eng'g economics lesson 3

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  • 8/12/2019 Eng'g Economics Lesson 3

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    Concepts from theexample problems

    ( F / P, i, N) Prob lem 1

    ( P / F, i, N) Prob lem 2

    ( F / A , i, N) Prob lem 3( A / F, i, N) Prob lem 4

    ( P / A , i, N) Prob lem 5

    ( A / P, i, N) Prob lem 6( P / G, i, N) Prob lem 7

    ( A / G, i, N) Prob lem 8

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    Example 1

    How much w ould you have to deposi ttoday to have $2000 in 4 years i f you can

    get a 12% interest rate compounded

    annual ly?GIVEN:

    F4= $2 000

    i = 12%FIND P:

    P = F4(P/F,i,n)

    = 2 000(P|F,12%,4)

    = 2 000(0.6355) = $1 271

    0 1 2 3

    n=4

    P?

    $2 000

    DIAGRAM:

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    Different Waysof Looking at P/F

    From previous examp le, i f you can earn 12%

    compounded annual ly, you need to depos i t

    $1271 to have $2000 in 4 years.

    You are ind ifferent between $1271 today and

    $2000 in 4 years, assum ing you can earn areturn on your money o f 12%.

    $1271 today and $2000 in 4 years are

    equivalent, i f you can earn 12% on you r money.

    The present wor th o f $2000 in 4 years is $1271(i = 12% cpd annually).

    If you could get 13% on your money, would you

    rather have the $1271 today, or $2000 in 4 years

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    Example 2

    Tui t ion costs are expected to inf late at the

    rate of 8% per year. The first years

    tu i t ion is due one year from now and w i ll

    be $10,000. To co ver tui t ion cost fo r 4

    years, a fund is to be set up today in an

    accoun t that w i l l earn in terest at the rate

    of 5% per year, compounded annual ly.

    How much must be deposi ted in to thefund today in o rder to pay the 4 years o f

    tu i t ion expenses?

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    Present Given Gradient (Geometric)

    gis the geometric gradient over the time period (time period: Time 0 to Time n, 1st flow at Time 1)

    Pis the present value of the flow at Time 0

    (n periods in the past)

    i is the effective interest rate for each period

    Note: cash flow starts with A1at Time 1, increases by constant g%

    0 n

    A1

    P ?

    1 2 3

    P = A1(P/A,g,i,n)

    11

    1

    1

    ( )

    ( )

    ( / , , , )

    ( )

    n

    g

    iwhen i g

    i g

    P A g i n

    nwhen i g

    i

    g = %

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    Example 2

    Tuit ion costs are expected to inf late at the rate of 8% peryear. The first years tuition is due one year from now and

    w il l be $10,000. To co ver tuit ion cos t for 4 years, a fun d is

    to be set up today in an acco unt th at wi l l earn interest at

    the rate of 5% per year, com pou nded annual ly. How m uch

    must be deposi ted into the fund tod ay in order to pay the 4years of tui t ion expenses?

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    Example 2 - Concept

    If you r r ich Aunt Edna wanted to put a

    sum of money in the bank today to pay

    for you r next four years o f tu i t ion, that

    sum wou ld be $39,759 assum ing 5%

    return on investment and tu i t ion that

    begin s at $10,000 increasing by 8% per

    year. This problem assumes tui t ion is

    due at the end of the year.

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    Complex Cash Flows

    Complex Cash Flows B reak apart(or separate) complex cash f lows

    into component cash f lows in order

    to use the standard form ulas.

    Remember: You can on ly combine

    cash f low s i f they occu r at the same

    po int in t ime.

    (This is l ike bu i ld ing w ith LEGOs!)

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    Problem 3A con struct ion f i rm is consider ing the purchase of an

    air compresso r.

    The comp ressor h as the fo l lowing expected end o f

    year maintenance costs :

    Year 1 $800

    Year 2 $800Year 3 $900

    Year 4 $1000

    Year 5 $1100

    Year 6 $1200

    Year 7 $1300

    Year 8 $1400

    What is the present equivalent maintenance cost i f th e

    interest rate is 12% per year compou nded annual ly?

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    Problem 3 Alt Soln 1GIVEN:

    MAINT COST1-8

    PER DIAGRAM

    i = 12%/YR, CPD ANNUALLYFIND P: P = PA+ PG + PF= A(P/A,i,n) + G(P/G,i,n) + F(P/F,i,n)

    = $700(P/A,12%,8) + $100(P/G,12%,8)+ $100(P/F,12%,1)

    = $700(4.9676) + $100(14.4715)+ $100(0.8929) = $5014

    PA?

    0

    1 2 3 n=8

    $700

    4

    NOTE: CAN BREAK INTO 3 CASH FLOWS:ANNUAL, LINEAR GRADIENT, AND FUTURE

    DIAGRAM:

    P ?

    0

    1 2 3 n=8

    $700

    $100

    $700

    4

    $200$300

    $100PG?

    0

    1 2 3 n=8

    $100$700$200 $300

    4 0 $100

    PF?

    n=1

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    Problem 3 Alt Soln 2GIVEN:

    MAINT COST1-8

    PER DIAGRAMi = 12%/YR, CPD ANNUALLY

    FIND P: P = PA+ P

    G(P

    PG)= A(P/A,i,n) + G(P/G,i,n-1)(P/F,i,1)

    = $800(P/A,12%,8) + $100(P/G,12%,7)(P/F,12%,1)

    = $800(4.9676) + $100(11.6443)(0.8929)= $5014DIAGRAM:

    P ?

    0

    1 2 3 n=8

    $800

    $100

    $600

    4

    $200

    PA?

    0

    1 2 3 n=8

    $800

    4

    PG?

    0 1 2 n=73

    $100

    $600

    $200NOTE: PGMUST BE OFFSET ONE YEARSOBRING THE OFFSET YEAR BACK TO TIME ZERO

    0

    PG?

    PPG

    ?

    1

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    Problem 4A young coup le has decided to make advance plans for

    financing their 3 year old daughters college education.Money can be deposited at 8% per year, com pou nded

    annually.

    What annu al depos it on each bir th day, from the 4thto the

    17th(inc lus ive), mus t be made to p rov ide $7,000 on each

    bir thd ay from the 18th

    to th e 21s t

    (inclu sive)?GIVEN:

    WITHDRAWALS18-21

    = $7 000i = r = 8%/YR, CPD YEARLY

    FIND A4-17

    :

    17

    21 yrs

    $7 000

    A ?

    DIAGRAM:

    4

    180P17= A(F/A,i,n) = A(P/A,i,n)

    = A(F/A,8%,14) = 7 000(P/A,8%,4)

    = A(24.2149) = 7 000(3.3121)

    A = $957

    STRATEGY: CAN BREAK INTO 2 CASH FLOWS,SO PICK A CONVENIENT POINT IN TIME AND SETDEPOSITS EQUAL TO WITHDRAWALS