equipotential surfaces - tamuc

21
z Draw equipotential surfaces for distributions of charges z Equipotential surfaces are always to electric field lines and to E Equipotential Surfaces

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Page 1: Equipotential Surfaces - TAMUC

Draw equipotential surfaces for distributions of charges

Equipotential surfaces are always ⊥ to electric field lines and to E

Equipotential Surfaces

Page 2: Equipotential Surfaces - TAMUC

Equipotential Surfaces

Page 3: Equipotential Surfaces - TAMUC

E field lines are ⊥ to the equipotential surface

If given equipotential surfaces can draw Efield lines

Equipotential Surfaces

Page 4: Equipotential Surfaces - TAMUC

Potential Difference

Calculate ∆V between points i and f in an electric field E

Need to find W when Eis not constant.

0qWVVV if −=−=Δ

Page 5: Equipotential Surfaces - TAMUC

Potential Difference

Calculate differential amount of work

Remember

sdFdW rr•=

EqFrr

=

sdEqdW rr•= 0

Page 6: Equipotential Surfaces - TAMUC

Potential Difference

Work is

Substitute to find ∆V

Potential decreases if path is in the direction of the electric field

∫ •−=−=−=Δf

iif sdE

qWVVV rr

0

∫ •=f

i

sdEqW rr0

Page 7: Equipotential Surfaces - TAMUC

Electric Potential of a Point Charge

Derive potential V around a charged particle

Imagine moving a + test charge from P to ∞Path doesn’t matter so choose line radially with E

∫ •−=−f

iif sdEVV rr

Page 8: Equipotential Surfaces - TAMUC

Electric Potential of a Point Charge

Sign of V is same sign as q+ charge produces +V- charge produces –V

|V | gets larger as r gets smallerIn fact V = ∞ when r = 0 (on top of charge)

Graphical representation of V for charges in the x-y plane – plot value of V on the z-axis as a function of x-y position

rqkV =

Page 9: Equipotential Surfaces - TAMUC

Electric Potential of a Point Charge

Page 10: Equipotential Surfaces - TAMUC

Electric Potential of a Point Charge

Page 11: Equipotential Surfaces - TAMUC

Electric Potential of n Charges

Use superposition principle to find the potential due to n point charges

This is an algebraic sum, not a vector sumInclude the sign of the charge

∑∑==

==n

i i

in

ii r

qkVV11

Page 12: Equipotential Surfaces - TAMUC

Electric Potential of 2 Unequal Charges

Page 13: Equipotential Surfaces - TAMUC

Force, Field & Potential of Point Charge

What is the force F, electric field E, and potential V, at a point P a distance r away from a point charge?

20

rqq

kF =

2rqkE =

rqkV =

Page 14: Equipotential Surfaces - TAMUC

Electric Potential (Exercise)

Rank a), b) and c) according to net electric potential V produced at point P by two protons. (Greatest first.)

⎟⎠⎞

⎜⎝⎛ +=

Dq

dqkV ALL EQUAL

Page 15: Equipotential Surfaces - TAMUC

Electric Potential

Replace one of the protons by an electron. Rank the arrangements now.

⎟⎠⎞

⎜⎝⎛ +−=

Dq

dqkV ALL EQUAL

Page 16: Equipotential Surfaces - TAMUC

Electric Field

How do we calculate E from V ?

VqW Δ−= 0

dEqdFWrrrr

•=•=

dsEqdVq θcos00 =−

dsdVE −=θcos

Page 17: Equipotential Surfaces - TAMUC

Electric Field

How do we calculate E from V ?

Component of E in direction of ds

Component of E in any direction is negative rate of change of V with distance in that direction

sVEs ∂∂

−=

dsdVE −=θcos

Page 18: Equipotential Surfaces - TAMUC

Electric Field

Take s axis to be x, y, or z axes

If E is uniform and s is ⊥ to equipotential surface

zVE

yVE

xVE zyx ∂

∂−=

∂∂

−=∂∂

−= ,,

sVEΔΔ

−=

Page 19: Equipotential Surfaces - TAMUC

Electric Field (Exercise)

3 pairs of parallel plates with same separation and V of each plate. E field is uniform between plates and ⊥ to the plates.

A) Rank (greatest first) magnitude of E between the plates

Page 20: Equipotential Surfaces - TAMUC

Electric Field (Exercise)

but asked for magnitude of E

2, then 1 & 3

sVEΔΔ

−=

dE 200

1 = dE 220

2 = dE 200

3 =

Page 21: Equipotential Surfaces - TAMUC

Electric Field (Exercise)

B) For which pair does E point to the right?

#3C) If an electron is released midway between plates in (3) what does it do?

Accelerate to the left