ejerc diag corte-momento
DESCRIPTION
Para que resuelvan vigasTRANSCRIPT
2 1 4 3
F
Q1
Q2
F = 6[kN]
Q1 = 4[kN/m]
Q2 =10[kN/m]
2 3 7 10
F
Q1
Q2
VA VB F1 F2
0 5 17/3
F1 = 16[kN]
F2 =12[kN/m]
−퐹 + 푉 − 퐹 − 퐹 + 푉 = 0 ⇒ 푉 + 푉 = 34
2 ∙ 퐹 − 3 ∙ 퐹 −113∙ 퐹 + 8 ∙ 푉 = 0 ⇒ 푉 = 10[푘푁] ⇒ 푉 = 24[푘푁]
0 - 2
−퐹 − 푉 = 0 ⇒ 푉 = −6[푘푁]
퐹 ∙ 푥 + 푀 = 0 ⇒ 푀 = −6 ∙ 푥
푉⃗
푀⃗ 푥
퐹⃗
0
푀 = 0[푘푁 ∙ 푚]
푀 = −12[푘푁 ∙ 푚]
2 - 3
2
F VA
0
푉⃗
푀⃗ 푥
−퐹 + 푉 − 푉 = 0 ⇒ 푉 = 18[푘푁]
퐹 ∙ 푥 − 푉 ∙ (푥 − 2) + 푀 = 0
⇒ 푀 = 18 ∙ 푥 − 48
푀 = −12[푘푁 ∙ 푚]
푀 = 6[푘푁 ∙ 푚]
푥 =83
= 2. 6[푚]
2 3
F Q1 VA
0
푦
푉⃗
푀⃗ 푥
3 - 7
Q1
Q2
푦
3 7 푥
푄 − 푄7− 3
=푦 − 푄푥 − 3
푦 =32∙ 푥 −
12
푦 =12∙ (3 ∙ 푥 − 1)
−퐹 + 푉 − 푄 ∙ (푥 − 3) −(푦 − 푄 ) ∙ (푥 − 3)
2− 푉 = 0 ⇒ 푉 =
−34∙ 푥 +
12∙ 푥 +
934
푉 = 18[푘푁] ; 푉 = −10[푘푁] ; 푥 =−1 ± 2√70
3≈ 5.244[푚] ; 푥 =
13
= 0. 3[푚] ∌ [3 − 7][푚]
퐹 ∙ 푥 − 푉 ∙ (푥 − 2) + 푄 ∙ (푥 − 3) ∙
(푥 − 3)2
+(푦 − 푄 ) ∙ (푥 − 3)
2∙
(푥 − 3)3
+ 푀 = 0
⇒ 푀 =−14∙ 푥 +
14∙ 푥 +
934∙ 푥 −
2374
푀 = 6[푘푁 ∙ 푚] ; 푀 = 30[푘푁 ∙ 푚] ; 푥 = (−10.284, 2.678, 8.606)[푚] ∌ [3 − 7][푚]
7 - 10
푉⃗
푀⃗ 푥
2 3 7
F VA
F1 F2
0 5 17/3
−퐹 + 푉 − 퐹 − 퐹 − 푉 = 0 ⇒ 푉 = −10[푘푁]
퐹 ∙ 푥 − 푉 ∙ (푥 − 2) + 퐹 ∙ (푥 − 5) + 퐹 ∙ 푥 −173
+ 푀 = 0
⇒ 푀 = −10 ∙ 푥 + 100
푀 √ =2
27137√70 − 694 ≈ 33.498[푘푁 ∙ 푚]
푀 = 30[푘푁 ∙ 푚]
푀 = 0[푘푁 ∙ 푚]
푥 = 10.0[푚]