![Page 1: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/1.jpg)
Section 5.6
Applications and Models: Growth and Decay; Com-pound Interest
![Page 2: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/2.jpg)
Exponential Growth
A quantity that experiences exponential growth will increase according tothe equation
P(t) = P0ekt
where
t is the time (in any given units)
P(t) is the amount at time t
P0 is the initial quantity.
k (which needs to be positive) is the exponential growth rate.
![Page 3: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/3.jpg)
Exponential Growth
A quantity that experiences exponential growth will increase according tothe equation
P(t) = P0ekt
where
t is the time (in any given units)
P(t) is the amount at time t
P0 is the initial quantity.
k (which needs to be positive) is the exponential growth rate.
![Page 4: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/4.jpg)
Exponential Growth
A quantity that experiences exponential growth will increase according tothe equation
P(t) = P0ekt
where
t is the time (in any given units)
P(t) is the amount at time t
P0 is the initial quantity.
k (which needs to be positive) is the exponential growth rate.
![Page 5: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/5.jpg)
Exponential Growth
A quantity that experiences exponential growth will increase according tothe equation
P(t) = P0ekt
where
t is the time (in any given units)
P(t) is the amount at time t
P0 is the initial quantity.
k (which needs to be positive) is the exponential growth rate.
![Page 6: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/6.jpg)
Exponential Growth (continued)
A quantity that experiences exponential growth also has a correspondingdoubling time. If the doubling time is T , then the population willincrease according to the equation
P(t) = P0ekt , where k =
ln 2
T
Notice you can also solve for T to get the equation T = ln 2k
![Page 7: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/7.jpg)
Examples
1. The exponential growth rate of a population of rabbits is 11.6% permonth. What is the doubling time?
About 6 months.
2. A sample of bacteria is growing in a Petri dish. There were originally2 thousand cells, and after 2 hours there are now 5 thousand cells.How long will it take for there to be 8 thousand cells?
About 3 hours.
![Page 8: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/8.jpg)
Examples
1. The exponential growth rate of a population of rabbits is 11.6% permonth. What is the doubling time?
About 6 months.
2. A sample of bacteria is growing in a Petri dish. There were originally2 thousand cells, and after 2 hours there are now 5 thousand cells.How long will it take for there to be 8 thousand cells?
About 3 hours.
![Page 9: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/9.jpg)
Examples
1. The exponential growth rate of a population of rabbits is 11.6% permonth. What is the doubling time?
About 6 months.
2. A sample of bacteria is growing in a Petri dish. There were originally2 thousand cells, and after 2 hours there are now 5 thousand cells.How long will it take for there to be 8 thousand cells?
About 3 hours.
![Page 10: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/10.jpg)
Examples
1. The exponential growth rate of a population of rabbits is 11.6% permonth. What is the doubling time?
About 6 months.
2. A sample of bacteria is growing in a Petri dish. There were originally2 thousand cells, and after 2 hours there are now 5 thousand cells.How long will it take for there to be 8 thousand cells?
About 3 hours.
![Page 11: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/11.jpg)
Compounded Interest
An an investment earning continuously compounded interest growsaccording to the formula:
P(t) = P0
(1 + r
n
)ntwhere
t is the time (in years)
P(t) is the total amount of money at time t
P0 is the principal - or initial amount of the investment.
r is the interest rate.
n is the number of times the interest is compounded per year.
Page 327 has a chart with key words to help figure out what n is.
![Page 12: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/12.jpg)
Compounded Interest
An an investment earning continuously compounded interest growsaccording to the formula:
P(t) = P0
(1 + r
n
)ntwhere
t is the time (in years)
P(t) is the total amount of money at time t
P0 is the principal - or initial amount of the investment.
r is the interest rate.
n is the number of times the interest is compounded per year.
Page 327 has a chart with key words to help figure out what n is.
![Page 13: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/13.jpg)
Compounded Interest
An an investment earning continuously compounded interest growsaccording to the formula:
P(t) = P0
(1 + r
n
)ntwhere
t is the time (in years)
P(t) is the total amount of money at time t
P0 is the principal - or initial amount of the investment.
r is the interest rate.
n is the number of times the interest is compounded per year.
Page 327 has a chart with key words to help figure out what n is.
![Page 14: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/14.jpg)
Compounded Interest
An an investment earning continuously compounded interest growsaccording to the formula:
P(t) = P0
(1 + r
n
)ntwhere
t is the time (in years)
P(t) is the total amount of money at time t
P0 is the principal - or initial amount of the investment.
r is the interest rate.
n is the number of times the interest is compounded per year.
Page 327 has a chart with key words to help figure out what n is.
![Page 15: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/15.jpg)
Compounded Interest
An an investment earning continuously compounded interest growsaccording to the formula:
P(t) = P0
(1 + r
n
)ntwhere
t is the time (in years)
P(t) is the total amount of money at time t
P0 is the principal - or initial amount of the investment.
r is the interest rate.
n is the number of times the interest is compounded per year.
Page 327 has a chart with key words to help figure out what n is.
![Page 16: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/16.jpg)
Compounded Interest
An an investment earning continuously compounded interest growsaccording to the formula:
P(t) = P0
(1 + r
n
)ntwhere
t is the time (in years)
P(t) is the total amount of money at time t
P0 is the principal - or initial amount of the investment.
r is the interest rate.
n is the number of times the interest is compounded per year.
Page 327 has a chart with key words to help figure out what n is.
![Page 17: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/17.jpg)
Continuously Compounded Interest
An an investment earning continuously compounded interest growsaccording to the formula:
P(t) = P0ekt
where
t is the time (in years)
P(t) is the total amount of money at time t
P0 is the principal - or initial amount of the investment.
k is the nominal interest rate.
Notice that this is exactly the same as the formula for exponentialgrowth. Problems involving exponential growth and continuouslycompounded interest work exactly the same.
![Page 18: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/18.jpg)
Continuously Compounded Interest
An an investment earning continuously compounded interest growsaccording to the formula:
P(t) = P0ekt
where
t is the time (in years)
P(t) is the total amount of money at time t
P0 is the principal - or initial amount of the investment.
k is the nominal interest rate.
Notice that this is exactly the same as the formula for exponentialgrowth. Problems involving exponential growth and continuouslycompounded interest work exactly the same.
![Page 19: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/19.jpg)
Continuously Compounded Interest
An an investment earning continuously compounded interest growsaccording to the formula:
P(t) = P0ekt
where
t is the time (in years)
P(t) is the total amount of money at time t
P0 is the principal - or initial amount of the investment.
k is the nominal interest rate.
Notice that this is exactly the same as the formula for exponentialgrowth. Problems involving exponential growth and continuouslycompounded interest work exactly the same.
![Page 20: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/20.jpg)
Continuously Compounded Interest
An an investment earning continuously compounded interest growsaccording to the formula:
P(t) = P0ekt
where
t is the time (in years)
P(t) is the total amount of money at time t
P0 is the principal - or initial amount of the investment.
k is the nominal interest rate.
Notice that this is exactly the same as the formula for exponentialgrowth. Problems involving exponential growth and continuouslycompounded interest work exactly the same.
![Page 21: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/21.jpg)
Continuously Compounded Interest
An an investment earning continuously compounded interest growsaccording to the formula:
P(t) = P0ekt
where
t is the time (in years)
P(t) is the total amount of money at time t
P0 is the principal - or initial amount of the investment.
k is the nominal interest rate.
Notice that this is exactly the same as the formula for exponentialgrowth. Problems involving exponential growth and continuouslycompounded interest work exactly the same.
![Page 22: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/22.jpg)
Example
Suppose that $82, 000 is invested at 412% interest, compounded
quarterly. Find the function for the amount to which the investmntgrows after t years.
P(t) = 82000(1.01125)4t
A father wishes to invest money to help pay for his son’s collegeeducation. The investment earns 5% compounded continuously.How much should he invest when his son is born so that he’ll have$50,000 when his son turns 18?
$20328.48
![Page 23: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/23.jpg)
Example
Suppose that $82, 000 is invested at 412% interest, compounded
quarterly. Find the function for the amount to which the investmntgrows after t years.
P(t) = 82000(1.01125)4t
A father wishes to invest money to help pay for his son’s collegeeducation. The investment earns 5% compounded continuously.How much should he invest when his son is born so that he’ll have$50,000 when his son turns 18?
$20328.48
![Page 24: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/24.jpg)
Example
Suppose that $82, 000 is invested at 412% interest, compounded
quarterly. Find the function for the amount to which the investmntgrows after t years.
P(t) = 82000(1.01125)4t
A father wishes to invest money to help pay for his son’s collegeeducation. The investment earns 5% compounded continuously.How much should he invest when his son is born so that he’ll have$50,000 when his son turns 18?
$20328.48
![Page 25: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/25.jpg)
Example
Suppose that $82, 000 is invested at 412% interest, compounded
quarterly. Find the function for the amount to which the investmntgrows after t years.
P(t) = 82000(1.01125)4t
A father wishes to invest money to help pay for his son’s collegeeducation. The investment earns 5% compounded continuously.How much should he invest when his son is born so that he’ll have$50,000 when his son turns 18?
$20328.48
![Page 26: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/26.jpg)
Exponential Decay
A quantity that experiences exponential decay will decrease according tothe equation
P(t) = P0e−kt
where
t is the time (in any given units)
P(t) is the amount at time t
P0 is the initial quantity.
k (which needs to be positive) is the decay rate.
![Page 27: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/27.jpg)
Exponential Decay
A quantity that experiences exponential decay will decrease according tothe equation
P(t) = P0e−kt
where
t is the time (in any given units)
P(t) is the amount at time t
P0 is the initial quantity.
k (which needs to be positive) is the decay rate.
![Page 28: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/28.jpg)
Exponential Decay
A quantity that experiences exponential decay will decrease according tothe equation
P(t) = P0e−kt
where
t is the time (in any given units)
P(t) is the amount at time t
P0 is the initial quantity.
k (which needs to be positive) is the decay rate.
![Page 29: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/29.jpg)
Exponential Decay
A quantity that experiences exponential decay will decrease according tothe equation
P(t) = P0e−kt
where
t is the time (in any given units)
P(t) is the amount at time t
P0 is the initial quantity.
k (which needs to be positive) is the decay rate.
![Page 30: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/30.jpg)
Exponential Decay (continued)
A quantity that experiences exponential decay also has a correspondinghalf-life. If the half-life if T , then the sample will decrease according tothe equation
P(t) = P0e−kt , where k =
ln 2
T
Notice you can also solve for T to get the equation T = ln 2k
![Page 31: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/31.jpg)
Example
The half-life of radium-226 is 1600 years. Find the decay rate.
k = ln 21600 ≈ 0.0004332 = 0.04332% per year
![Page 32: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/32.jpg)
Example
The half-life of radium-226 is 1600 years. Find the decay rate.
k = ln 21600 ≈ 0.0004332 = 0.04332% per year
![Page 33: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/33.jpg)
Newton’s Law of Cooling
An object that’s hotter/colder than it’s surrounding environment willcool off/heat up according to the equation
T (t) = T0 + (T1 − T0)e−kt
where
t is the time (in any given units)
T (t) is temperature of the object at time t
T0 is temperature of the surrounding environment
T1 is the initial temperature of the object
k is a constant that depends on the physical properties of the objectand its surrounding. It will change based on how easily they transferheat to each other.
![Page 34: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/34.jpg)
Newton’s Law of Cooling
An object that’s hotter/colder than it’s surrounding environment willcool off/heat up according to the equation
T (t) = T0 + (T1 − T0)e−kt
where
t is the time (in any given units)
T (t) is temperature of the object at time t
T0 is temperature of the surrounding environment
T1 is the initial temperature of the object
k is a constant that depends on the physical properties of the objectand its surrounding. It will change based on how easily they transferheat to each other.
![Page 35: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/35.jpg)
Newton’s Law of Cooling
An object that’s hotter/colder than it’s surrounding environment willcool off/heat up according to the equation
T (t) = T0 + (T1 − T0)e−kt
where
t is the time (in any given units)
T (t) is temperature of the object at time t
T0 is temperature of the surrounding environment
T1 is the initial temperature of the object
k is a constant that depends on the physical properties of the objectand its surrounding. It will change based on how easily they transferheat to each other.
![Page 36: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/36.jpg)
Newton’s Law of Cooling
An object that’s hotter/colder than it’s surrounding environment willcool off/heat up according to the equation
T (t) = T0 + (T1 − T0)e−kt
where
t is the time (in any given units)
T (t) is temperature of the object at time t
T0 is temperature of the surrounding environment
T1 is the initial temperature of the object
k is a constant that depends on the physical properties of the objectand its surrounding. It will change based on how easily they transferheat to each other.
![Page 37: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/37.jpg)
Newton’s Law of Cooling
An object that’s hotter/colder than it’s surrounding environment willcool off/heat up according to the equation
T (t) = T0 + (T1 − T0)e−kt
where
t is the time (in any given units)
T (t) is temperature of the object at time t
T0 is temperature of the surrounding environment
T1 is the initial temperature of the object
k is a constant that depends on the physical properties of the objectand its surrounding. It will change based on how easily they transferheat to each other.
![Page 38: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/38.jpg)
Example
A roasted turkey is taken from an oven when its temperature hasreached 185◦F and is placed on a table in a room where thetemperature is 75◦F. If the temperature is 150◦ in half an hour,what is the temperature after 45 minutes?
137◦F
![Page 39: Section 5.6 - Applications and Models: Growth and Decay; Compound Interestain.faculty.unlv.edu/124 Notes/Chapter 5/Section 5.6 Presentation.pdf · n is the number of times the interest](https://reader033.vdocuments.mx/reader033/viewer/2022042911/5f433ec0a9549c45c8710d79/html5/thumbnails/39.jpg)
Example
A roasted turkey is taken from an oven when its temperature hasreached 185◦F and is placed on a table in a room where thetemperature is 75◦F. If the temperature is 150◦ in half an hour,what is the temperature after 45 minutes?
137◦F