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Flexible octahedra, their generalization and application Georg Nawratil Institute of Discrete Mathematics and Geometry Research was supported by FWF (I 408-N13) Habilitationskolloquium, Vienna June 27 2011, Austria

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Flexible octahedra,

their generalization and application

Georg Nawratil

Institute of Discrete Mathematics and Geometry

Research was supported by FWF (I 408-N13)

Habilitationskolloquium, Vienna June 27 2011, Austria

Bricard octahedra

An octahedron is called flexible ifits spatial shape can be changedcontinuously due to changes of itsdihedral angles only, i.e. every faceremains congruent to itself duringthe flex.

All flexible octahedra in E3, whereno two faces coincide permanentlyduring the flex, were firstly determi-ned by Bricard [1].

There are 3 types of these so-calledBricard octahedra:

Bricard octahedra of type I

All three pairs of opposite vertices aresymmetric with respect to a line.

Habilitationskolloquium, Vienna June 27 2011, Austria 1

Bricard octahedra

Bricard octahedra of type II

Two pairs of opposite vertices aresymmetric with respect to a planethrough the remaining two vertices.

Bricard octahedra of type III

These octahedra possess two flat posesand can be constructed as follows:

Habilitationskolloquium, Vienna June 27 2011, Austria 2

Different points of view

Kokotsakis mesh

Σ0

A Kokotsakis mesh is a polyhedralstructure consisting of a n-sided cen-tral polygon Σ0 surrounded by a beltof polygons.

Stewart Gough platform

A SGP is a parallel manipulator wherethe platform is connected via threeSpherical-Prismatical-Spherical (SPS)legs with the base.

Habilitationskolloquium, Vienna June 27 2011, Austria 3

Table of contents

[1] Flexible octahedra in the projective extension of E3

[a] Reducible compositions of spherical four-bar linkages

[b] Flexible octahedra with no pair of opposite vertices at infinity

[c] Flexible octahedra with one pair of opposite vertices at infinity

[d] Special cases & Application in robotics

[2] Flexible 3 × 3 complexes[a] Stachel’s conjecture

[b] Classification of reducible compositions of spherical four-bar linkages

[3] Stewart Gough platforms[a] Self-motions and the Borel Bricard problem

[b] Self-motions implied by Bricard octahedra I

Habilitationskolloquium, Vienna June 27 2011, Austria 4

[1a] Motivation

Σ2

Σ1

Σ0

A1

I20B1

A2B2

I10

I30

Σ3

γ1α1

β1δ1

γ2

α2β2

δ2

I10 I20I30

A1

B1

A2

B2

a1

b2

ϕ1ϕ2

ϕ3

α1 β1

γ1

δ1

α2β2

γ2

δ2x

y

z

S2

The relative motions Σi+1/Σi between consecutive systems are spherical four-bars.

Habilitationskolloquium, Vienna June 27 2011, Austria 5

[1a] Transmission by a spherical four-bar mechanism

Under consideration of ti = tan(ϕi/2) the transmission ϕ1 7→ ϕ2 can be writtenaccording to Stachel [2] as follows:

C : c22t21t

22+c20t

21+c02t

22+c11t1t2+c00 = 0

c11 = 4 sα1 sβ1 6= 0,

c00 = N1 −K1 + L1 +M1,

c02 = N1 +K1 + L1 −M1,

c20 = N1 −K1 − L1 −M1,

c22 = N1 +K1 − L1 +M1,

K1 = cα1 sβ1 sδ1 , M1 = sα1 sβ1 cδ1 ,

L1 = sα1 cβ1 sδ1 , N1 = cα1 cβ1 cδ1 − cγ1 .

I10I20

AB

S2

ϕ1ϕ2

Σ1 Σ2

Σ0

xy

z

Habilitationskolloquium, Vienna June 27 2011, Austria 6

[1a] Composition of two spherical four-bar linkages

The transmission between the angles ϕ1, ϕ2 and ϕ3 can be expressed by the twobiquadratic equations:

C : c22t21t

22 + c20t

21 + c02t

22 + c11t1t2 + c00 = 0

D : d22t22t

23 + d20t

22 + d02t

23 + d11t2t3 + d00 = 0

We eliminate t2 by computing the resultantof C and D with respect to t2. This yields abiquartic equation X = 0 where X equals:

˛

˛

˛

˛

˛

˛

˛

˛

˛

c22t21 + c02 c11t1 c20t

21 + c00 0

0 c22t21 + c02 c11t1 c20t

21 + c00

d22t23 + d20 d11t3 d02t

23 + d00 0

0 d22t23 + d20 d11t3 d02t

23 + d00

˛

˛

˛

˛

˛

˛

˛

˛

˛

I10 I20I30

A1

B1

A2

B2

a1

b2

ϕ1ϕ2

ϕ3

α1 β1

γ1

δ1

α2β2

γ2

δ2x

y

z

S2

Habilitationskolloquium, Vienna June 27 2011, Austria 7

[1a] Reducible compositions

In the following we are interested in the conditions the cij’s and dij’s have to fulfillsuch that X splits up into the product FG.

If at least one of the factors F or G corresponds to the transmission function of aspherical coupler, i.e. for example

F : f22t21t

23 + f20t

21 + f02t

23 + f11t1t3 + f00 = 0 with f11 6= 0,

we get a reducible composition with a spherical coupler component.

We denote the coefficients of ti1tj3 of Y := FG and X by Yij and Xij. By the

comparison of these coefficients we get the 13 equations Yij −Xij = 0 with

(i, j) ∈ (4, 4), (4, 2), (4, 0), (3, 3), (3, 1), (2, 4), (2, 2), (2, 0), (1, 3), (1, 1), (0, 4), (0, 2), (0, 0) .

This non-linear system of equations was solved explicitly by the resultant method.

Habilitationskolloquium, Vienna June 27 2011, Austria 8

Theorem 1 Nawratil [3]

If a reducible composition of two spherical four-bar linkages with a spherical couplercomponent is given, then it is one of the following cases:

(a) One of the following four cases hold:

c00 = c22 = 0, d00 = d22 = 0, c20 = c02 = 0, d20 = d02 = 0,

(b) The following algebraic conditions hold for λ ∈ R \ 0:

c00c20 = λd00d02, c22c02 = λd22d20,

c211 − 4(c00c22 + c20c02) = λ[d211 − 4(d00d22 + d20d02)],

(c) One of the following two cases hold:

c22 = c02 = d00 = d02 = 0, d22 = d20 = c00 = c20 = 0,

(d) One of the following two cases hold for A ∈ R \ 0 and B ∈ R:

• c20 = Ad02, c22 = Ad22, c02 = Bd22, c00 = Bd02, d00 = d20 = 0,

• d02 = Ac20, d22 = Ac22, d20 = Bc22, d00 = Bc20, c00 = c02 = 0.

Habilitationskolloquium, Vienna June 27 2011, Austria 9

[1a] Geometric aspects of Theorem 1(a)

Spherical isogram

(i) c00 = c22 = 0 ⇐⇒ β1 = α1 and δ1 = γ1,which determine a spherical isogram.

(ii) c20 = c02 = 0 ⇐⇒ β1 = π − α1 andδ1 = π − γ1. Note that the couplers ofboth isograms have the same movementbecause we get item (ii) by replacing I20of item (i) by its antipode.

I10I20

A1B1

α1 β1

δ1

γ1

Remark 1The cosines of opposite angles in the spherical isograms (of both types) are equal.

Habilitationskolloquium, Vienna June 27 2011, Austria 10

[1a] Geometric aspects of Theorem 1(b)

I10 I20 I30

A1

B1=A2

B2

K

L

χ1χ1

I10I20

I30

A1

B1

A2

B2

ϕ1ϕ2ϕ2

ϕ3

χ1

χ 1ψ 2

α1

β1

γ1

δ1

α2

β2

γ 2

δ2

Burmester’s focal mechanism:A planar composition of two four-bars with a planar coupler component. Due toWunderlich [4] this composition is characterized by Dixon’s angle condition.

Habilitationskolloquium, Vienna June 27 2011, Austria 11

[1a] Geometric aspects of Theorem 1(b)

Spherical mechanism of Dixon type

(i) In Nawratil & Stachel [5] it wasshown that the algebraic characterizati-on of item (b) is equivalent with Dixon’sangle condition. Therefore cχ1 = −cψ2

holds with χ1 = ∢I10A1B1 and ψ2 =∢I30B2A2.

(ii) We get the case cχ1 = cψ2 from item(i) by replacing either I30 or I10 by itsantipode.

I10I20

I30

A1

B1

A2

B2

ϕ1ϕ2ϕ2

ϕ3

χ1

χ 1ψ 2

α1

β1

γ1

δ1

α2

β2

γ 2

δ2

Habilitationskolloquium, Vienna June 27 2011, Austria 12

[1a] Geometric aspects of Theorem 1(c)

Spherical deltoid

⋆ c00 = c02 = 0 ⇐⇒ α1 = δ1 and β1 = γ1

By replacing I20 by its antipode, we get thecorresponding mechanism with:δ1 = π − α1, β1 = π − γ1 ⇐⇒ c22 = c20 = 0

⋆ c22 = c02 = 0 ⇐⇒ α1 = γ1 and β1 = δ1

By replacing I10 by its antipode, we get thecorresponding mechanism with:α1 = π − γ1, δ1 = π − β1 ⇐⇒ c00 = c20 = 0

I10 I20

A1

B1

γ1

β1δ1

α1

Remark 2The cosines of one pair of opposite angles in spherical deltoids are equal.

Habilitationskolloquium, Vienna June 27 2011, Austria 13

[1a] Geometric aspects of Theorem 1(d)

Orthogonal spherical four-bars

Both couplers are so-called orthogonal sphericalfour-bar mechanisms (cf. Stachel [2]), asthe diagonals of the spherical quadrangles areorthogonal.

Moreover, the diagonals A1I20 and I20B2

coincide.

Remark 3Especially, all spherical deltoid are orthogonal.

I10

I20I30

A1 B1

β1

δ2

A2

B2

δ1

α1

α2 β2

γ1

γ2

Habilitationskolloquium, Vienna June 27 2011, Austria 14

[1b] The closure condition

The Kokotsakis mesh for n = 3 is flexible ifand only if the transmission of the compositionof the two spherical four-bar linkages C and Dequals the one of the single spherical four-barlinkage R (= I10Ir0B3A3) which meets theclosure condition Ir0 = I30.

Octahedra where no pair of opposite vertices areideal points possess at least one finite face. Wecan assume w.l.o.g. that this face is the centralpolygon of the Kokotsakis mesh.

I10 I20 I30 Ir0

A1B1

A2

B2

A3

B3

Habilitationskolloquium, Vienna June 27 2011, Austria 15

[1b] No opposite vertices as ideal points

The closure condition Ir0 = I30 can only be fulfilled by spherical mechanisms ofDixon type (ii) and by spherical isograms.

Theorem 2 Nawratil [6]

If an octahedron in the projective extension of E3 is flexible, where no pair ofopposite vertices are ideal points, then its spherical image is a composition ofspherical four-bar linkages C, D and R of the following type:

A. C and D, C and R as well as D and R form a spherical mechanism of Dixontype (ii),

B. C and D form a spherical mechanism of Dixon type (ii) and R is a sphericalisogram,

C. C, D (⇒ and R) are spherical isograms.

Habilitationskolloquium, Vienna June 27 2011, Austria 16

[1b] All vertices are finite

Type A

V1

V2

V3

V5

V6V4

Bricard octahedron I(cf. Kokotsakis [7])

Type B

V1

V2

V3

V5

V6V4

Bricard octahedron II(cf. Kokotsakis [7])

Type C

V1

V2

V3

V5

V6V4

Bricard octahedron III(cf. Kokotsakis [7])

Habilitationskolloquium, Vienna June 27 2011, Austria 17

[1b] Central Triangles with one ideal point

The four faces of the octahedra through the ideal point form a 4-sides prism. Un-der consideration of ti = tan(ϕi/2), the input angle ϕ1 and the output angle ϕ2 of a

planar four-bar linkage (= orthogonalcross section of prism) are related by:

p22t21t

22+p20t

21+p02t

22+p11t1t2+p00 = 0

p11 = −8ab 6= 0,

p22 = (a− b+ c + d)(a− b− c+ d),

p20 = (a+ b+ c+ d)(a + b− c + d),

p02 = (a+ b+ c− d)(a+ b− c− d),

p00 = (a− b+ c− d)(a− b− c− d).

ϕ1 ϕ2

a b

d

c

Lemma 1 Nawratil [6]

If a reducible composition of a planar anda spherical four-bar linkage with a sphericalcoupler component is given, then the sameconditions as in Theorem 1 are fulfilled.

Habilitationskolloquium, Vienna June 27 2011, Austria 18

[1b] One vertex is an ideal point

Type A

V1

V2

V3∈ω

V5

V6V4

Thm 3 Nawratil [6]

There do not exist fle-xible octahedra of typeA where only one ver-tex is an ideal point.

Type B

V1

V2

V3∈ω

V5

V6V4

Thm 4 Nawratil [6]

Bricard octahedron IIwhere one vertex loca-ted in the plane of sym-metry is an ideal point.

Type C

V1

V2

V3∈ω

V5

V6V4

Thm 5 Nawratil [6]

Bricard octahedron IIIwhere one vertex is anideal point (see alsoStachel [8]).

Habilitationskolloquium, Vienna June 27 2011, Austria 19

[1b] Flexible octahedra with edge or face at infinity

Do there exist flexible octahedra with a finite face Σ0, where one edge or one faceis at infinity?

Theorem 6 Nawratil [9]

There do not exist flexible octahedron of type C with a finite face Σ0 and one edgeor face at infinity.

Based on Theorem 3 we can even generalize this result as follows:

Theorem 7 Nawratil [9]

In the projective extension of E3 there do not exist flexible octahedra with a finiteface Σ0 and one edge or face at infinity.

Habilitationskolloquium, Vienna June 27 2011, Austria 20

[1c] One pair of opposite vertices are ideal points

Theorem 8 Nawratil [9]

The two pairs of opposite vertices (V1, V4) and (V2, V5) are symmetric with respectto a common line as well as the edges of the prisms through the ideal points V3

and V6, respectively.

Type A

V1

V2

V3∈ω

V5

V6∈ωV4

V1

V4

V5

V2

Habilitationskolloquium, Vienna June 27 2011, Austria 21

[1c] One pair of opposite vertices are ideal points

Theorem 9 Nawratil [9]

One pair of opposite vertices (V2, V5) is symmetric with respect to a plane, whichcontains the vertices (V3, V6). Moreover, also the edges of the prisms through theideal points V1 and V4 are symmetric with respect to this plane.

Type B

V1∈ω

V2

V3

V5

V6V4∈ω

V3

V6

V2

V5

Habilitationskolloquium, Vienna June 27 2011, Austria 22

[1c] One pair of opposite vertices are ideal points

Theorem 10 Nawratil [9]

The vertices V1, V2, V4, V5 are coplanar and form an antiparallelogram and its planeof symmetry is parallel to the edges of the prisms through the ideal points V3 andV6, respectively.

Type B

V1

V2

V3∈ω

V5

V6∈ωV4

V1

V5

V4

V2

Habilitationskolloquium, Vienna June 27 2011, Austria 23

[1c] One pair of opposite vertices are ideal points

Theorem 11 Nawratil [9]

The vertices V1, V2, V4, V5 are coplanar and form a parallelogram. The ideal pointsV3 and V6 can be chosen arbitrarily.

Type B

V1

V2

V3∈ω

V5

V6∈ωV4

V2

V4

V5

V1

Habilitationskolloquium, Vienna June 27 2011, Austria 24

[1c] One pair of opposite vertices are ideal points

Theorem 12 Nawratil [9]

This type is characterized by the existence of two flat poses and consists of twoprisms through the ideal points V3 and V6, where the orthogonal cross sections arecongruent antiparallelograms. The construction can be done as follows:

Type C

V1

V2

V3∈ω

V5

V6∈ωV4

V1

V2

V4

V5

Habilitationskolloquium, Vienna June 27 2011, Austria 25

[1c] One pair of opposite vertices are ideal points

Theorem 13 Nawratil [9]

The vertices V1, V2, V4, V5 are coplanar and form a deltoid and the edges of theprisms through the ideal points V3 and V6 are orthogonal to the deltoid’s line ofsymmetry.

Type D

V1

V2

V3∈ω

V5

V6∈ωV4V2

V4 V5

V1

Habilitationskolloquium, Vienna June 27 2011, Austria 26

[1d] Special cases

Theorem 14 Nawratil [9]

In the projective extensionof E3 any octahedron isflexible where at least twoedges are ideal lines butno face coincides with theplane at infinity.

There are only two types ofoctahedra fulfilling the re-quirements of theorem 14.

V1

V4

V2

V5

V6

V3

V1

V4

V2

V5

V1

V1

V1

V6

V5

V3V2

V4

V4

V2

V4

Habilitationskolloquium, Vienna June 27 2011, Austria 27

[1d] Application in robotics

A TSSM consists of a platform Σ, which is connected via three SPR legs with thebase Σ0, where the axes ri of the R-joints are coplanar.

Following was shown in Nawratil [10]:

Self-motions of TSSMs can only be:

⋆ circular translations,

⋆ pure rotations,

⋆ planar four-bar motions,

⋆ spherical four-bar motions,

⋆ self-motions of Bricard octahedra,

⋆ self-motions of flexible octahedra

with one vertex at infinity.

ΣΣΣΣΣΣΣΣΣΣΣΣΣΣΣΣΣ

Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0r1r1r1r1r1r1r1r1r1r1r1r1r1r1r1r1r1 r3r3r3r3r3r3r3r3r3r3r3r3r3r3r3r3r3

r2r2r2r2r2r2r2r2r2r2r2r2r2r2r2r2r2

Habilitationskolloquium, Vienna June 27 2011, Austria 28

[2] Flexible 3 × 3 complexes

A 3 × 3 complex, which is also known as Neunflach, is a Kokotsakis mesh with aquadrilateral as central polygon.

M denotes as polyhedral mesh with va-lence 4 composed of planar quadrilaterals.

Bobenko, Hoffmann, Schief [11]:M in general position is flexible ⇐⇒all its 3 × 3 complexes are flexible

Application: architectural design of flexi-ble claddings composed of planar quads.

V1

V2

V3

V4

Σ0

Σ1

Σ2

Σ3

Σ4

Habilitationskolloquium, Vienna June 27 2011, Austria 29

[2a] Stachel’s conjecture

A 3× 3 complex is non-trivially flexible ifand only if the transmission ϕ1 7→ ϕ3 canbe decomposed in at least two differentways into two spherical four-bars.

Stachel’s conjectureAll multiply decomposable compounds oftwo spherical four-bars are reducible withexception of the translatory type andplanar-symmetric type.

V1

V2

V3

V4

V1

V2V3

V4

Habilitationskolloquium, Vienna June 27 2011, Austria 30

[2b] Classification of reducible compositions

Theorem 15 Nawratil [12]

If a reducible composition of two spherical four-bar mechanisms C and D is given, then it is oneof the following cases:

I. One of the quadrangles C or D is an isogram.

II. C and D form a spherical mechanism of Dixontype.

III. C and D are orthogonal four-bars and thediagonals A1I20 and I20B2 coincide.

IV. One of the quadrangles C or D is a deltoid.

I10

I20I30

A1 B1

β1

δ2

A2

B2

δ1

α1

α2 β2

γ1

γ2

The work on a complete classification of 3 × 3 complexes is in progress.

Habilitationskolloquium, Vienna June 27 2011, Austria 31

[3] Stewart Gough Platform

The geometry of a SGP is given by the sixbase anchor points Mi ∈ Σ0 and by the sixplatform points mi ∈ Σ.

A SGP is called planar, if M1, . . . ,M6 arecoplanar and m,1 , . . . ,m6 are coplanar.

Mi and mi are connected with a SPS leg.

Merlet [13]A SGP is singular (infinitesimal flexible,shaky) if and only if the carrier lines of thesix SPS legs belong to a linear line complex.

Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0

ΣΣΣΣΣΣΣΣΣΣΣΣΣΣΣΣΣ

MiMiMiMiMiMiMiMiMiMiMiMiMiMiMiMiMi

mimimimimimimimimimimimimimimimimi

Habilitationskolloquium, Vienna June 27 2011, Austria 32

[3a] Self-motions and the Borel Bricard problem

If all P-joints are locked, a SGP is ingeneral rigid. But, in some special cases themanipulator can perform an n-parametricmotion (n > 0), which is called self-motion.

Note that in each pose of the self-motion,the SGP has to be singular. Moreover, allself-motions of SGPs are solutions to thefamous Borel Bricard problem.

Borel Bricard problem (still unsolved)

Determine and study all displacements of arigid body in which distinct points of thebody move on spherical paths.

Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0Σ0

ΣΣΣΣΣΣΣΣΣΣΣΣΣΣΣΣΣ

MiMiMiMiMiMiMiMiMiMiMiMiMiMiMiMiMi

mimimimimimimimimimimimimimimimimi

Habilitationskolloquium, Vienna June 27 2011, Austria 33

[3a] Architecturally singular SGPs

SGPs which are singular in every configuration, are called architecturally singular.

Architecturally singular SGPs are well studied:

⋆ For the planar case see Roschel & Mick [14],

Karger [15], Nawratil [16], Wohlhart [17].

⋆ For the non-planar case see Karger [18] and

Nawratil [19].

It is well known, that architecturally singularSGPs possess self-motions in each pose.

Therefore we are only interested in self-motionsof non-architecturally singular SGPs. Only a fewsuch motions are known.

Habilitationskolloquium, Vienna June 27 2011, Austria 34

[3b] Redundant SGPs

According to Husty [20], the “sphere constraint” that mi is located on a spherewith center Mi and radius Ri can be expressed by a homogeneous quadraticequation Λi in the Study parameters.

Therefore the direct kinematic problem corresponds to the solution of the systemΛ1, . . . ,Λ6,Ψ where Ψ denotes the equation of the Study quadric.

If a planar SGP is not architecturally singular, then at least a one-parametric set oflegs Λ+ can be added without changing the direct kinematics (cf. Husty et al

[21]) and singularity surface (cf. Borras et al [22]):

Λ+ = λ1Λ1 + . . .+ λ6Λ6

Habilitationskolloquium, Vienna June 27 2011, Austria 35

[3b] Redundant SGPs

Moreover, it was shown in Husty et al [21] that in general the base anchorpoints Mi as well as the corresponding platform anchor points mi are located onplanar cubic curves C and c, which can also split up.

U2U2U2U2U2U2U2U2U2U2U2U2U2U2U2U2U2

U3U3U3U3U3U3U3U3U3U3U3U3U3U3U3U3U3

U1U1U1U1U1U1U1U1U1U1U1U1U1U1U1U1U1

u3u3u3u3u3u3u3u3u3u3u3u3u3u3u3u3u3

u2u2u2u2u2u2u2u2u2u2u2u2u2u2u2u2u2 u1u1u1u1u1u1u1u1u1u1u1u1u1u1u1u1u1

Cubic C of the octahedral SGP

U4U4U4U4U4U4U4U4U4U4U4U4U4U4U4U4U4

U6U6U6U6U6U6U6U6U6U6U6U6U6U6U6U6U6

U5U5U5U5U5U5U5U5U5U5U5U5U5U5U5U5U5

u6u6u6u6u6u6u6u6u6u6u6u6u6u6u6u6u6

u4u4u4u4u4u4u4u4u4u4u4u4u4u4u4u4u4u5u5u5u5u5u5u5u5u5u5u5u5u5u5u5u5u5

Cubic c of the octahedral SGP

Habilitationskolloquium, Vienna June 27 2011, Austria 36

[3b] Darboux and Mannheim motion

The Darboux constraint that ui movesin a plane ∈ Σ0 orthogonal to thedirection of the ideal point Ui is ahomogeneous quadratic equation Ωiin the Study parameters (i = 1, 2, 3).

U1U1U1U1U1U1U1U1U1U1U1U1U1U1U1U1U1

u1u1u1u1u1u1u1u1u1u1u1u1u1u1u1u1u1

The Mannheim constraint that a planeof Σ orthogonal to uj slides throughthe point Uj ∈ Σ0 is a homogeneousquadratic equation Πj in the Studyparameters (j = 4, 5, 6).

U6U6U6U6U6U6U6U6U6U6U6U6U6U6U6U6U6

u6u6u6u6u6u6u6u6u6u6u6u6u6u6u6u6u6

Habilitationskolloquium, Vienna June 27 2011, Austria 37

[3b] Self-motions implied by Bricard octahedra I

It was shown in Nawratil [23], that the system Ω1,Ω2,Ω3,Π4,Π5,Π6 is redundant=⇒ manipulator u1, . . . ,U6 is architecturally singular.

Moreover, if the underlying SGP is a Bricard octahedron of type I, then u1, . . . ,U6

has even a two-parametric self-motion (cf. Nawratil [23]).

By adding an arbitrary leg Λ to Ω1,Ω2,Ω3,Π4,Π5 we get an one-parametricself-motion. Further legs Λ+ are determined by:

Λ+ = λΛ +

3∑

i=1

νiΩi +

5∑

j=4

µjΠj.

Habilitationskolloquium, Vienna June 27 2011, Austria 38

[3b] Example

0

5

10

15

20

25

–20 –15 –10 –5 0 5 10

M1

M6

M3

M2 M7 U6U5

U4M4 M5

–2

0

2

4

6

8

–80 –60 –40 –20 0

m4

m5

m7

m6 m2

m1m3

u3

u1

u2

Remark 4All self-motions implied by Bricard octahedra of type I are line-symmetric motions.

Habilitationskolloquium, Vienna June 27 2011, Austria 39

[3b] Future research

This approach can also be applied to general planar SGPs:

Definition 1 Nawratil [23]

Assume M is a 1-parametric self-motion of a non-architecturally singular SGPm1, . . . ,M6. Then M is of type n DM (Darboux Mannheim) if the correspondingarchitecturally singular manipulator u1, . . . ,U6 has an n-parametric self-motion U(which includes M).

Moreover, it was shown in Nawratil [23], that all 1-parametric self-motionsof general planar SGPs (non-architecturally singular) are type I or type II DMself-motions.

Based on the Darboux and Mannheim constraints we were able to present a set of24 equations yielding a type II DM self-motion.

Habilitationskolloquium, Vienna June 27 2011, Austria 40

[3b] Future research

Γ080 = F1[8]F2[18]2, Γ800 = (b2 − b3)

2(L1 − g4)

2F3[8],

Γ170 = F2[18]F4[283], Γ710 = (b2 − b3)(L1 − g4)F5[170],

Γ620[2054], Γ602[1646], Γ260[6126], Γ062[4916],

Γ026[5950], Γ116[3066], Γ530[4538], Γ512[4512],

Γ152[6514], Γ440[7134], Γ422[6314], Γ242[7622],

Γ044[6356], Γ314[6934], Γ224[7096], Γ134[6656],

Γ206[5950], Γ350[7166], Γ404[5766], Γ332[6982].

Based on these 24 equations Γijk = 0 (in 14 unknowns), we were already able tocompute first results for type II DM self-motions in Nawratil [24], which raisethe hope of giving a complete classification of these self-motions in the future.

Habilitationskolloquium, Vienna June 27 2011, Austria 41

References

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[21] Husty M, Mielczarek S, Hiller M (2002) A redundant spatial Stewart-Gough platform with a maximal forwardkinematics solution set. In: Lenarcic J, Thomas F (eds) Advances in Robot Kinematics: Theory and Applications,

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[24] Nawratil G (2011) Basic result on type II DM self-motions of planar Stewart Gough platforms. In Proc. of 1st

Workshop on Mechanisms, Transmissions and Applications, Timisoara, Romania, Springer (2011) to appear

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