HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
π π βππ π+ππ
π π+π
π π+ππ+π π βπ=π π+ππ π+ππ=π π+π
π π=π π βπβπ π=βππ=π
Then substitute to answer the question.
HomeworkMrs. Rivas
4x β 1 2x + 15
8x + 8
X = 3
mβ AOB = 4x β 1 = 4(3) β 1 = 11
mβ BOC = 2x + 15 = 2(3) + 15 = 21
mβ AOC = 8x + 8 = 8(3) + 8 = 32
HomeworkMrs. Rivas
8x + 13
πππ βπ
3x β 10
π π βππ+π π+ππ=πππ βππππ+π=πππ βπ
πππ=πππ βπβπ=βππ=π
Then substitute to answer the question.
HomeworkMrs. Rivas
8x + 13
12x β 6
3x β 10
X = 9
mβ BOC = 3x β 10 = 3(9) β 10 = 17
mβ COD = 8x + 13= 8(9) + 13 = 85
mβ BOD = 12x β 6
= 12(3) β 6 = 102
HomeworkMrs. Rivas
Always read the question and draw a picture.
A
B
C
E
F
2x + 483x + 8
3x + 8 = 2x + 48β 8 β 8 3x = 2x + 40
β 2x β 2x
x = 403(40) + 8 = 128 2(40) + 48 = 128
HomeworkMrs. Rivas
Always read the question and draw a picture.
J
K
L2x β 3 N
P
M5x + 2
2x β 3 + 5x + 2 = 90ΒΊ2x β 3 + 5x + 2 = 90ΒΊ7x β 1 = 90ΒΊ
+ 1 + 17x = 91ΒΊ7 7x = 13ΒΊ2(13) β 3 = 23
5(13) + 2 = 67
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
HomeworkMrs. Rivas
Always read the question and draw a picture.
J
K
M
L
86
If β JKM = 86 then β MKL = 86, so β JKL has to be equal to 86 + 86 = 172.
HomeworkMrs. Rivas
Always read the question and draw a picture.
R
S
V
T
62
Since bisect means cut in half. Then, mβ RSV = 62 Γ· 2 = 31
HomeworkMrs. Rivas
P
Q
S
R
3x5x β 20
Always read the question and draw a picture.
3x = 5x β 20β 5xβ 5x
3(10) = 30
β 2x = β 202 2
x = 105(10) β 20 = 30
So, mβ PQR = 30 + 30 = 60
HomeworkMrs. Rivas
Always read the question and draw a picture.
P
Q
S
R
2x + 1
4x β 15
2x + 1 = 4x β 15
β 4xβ 4xβ 2x = β 16
2 2x = 8
β 1 β 1 2x = 4x β 16
2(8) + 1 = 17 4(8) β 15 = 17
So, mβ PQR = 17 + 17 = 34
HomeworkMrs. Rivas
Always read the question and draw a picture.
P
Q
S
R
3x β 1230
30 + 30 = 3x β 12
+ 12+ 1272 = 3x
33x = 24
60 = 3x β 12
3(24) β 12 = 60
HomeworkMrs. Rivas
Always read the question and draw a picture.
P
Q
S
R
2x + 10
5x β 17
2x + 10 = 5x β 17
β 5xβ 5xβ 3x = β 27
3 3x = 9
β 10 β 10 2x = 5x β 27
2(9) + 10 = 28 5(9) β 17 = 28
So, mβ PQR = 28 + 28 = 56
HomeworkMrs. Rivas
Always read the question and draw a picture.
7x β 1 + 4x + 3 = 90ΒΊ11x + 2 = 90ΒΊ
β 2 β 211x = 88ΒΊ11 11
x = 8
mβ MLN = 7(8) β 1 = 55
mβ JKL = 4(8) + 3 = 35a). b).
c). I can check the answer by adding 55 and 35, and it should be 90ΒΊ. 55 + 35 = 90ΒΊ
HomeworkMrs. Rivas
HomeworkMrs. Rivas