Elimination!

“You can be GREAT

if you can ELIMINATE!”

Original Equation

9c+6b=54C+b=7

Elimination!

9c+6b=54-6c-6b=-42

__________3c/3=12/3

__________*C=4

C+b=7x-6

__________-6c-6b=-42

4+b=7-4 -4

__________*B=3

Substitution!

9c+6b=549c+6(7-c)=549c+42-6c=54

-42 -42__________

9c-6c=123c/3=12/3

__________*c=4

c+b=7-c -c

_________b=7-c

4+b=7-4 -4

_______*b=3

X=b (KEY)

Y=c

Graphing!

6x+9y=54-6 -6

_________9y/9=-6x+54/9_____________

Y=-2/3x+6

y+x=7-x -x

________Y=-x+7

First Line: Down 2 Right 3

(3,4) INTERSECTION POINT

Second Line: Down 1 Right 1

Conclusion!

That Claire bought 3 books and 4 CDs!

Check For Graphing!

6(x) + 9(y)= 546(3) + 9(4) = 54

18+36= 54

y+x=74+3=7

Steps For Elimination!

• Write the system so that like terms are aligned.

• ELIMINATE one of the variables and solve for the other variable.

• Substitute the value of the variables into one of the original equations and solve for the other variable.

• Write the answer from the last 2 steps as (x,y). And check to see if you’re correct.

Terms and Definitions

• “B” or “x” stands for books• “C” or “Y” stands for CDs• $54 is the total amount Claire had!• She only bought 7 items!