drawing process of wire and bar

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  • 8/12/2019 Drawing Process of Wire and Bar

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    Wire and Bar Drawing:

    Drawing is an operation in which the cross section of a bar, rod, or

    wire is reduced by pulling it through a die opining as in figure (40).

    The general features of the process are similar to those of extrusion.

    The difference is that the work is pulled through the die in drawing,

    whereas it is pushed through the die in extrusion.

    The basic difference between bar drawing and wire drawing is the

    stock size that is processed. Bar drawing is the term used for large-

    diameter bar and rod stock, while wire drawing applies to small-

    diameter stock. Wire sizes down to 0.001 in (0.03 mm) are possible in

    wire drawing.

    Bar drawing is generally accomplished as a single-draft operation: the

    stock is pulled through one die opining because the beginning stock has

    a large diameter, it is in the form of a straight piece rather than coiled.

    By contrast, wire is drawn from coils consisting of several hundred (or

    even several thousand) feet of wire and is passed through a series of

    draw dies. The number of dies varies typically between 4 and 12.

    Figure (40) Drawing processes.

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    In drawing operation the change in size of the work is usually given by

    the area reduction, defined as follows:

    AAAr f

    Where r= area reduction in drawing.

    A = original area of work in^2(mm^2).

    fA = final area of work in^2(mm^2).

    In bar drawing, rod drawing, and in drawing of large-diameter wire

    for upsetting and heading operations, the term draft is used to denote

    the before and after difference in size of the processed work. The draft

    is simply the difference between original and final stock diameters:

    fDDd

    Where d= draft, in(mm).

    D = original diameter, in(mm).

    fD = final work diameter, in(mm).

    Analysis of Drawing:

    Mechanics of drawing, if no friction work occurred in drawing,

    true strain could be determined as follows:

    rA

    A

    f

    1

    1lnln

    The stress that results from this ideal deformation is given by:

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    f

    ffA

    AYY

    ln

    Where

    fY = average flow stress based on the value of strain because

    friction is present in drawing and work experiences in homogeneous

    deformation, the actual stress is larger than provided by the above

    equation.

    In addition to the ratio fAA / , other variables that influence draw

    stress are die angle and coefficient of friction at the work-die interface.

    We present the equation suggested by Schey:

    f

    fdA

    AY

    ln)tan

    1(

    Where d = draw stress,lb/in^2(MPa).

    = die-work coefficient of friction.

    = die angle (half angle) as defined in figure 1.

    = factor that accounts for in homogeneous deformation.

    CL

    D12.088.0

    Where D = average diameter of work during drawing, in(mm).

    CL = contact length of the work with the draw die, in(mm).

    sin2,

    2

    f

    C

    f DDL

    DDD

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    The corresponding draw force is then the area of the drawn cross

    section multiplied by the draw stress;

    f

    ffdfA

    AYAAF

    ln)tan

    1(

    Where F= draw force, lb(N).

    The power required in a drawing operation is the draw force

    multiplied by exit velocity of the work.

    Example:wire is drawn through a draw die with entrance angle =

    15

    starting diameter is 0.1 in, and final diameter 0.08 in. the coefficient of

    friction at the work-die interface =0.07. The metal has a strength

    coefficient K=30000lb/in^2, and a strain hardening exponent n=0.2.

    Determine the draw stress and draw force in this operation?

    Solution:

    inDD

    D f

    09.02

    08.01.0

    2

    inDD

    L f

    C 0386.015sin2

    08.0_1.0

    sin2

    16.10386.0

    09.012.088.012.088.0

    CL

    D

    222 00786.01.044

    inDA

    222 00503.008.0

    44

    hnDA ff

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    446.000503.0

    00786.0lnln

    fA

    A

    22.0

    /212752.1

    )446.0(30000

    1inlb

    n

    KY

    n

    f

    f

    fdA

    AY

    ln)tan

    1(

    2/13882)446.0)(16.1)(

    15tan

    07.01(21275 inlbd

    lbAF fd 7000503.0*13882