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Page 1: Entrance exam example 2018/ Engineering - arcada.fiΒ Β· Entrance exam example 2018/ Engineering The following are some examples of the type of questions asked in the entrance exam

Entrance exam example 2018/ EngineeringThe following are some examples of the type of questions asked in the entrance exam. The answers are given on page 2.

1. 5

π‘₯+

1

π‘₯= 2π‘₯

2. 1

π‘₯βˆ’ 4π‘₯ = 0

3. √π‘₯2 βˆ’ 9 = 9

4. Solve π‘Ž and 𝑏 if 10 = 2π‘Ž + 1𝑏 and 0 = βˆ’5π‘Ž + 4𝑏

5. There is a square that touches the inside of a circle. The radius of the circle is 𝑅 = 1. Draw

that this setup. A) Calculate the length of the squares sides. b) Calculate the ratio of the area

of the square to the area of the circle

6. Find the zeros of the function 𝑦 = 2π‘₯2 + 3π‘₯ βˆ’ 9, indicate the position of this

minimum/maximum and create a sketch for the function from βˆ’4 ≀ π‘₯ ≀ +4.

7. Find the intersections of a circle and a line if 𝑅2 = π‘₯2 + 𝑦2 = 1 and a line is 𝑦 = 3π‘₯.

Logic

1. There are trees in the forest, on average one tree per 10 π‘š2. Each tree is 20 meters high and

the equivalent shape of the tree trunk is a cylinder with a constant diameter of 25 π‘π‘š.

Calculate the timber volume per hectare.

2. There is a fence of length L. Calculate the ratio of the areas if the fenced geometry is either a

square or a circle?

3. What is the total density of a mixture from 30% of A with density of 𝜌𝐴 = 1000π‘˜π‘”

π‘š3 and 70%

of B with a density of 𝜌𝐡 = 5000π‘˜π‘”

π‘š3?

Physics

1. A satellite orbits earth in a geostationary orbit. This means the satellite is permanently above

the same position at the equator. The satellite orbit is 36000 π‘˜π‘š above earth surface, earth

radius is 6400km. What is the approximate orbital velocity of the satellite?

2. The wave velocity in a solid is 𝑣 = √𝐸

𝜌. Assume a material with a Young’s modulus of 𝐸 =

1000 βˆ™ 106 π‘ƒπ‘Ž and density of 𝜌 = 1000π‘˜π‘”

π‘š3. How long time does an acoustic wave with

before velocity need to travel along a rail line of 1000 π‘˜π‘š.

Chemistry

1. Balance the following equation.

C4H10(l) + O2(g) β†’ CO2(g) + H2O(g)

2 C4H10(l) + 13 O2(g) β†’ 8 CO2(g) + 10 H2O(g)

2. There are 3 ketone isomers with the formula C5H10O. Draw their structures.

Mathematics

Page 2: Entrance exam example 2018/ Engineering - arcada.fiΒ Β· Entrance exam example 2018/ Engineering The following are some examples of the type of questions asked in the entrance exam

Mathematics

1. answer: 𝒙 = Β±βˆšπŸ‘

2. answer: 𝒙 = ±𝟏

𝟐

3. answer: 𝒙 = ±𝟏𝟎

4. answer: 𝒂 =πŸ’πŸŽ

πŸπŸ‘and 𝒃 =

πŸ“πŸŽ

πŸπŸ‘

5. answer A) βˆšπŸπ‘Ή = √𝟐 B) 𝑨𝒔𝒒𝒖𝒂𝒓𝒆

π‘¨π’„π’Šπ’“π’„π’π’†=

(√𝟐 𝟏)𝟐

𝝅 𝟏𝟐 =𝟐

𝝅

6. answer: π’™πŸ = βˆ’πŸ‘ and π’™πŸ = +𝟏. πŸ“

7. answer: π’™πŸ/𝟐 = ±√𝟏

𝟏𝟎

Logic

1. answer: π‘½π’Š = π…π‘ΉπŸπ’‰ = 𝝅 𝟎. πŸπŸπŸ“πŸπŸπŸŽ π’ŽπŸ‘, 𝑡 =𝟏𝟎𝟎𝟎𝟎

𝟏𝟎

π’ŽπŸ

π’ŽπŸ = 𝟏𝟎𝟎𝟎 𝒕𝒓𝒆𝒆𝒔. 𝑽𝒕𝒐𝒕 = 𝑡 π‘½π’Š =

𝟏𝟎𝟎𝟎 𝝅 𝟎. πŸπŸπŸ“πŸπŸπŸŽ π’ŽπŸ‘

2. answer: 𝒂𝒔𝒒𝒖𝒂𝒓𝒆 =𝑳

πŸ’and 𝑹 =

𝑳

πŸπ…leaves

𝑨𝒔𝒒𝒖𝒂𝒓𝒆

π‘¨π’„π’Šπ’“π’„π’π’†= (

𝑳

πŸ’)𝟐 (πŸπ…)𝟐

π…π‘³πŸ =𝝅

πŸ’

3. answer: 𝝆𝒕𝒐𝒕 = 𝟎. πŸ‘ 𝝆𝑨 + 𝟎. πŸ• 𝝆𝑩 = πŸ‘πŸŽπŸŽπ’Œπ’ˆ

π’ŽπŸ‘ + πŸ‘πŸ“πŸŽπŸŽπ’Œπ’ˆ

π’ŽπŸ‘ = πŸ‘πŸ–πŸŽπŸŽπ’Œπ’ˆ

π’ŽπŸ‘

Physics

1. answer: |οΏ½βƒ—βƒ—οΏ½ | =𝒔

𝒕=

πŸπ…π‘Ή

𝒕= πŸπ…

𝑹𝒆𝒂𝒓𝒕𝒉+π‘Ήπ’π’“π’ƒπ’Šπ’•

𝒕= πŸπ…

πŸ’πŸπŸ’πŸŽπŸŽ

πŸπŸ’[π’Œπ’Ž

𝒉]

2. answer: 𝒗 = βˆšπ‘¬

𝝆= √

𝟏𝟎𝟎𝟎

πŸπŸŽπŸŽπŸŽπŸπŸŽπŸ” 𝑡 π’ŽπŸ‘

π’ŽπŸ π’Œπ’ˆ= 𝟏𝟎𝟎𝟎

π’Ž

𝒔. Time of flight 𝒕 =

𝒔

𝒗=

𝟏𝟎𝟎𝟎

𝟏𝟎𝟎𝟎

π’Œπ’Ž

π’Ž/𝒔= 𝟏𝟎𝟎𝟎 𝒔

For further information related to the questions and answers below, please contact [email protected]