For Sell and tube heat exchanger, pump, compressor and valve.

Designed by:-Lulwa H. Hamada 203114435

EQUIPMENT DESIGN

Heat Exchanger

Heat exchangers transfer heat energy from one fluid or gas to another without mixing the two .

Assumptions:

1- Use shell and tube heat exchanger, one shell and two tube passes.

2- The value of the overall heat transfer coefficient was assumed to be 100.

3- Assume the outer, the inner diameter and the length of the tube.

Design procedure-:

1 .Heat load ,(kW) Q = (m Cp ΔT)hot =(m Cp ΔT)cold

2 .Tube side flow , (kg/hr)

3.Log mean Temperature, (˚C)

1

2

12

TT

LN

TTTLM

cold

hotcold TCp

Qm

ΔT1= Thi-Tco ΔT2= Tho-Tci

Where,

Thi: inlet hot stream temperature (˚C) Tho: outlet stream temperature (˚C)

Tci: inlet cold stream temperature (˚C) Tco: outlet cold temperature (˚C)

Where,ΔTm= Ft ΔTlm

4-Provisional Area, (m2)

mo TU

QA

5 .Number of tubes Number of tubes = provisional area / area of one tube

Area of one tube = L * do *π

6 .Bundle diameter

Db: bundle diameter Nt: number of tubesK1: constant from table.n1: constant from table.

1

1

1

nt

ob k

NdD

7 .Shell diameterDs = Db + (shell inside diameter -bundle diameter)

8 .Tube side CoefficientMethod 1

Method 2

2.0

8.0)02.035.1(4200

di

uthi t

14.0

33.0PrRe

wh

f Jdi

Khi

9 .Shell side Coefficient

10 .Overall heat transfer coefficient

33.0PrRehjNu

e

fS d

kNuh

ii

o

id

oi

o

odo hd

d

hdi

d

kw

d

dLNd

hhU

11

2

1110

0

11 .Pressure dropa. Tube side

b. Shell side

12 .Shell thickness

2*5.282

m

wifp dLjNP

14.02

28

w

s

be

sf

uL

Ld

DjP

Pr

0.6i

oj

t CSE P

Where;t: shell thickness (in)P: internal pressure (psig)ri: internal radius of shell (in)EJ: efficiency of jointsS: working stress (psi)Cc: allowance for corrosion (in)

Equipment nameE-100

Heat load (kW)720.24503

Overall heat transfer coefficient (W/m2 oC)

100

LMTD (oC)33.024155

Number of tubes 1898

Tube length (m)2.2858185

Tube diameter (mm)918.61

Heat transfer area (m2)218.0964

Thickness (mm) 16.352997

Shell diameter (m)0.98261

Material of constructionCarbon steel

Cost ($)73,900

Pump

a) Assumptions-:Centrifugal pump.

b) Design procedures-: 1.Calculate the flow rate, m= ρ * Q

2.Calculate the work shift, Ws = -ha * g3.Assume efficiency, ζ.

4.Calculate the Brake horse power = (-Ws * m) / (ζ * 1000)

5.Calculate the diameter, d.

84.4116.084.11013.4 dQEP

Equipment nameP-100

Power (kW)1241.77

Efficiency%75

Material of constructionCarbon steel

Cost ($)69,100

Compressor

a) Assumptions-:Centrifugal compressor.

b) Design procedures-: 1.Calculate comparison factor n.

2.Calculate work done.

W= [nR(T1-T2)]/[1-n]

2

1

2

1

ln

ln

1T

T

Pp

n

n

3.Calculate horse power.

Hp = (mol rate/3600 )*(1/M.wt)*(W)*(.001341/.0009486)

4.Calculate K.

K = (Mwt*CP)/(Mwt*CP-1.986)

5.Calculate efficiency of compressor.

Ep = [n/(n-1)]/[k/(k-1)]

Equipment nameK-100

Power (hp)1096.89

Efficiency%88.0829

Material of constructionCarbon steel

Cost ($)269,400

Valves

There are many types for valves, such as-:

1 -Ball valve, which is good for on/off control.2 -Butterfly valve, particularly in large pipes.

3 -Choke valve: a valve that lifts up and down a solid cylinder which is placed around or inside another cylinder which has holes or slots.

4 -Check valve or non-return valve, allows the fluid to pass one direction only.

5 -Diaphragm valve, a sanitary valve predominantly used in the pharmaceutical industry.

6 -Gate valve, mainly for on/off control.7 -Globe valve, which is good for regulating flow.

8 -Needle valve, for gently releasing high pressures.9 -Piston valve.

10 -Plug valve, for on/off control.

a) Assumptions-:Gate valve.

b) Design procedures -:1.Take the value of the pipe diameter from

Hysys.

2.Estimate the cost of the valve at the inlet pressure from figure at Pinlet.

Equipment nameVLV-100

Flow Rate (Kmole/hr) 20632

Pressure Drop (Kpa) 5066

Material of constructionStainless steel

Cost ($)550