electric potential i physics 2102 jonathan dowling physics 2102 lecture: 08 fri 30 jan ch24.1-5...
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![Page 1: Electric Potential I Physics 2102 Jonathan Dowling Physics 2102 Lecture: 08 FRI 30 JAN Ch24.1-5 Danger!](https://reader036.vdocuments.mx/reader036/viewer/2022082818/56649f155503460f94c2b181/html5/thumbnails/1.jpg)
Electric Potential IElectric Potential I
Physics 2102
Jonathan Dowling
Physics 2102 Physics 2102 Lecture: 08 FRI 30 JANLecture: 08 FRI 30 JAN
Ch24.1-5
Danger!
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Electric Potential EnergyElectric Potential EnergyElectric Potential Energy U is Negative of the Work W to Bring Charges in From Infinity:
U = –W∞
The Change in Potential Energy U Between an Initial and Final Configuration Is Negative the Work W Done by the Electrostatic Forces:
U = Uf - Ui = -W
• What is the potential energy of a single charge? • What is the potential energy of a dipole? • A proton moves from point i to point f in a uniform electric field, as shown. - Does the electric field do positive or negative work on the proton? - Does the electric potential energy of the proton increase or decrease?
+Q –Qa
+Q
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Electric PotentialElectric PotentialElectric potential difference between two points = work per unit charge needed to move a charge between the two points:
V = Vf – Vi = –W/q = U/q
0
0
0
f f
i i
f
f i
i
dW F ds
dW q E ds
W dW q E ds
WV V V E ds
q
= •
= •
= = •
= − =− =− •
∫ ∫
∫
r rr r
r r
r r
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Electric Potential Electric Potential Energy, Energy,
Electric PotentialElectric PotentialUnits :
Potential Energy = U = [J] = Joules
Electric Potential = V = U/q = [J/C] = [Nm/C] = [V]
= Volts
Electric Field = E = [N/C] = [V/m] = Volts per meter
Electron Volt = 1eV = Work Needed to Move an
Electron Through a Potential Difference of 1V:
W = qV = e x 1V = 1.60 10–19 C x 1J/C = 1.60 10–19 J
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Equipotential SurfacesEquipotential Surfaces
• The Electric Field is Tangent to the Field
Lines
• Equipotential Surfaces are Perpendicular to
Field Lines• Work Is Needed to Move a Charge Along a Field Line.
• No Work Is Needed to Move a Charge Along an Equipotential Surface.
• Electric Field Lines Always Point Towards Equipotential Surfaces With Lower Potential.
0
f
f i
i
WV V V E ds
q = − =− =− •∫
r r
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Electric Field Lines and Electric Field Lines and Equipotential SurfacesEquipotential Surfaces
http://www.cco.caltech.edu/~phys1/java/phys1/EField/EField.html
Why am I smiling?I’m About to Be
Struck byLightning!
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Electric Potential and Electric Potential and Electric Potential EnergyElectric Potential Energy
The change in potential energy of a charge q moving from point i to point f is equal to the work done by the applied force, which is equal to minus the work done by the electric field, which is related to the difference in electric potential:
f i appU U U W W q V = − = =− = We move a proton from point i to point f in a uniform electric field, as shown.
• Does the electric field do positive or negative work on the proton? • Does the electric potential energy of the proton increase or decrease? • Does our force do positive or negative work ? • Does the proton move to a higher or lower potential?
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ExampleExampleConsider a positive and a negative charge,
freely moving in a uniform electric field. True or false?
(a) Positive charge moves to points with lower potential.
(b) Negative charge moves to points with lower potential.
(c)Positive charge moves to a lower potential energy position.
(d)Negative charge moves to a lower potential energy position
–Q +Q 0+V
–V
(a) True(b) False(c) True(d) True
+ + + + + + + + +
– – – – – – – –
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Conservative ForcesConservative ForcesThe potential difference between two points is independent of the path taken to calculate it: electric forces are “conservative”.
0 0
f
f i
i
W UV V V E ds
q q
= − =− = =− •∫
r r
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Summary:Summary:• Electric potential: work needed to bring +1C from
infinity; units V = Volt
• Electric potential uniquely defined for every point
in space -- independent of path!
• Electric potential is a scalar — add contributions
from individual point charges
• We calculated the electric potential produced by a
single charge: V=kq/r, and by continuous charge
distributions:
V=∫kdq/r
• Electric potential energy: work used to build the
system, charge by charge. Use W=qV for each charge.