![Page 1: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/1.jpg)
Lecture No.15Chapter 5
Contemporary Engineering EconomicsCopyright © 2010
Contemporary Engineering Economics, 5th edition, © 2010
![Page 2: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/2.jpg)
Chapter Opening Story – GE’s Healthymagination ProjectGE Unveils $6 Billion Health-Unit Plan:• Goal: Increase the market share in the healthcare sector.• Strategies: Develop products that will lower costs, increase access and improve health-care quality.• Investment required: $6 billion over six years• Desired project outcome: Would help GE’s health-care unit grow at least twice as fast as the broader economy.
Contemporary Engineering Economics, 5th edition, © 2010
![Page 3: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/3.jpg)
Ultimate QuestionsGE’ s Point of View:
Would there be enough demand for their products to justify the investment required in new facilities and marketing?
What would be the potential financial risk if the actual demand is far less than its forecast or adoption of technology is too slow?
If everything goes as planned, how long does it take to recover the initial investment?
Contemporary Engineering Economics, 5th edition, © 2010
![Page 4: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/4.jpg)
Bank Loan vs. Project Cash Flows
Contemporary Engineering Economics, 5th edition, © 2010
![Page 5: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/5.jpg)
Contemporary Engineering Economics, 5th edition, © 2010
Example 5.1 Describing Project Cash Flows – A Computer-Process Control Project
Year(n)
Cash Inflows(Benefits)
Cash Outflows(Costs)
NetCash Flows
0 0 $650,000 -$650,000
1 215,500 53,000 162,500
2 215,500 53,000 162,500
… … … …
8 215,500 53,000 162,500
![Page 6: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/6.jpg)
Cash Flow Diagram for the Computer Process Control Project
Contemporary Engineering Economics, 5th edition, © 2010
![Page 7: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/7.jpg)
Contemporary Engineering Economics, 5th edition, © 2010
Principle: How fast can I recover my initial investment?
Method: Based on the cumulative cash flow (or accounting profit)
Screening Guideline: If the payback period is less than or equal to some specified bench-mark period, the project would be considered for further analysis.
Weakness: Does not consider the time value of money
![Page 8: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/8.jpg)
Contemporary Engineering Economics, 5th edition, © 2010
N Cash Flow Cum. Flow
0123456
-$105,000+$20,000$15,000$25,000$35,000$45,000$45,000$35,000
-$85,000-$70,000-$45,000-$10,000$35,000$80,000
$115,000
Payback period should occurs somewherebetween N = 3 and N = 4.
![Page 9: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/9.jpg)
Contemporary Engineering Economics, 5th edition, © 2010
$85,000
$15,000$25,000
$35,000$45,000 $45,000
$35,000
0
1 2 3 4 5 6Years
Ann
ual c
ash
flow
-100,000
-50,000
0
50,000
100,000
150,000
0 1 2 3 4 5 6Years (n)
3.2 years Payback period
Cum
ulat
ive
cash
flo
w (
$)
![Page 10: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/10.jpg)
Practice ProblemHow long does it take to recover the initial
investment for the computer process control system project in Example 5.1?
Contemporary Engineering Economics, 5th edition, © 2010
![Page 11: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/11.jpg)
Contemporary Engineering Economics, 5th edition, © 2010
Discounted Payback Period Principle:
How fast can I recover my initial investment plus interest?
Method: Based on the cumulative discounted cash flow
Screening Guideline: If the discounted payback period (DPP) is less than or equal to some specified bench-mark period, the project could be considered for further analysis.
Weakness: Cash flows occurring after DPP are ignored
![Page 12: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/12.jpg)
Contemporary Engineering Economics, 5th edition, © 2010
Discounted Payback Period Calculation
Period (n)
Cash Flow (An)
Cost of Funds(15%)*
Ending Cash Balance
0 -$85,000 0 -$85,000
1 15,000 -$85,000(0.15) = -$12,750 -82,750
2 25,000 -$82,750(0.15) = -12,413 -70,163
3 35,000 -$70,163(0.15) = -10,524 -45,687
4 45,000 -$45,687(0.15) =-6,853 -7,540
5 45,000 -$7,540(0.15) = -1,131 36,329
6 35,000 $36,329(0.15) = 5,449 76,778
* Cost of funds = (Unrecovered beginning balance) X (interest rate)
![Page 13: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/13.jpg)
Illustration of Discounted Payback Period
Contemporary Engineering Economics, 5th edition, © 2010
![Page 14: Lecture No.15 Chapter 5 Contemporary Engineering Economics Copyright © 2010 Contemporary Engineering Economics, 5 th edition, © 2010](https://reader035.vdocuments.mx/reader035/viewer/2022062421/56649d305503460f94a0913f/html5/thumbnails/14.jpg)
Payback periods can be used as a screening tool for liquidity, but we need a measure of investment
worth for profitability.
Contemporary Engineering Economics, 5th edition, © 2010