Department of Electrical and Electronic Engineering

Bangladesh University of Engineering and Technology

Course No.: EEE 316 Group No.: 05

Course Name: Microprocessor and Interfacing Sessional.

Experiment No.: 02, 03, 04

Experiment Name:

Logical Instructions, Jump Commands, LOOPs and Arrays in Assembly Language

Date of Performance: 21/01/2014 Name: Musbiha Binte Wali

Date of Submission: 25/01/2014 Level: 3 Term: 2

Section: A1

Student No.: 0906022

Objective:

To be familiar with the operations of Arrays in assembly language programming.

Home Task: To write complete assembly language for the operation of

finding out how many numbers divisible by 5 lie in between two given input numbers DATA1 and DATA2.

Also finding out those numbers.

Code:

CODE SEGMENT

ASSUME CS:CODE, DS:CODE

;

ORG 100H

;

MAIN: MOV AX, CS

MOV DS, AX

;

MOV BX, 0

MOV CX, 0

MOV DX, 0

MOV CL, DATA2

SUB CL, DATA1

ADD CL, 1

beginn: ;LOOP STARTS

MOV AL, CL

ADD AL, DATA1

SUB AL, 1

CBW ;AH will have the remainder

MOV BL, 5

DIV BL

CMP AH, 0

JZ AN_

JMP END_

AN_:

ADD DL, 1 ;When Remainder is zero

MOV AL, CL

ADD AL, DATA1

SUB AL, 1

MOV BL,DL

MOV [ARR+BX-1], AL

END_:

loop beginn

;

MOV ANS, DL

MOV AH, 4CH

INT 21H

;

ORG 1500H

DATA1 DB 22

ORG 1510H

DATA2 DB 39

ORG 1540H

ANS DB ? ;how many numbers

ORG 1600H

ARR DB 80 DUP(0) ;solution array

;

CODE ENDS

END

END MAIN

Debug Results:

In each debugging, DATA1’s value is at 1410:1500.

DATA2’s value is at 1410:1510. Answer ANS’s value is at 1410:1540.

Answer ARRAY is at 1410:1600.

For DATA1= 2 and DATA2= 4, Answer=0 (at 1410:1540) and the Answer array contains no contents (at 1410:1600)

For DATA1= 14 and DATA2= 16, Answer=01 (at 1410:1540) and the Answer array contains one content which is 15 (at 1410:1600)

For DATA1= 22 and DATA2= 39, Answer=03 (at 1410:1540) and the Answer array contains three contents which are 35, 30, 25

(at 1410:1600)

For DATA1= 15 and DATA2= 50, Answer=08 (at 1410:1540) and the Answer array contains eight contents which are 50, 45, 40,

35, 30, 25, 20, 15 (at 1410:1600)

Lab Task: Taking an input array and reversing the case of each array-element; if any of them is digit, expressing that

as 10’s complement

Code: CODE SEGMENT

ASSUME CS:CODE, DS:CODE

;

ORG 100H

;

MAIN: MOV AX, CS

MOV DS, AX

;

ORG 100H

ARR_ DB '1','A' ,'a','2','3','4','7','5','G','h','4','k'; ;input array

ORG 1500H;

ANS DB 12 DUP(0);

MOV CX ,12;

MOV DL, 106;

LOOP1:

MOV BX,CX;

MOV AL,[ARR_+BX-1];

CMP AL,'9';

JG SKIP;

SUB DL,AL;

MOV AL, DL;

MOV DL,106;

MOV [ANS+BX-1],AL;

JMP EXIT_;

SKIP:

CMP AL,'Z';

JG SKIP1;

ADD AL,32;

MOV [ANS+BX-1],AL;

JMP EXIT_;

SKIP1:

SUB AL,32;

MOV [ANS+BX-1],AL;

EXIT_:

LOOP LOOP1;

MOV AH, 4CH

INT 21H

CODE ENDS

END MAIN

Result:

In debugging window, Input array is at 1413:0200.

Output array is at 1413:1500. Input array was: 1Aa23475Gh4k

Output array is: 9aA87635gH6K