exam, examples & friction - high energy physicsjcumalat/phys1110/lectures/lec12.pdfexam,...
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Exam, Examples & Friction
• Exam Thursday, 7:30pm – Bring a #2 pencil – Will be 2 long answer questions
in addition to 15 multiple choice – Room assignments on web page – Calculators and 1 double sided
sheet of notes allowed – No formula sheet on exam!
• CAPA homework due next Tuesday
Web page: http://www.colorado.edu/physics/phys1110/phys1110_sp12/
Announcements:
Pulleys on Ships, Normally known as Blocks – hence block and tackle
Exam Locations-also on web page Sec Recita)onTime RecRoom Examroom TA
Rec301 0800‐0850 G‐2B75 Hum1B50 Colussi,Victor
Rec302 0800‐0850 G‐2B77 Math100 Houlton,John
Rec303 0800‐0850 G‐2B60 Math100 Koller,Andrew
Rec304 0900‐0950 G‐2B75 Hum1B50 VonStecher,Javier
Rec305 0900‐0950 G‐2B77 Math100 Houlton,John
Rec306 0900‐0950 G‐2B60 Chem142 Dai,Jixia
Rec307 1000‐1050 G‐2B75 Chem140 Kravtsov,Vasily
Rec308 1000‐1050 G‐2B77 Chem140 Barbee,John
Rec309 1000‐1050 G‐2B60 Chem142 Dai,Jixia
Rec310 1100‐1150 G‐2B75 Math100 Koller,Andrew
Rec311 1100‐1150 G‐2B77 Math100 Houlton,John
Rec312 1200‐1250 G‐2B75 Math100 Koller,Andrew
Rec313 1200‐1250 G‐2B77 Hum1B50 Colussi,Victor
Rec314 0100‐0150 G‐2B75 Math100 Houlton,John
Rec315 0100‐0150 G‐2B77 Math100 Koller,Andrew
Rec316 0100‐0150 G‐2B60 Chem140 Kravtsov,Vasily
Rec317 0200‐0250 G‐2B75 Chem140 Kravtsov,Vasily
Rec318 0200‐0250 G‐2B77 Chem140 Barbee,John
Rec319 0200‐0250 G‐2B60 Hum1B50 Colussi,Victor
Rec320 0300‐0350 G‐2B75 Chem140 Kravtsov,Vasily
Rec321 0300‐0350 G‐2B77 Chem140 Barbee,John
Rec322 0300‐0350 G‐2B60 Chem142 Dai,Jixia
Rec323 0400‐0450 G‐2B75 Chem140 Barbee,John
Rec324 0400‐0450 G‐2B77 Hum1B50 Colussi,Victor
Rec325 1100‐1150 G‐2B60 Hum1B50 VonStecher,Javier
Rec326 1200‐1250 G‐2B60 Chem142 Dai,Jixia
Math, Chemistry, Humanities
-not physics
Circular motion revisited We know that a change in velocity direction is a form of acceleration even if the speed is not changing Can divide acceleration into tangential and radial
components: and
Also know a net force is required for acceleration to occur
Thus, for uniform circular motion Newton’s 2nd law becomes Note that is not a force.
There must be a net force causing the radial acceleration
What is the force?
A car going around a corner on a level surface
For each of the scenarios, what is the force which causes the radial acceleration?
Friction between tires and pavement
A car going around a banked curve Friction between tires and pavement and a component of the normal force
Satellite orbiting the Earth Earth’s gravity
Prev. Clicker question Set frequency to BA
A rider in a "Barrel O’ Fun" finds herself stuck with her back to the wall. Which diagram correctly shows the forces acting on her?
A B C D E
No acceleration in y-direction:
In the horizontal direction:
Clicker question 1 Set frequency to BA
Which tension is larger: T1 or T2 ?
A) T1 B) T2 C) Both have the same magnitude.
A mass M is supported by two threads as shown. The free-body diagram correctly shows the directions of the forces but does not correctly show their magnitudes.
T1 must be larger, since |T1x | = T2
Clicker question 2 Set frequency to BA A person sits normally in a chair on a Ferris Wheel, which rotates with constant speed. As they go around the circle, at which point is the magnitude of the net force on the person a MAXIMUM?
A: Top B: Bottom
C: Right
D: Same at all positions.
Answer: Uniform motion means constant centripetal acceleration, so Fnet is the same everywhere
Clicker question 3 Set frequency to BA A person sits normally in a chair on a Ferris Wheel, which rotates with constant speed. As they go around the circle, at which point is the magnitude of the normal force of the seat on the person a MAXIMUM?
A: Top B: Bottom
C: Right
D: Same at all positions.
N is ALWAYS up wherever you are. Calling ”up" the "positive" direction, Newton's law says TOP: Fnet = +N - mg = - mv^2/R or N = mg - mv^2/R BOTTOM: Fnet = +N - mg = +mv^2/R or N = mg + mv^2/R. So, normal force is bigger at the bottom.
It seems reasonable. If you go fast, you practically lift off your seat. At the bottom, you are squished into it...
(Note ,difference with the bucket problem. Here, faster speeds means you're more likely to fly out at the top. In the bucket question, SLOWER speeds is the situation where we might fall out at the top. )
Pulleys Revisited
200 N supporting force in rod
You supply the lifting force and put tension/stress on the rod holding the load up.
100 N Load 100 N Load
100 N Lifting
Pulleys
Double Pulley 125 N
Triple Pulley
Sail Boat Crane
How a rope/cable elevator works
Need a dead weight to balance the weight of the elevator.
Clicker question 4 Set frequency to BA
A mass M is supported as shown on an incline plane. The free-body diagram correctly shows the directions of the forces but does not correctly show their magnitudes.
N – mg cos(θ) = 0
A student chooses a tilted coordinate system as shown, and then proceeds to write down Newton's 2nd Law. What is the correct equation for the y-direction ?
Clicker question 5 Set frequency to BA
A mass slides down a rough inclined plane with some non-zero acceleration a1. The same mass is shoved up the same incline with a large, brief initial push. As the mass moves up the incline, its acceleration is a2. How do a1 and a2 compare?
How do a1 and a2 compare?
A: a1 > a2 B: a1 = a2 C: a1 < a2
The forces in the "down the ramp" direction (right picture) would be a component of weight, mg*sin(θ), and the frictional force. In the left picture, those are in OPPOSITE directions (gravity is pulling it DOWN the ramp, friction is pushing UP the ramp, opposite v). So, in this case, the two forces oppose each other, meaning less net force, smaller acceleration.
Ladder Discussion A ladder of weight WL leans against a wall. The ladder has rollers at the top so that the wall exerts a normal force only on the top of the ladder. A person of weight WP slowly climbs the ladder.
FWall
WL
WP
Fx
Fy
(friction)
As the person ascends the ladder, the force from the wall (Fwall) A) increases B) decreases C) stays the same.
17
Friction Friction occurs when two materials slide past one another
On a microscopic level, molecules in one material form bonds with molecules in the other material
Friction acts parallel to the surface (perpendicular to the normal force).
Friction only acts to oppose motion
Not enough friction!
Force of kinetic friction is It depends on which depends on the materials and on the normal force N which is the force pushing the materials together.
is the coefficient of kinetic friction
Friction Experiments have found two main types of sliding friction
Static friction is the force exerted when the two objects are not in motion relative to each other (no slipping)
Kinetic friction is the force exerted when the two objects are in motion relative to each other (slipping)
m v
m
Formula for static friction is similar: .
Static friction
The static friction will oppose forces which try to slide one object across another. However, once the maximum possible static friction force is exceeded the object will “break loose” and start moving.
m m
If the block is not moving then:
is the coefficient of static friction
Static and Kinetic Friction
Applied force
Forc
e of
fric
tion
kinetic friction
Start with object at rest feeling a normal force of N Start applying a force perpendicular to N. Up to a force of µsN static friction prevents movement After movement starts, frictional force is reduced to µkN.
Clicker question 6 Set frequency to BA
A stationary block sits on an inclined plane. The coefficient of static friction is µS = 0.2. The normal, gravity, and static friction force are shown. Which set of relations applies to this situation? A. B. C.
θ
N
mg
Ff
Clicker question 7 Set frequency to BA
A stationary block sits on an inclined plane. The coefficient of static friction is µs = 0.2. If the angle of the plane increases, eventually the block begins to slide. Sliding will begin when…
A. B. C. D. None of the above
From the previous question we know &
N
mg
Ff
The maximum possible static friction force is . When the opposing force exceeds this, the block will start sliding.
Combining these 3 equations gives
so
Fluid resistance Another type of force similar to friction is due to moving through a medium like air or water called fluid resistance Fluid resistance depends on the size and shape of the object and the medium being traversed The force direction is opposite the velocity with a magnitude of approximately where the proportionality constants depend on the object and medium
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f = −kv −Dv 2
For small v, the kv term dominates while for larger v, the Dv2 term (called drag) dominates
Falling objects experience a constant force due to gravity and as the speed increases the drag force increases until balance is reached. This speed is the terminal velocity.
Because the resistance force is not constant, acceleration is not constant and so integral calculus is needed
Fluid resistance , so force increases with speed. If a constant force is trying to increase the speed, at some point the resistance will match that force and the speed will no longer increase
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f = −kv −Dv 2
Result for terminal velocity:
Fluid resistance At high speeds the force is and it has been found that where ρ is the medium density, A is the cross sectional area, and CD is the drag coefficient (generally between 0.1 and 1)
Top submarine speed = 80 km/hr where
Top airplane speed = 3500 km/hr where