Transcript
Page 1: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

Oxidation ReductionRegents Review

Page 2: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

Zn(s) + Pb2+ (aq) → Zn2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from:

A)    Pb(s) to Zn(s)B)    Pb2+(aq) to Zn2+(aq)C)    Zn(s) to Pb(s)D)    Zn2+(aq) to Pb2+(aq)Correct Answer: Option C - Zn(s) to Pb(s)

Page 3: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

Correct Answer is flow of ions

Page 4: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

All the metals listed above Mg in Reference Table J would be more readily oxidized (give up electrons

Page 5: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

Correct answer: (2) Zn (s) ® Zn2+ (aq) + 2e-

Page 6: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

Correct Answer:  (3) at the cathode in an electrolytic cell and the anode in a voltaic cell

Page 7: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

Correct Answer: (3) +3

Page 8: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

Correct answer: In a voltaic cell, the reaction is spontaneous. In an electrolytic cell, it is nonspontaneous.

Page 9: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

Correct answer: Al+3 + 3e- →  Al

Page 10: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

(1) is the correct answer.  Reduction means the gain of an electron, which removes the positive charge from potassium (because an electron is negatively charged).

Page 11: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

(3) the total number of electrons lost equals the number of electrons gained.

Page 12: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

Given the redox reaction: Ni + Sn4+ → Ni2+ + Sn2+

Which species has been oxidized?NiSn4+

Ni2+

Sn2+

Correct Answer is Ni

Page 13: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

In the reaction: 2H2(g) + O2(g) → 2H2O(g), the oxidizing agent is

H2

O2

H−

O2−

Correct answer is O2

Page 14: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

The diagram shows a voltaic cell. The reaction occurs at 1 atmosphere and 298 K. When the switch is closed, what occurs? Pb is oxidized and electrons flow to the Zn electrode. Pb is reduced and electrons flow to the Zn electrode. Zn is oxidized and electrons flow to the Pb electrode. Zn is reduced and electrons flow to the Pb electrode.

Correct Answer is Choice 3

Page 15: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

In the reaction: Pb + 2Ag+ → Pb2+ + 2Ag, the Ag+ isreduced, and the oxidation number changes

from +1 to 0reduced, and the oxidation number changes

from +2 to 0oxidized, and the oxidation number

changes from 0 to +1oxidized, and the oxidation number

changes from +1 to 0

Correct Answer is Choice 1

Page 16: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

The diagram represents the electroplating of a metal fork with Ag(s). Which part of the electroplating is represented by the fork?the anode, which is the negative electrode the cathode, which is the negative electrode the anode, which is the positive electrode the cathode, which is the positive electrode

Correct Answer is Choice 2

Page 17: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

The diagram represents the electroplating of a fork with Ag(s). Which equation represents the half-reaction that takes place at the fork?Ag+ + NO3

− → AgNO3

AgNO3 → Ag+ + NO3−

Ag+ + e− → Ag(s)Ag(s) → Ag+ + e−

Correct Answer is Choice 3

Page 18: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

What is the oxidation number of iodine in NaIO3?+1 +5 +3 +6

Correct Answer is +5

Page 19: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

In the reaction: 2Mg + O2 → 2MgO, the magnesium is theoxidizing agent and is reducedoxidizing agent and is oxidizedreducing agent and is reducedreducing agent and is oxidized

Correct Answer is Choice 4

Page 20: Oxidation Reduction Regents Review. Zn(s) + Pb 2 + (aq) → Zn 2 + (aq) + Pb(s) In the completed external circuit, the electrons flow from: A) Pb(s) to

The diagram represents a chemical cell at 298 K and 1 atmosphere. Which species represents the cathode? Zn Zn2+

Cu Cu2+

Correct answer is Cu


Top Related