Transcript
Page 1: PARTS OF SIMILAR TRIANGLES

PARTS OF SIMILAR TRIANGLES

• Recognize and use proportional relationships of corresponding perimeters of similar triangles.

• Recognize and use proportional relationships of corresponding angle bisectors, altitudes, and medians of

similar triangles.

JOHN B. CORLEY

Page 2: PARTS OF SIMILAR TRIANGLES

PROPORTIONAL PERIMETERS THEOREM

If two triangles are similar, then the perimeters are proportional to the corresponding sides.

JOHN B. CORLEY

Page 3: PARTS OF SIMILAR TRIANGLES

Example 1 – Perimeters of Similar Triangles

12

35

37

5

If ∆LMN ~ ∆QRS, QR = 35, RS = 37, SQ = 12, and NL = 5, find the perimeter of ∆LMN

JOHN B. CORLEY

N

MS

Q R

L

Page 4: PARTS OF SIMILAR TRIANGLES

Example 1 – Perimeters of Similar Triangles, cont.

N

MS

Q R

L

12

35

37

5

Let x represent the perimeter of ∆LMN. The perimeter of ∆QRS = 35 + 37 + 12 or 84.

Perimeter = 84

JOHN B. CORLEY

Page 5: PARTS OF SIMILAR TRIANGLES

Example 1 – Perimeters of Similar Triangles, cont.

N

MS

Q R

L

12

35

37

5

Let x represent the perimeter of ∆LMN. The perimeter of ∆QRS = 35 + 37 + 12 or 84.

Perimeter = 84

35

420128412

5

ofperimeter ofPerimeter

x

x

x

QRSLMN

SQNL

JOHN B. CORLEY

Page 6: PARTS OF SIMILAR TRIANGLES

SPECIAL SEGMENTS OF SIMILAR TRIANGLES

Corresponding Altitudes

TUPQ

UVQR

TVPR

UWQA U

W V

AP R

Q

T

JOHN B. CORLEY

Page 7: PARTS OF SIMILAR TRIANGLES

SPECIAL SEGMENTS OF SIMILAR TRIANGLES

Corresponding Angle Bisectors

TUPQ

UVQR

TVPR

UXQB

JOHN B. CORLEY

X

B

U

P R

Q

T

Page 8: PARTS OF SIMILAR TRIANGLES

SPECIAL SEGMENTS OF SIMILAR TRIANGLES

Corresponding Medians

TUPQ

UVQR

TVPR

UYQM

Y

M

U

P R

Q

T V

JOHN B. CORLEY

Page 9: PARTS OF SIMILAR TRIANGLES

Example 2 – Medians of Similar Triangles

∆ABC ~ ∆DEF

BG and EH are medians

BC = 30, BG = 15, EF = 15

Find EH

JOHN B. CORLEY

3015

15x

E

HF

GA C

B

D

Page 10: PARTS OF SIMILAR TRIANGLES

Example 2 – Medians of Similar Triangles

∆ABC ~ ∆DEF

BG and EH are medians

BC = 30, BG = 15, EF = 15

Find EH

5.7

22530153015

x

xx

EFBC

EHBG

JOHN B. CORLEY

3015

15x

E

HF

GA C

B

D

Page 11: PARTS OF SIMILAR TRIANGLES

Example 3 – Solve Problems with Similar Triangles

PHOTOGRAPHY

JOHN B. CORLEY

6.16 m35 mm 42 mm x

Page 12: PARTS OF SIMILAR TRIANGLES

ANGLE BISECTOR THEOREM

BP R

Q

An angle bisector in a triangle separates the opposite side into segments that have the same ratio as the other two sides.

RQPQ

BRPB

JOHN B. CORLEY


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