Download - Do an Tot Nghiep - Truong Duc Tien - 2
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TRNG I HC BCH KHOA H NI
VIN IN
B MN T NG HO XNCN
====o0o====
N TT NGHIP
TI:
THIT K B NGUN HIU CH!NH H CNG U"T
#$P%C&
Trng b mn : TS. Trn Trng Minh
Gio vin hng dn : TS. Ngu!n "#ng $u%ng
Sinh vin &h'( hi)n : Tr*ng +,( Ti-n
/ : T+" 1 234
MSS5 : 006434
H' ()*+ ,-./01
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B GIO $2C V O TOTRNG I HC BCH KHOA HN
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CNG H3A X4 HI CH5 NGH6A VIT NAMc lp T do Hnh phc
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NHIM V2
N TT NGHIP
" v7 &n 8inh vin: Tr*ng +,( Ti-n S9 hi)u 8inh vin: 006434
2h% 34 2ho%;5i)n: +i)n Ng7nh: T' nghi)/ (ng nghi)/
1. u thit k:
Thi-& ?- b ngu#n 89 hi)u (h@nh h) 89 (ng 8uA& BCDEF.
2. Cc s liu ban u:
F( &hng 89 &hi-& ?- u (u
H Gi &rI hi)u dJng (K%
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M2C J2C
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L.L. nh hng (K% h) 89 (ng 8uA& nh &on &hng 89 mc(h \'( ...............................................................................
4..L. T>nh &on (ng 8uA& v7 dYng nh &on v7 &hi-& ?- (un (m .................................................................... 4
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4... T>nh &on gi &rI (K% &J \( nh (hn DEF diod.................................................................................... 4L4... Mc(h &r gip/
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C%nh mJ( bng 89 \i)u
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{ng 4.L. F( &hng 89 (K% \i TC1X }~. ................................................................... f{ng 4.. Tng h/ \inh ?i)n 8 dJng &rong mc(h \'( ................................................... 4f{ng .L. Fhu^n
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C%nh mJ( & vi-& &P&
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i ni
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i ni
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Fh*ng L. Nhqng vAn
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Fh*ng L. Nhqng vAn nh h) 89 (ng 8uA& m& ((h &ng u&` &rong
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Fh*ng L. Nhqng vAn
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Fh*ng L. Nhqng vAn nh h) 89 (ng 8uA& \7 vi)( &hm v7o h% b& r% (( (un da
h% &J dJ` nh
(m ?hng ( &h^
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Fh*ng L. Nhqng vAn
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Fh*ng L. Nhqng vAn
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Fh*ng . '% (hn /h*ng n mc(h \'( v7 /h*ng n (
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Fh*ng . '% (hn /h*ng n mc(h \'( v7 /h*ng n
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Fh*ng . '% (hn /h*ng n mc(h \'( v7 /h*ng n
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Fh*ng . '% (hn /h*ng n mc(h \'( v7 /h*ng n
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Fh*ng . '% (hn /h*ng n mc(h \'( v7 /h*ng n
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Fh*ng . '% (hn /h*ng n mc(h \'( v7 /h*ng n nh njng \z &>n hi)u 89` nh n
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Fh*ng . '% (hn /h*ng n mc(h \'( v7 /h*ng n
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Fh*ng . '% (hn /h*ng n mc(h \'( v7 /h*ng n
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Fh*ng . '% (hn /h*ng n mc(h \'( v7 /h*ng n
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Fh*ng . '% (hn /h*ng n mc(h \'( v7 /h*ng n
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Fh*ng . '% (hn /h*ng n mc(h \'( v7 /h*ng n
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
L
Fhu ?t
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
Ccng dYng
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
4
\7 ` v7 nh
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
Fud = . = .0`00X = 0`0L6 B(m B4.X
{( 4: Ti-& di)n da &rn B?hng ?^ ((h nh &on
Fu|B{
.Bd 4`L.B0.0L6 = = = 0`00L4 B(m
B4.L0
C'% v7o &hng 89 &i-& di)n da` &@ 89 nh
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
3
{( X: w(
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
f
1 ") 89 S4= di)n &>(h (% 8 hi)u u; di)n &>(h (% 8
1 ") 89 S= di)n &>(h (% 8 hi)u u; Bdi)n &>(h (% 8 hi)u u H ((h nh nh
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
"]nh 4.. "]nh dcng \i &rong &h'( &-.
{( L: T>nh m& nh 89 \ng 8i da (h/ u (u
n 14|B{
|B
{
f
0`0L4fS = = =L0`f3
L`6.L0 B4.
Fhn 89 8i (h/ \7 Sn= LL
{( L3: T>nh 89 vYng da u (u
% u4
n |B{f
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S LL.L 6.L0= = = B4.4
Fhn N = L vYng
{( Lf: T>nh ?h h ?hng ?h> (n &hi-&
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
6
16 16(
g 1
0`N L0 0`..L .`LL.L0\ = = = 0`X3 B(m
`L.L0 B4.
{( L: T>nh h) 89 & &hng &n (K% ?h h
g
g(
0`X3\ G .4`3E L \n L .\n `4
\ ` 0`X3LL
= + = + =
B4.3
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1g
L 16 16(
\ 0`X3.`L.L0N = = = 60`06
0` E.L0 0`..`LL.`4.L0 B4.f
Fhn NL= 60 vYng.
{( LX: T>nh & (m nh gi &rI mi m& nh &on & (m o% (hi_u
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
X
1L 1
%(g
[0`N .L0
0`.60.`4.L0{ = = = 0`0L BT
\ .0`X3
B4.4
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n %(O;2 = ? Q { B4.44
Trong nh &n h%o \i
14 14Q rQD = | BL0 .O;2 = L.L0 .0`03 = 0`00f BO B4.4
{( : Tng &n h%o
Fu QD D D LL 0f 0`00f LL 0 BO = + = + B4.43
{( 6: M& (h b_ m&
&
D LL`0 O = = = 0`L04 B (m L0`X
B4.4f
{( X: + &jng nhi)&
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
40
1 ") 89 &n h%o nh h*n gi &rI u (u (hn &r(
1 ") 89 \A/
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
4L
(A/ ho( &iu &hJ 8' (hnh \)(h giq% h%i (ng 8uA& n7. Ngo7i (h,( njng
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
4
L00?"R. C'% v7o (( &hng 89 &rn &% \'% (hn diod 8(ho&&? ( &n: My40f0DT` (hIu
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
44
1X1L0 1Xo 8
8o
[ & `6.63.L0F = 0`3. = 0`3. =`3.L0 = 0`3.L0 = 0`3 BnE
.00 B4.4
1Xon
8 1X8
& L3.L0y = = = f BF .0`3.L0 B4.
1X y 8 oD = 0`3QF = 0`3.L00000.0`3.L0 .00 = `04 BO B4.3
2hi v%n m dYng
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
4
&r'( &i-/ (ho &J m7 ?hng u% (un (m` nh v &J
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
43
Trong &h'( &- &hi-& ?-` &% (n 8 dJng b/%88 diod
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
4f
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Fh*ng 4. T>nh &on &hi-& ?- mc(h \'(
4
L Tr%n8i8&or F66 L6 Fu (h] 3 LLX Fhan n9i (( \oci
Nh v` &% ( 8*
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Fh*ng . Tri^n ?h%i b
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Fh*ng . Tri^n ?h%i b
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Fh*ng . Tri^n ?h%i b
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Fh*ng . Tri^n ?h%i b (h mu (K% dYng
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Fh*ng . Tri^n ?h%i b (h mu` &h'( &- ngi &% &hng (hn &n 89 mc(h vYng
nh \7 &n 89 &r>(h mu (K%
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Fh*ng . Tri^n ?h%i b
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Fh*ng . Tri^n ?h%i b
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Fh*ng . Tri^n ?h%i b
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Fh*ng . Tri^n ?h%i b
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Fh*ng . Tri^n ?h%i b
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Fh*ng . Tri^n ?h%i b
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Fh*ng . Tri^n ?h%i b nh n7 v_ m& &hi gi%n &>nh &on &9n rA& nhi_u (hu ?t m v7
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Fh*ng . Tri^n ?h%i b
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Fh*ng 3. M /hng v7 ?-& u &h'( nghi)m
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Fh*ng 3. M /hng v7 ?-& u &h'( nghi)m
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Fh*ng 3. M /hng v7 ?-& u &h'( nghi)m
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Fh*ng 3. M /hng v7 ?-& u &h'( nghi)m
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DhJ \J(
fX
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DhJ \J(
0
%****-------Tinh so soi day chap, so vong day-------****%
J=(2*Eng*10^4)/(Bm*Ap*ku) %mat do dong dienIrms=Ipk/sqrt(2); %dong dien hieu dungAw=Irms/J; %tiet dien day tran yeu cauSn1=Aw/Awd; %so soi day chap
Sn=floor(Sn1); %lay gia tri nguyen lon honNx=(Wa*ku)/(Sn*Awd); %so vong day chua ke den tu thong tanN=round(Nx); %lay gia tri xap xi nguyen cua so vong daylg=((0.4*pi*N*N*Ac*(10^(-8)))/L) - (MPL/tutham); %Khe ho khong khi can thietF=1+(lg/sqrt(Ac))*log((2*G)/lg); %tinh he so tu thong tan cua khe hoN1x=sqrt((lg*L)/(0.4*pi*Ac*F*10^(-8)));%so vong day tinh den ton hao tren khe
hoN1=round(N1x); %lay xap xi nguyen cua so vong day
%****-------kiem nghiem-------****%
Bpk=F*((0.4*pi*N1*Ipk1*(10^(-4)))/lg);%tu cam dinhr1=r/Sn; %Gia tri moi mat do dien tro dai cua dayR=MLT*N1*r1*10^(-6);%Dien tro day quan
PCu=(Irms^2)*R; %Ton hao tren cuon day donganphal=PCu/Po %He so ton hao thuc teBac=(0.4*pi*N1*(deltaI/2)*(10^(-4)))/lg; %Tu cam xoay chieufprintf('\n Tra bang ton hao cua loi ferrit ung voi tan so va vat lieu da
chon:');kfe=input('\n He so ton hao loi kfe=');m=input('\n So mu cua tan so m=');n=input('\n So mu cua dien cam xoay chieu n=');tisocongsuat=kfe*(f^m)*((Bac)^n); %Ti so cong suatPfe=Wrfe*(10^(-3))*tisocongsuat; %Ton hao loiPt=PCu+Pfe; %Tong ton haophi=Pt/At; %Mat do cong suat tren dien tich be matTr=450*(phi)^(0.826); %Do tang nhiet dokut=(N1*Sn*Awd)/Wa; %He so lap day cua so tinh toan
fprintf('\n So vong day can quan n = %d', N1)fprintf('\n So day chap Sn = %d', Sn)fprintf('\n Do tang nhiet do Tr = %d', Tr)fprintf('\n He so lap day cua so tinh toan kutt = %d', kut)fprintf('\n Khe ho khong khi can thiet lg = %f', lg)if(Bm( Q>Q ?=(: Qkl ;) m*qD ?*|( ;(:
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DhJ \J(
kp1=((phi)*wc1*l)/(Vo*ki*sqrt(phi*phi+1))ki1=kp1/ti1Ri=tf([kp1 kp1/ti1],[1 0])fc2=15wc2=2*pi*fc2gc=km/(0.81*ki*kin*Vo)
phi=sqrt(3);ti2=phi/wc2kp2=((phi)*wc2*c)/(gc*ko*sqrt(phi*phi+1))ki2=kp2/ti2Rv=tf([kp2 kp2/ti2],[1 0])
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