example 1 solve a triangle for the sas case solve abc with a = 11, c = 14, and b = 34°. solution...

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EXAMPLE 1 Solve a triangle for the SAS case olve ABC with a = 11, c = 14, and B = 34°. SOLUTION e the law of cosines to find side length b. b 2 = a 2 + c 2 – 2ac cos B b 2 = 11 2 + 14 2 – 2(11)(14) cos 34° b 2 61.7 b 2 61.7 7.8 5 Law of cosines Substitute for a, c, and B. Simplify. Take positive square root.

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Page 1: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

EXAMPLE 1 Solve a triangle for the SAS case

Solve ABC with a = 11, c = 14, and B = 34°.

SOLUTION

Use the law of cosines to find side length b.

b2 = a2 + c2 – 2ac cos B

b2 = 112 + 142 – 2(11)(14) cos 34°

b2 61.7

b2 61.7 7.85

Law of cosines

Substitute for a, c, and B.

Simplify.

Take positive square root.

Page 2: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

EXAMPLE 1 Solve a triangle for the SAS case

Use the law of sines to find the measure of angle A.

sin Aa

sin Bb

=

sin A11

=sin 34°7.85

sin A =11 sin 34°

7.850.7836

A sin –1 0.7836 51.6°

Law of sines

Substitute for a, b, and B.

Multiply each side by 11 andSimplify.

Use inverse sine.

The third angle C of the triangle is C 180° – 34° – 51.6° = 94.4°.

In ABC, b 7.85, A 51.68, and C 94.48.ANSWER

Page 3: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

EXAMPLE 2 Solve a triangle for the SSS case

Solve ABC with a = 12, b = 27, and c = 20.

SOLUTION

First find the angle opposite the longest side, AC . Use the law of cosines to solve for B.

b2 = a2 + c2 – 2ac cos B

272 = 122 + 202 – 2(12)(20) cos B

272 = 122 + 202

– 2(12)(20)= cos B

– 0.3854 cos B

B cos –1 (– 0.3854) 112.7°

Law of cosines

Substitute.

Solve for cos B.

Simplify.

Use inverse cosine.

Page 4: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

EXAMPLE 2 Solve a triangle for the SSS case

Now use the law of sines to find A.

sin Aa =

sin Bb

sin A12

sin 112.7°27

=

sin A =12 sin 112.7°

270.4100

A sin–1 0.4100 24.2°

Law of sines

Substitute for a, b, and B.

Multiply each side by 12 and simplify.

Use inverse sine.

The third angle C of the triangle is C 180° – 24.2° – 112.7° = 43.1°.

In ABC, A 24.2, B 112.7, and C 43.1.ANSWER

Page 5: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

EXAMPLE 3 Use the law of cosines in real life

Science

Scientists can use a set of footprints to calculate an organism’s step angle, which is a measure of walking efficiency. The closer the step angle is to 180°, the more efficiently the organism walked.

The diagram at the right shows a set of footprints for a dinosaur. Find the step angle B.

Page 6: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

EXAMPLE 3 Use the law of cosines in real life

SOLUTION

b2 = a2 + c2 – 2ac cos B

3162 = 1552 + 1972 – 2(155)(197) cos B

3162 = 1552 + 1972

– 2(155)(197)= cos B

– 0.6062 cos B

B cos –1 (– 0.6062) 127.3° Use inverse cosine.

Simplify.

Solve for cos B.

Substitute.

Law of cosines

The step angle B is about 127.3°.ANSWER

Page 7: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

GUIDED PRACTICE for Examples 1, 2, and 3

Find the area of ABC.

1. a = 8, c = 10, B = 48°

SOLUTION

Use the law of cosines to find side length b.

b2 = a2 + c2 – 2ac cos B

b2 = 82 + 102 – 2(8)(10) cos 48°

b2 57

b2 57 7.55

Law of cosines

Substitute for a, c, and B.

Simplify.

Take positive square root.

Page 8: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

GUIDED PRACTICE for Examples 1, 2, and 3

Use the law of sines to find the measure of angle A.

sin Aa

sin Bb

=

sin A 8

=sin 48°7.55

sin A =8 sin 48°

7.550.7874

A sin –1 0.7836 51.6°

Law of sines

Substitute for a, b, and B.

Multiply each side by 8 andsimplify.

Use inverse sine.

The third angle C of the triangle is C 180° – 48° – 52.2° = 79.8°.

In ABC, b 7.55, A 52.2°, and C 94.8°.ANSWER

Page 9: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

162 = 142 + 92 – 2(14)(9) cos B

GUIDED PRACTICE for Examples 1, 2, and 3

Find the area of ABC.

2. a = 14, b = 16, c = 9

SOLUTION

First find the angle opposite the longest side, AC . Use the law of cosines to solve for B.

b2 = a2 + c2 – 2ac cos B

162 = 142 + 92

– 2(14)(9)= cos B

Law of cosines

Substitute.

Solve for cos B.

Page 10: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

GUIDED PRACTICE for Examples 1, 2, and 3

– 0.0834 cos B

B cos –1 (– 0.0834) 85.7°

Simplify.

Use inverse cosine.

sin Aa

= sin Bb

sin A14

sin 85.2°16

=

sin A =14sin 85.2°

160.8719

Law of sines

Substitute for a, b, and B.

Multiply each side by 14 and simplify.

Use the law of sines to find the measure of angle A.

Page 11: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

GUIDED PRACTICE for Examples 1, 2, and 3

The third angle C of the triangle is C 180° – 85.2° – 60.7° = 34.1°.

A sin–1 0.8719 60.7° Use inverse sine.

In ABC, A 60.7°, B 85.2°, and C 34.1°.

ANSWER

Page 12: EXAMPLE 1 Solve a triangle for the SAS case Solve ABC with a = 11, c = 14, and B = 34°. SOLUTION Use the law of cosines to find side length b. b 2 = a

GUIDED PRACTICE for Examples 1, 2, and 3

SOLUTION

b2 = a2 + c2 – 2ac cos B

3352 = 1932 + 1862 – 2(193)(186) cos B

3352 = 1932 + 1862

– 2(193)(186)= cos B

– 0.5592 cos B

B cos –1 (– 0.5592) 127° Use inverse cosine.

Simplify.

Solve for cos B.

Substitute.

Law of cosines

3. What If? In Example 3, suppose that a = 193 cm, b = 335 cm, and c = 186 cm. Find the step angle θ.

The step angle B is about 124°.ANSWER