Transcript
![Page 1: Ch03-Slides-#05zyang/Teaching/20162017... · 1 = 6 Ω, R 2 = R 3 = 2 Ω, R 4 = 4 Ω, and R 5 = R 6 = 4 Ω. Ch03 Exercise Discussion #03 20170215 Page 7 . 20170215 Page 8 . 20170215](https://reader033.vdocuments.mx/reader033/viewer/2022060311/5f0af1527e708231d42e19bb/html5/thumbnails/1.jpg)
Ch03-Slides-#05Thursday, February 2, 2017 7:26 PM
20170215 Page 1
![Page 2: Ch03-Slides-#05zyang/Teaching/20162017... · 1 = 6 Ω, R 2 = R 3 = 2 Ω, R 4 = 4 Ω, and R 5 = R 6 = 4 Ω. Ch03 Exercise Discussion #03 20170215 Page 7 . 20170215 Page 8 . 20170215](https://reader033.vdocuments.mx/reader033/viewer/2022060311/5f0af1527e708231d42e19bb/html5/thumbnails/2.jpg)
20170215 Page 2
![Page 3: Ch03-Slides-#05zyang/Teaching/20162017... · 1 = 6 Ω, R 2 = R 3 = 2 Ω, R 4 = 4 Ω, and R 5 = R 6 = 4 Ω. Ch03 Exercise Discussion #03 20170215 Page 7 . 20170215 Page 8 . 20170215](https://reader033.vdocuments.mx/reader033/viewer/2022060311/5f0af1527e708231d42e19bb/html5/thumbnails/3.jpg)
Supermesh: Two adjoining meshes that share a current source constitute a supermesh. The current source may be of the independent or dependent type, and it may include a resistor in series with it.
20170215 Page 3
![Page 4: Ch03-Slides-#05zyang/Teaching/20162017... · 1 = 6 Ω, R 2 = R 3 = 2 Ω, R 4 = 4 Ω, and R 5 = R 6 = 4 Ω. Ch03 Exercise Discussion #03 20170215 Page 7 . 20170215 Page 8 . 20170215](https://reader033.vdocuments.mx/reader033/viewer/2022060311/5f0af1527e708231d42e19bb/html5/thumbnails/4.jpg)
20170215 Page 4
![Page 5: Ch03-Slides-#05zyang/Teaching/20162017... · 1 = 6 Ω, R 2 = R 3 = 2 Ω, R 4 = 4 Ω, and R 5 = R 6 = 4 Ω. Ch03 Exercise Discussion #03 20170215 Page 7 . 20170215 Page 8 . 20170215](https://reader033.vdocuments.mx/reader033/viewer/2022060311/5f0af1527e708231d42e19bb/html5/thumbnails/5.jpg)
20170215 Page 5
![Page 6: Ch03-Slides-#05zyang/Teaching/20162017... · 1 = 6 Ω, R 2 = R 3 = 2 Ω, R 4 = 4 Ω, and R 5 = R 6 = 4 Ω. Ch03 Exercise Discussion #03 20170215 Page 7 . 20170215 Page 8 . 20170215](https://reader033.vdocuments.mx/reader033/viewer/2022060311/5f0af1527e708231d42e19bb/html5/thumbnails/6.jpg)
20170215 Page 6
![Page 7: Ch03-Slides-#05zyang/Teaching/20162017... · 1 = 6 Ω, R 2 = R 3 = 2 Ω, R 4 = 4 Ω, and R 5 = R 6 = 4 Ω. Ch03 Exercise Discussion #03 20170215 Page 7 . 20170215 Page 8 . 20170215](https://reader033.vdocuments.mx/reader033/viewer/2022060311/5f0af1527e708231d42e19bb/html5/thumbnails/7.jpg)
Example 3-4: Circuit with Three Meshes. Use mesh analysis to (a) obtain mesh-current equations for the circuit in Fig. 3-7 and then (b) determine the current in R4,
given that V0 = 18 V, R1 = 6 Ω, R2 = R3 = 2 Ω, R4 = 4 Ω,
and R5 = R6 = 4 Ω.
Ch03 Exercise Discussion #03
20170215 Page 7
![Page 8: Ch03-Slides-#05zyang/Teaching/20162017... · 1 = 6 Ω, R 2 = R 3 = 2 Ω, R 4 = 4 Ω, and R 5 = R 6 = 4 Ω. Ch03 Exercise Discussion #03 20170215 Page 7 . 20170215 Page 8 . 20170215](https://reader033.vdocuments.mx/reader033/viewer/2022060311/5f0af1527e708231d42e19bb/html5/thumbnails/8.jpg)
20170215 Page 8
![Page 9: Ch03-Slides-#05zyang/Teaching/20162017... · 1 = 6 Ω, R 2 = R 3 = 2 Ω, R 4 = 4 Ω, and R 5 = R 6 = 4 Ω. Ch03 Exercise Discussion #03 20170215 Page 7 . 20170215 Page 8 . 20170215](https://reader033.vdocuments.mx/reader033/viewer/2022060311/5f0af1527e708231d42e19bb/html5/thumbnails/9.jpg)
20170215 Page 9