electricity & magnetism lecture 13
TRANSCRIPT
Worms Feel B field
Worms(C.elegans)cansensetheearth’smagne9cfield.
Whyisthezeroofpoten9alenergyfortheclosedlooptakenfromwhereitisperpendiculartotheelectricfield?
Idonotunderstandifthereisnonetforceontheloophowtherecanbetorqueandhowthetorquedoesn'teventuallystop.
canyouprovehowthecrossproductworks?
WhenarewegeOngourmidtermmarksback:o
Application: Mass spectrometer
Avelocityselectorisusedtoselectionsofgivenvelocity.
ThentheyareprojectedintoaregionofconstantBandzeroE.
Theradiusofcurvaturedependsontheion’smass.
Adetectorshowsthevariousmassesinthebeam.
Clicker Question
A B C
Electricity&Magne9smLecture13,Slide3
What is the force on section a-b on the loop?
A. Zero B. Out of page C. Into the Page
A square loop of wire is carrying current in the clockwise direction. There is a horizontal uniform magnetic field pointing to the right.
A B C
Clicker Question
Electricity&Magne9smLecture13,Slide4
What is the force on section b-c on the loop?
A. Zero B. Out of page C. Into the Page
A square loop of wire is carrying current in the clockwise direction. There is a horizontal uniform magnetic field pointing to the right.
What is the force on section c-d on the loop?
A. Zero B. Out of page C. Into the Page
Clicker Question
Electricity&Magne9smLecture13,Slide5
A square loop of wire is carrying current in the clockwise direction. There is a horizontal uniform magnetic field pointing to the right.
CheckPoint 2
Electricity&Magne9smLecture13,Slide6
What is the direction of the net force on the loop?
A. Out of page B. Into the Page C. Zero
A square loop of wire is carrying current in the clockwise direction. There is a horizontal uniform magnetic field pointing to the right.
A square loop of wire is carrying current in the clockwise direction. There is a horizontal uniform magnetic field pointing to the right.
CheckPoint 4
Inwhichdirec9onwillthelooprotate?(assumethezaxisisoutofthepage)
A) AroundthexaxisB) AroundtheyaxisC) AroundthezaxisD) Itwillnotrotate
x
y
Electricity&Magne9smLecture13,Slide7
A square loop of wire is carrying current in the clockwise direction. There is a horizontal uniform magnetic field pointing to the right.
CheckPoint 6
Electricity&Magne9smLecture13,Slide8
Whatisthedirec9onofthenettorqueontheloop?
A) up(onpage)B) down(onpage)C) outofpageD) intopageE) nettorqueiszero
into page out of page
Magnetic Dipole Moment
Areavector Magnitude=Area
Direc9onusesR.H.R.
Magne9cDipolemoment
Electricity&Magne9smLecture13,Slide9
µ Makes Torque Easy!
Thetorquealwayswantstolineµ upwithB!
Electricity&Magne9smLecture13,Slide10
Bµ
turns µ toward B
x
y
z
B
µ
turnsµ toward Bx
y
z
Practice with µ and τ
Bµ
Inthiscaseµ isoutofthepage(usingrighthandrule)
I
Electricity&Magne9smLecture13,Slide11
Bµ
xy
z
isup(turnsµ toward B)
Practice with µ and τ
Bµ
Inthiscaseµ isINtothepage(usingrighthandrule)
I
Electricity&Magne9smLecture13,Slide11
B
µ
xy
z
isdown(turnsµ toward B)
⨂
Magnetic Field does Work on Current-carrying wire
FromPhysics120:
FromPhysics121:
DefineU = 0 atposi9onofmaximumtorque
Electricity&Magne9smLecture13,Slide13
-1.0000
-0.7500
-0.5000
-0.2500
0.0000
0.2500
0.5000
0.7500
1.0000
0 45 90 135 180
BµU = ��µ · �B
W =Z ⇥/2
�µB sin ��d�� = µB cos � = ⇤µ · ⇤BText
U
angle (°)
CheckPoint 10
U = 0U = −µBcosθθ
U = +µBcosφ
φ
Electricity&Magne9smLecture13,Slide14
Which orientation has the lowest potential energy?
Wby f ield = ��U = Ui � U f
U = �µ · �B
BYWHOM?
BYYOU
BYFIELD
θc
θaφa
CheckPoint 12
Electricity&Magne9smLecture13,Slide15
C):
B):
A):
Howmuchdoesthepoten9alenergyofthesystemchangeasthecoilmovesfromitsini9alposi9ontoitsfinalposi9on.
ConceptualAnalysisAcurrentloopmayexperienceatorqueinaconstantmagne9cfield
τ = µ X B Wecanassociateapoten9alenergywiththeorienta9onofloop
U = − µ · B
z
x
y
B .30˚
y
z
I
ini9al final
StrategicAnalysisFind µCalculatethechangeinpoten9alenergyfromini9altofinal
a
B
Calculation
Asquareloopofsidea liesinthex−zplanewithcurrentI asshown.Theloopcanrotateaboutx axiswithoutfric9on.AuniformfieldBpointsalongthe+z axis.Assumea, I,andBareknown.
Electricity&Magne9smLecture13,Slide16
Whatisthedirec9onofthemagne9cmomentofthiscurrentloopinitsini9alposi9on?
A)+x B)−x C)+y D)−y
Asquareloopofsidea liesinthex−zplanewithcurrentI asshown.Theloopcanrotateaboutx axiswithoutfric9on.AuniformfieldBpointsalongthe+z axis.Assumea, I,andBareknown.
xinitial final
z
x
y
B .30˚
y
z
I
ini9al final
a
B
Calculation
Electricity&Magne9smLecture13,Slide17
Whatisthedirec9onofthetorqueonthiscurrentloopintheini9alposi9on?
A)+xB)−xC)+yD)−y
y
z
x
y
B .30˚
y
z
I
ini9al final
a
B
Calculation
Asquareloopofsidea liesinthex−zplanewithcurrentI asshown.Theloopcanrotateaboutx axiswithoutfric9on.AuniformfieldBpointsalongthe+z axis.Assumea, I,andBareknown.
Electricity&Magne9smLecture13,Slide18
µ
U = ��µ · �B
Calculation
Whatisthepoten9alenergyoftheini9alstate?
A)Uinitial < 0B)Uinitial = 0 C)Uinitial > 0
z
x
y
B .30˚
y
z
I
ini9al final
a
BAsquareloopofsidea liesinthex−zplanewithcurrentI asshown.Theloopcanrotateaboutx axiswithoutfric9on.AuniformfieldBpointsalongthe+z axis.Assumea, I,andBareknown.
Electricity&Magne9smLecture13,Slide19
Whatisthepoten9alenergyofthefinalstate?
A)Ufinal< 0 B)Ufinal = 0 C)Ufinal > 0
y
initial
z
x
y
B .30˚
y
z
I
ini9al final
a
B
Calculation
Asquareloopofsidea liesinthex−zplanewithcurrentI asshown.Theloopcanrotateaboutx axiswithoutfric9on.AuniformfieldBpointsalongthe+z axis.Assumea, I,andBareknown.
Electricity&Magne9smLecture13,Slide20
µµ
U = ��µ · �B
-1.0000-0.7500-0.5000-0.25000.00000.25000.50000.75001.0000
0 45 90 135 180angle (°)
U
A)B)C)
Whatisthepoten9alenergyofthefinalstate?
z
x
y
B .30˚
y
z
I
ini9al final
a
B
Calculation
Asquareloopofsidea liesinthex−zplanewithcurrentI asshown.Theloopcanrotateaboutx axiswithoutfric9on.AuniformfieldBpointsalongthe+z axis.Assumea, I,andBareknown.
Electricity&Magne9smLecture13,Slide21
µµU = ��µ · �B