estquantica8_1s2011

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    N N

    = (q1,...qN)

    qi

    N

    xp h

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    3He

    4He

    (q1,...,qi,...,qj,...,qN) = (q1,...,qj ,....,qi,...,qN)

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    nj = 0 1

    nj = 0, 1, 2,...

    1, 2

    A, B

    1 2

    1(rA)1(rB)

    2(rA)2(rB)

    12[1(rA)2(rB) + 1(rB)2(rA)]

    A B

    1 2

    12[1(rA)2(rB) 1(rB)2(rA)]

    A B

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    1 2

    1 2

    A, B

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    1 2 3 4 1 2 3 4 1 2 3 4

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    m L 0 < x < L

    n(x)

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    Hn(x) =nn(x)

    H= p2

    2m

    n(x) =Ceikx

    n=

    2k2

    2m

    k

    V(x) = 0, 0< x < L

    = , x

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    n(0) = n(L) = 0

    n(x) =

    2L

    sin

    nxL

    , n= 1, 2,...

    n =

    22n2

    8mL2

    (x) = (x+ L)

    exp(ikL) = 1

    k = 2L

    n, n= 0, 1, 2,...

    L

    ST P

    k 2/L

    L

    k

    f(k)

    k

    2/Lf(k) =

    L

    2

    kf(k)

    (r) =

    8

    V exp

    ik r

    k =

    2

    L1n1x1+

    2

    L2n2x2+

    2

    L3n3x3

    ni = 0, 1, 2,...

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    k =

    2k2

    2m

    k

    f(k) V(2)3

    3kf(k)

    {n1, n2,...,nj,...} {nj}

    nj

    N N

    {nj

    }

    E{nj} =j

    jnj

    N=N{nj} =j

    nj

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    Z(T , V , N ) =

    {nj},(P

    jnj=N)

    exp

    j

    jnj

    {nj} N

    Z(T , V , ) =

    N=0

    exp {N} Z(T , V , N )

    =

    N=0

    exp {N}

    {nj},(P

    jnj=N)

    exp {1n1 2n2 ...}

    =

    N=0

    {nj},(

    Pjnj=N)

    exp{

    (1

    )n1

    (2

    )n2

    ...}

    n1, n2,...

    N=n1+ n2+ ... N.

    Z=

    n1,n2,...

    exp {(1 )n1 (2 )n2 ...}

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    Z =

    N=0

    {nj},(Pnj=N)...

    =

    N=0

    n1,n2;n1+n2=N

    ...

    ={nj},0

    ... +{nj},1

    ... +{nj},2

    ... +{nj},3

    ... + ...

    =

    0,0

    ...

    +

    0,1

    ... +1,0

    ...

    +

    0,2

    ... +1,1

    ... +0,2

    ...

    +

    0,3

    ... +1,2

    ... +2,1

    ... +

    = 0,0

    ... +0,1

    ... +0,2

    ... + ...+1,0

    ... +1,1

    ... +1,2

    ... + ...+2,0

    ... +2,1

    ... + ..

    =

    0,n2=0

    ...

    +

    1,n2=0

    ...

    +

    2,n2=0

    ...

    + ...

    =

    n1=0

    n2=0

    ...

    =n1,n2

    ...

    Z=

    n1

    exp {(1 )n1}

    n2

    exp {(2 )n2}

    ...

    Z= Z(T , V , ) =

    jn

    exp {(j )n}

    nj

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    nj = 1

    jln Z

    n 0

    Z(T , V , ) =j

    n=0

    exp {(j )n}

    n=0

    exp {(j )n} = [1 exp {(j )}]1

    exp {(j )} < 1 j j 0 exp {} < 1 < 0

    0

    Z(T , V , ) =j

    [1 exp {(j )}]1

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    lnZ(T , V , ) = j

    ln[1 exp {(j )}]

    nj = 1exp {(j )} 1

    exp {(j )}

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    lnZFD,BE(T , V , ) = j

    ln[1 exp {(j )}]

    njFD,BE= 1

    exp {(j )} 1

    F D BE

    nj (j )

    nj 1 j < nj 0 j > T 0 nj

    nj 0 nj 1 j T 0 nj

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    (j )

    j T

    j T

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    nj 1 j

    nj 1

    exp {(j )} 1

    j

    z= exp {} 1

    exp {}

    ln ZFD,BE=j

    exp {(j )} 1

    2j

    exp {2(j )} + ...

    njFD,BE= exp {(j )} [1 exp {(j )} + ...]

    ln Zsc=j

    exp {(j }

    njsc= exp {(j )}

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    j k, = 2k2

    2m

    ln Zsc=k,

    exp

    2k2

    2m

    V

    ln Zsc = V

    (2)3

    3k exp

    2k2

    2m

    = V

    (2)3exp ()

    2kTm

    2

    3/2

    = V exp() 2kTmh2

    3/2

    sc= V 2mkT

    h2 3/2

    (kT)5/2 exp

    kT

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    MBN = 1N!

    distN

    N

    ZMBN = 1

    N!

    ZdistN

    1 2 3

    ZMBN =ZN1

    N!N=2 ZMB2 =

    Z212!

    ZMB2 = 1

    2!

    e1 + e2 + e3

    2=

    1

    2e21 +

    1

    2e22 +

    1

    2e23

    +e(1+2) + e(2+3) + e(1+3)

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    ZBE2 =e21 + e22 + e23 + e(1+2) + e(2+3) + e(1+3)

    ZFD2 =e(1+2) + e(2+3) + e(1+3)

    nk

    x= (k)

    x x

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    nk

    x= (k )

    lnZsc= V z

    2kTm

    h2

    3/2

    j

    nj

    =z

    zln Zsc= V z

    2kTm

    h2

    3/2 N

    N

    exp() =N

    V

    1

    h2

    2kTm3/2

    N

    V

    1

    h2

    2kTm

    3/2 1

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    N

    V

    1/3=a

    T = h2mkT

    (3/2)kT v =

    3kT/m

    =3kT

    2h

    T = v = 2h3kT m

    a T

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    lnZsc= zj

    exp(j)

    N

    N=z

    zln Zsc( , z , V ) =zj

    exp(j)

    njsc= zexp(j) = Nexp(j)

    jexp (j)

    njscN

    = exp(j)

    jexp (j)

    njscN

    p0(v) v=V

    (2)3exp2k2

    2m

    3k

    V(2)3

    exp

    2k2

    2m

    3k

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    p= mv = k

    p0(v) = 42kTm

    3/2

    v2 expmv2

    2kT

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