ece317 : feedback and control

19
ECE317 : Feedback and Control Lecture: ODE solution via Laplace transform Dr. Richard Tymerski Dept. of Electrical and Computer Engineering Portland State University 1

Upload: others

Post on 16-Nov-2021

5 views

Category:

Documents


2 download

TRANSCRIPT

Page 1: ECE317 : Feedback and Control

ECE317 : Feedback and Control

Lecture:ODE solution via Laplace transform

Dr. Richard Tymerski

Dept. of Electrical and Computer Engineering

Portland State University

1

Page 2: ECE317 : Feedback and Control

Course roadmap

2

Laplace transform

Transfer function

Block Diagram

Linearization

Models for systems

• electrical

• mechanical

• example system

Modeling Analysis Design

Stability

• Pole locations

• Routh-Hurwitz

Time response

• Transient

• Steady state (error)

Frequency response

• Bode plot

Design specs

Frequency domain

Bode plot

Compensation

Design examples

Matlab & PECS simulations & laboratories

Page 3: ECE317 : Feedback and Control

Laplace transform (review)

• One of most important math tools in the course!

• Definition: For a function f(t) (f(t)=0 for t<0),

• We denote Laplace transform of f(t) by F(s).

3

f(t)

t0

F(s)

(s: complex variable)A:=B (A is defined by B.)

Page 4: ECE317 : Feedback and Control

Laplace transform table

4

Inverse Laplace

Transform

(u(t) is often omitted.)

Page 5: ECE317 : Feedback and Control

Advantages of s-domain (review)

• We can transform an ordinary differential equation into an algebraic equation which is easy to solve.

(This lecture)

• It is easy to analyze and design interconnected (series, feedback etc.) systems.

• Frequency domain information of signals can be easily dealt with.

5

Page 6: ECE317 : Feedback and Control

An advantage of Laplace transform

• We can transform an ordinary differential equation (ODE) into an algebraic equation (AE).

6

ODE AE

Partial fraction

expansionSolution to ODE

t-domain s-domain

1

2

3

Page 7: ECE317 : Feedback and Control

Example 1 (distinct roots)

ODE with initial conditions (ICs)

1. Laplace transform

7

distinct roots

Page 8: ECE317 : Feedback and Control

Properties of Laplace transformDifferentiation (review)

8

t-domain

s-domain

Page 9: ECE317 : Feedback and Control

Example 1 (cont’d)

2. Partial fraction expansion

Multiply both sides by s(s+1)(s+2) :

Compare coefficients:

9

unknowns

Page 10: ECE317 : Feedback and Control

Example 1 (cont’d)

3. Inverse Laplace transform

If we are interested in only the final value of y(t), apply the Final Value Theorem, without explicitly computing y(t):

10

(You may omit u(t).)

Page 11: ECE317 : Feedback and Control

Example 2 (repeated roots)

ODE with zero initial conditions (ICs)

1. Laplace transform

11

Repeated roots

Page 12: ECE317 : Feedback and Control

Example 2 (cont’d)

2. Partial fraction expansion

Multiply both sides by

Compare coefficients:

12

unknowns

Page 13: ECE317 : Feedback and Control

Example 2 (cont’d)

3. Inverse Laplace transform

If we are interested in only the final value of y(t), apply the Final Value Theorem, without explicitly computing y(t):

13

(u(t) omitted.)

Page 14: ECE317 : Feedback and Control

Properties of Laplace transformFrequency shift theorem (review)

14

Proof.t-domain

s-domain

Ex.

Page 15: ECE317 : Feedback and Control

Example 3 (complex roots)

ODE with zero initial conditions (ICs)

1. Laplace transform

15

Complex roots

Page 16: ECE317 : Feedback and Control

Example 3 (cont’d)

2. Partial fraction expansion

Multiply both sides by

Compare coefficients:

16

unknowns

Page 17: ECE317 : Feedback and Control

Example 3 (cont’d)

3. Inverse Laplace transform

17

Page 18: ECE317 : Feedback and Control

Laplace transform table

18

Frequency shift theorem

Page 19: ECE317 : Feedback and Control

Summary

• Solution to ODE via Laplace transform1. Laplace transform

2. Partial fraction expansion

3. Inverse Laplace transform

• Next, modeling of physical systems in s-domain

19