f2 aula03-intensivão
TRANSCRIPT
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colisão das moléculas
com as paredes do
recipiente
1 atm = 76 cmHg = 760 mmHg=1,0.105Pa=1,0.105 N/m²
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O nível do mercúrio é 76 cm ,ao nível do mar, para qualquer inclinação do tubo .
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É o volume do recipiente que o contem.
1 cm³=10-3 l=10-6 m³1 ml= 1 cm³1 m³=103 l
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T = ΘC + 273
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ISOBÁRICA Pressão
constante..V k T
ou
Vk
T
=
=
1 2
1 2
V V
T T=
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Volume constante.
.p k T
ou
pk
T
=
=1 2
1 2
p p
T T=
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Temperatura constante.
ISOTÉRMICA
a b cT T T
ISOTERMAS
> > 1 1 2 2. .p V p V=.
kV
p
ou
pV k
=
=
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V
T=1
1
V
T2
2
P1 P 2 xx
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P . V = n . R . TP . V = n . R . T P – PressãoP – Pressão
V – VolumeV – Volume
T – Temperatura T – Temperatura
R – Constante geral dos R – Constante geral dos gases.gases.
n – Número de molsn – Número de mols
R = 0,082 atm.l/mol.K R = 8,31 J/mol.K