shear force at d/2 from right face of cantilever Vrc (BP*(LR-pw1/2-d/2)) t 7.173116
shear force at d/2 from R.col towards middle Vxr (BP*(LR+pw1/2+d/2)) t 1.951696
Moment on front cantilever Mfc BP x LF X LF / 2 t-m 5.06934
Moment on back cantilever Mrc BP x LB X LB / 2 t-m 5.06934
Moment at middle of Y direction MY BP*((B/2)*(B/2)/2) - t-m 5.06934
N/mm2
Beeta-c
Ks
tc 0.25 √ fck
Shear force at d/2 from front face of cantilever Vfc BP*(LF-pd4/2-d/2) t 8.186985
shear force at d/2 from F.col towards middle Vyf BP*(LF+pd4/2+d/2))-(t 1.951696
Shear force at d/2 from Back face of cantilever Vbc (BP*(LB-pd1/2-d/2)) t 3.624578
shear force at d/2 from B.col towards middle Vyb (BP*(LB+pd1/2+d/2))- t 6.514102
1. Reinforcement details for right / left side cantileverProvide reinforcement at BOTTOM
M= 4.11E+07 NmmV= 71731.1649 N
Condition Norm (1)
Mu 61592484.4 NmmVu 107596.747 Nxu, max/d = 0.45602606 Ref IS 456Mu lim = 590198738 Nmm [ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
Singly reinforced beam possible SINCE Mu lim
xu = 910.430122 and 15.051
Choose xu = 15.0506471
Ast = 373.671238 sqmm [Ast = 0.36 fck b xu / 0.87 fy ]
minimum Reinforcement = 0.12% of Gross area 540 sqmmMinimum reinforcement is greater than required Ast hence provide minimum reinforcement
Consider 12 dia Spacing 209.5238
Provided 12 dia Spacing 150
Hence Shear reinforcement is not required AS tc is > tv
2. Reinforcement details at midspan along X directionProvide reinforcement at BOTTOM
M= 4.11E+07 NmmV= 34724.9809 N
Condition Norm (1)
Mu 61592484.4 NmmVu 52087.47 N
xu, max/d = 0.45602606 Ref IS 456Mu lim = 590198738 Nmm [ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
Singly reinforced beam possible SINCE Mu lim
xu = 910.430122 and 15.051
Choose xu = 15.0506471
Ast = 373.671238 sqmm [Ast = 0.36 fck b xu / 0.87 fy ]
minimum Reinforcement = 0.12% of Gross area 540 sqmmMinimum reinforcement is greater than required Ast hence provide minimum reinforcement
Consider 12 dia Spacing 209.5238
Provide 12 dia Spacing 150
Hence Ast = 754.285714 sqmm
Hence Shear reinforcement is not required AS tc is > tv
3. Reinforcement details for front / Rear side cantileverProvide reinforcement at BOTTOM
M= 5.07E+07 NmmV= 81869.8455 N
Condition Norm (1)
Mu 76040104.2 NmmVu 122804.768 Nxu, max/d = 0.45602606 Ref IS 456Mu lim = 590198738 Nmm [ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
Singly reinforced beam possible SINCE Mu lim
xu = 906.825872 and 18.655
Choose xu = 18.6548976
Ast = 463.156078 sqmm [Ast = 0.36 fck b xu / 0.87 fy ]
minimum Reinforcement = 0.12% of Gross area 540 sqmmMinimum reinforcement is greater than required Ast hence provide minimum reinforcement
Consider 12 dia Spacing 209.5238
Provided 12 dia Spacing 150
Hence Ast = 754.285714 sqmm
Hence Shear reinforcement is not required AS tc is > tv
4. Reinforcement details at midspan along Y directionProvide reinforcement at TOP
M= 5.07E+07 NmmV= 65141.0226 N
Condition Norm (1)
Mu 76040104.2 NmmVu 97711.534 Nxu, max/d = 0.45602606 Ref IS 456Mu lim = 590198738 Nmm [ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
Singly reinforced beam possible SINCE Mu lim
xu = 906.825872 and 18.655
Choose xu = 18.6548976
Ast = 463.156078 sqmm [Ast = 0.36 fck b xu / 0.87 fy ]
minimum Reinforcement = 0.12% of Gross area 540 sqmmMinimum reinforcement is greater than required Ast hence provide minimum reinforcement
Consider 12 dia Spacing 209.5238
Provide 12 dia Spacing 150
Hence Ast = 754.285714 sqmm
Hence Shear reinforcement is not required AS tc is > tv
LX LR
Y
x X
Y
PrtPlt
PrbPlb
1
b = 1000 mm
d = 385 mm
fy = 500 N/sqmm
fck = 30 N/sqmm
1
[ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
> Mu
[xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416
[Ast = 0.36 fck b xu / 0.87 fy ]
Minimum reinforcement is greater than required Ast hence provide minimum reinforcement
mm
mm
b = 1000 mm
d = 385 mm
fy = 500 N/sqmm
fck = 30 N/sqmm
1
[ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
> Mu
[xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416
[Ast = 0.36 fck b xu / 0.87 fy ]
Minimum reinforcement is greater than required Ast hence provide minimum reinforcement
mm
mm
b = 1000 mm
d = 385 mm
fy = 500 N/sqmm
fck = 30 N/sqmm
1
[ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
> Mu
[xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416
[Ast = 0.36 fck b xu / 0.87 fy ]
Minimum reinforcement is greater than required Ast hence provide minimum reinforcement
mm
mm
b = 1000 mm
d = 385 mm
fy = 500 N/sqmm
fck = 30 N/sqmm
1
[ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
> Mu
[xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416
[Ast = 0.36 fck b xu / 0.87 fy ]
Minimum reinforcement is greater than required Ast hence provide minimum reinforcement
mm
mm
OWNER COASTAL ENERGEN PRIVATE LIMITED
CONSULTANT
PROJECT2x600 MW MUTIARA THERMAL POWER PROJECT
NEAR TUTICORIN, TAMILNADU.
CONTRACTORGMW PVT LTD885, G.I.D.C. INDUSTRIAL ESTATE, MAKARPURA, VADODARA
(GUJRAT)
TITLE FOUNDATION DESIGN OF HEAVY OIL COOLER
DOC/DRG NO GMW/MBOP/FOH/C/DOC-036
DATE PPD CHK APP Sheets Rev
14.07.11 RMK RS BVR 0
TATA CONSULTING ENGINEERS LIMITED MUMBAI
Y
X X
Y
PARTICULARS SYMBOL
INPUT DATA (GENERAL)
SAEF BEARING CAPACITY (NET SBC) SBCFOUNDING DEPTH FROM GRADED LEVEL H
PEDESTAL HEIGHT ABOVE GRADED LEVELGRADE OF CONCRETE fckGRADE OF STEEL fyTOTAL WEIGHT (FULL OF WATER) WY-DIRECTION PARAMETERS
CENTER TO CENTER DISTANCE OF PEDESTALS
FRONT CANTILEVER DISTANCE FROM CENTER LINE OF PED
Ht
LY
LF
BACK CANTILEVER DISTANCE FROM CENTER LINE OF PED
X-DIRECTION PARAMETERS
CENTER TO CENTER DISTANCE OF PEDESTALS
RIGHT CANTILEVER DISTANCE FROM CENTER LINE OF PED
LEFT CANTILEVER DISTANCE FROM CENTER LINE OF PED
VERTICAL LOADHORIZONTAL SHEAR IN X -DIRECTION X1HORIZONTAL SHEAR IN Y-DIRECTION Y1
MOMENT ABOUT Y-Y DUE TO HOR SHEAR IN X-DIR
MOMENT ABOUT X-X DUE TO HOR SHEAR IN Y-DIR
VERTICAL LOADHORIZONTAL SHEAR IN X -DIRECTION X2HORIZONTAL SHEAR IN Y-DIRECTION Y2
MOMENT ABOUT Y-Y DUE TO HOR SHEAR IN X-DIR
MOMENT ABOUT X-X DUE TO HOR SHEAR IN Y-DIR
VERTICAL LOADHORIZONTAL SHEAR IN X -DIRECTION x3HORIZONTAL SHEAR IN Y-DIRECTION y3
MOMENT ABOUT Y-Y DUE TO HOR SHEAR IN X-DIR
MOMENT ABOUT X-X DUE TO HOR SHEAR IN Y-DIR
VERTICAL LOADHORIZONTAL SHEAR IN X -DIRECTION x4HORIZONTAL SHEAR IN Y-DIRECTION y4
MOMENT ABOUT Y-Y DUE TO HOR SHEAR IN X-DIR
MOMENT ABOUT X-X DUE TO HOR SHEAR IN Y-DIR
INPUT WATER TABLE HEIGHT FROM FGL(Assumed) Hw
LB
LX
LR
LL
INPUT LOAD DATA (RIGHT TOP PEDESTAL) AT BASE PLATE LEVEL
prt
MyRt
MxRt
INPUT LOAD DATA (RIGHT BOT PEDESTAL) AT BASE PLATE LEVEL
prb
MyRb
MxRb
INPUT LOAD DATA (LEFT TOP PEDESTAL) AT BASE PLATE LEVEL
pLt
MyLt
MxLt
INPUT LOAD DATA (LEFT BOT PEDESTAL) AT BASE PLATE LEVEL
pLb
MyLb
MxLb
CAL CULATIONS:
LENGTH OF MAT L
WIDTH OF MAT B
AREA OF MAT ATHICKNESS OF THE RAFT T
TOTAL VERTICAL LOAD Wapp
SELFWEIGHT OF RAFTPEDESTAL WIDTH (top right) pw1PEDESTAL DEPTH (top right) pd1PEDESTAL WIDTH (bot right) pw2PEDESTAL DEPTH (bot right) pd2PEDESTAL WIDTH (top left) pw3PEDESTAL DEPTH (top left) pd3PEDESTAL WIDTH (bot left) pw4PEDESTAL DEPTH (bot left) pd4
SELFWEIGHT OF PEDESTALS
UNIT WEIGHT OF SOIL s
SOIL WEIGHT
TOTAL WEIGHT
CG OF APPLIED LOAD
TOTAL APPILED MOMENT ABOUT Y-Y
TOTAL APPILED MOMENT ABOUT X-X
Weight of top right pedestal Wp1Weight of bottom right pedestal Wp2Weight of top left pedestal Wp3Weight of bottom left pedestal Wp4
Weight of soil at top right pedestal Ws1Weight of soil at bottom right pedestal Ws2Weight of soil at top left pedestal Ws3Weight of soil at bottom left pedestal Ws4
Moment of soil weight about Y-Y Msx
Moment of soil weight about X-X Msy
TAKING MOMENT ABT LOWER LEFT CORNER-CG..
WR
WP
WS
WT
Mapp-y
Mapp-x
X-BAR X-bar
Y-BAR Y-barEx ExEy Ey
MOMENT DUE TO Ex (about Y-Y)
MOMENT DUE TO Ey (about X-X)
TOTAL Moment about X-X Mx
TOTAL Moment about Y-Y My
Zxx Zxx
Zyy Zyy
Mx/Zx Mx/Zx
My/Zy My/Zy
P/A P/A
pressure at bottom left - 1 P1
Pressure at top right - 3 P2
pressure at top left -2 P3
pressure at right bottom -4 P4
CHECK FOR BEARINGAllowable bearing
Contact area of footing with soil b'n 1&2Contact area of footing with soil b'n 2&3Contact area of footing with soil b'n 3&4Contact area of footing with soil b'n 1&4Average contact areaFor wind contact area is increased by 20%Check for 80% contact area
Mey
Mex
e in X direction exe in Y direction eyk factor for redistribution of pressure in X directionk factor for redistribution of pressure in Y direction
Maximum base PressureCheck for allowable pressure
CHECK FOR FACTOR OF SAFETY ABT X-X
OVERTURNING MOMENT OTM
RESISTING MOMENT RTMFOS
CHECK FOR FACTOR OF SAFETY ABT Y-Y
OVERTURNING MOMENT OTM
RESISTING MOMENT RTMFOS
CHECK FOR UPLIFT PRESSURE
Total uplift pressure Pw
Total Reisting pressureFOS WT/Pw
CHECK FOR SLIDING X DIRECTION
Distributing force PxRestoring force including uplift PrxFOS Prx/Px
CHECK FOR SLIDING Y DIRECTION
Distributing force PyRestoring force including uplift PryFOS Pry/Py
CHECK FOR PUNCHING STRESSLTP
WT
Allowable shear stress under limit state SS
Depth required Dcheck
DESIGN OF FOOTING REINFORCEMENTS
Maximum base pressure under normal condition = 7.53656019MAXIMUM BASE PRESSURE (1) (under limit state) 7.53656019Uplift due to water pressure (2) 0self weight of soil and base raft (3) 2.87325
Design base pressure = (1)+(2)-(3) 4.66331019
DESIGN BASE PRESSURE 4.66331019
Calculation of Bending moment and Shear Force
Moment on left cantilever MlcMoment on Right cantilever MrcMoment at middle of X direction MxShear force at d/2 from left face of cantilever Vlcshear force at d/2 from L.col towards middle VxlShear force at d/2 from right face of cantilever Vrcshear force at d/2 from R.col towards middle Vxr
Moment on front cantilever MfcMoment on back cantilever MrcMoment at middle of Y direction MYShear force at d/2 from front face of cantilever Vfcshear force at d/2 from F.col towards middle VyfShear force at d/2 from Back face of cantilever Vbcshear force at d/2 from B.col towards middle Vyb
1. Reinforcement details for right / left side cantileverProvide reinforcement at BOTTOM
M= 1.89E+07
Beeta-c
Ks
tc
V= 32992.9196
Condition Norm (1)
Mu 28329609.4Vu 49489.379xu, max/d = 0.45602606Mu lim = 590198738
Singly reinforced beam
xu = 918.619905
Choose xu = 6.86086388
Ast = 170.338689minimum Reinforcement = 0.12% of Gross area 540
Minimum reinforcement is greater than required Ast hence provide minimum reinforcement
Consider 12Provided 12
Hence Shear reinforcement is not required
2. Reinforcement details at midspan along X directionProvide reinforcement at TOP
M= 1.89E+07V= 15971.8374
Condition Norm (1)
Mu 28329609.4Vu 23957.76xu, max/d = 0.45602606Mu lim = 590198738
Singly reinforced beam
xu = 918.619905
Choose xu = 6.86086388
Ast = 170.338689minimum Reinforcement = 0.12% of Gross area 540
Minimum reinforcement is greater than required Ast hence provide minimum reinforcement
Consider 12Provide 12Hence Ast = 754.285714
Hence Shear reinforcement is not required
3. Reinforcement details for front / Rear side cantileverProvide reinforcement at BOTTOM
M= 2.33E+07V= 37656.2297
Condition Norm (1)
Mu 34974826.4Vu 56484.345xu, max/d = 0.45602606Mu lim = 590198738
Singly reinforced beam
xu = 916.995563
Choose xu = 8.48520621
Ast = 210.667189minimum Reinforcement = 0.12% of Gross area 540
Minimum reinforcement is greater than required Ast hence provide minimum reinforcement
Consider 12Provided 12Hence Ast = 754.285714
Hence Shear reinforcement is not required
4. Reinforcement details at midspan along Y direction
Provide reinforcement at TOP
M= 2.33E+07V= 29961.7679
Condition Norm (1)
Mu 34974826.4Vu 44942.652xu, max/d = 0.45602606Mu lim = 590198738
Singly reinforced beam
xu = 916.995563
Choose xu = 8.48520621
Ast = 210.667189minimum Reinforcement = 0.12% of Gross area 540
Minimum reinforcement is greater than required Ast hence provide minimum reinforcement
Consider 12
Provide 12
Hence Ast = 754.285714
Hence Shear reinforcement is not required
LL LX LR
Y
LB
X x X
LY
LF
Y
FORMULA UNIT LOAD
Fixed
Load case (1) Normal 1.00
15.00
m 1.50
m 0.30
N/sqmm 30.00
N/sqmm 500.00
T 25.42
m 0.00
m 1.00
t/m2
PrtPlt
PrbPlb
m 1.00
m 0.00
m 0.90
m 0.90
tonne 0.00
tonne 0.00
tonne 0.00
t-m 0.00
t-m 0.00
tonne 0.00
tonne 0.00
tonne 0.00
t-m 0.00
t-m 0.00
W/2 tonne 12.71
tonne 0.00
tonne 0.00
5kNm + x3 * (Ht+H) t-m 0.50
t-m 0.50
tonne 0.00
tonne 0.00
tonne 0.00
t-m 0.00
t-m 0.00
m 4.00
m 1.80
m 2.00
L*B 3.60
m 0.45
t 12.71
A*T*2.5 t 4.05
m 0.00
m 0.00
m 0.00
m 0.00
m 0.30
m 0.90
m 0.00
m 0.00
t 0.91
1.80
(A-(4xPWxPD))x(H-T)xs t 6.29
t 23.96
t-m 0.50
t-m 0.50
pw1xpd1*(H-T+Ht)*2.5 t 0.00
pw2xpd2*(H-T+Ht)*2.5 t 0.00
pw3xpd3*(H-T+Ht)*2.5 t 0.91
pw4xpd4*(H-T+Ht)*2.5 t 0.00
pw1xpd1*(H-T)*s t 0.00
pw2xpd2*(H-T)*s t 0.00
pw3xpd3*(H-T)*s t 0.51
pw4xpd4*(H-T)*s t 0.00
tm 5.66
tm 6.29
Lx+LL+LR
Ly+LF+LB
m2
prt+prb+pLt+pLb
(sum area ped)(H-T+Ht)*2.5
t/m3
Wapp+WR+WP+WS
MyRt+MyRb+MyLt+MyLb
MxRt+MxRb+MXLt+MXLb
LxBx(H-T)sxL/2-Ws1xLx+LL-
Ws2xLx+LL-Ws3xLL-Ws4xLL
LxBx(H-T)sxB/2-Ws1xLf+Ly-Ws2xLf-Ws3xLf+Ly-Ws4xLf
m 0.90
m 1.00
L/2-X-bar m 0.00
B/2-Y-bar m 0.00
t-m 0.00
t-m 0.00
t-m 0.50
t-m 0.50
1/6(B*B*L) 1.20
1/6(L*L*B) 1.08
Mx/Zx 0.42
My/Zy 0.46
6.66
P/A+ Mx/Zx+My/Zy 7.54
P/A- Mx/Zx-My/Zy 5.78
P/A- Mx/Zx+My/Zy 6.70
P/A+ Mx/Zx-My/Zy 6.61
SBC + (H*1 OR 1.25)s 17.70
SAFE
100.00
100.00
100.00
100.00
100.00
100.00
SAFE
((prt*Lx+LL)+(prb*LX+LL)+
(pLt*LL)+(pLb*LL)+(WR)*L/2)+
(Wp1*Lx+LL)+(Wp2*Lx*LL)+
(Wp3*LL)+(Wp4*LL)+Msx/
WT
((prt*Ly+LF)+(pLT*Ly+LF)+
(pLB*LF)+(pRb*LF)+(WR)*B/2+
(Wp1*Lf+Ly)+(Wp2*Lf)+
(Wp3*Lf+Ly)+(Wp4*Ly)
+Msy)/WT
Ex*WT
Ey*WT
Mapp-x+Mex
Mapp-y+Mey
m3
m3
t/m2
t/m2
WT/A t/m2
t/m2
t/m2
t/m2
t/m2
NO TENSION
My / WT 0.0208638
Mx / WT 0.0208638
1
1.000
max(P1,P2,P3,P4) 7.54
SBC + (H*1 OR 1.25)s 17.70
SAFE
Mx t-m 0.50
t-m 23.96
48
SAFE
My t-m 0.50
t-m 21.57
43
SAFE
(H-Hw)*1*A tonne -9.00
tonne 23.96
-2.66
SAFE
X1+X2+X3+X4 tonne 0.00
0.3(Wr-Pw) tonne 9.89
#DIV/0!
SAFE
Y1+Y2+Y3+Y4 tonne 0.00
0.3(Wr-Pw) tonne 9.89
#DIV/0!
SAFE
WT x (B/2+EY)
WT x (L/2 + Ex)
Ks x tc 1.14
min of pw3/pd3 or pd3/pw3 0.33
0.5 + Beeta c 0.83
1.37
(Plt - BP*pw3*pd3)/(2pw3+2pd3)*SS mm 38.98
SAFE
1 11.304840277778 7.5365602t/m2 Hence condition is 1
t/m2t/m2
t/m2
t/m2
BP x LL X LL / 2 t-m 1.88864063
BP x LR X LR / 2 t-m 1.88864063
(BP*(L/2)*(L/2))/2 - P*Lx/2 t-m 1.88864063
BP*(LL-pw3/2-d/2) t 2.59979543
BP*(LL+pw3/2+d/2))-(P) t 1.59718374
(BP*(LR-pw1/2-d/2)) t 3.29929196
(BP*(LR+pw1/2+d/2))-(P) t 0.89768721
BP x LF X LF / 2 t-m 2.33165509
BP x LB X LB / 2 t-m 2.33165509
BP*((B/2)*(B/2)/2) - P*LY/2 t-m 2.33165509
BP*(LF-pd4/2-d/2) t 3.76562297
BP*(LF+pd4/2+d/2))-(P) t 0.89768721
(BP*(LB-pd1/2-d/2)) t 1.66713339
(BP*(LB+pd1/2+d/2))-(P) t 2.99617679
b = 1000 mm
Nmm d = 385 mm
N/mm2
0.25 √ fck
N fy = 500 N/sqmm
fck = 30 N/sqmm
NmmN
Ref IS 456Nmm [ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
possible SINCE Mu lim > Mu
[xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416
and 6.8608638756789
sqmm [Ast = 0.36 fck b xu / 0.87 fy ]
sqmmMinimum reinforcement is greater than required Ast hence provide minimum reinforcement
dia Spacing = 209.52381 mm
dia Spacing = 150 mm
AS tc is > tv
b = 1000 mm
Nmm d = 385 mm
N fy = 500 N/sqmm
fck = 30 N/sqmm
NmmN
Ref IS 456Nmm [ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
possible SINCE Mu lim > Mu
and 6.8608638756789 [xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416
sqmm [Ast = 0.36 fck b xu / 0.87 fy ]
sqmmMinimum reinforcement is greater than required Ast hence provide minimum reinforcement
dia Spacing = 209.52381 mm
dia Spacing = 150 mm
sqmm
AS tc is > tv
b = 1000 mm
Nmm d = 385 mm
N fy = 500 N/sqmm
fck = 30 N/sqmm
NmmN
Ref IS 456Nmm [ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
possible SINCE Mu lim > Mu
and 8.4852062140256 [xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416
sqmm [Ast = 0.36 fck b xu / 0.87 fy ]
sqmmMinimum reinforcement is greater than required Ast hence provide minimum reinforcement
dia Spacing = 209.52381 mm
dia Spacing = 150 mm
sqmm
AS tc is > tv
b = 1000 mm
Nmm d = 385 mm
N fy = 500 N/sqmm
fck = 30 N/sqmm
NmmN
Ref IS 456Nmm [ Mu lim = 0.36 (xu, max/d) (1 - 0.42 xu, max/d ) b d2 fck ]
possible SINCE Mu lim > Mu
and 8.4852062140256 [xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416
sqmm [Ast = 0.36 fck b xu / 0.87 fy ]
sqmmMinimum reinforcement is greater than required Ast hence provide minimum reinforcement
dia Spacing = 209.52381 mm
dia Spacing = 150 mm
sqmm
AS tc is > tv
1
[xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416
1
[xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416
1
[xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416
1
[xu = (d ± (d 2 - (4.62Mu/fckb))/2*0.416