expected utility and jensen's inequality

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  • 7/31/2019 Expected Utility and Jensen's Inequality

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    Economic Rationality Qua

    Expected Utility Theory

    The math behind it via Jensens inequal

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    If u is strictly concave and 0 < p < 1,

    u(E(x)) > E(u(x)).

    Jensens InequalityDerivation for the two-point support ca

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    If u is strictly concave and 0 < p < 1,

    u(E(x)) > E(u(x)).

    Jensens InequalityDerivation for the two-point support ca

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    If u is strictly concave and 0 < p E(u(x)).

    Jensens InequalityDerivation for the two-point support ca

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    x is a random variable with realizationsand x2, x1 < x2.

    u is the utility function. u is increasing

    strictly concave.p = prob{x = x1}, 1 p = prob{x = x2}

    Model Setup

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    x is a random variable with realizationsand x2, x1 < x2.

    u is the utility function. u is increasing

    strictly concave.p = prob{x = x1}, 1 p = prob{x = x2}

    Model Setup

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    x is a random variable with realizationsand x2, x1 < x2.

    u is the utility function. u is increasing

    strictly concave.p = prob{x = x1}, 1 p = prob{x = x2}

    Model Setup

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    E(x) = px1 + (1-p)x2E(u(x)) = pu(x1) + (1-p)u(x2)

    Expectation of x and

    Expectation of u(x)

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    E(x) = px1 + (1-p)x2E(u(x)) = pu(x1) + (1-p)u(x2)

    Expectation of x and

    Expectation of u(x)

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    Graph of Model Setup

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    Larger D: Base = x2 - x1 Height = u(x2) u

    Smaller D: Base = E(x) - x1

    Height = ?

    Base and Height

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    Larger D: Base = x2 - x1 Height = u(x2) u

    Smaller D: Base = E(x) - x1

    Height = ?

    Base and Height

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    Larger D: Base = x2 - x1 Height = u(x2)

    Smaller D: Base = E(x) - x1 Height = ?

    E(x) - x1 = px1 + (1 p)x2 x1 = (1 p)(

    A little bit of algebra

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    Larger D: Base = x2 - x1 Height = u(x2)

    Smaller D: Base = (1 p)(x2x1).

    Smaller D: Height = (1 p)[u(x2) u(x1)].

    Conclusion

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    u(x1) + (1 p)[u(x2) u(x1)] =

    u(x1) - (1 p)u(x1) + (1 p)u(x2) =

    pu(x1) + (1 p)u(x2) = E(u(x))

    More Algebra

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    u(x1) + (1 p)[u(x2) u(x1)] =

    u(x1) - (1 p)u(x1) + (1 p)u(x2) =

    pu(x1) + (1 p)u(x2) = E(u(x))

    More Algebra

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    u(x1) + (1 p)[u(x2) u(x1)] =

    u(x1) - (1 p)u(x1) + (1 p)u(x2) =

    pu(x1) + (1 p)u(x2) = E(u(x))

    More Algebra

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    Justification of Labeling

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    Constant Absolute Risk Aversion

    Constant Relative Risk Aversion

    Quadratic Utility

    Three Functional Forms for u

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    Constant Absolute Risk Aversion

    Constant Relative Risk Aversion

    Quadratic Utility

    Three Functional Forms for u

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    Constant Absolute Risk Aversion

    Constant Relative Risk Aversion

    Quadratic Utility

    Three Functional Forms for u

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    u(x) = -ke-gx

    + c; k, g, and c constants; k

    u(x) = gke-gx > 0, u(x) = -g2ke-gx < 0.

    -u(x)/u(x) = g.

    Constant Absolute Risk Aversio

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    u(x) = -ke-gx

    + c; k, g, and c constants; k

    u(x) = gke-gx > 0, u(x) = -g2ke-gx < 0.

    -u(x)/u(x) = g.

    Constant Absolute Risk Aversio

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    u(x) = -ke-gx

    + c; k, g, and c constants; k

    u(x) = gke-gx > 0, u(x) = -g2ke-gx < 0.

    -u(x)/u(x) = g.

    Constant Absolute Risk Aversio

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    u(x) = kxa

    + c; k, a, and c constants; k > 0, 0

    u(x) = akxa-1 > 0, u(x) = a(a-1)kxa-2 < 0.

    -xu(x)/u(x) = 1 - a.

    Constant Relative Risk Aversio

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    u(x) = kxa

    + c; k, a, and c constants; k > 0, 0

    u(x) = akxa-1 > 0, u(x) = a(a-1)kxa-2 < 0.

    -xu(x)/u(x) = 1 - a.

    Constant Relative Risk Aversio

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    u(x) = -ax2

    + bx + c; a, b, and c constants; a

    u(x) = -2ax + b > 0 if x < b/2a, u(x) = -2a 0 if x < b/2a, u(x) = -2a