resolução comentada - cfo 2012 - afam

27
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Resolução:

Observar as características da chamada democracia ateniense, que restringia o poder político somente aos filhos de cidadãos, que excluía da condição de cidadão as mulheres e os estrangeiros.

Alternativa B

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Resolução:

Análise do texto, uma vez que as resposta correta pode ser extraída dos trechos"[...] fugindo à cólera divina [...]" e "[...] As pessoas odiavam-se umas às outras a ponto de, se um filho fosse atingido pelo mal, o pai se recusar terminantemente a ficar do seu lado [...]", fragmentos que remetem diretamente à idéia de "castigo divino" e "desagregação social", resposta correta.

Alternativa A

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Resolução:

Apesar de aparentemente simples a resposta, o candidato poderia confundir iluminismo com positivismo, pois o texto induz a observarmos o "progresso" como fator central da ques tão , e o pos i t i v i smo é carac te r i zado pe lo "progresso" (lembrar-se do lema da bandeira do Brasil "Ordem e Progresso). Contudo, a resposta certa estava vinculada ao período, uma vez que tanto o positivismo como o iluminismo tem como um de suas características a crença no progresso, mas o iluminismo é típico do século XVIII e o positivismo do século XIX, portanto, a resposta certa seria "iluminismo", visto que o texto faz menção ao século XVIII.

Alternativa E

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RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

1

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Resolução:

A questão cobrou duas das causas fundamentais do pioneirismo dos ingleses para executar sua "Revolução Industrial". O candidato deveria lembrar-se de que o controle do poder pelo parlamento da Inglaterra deu as condições políticas para a "Revolução Industrial", pela supremacia dos interesses da burguesia sobre os interesses do Rei. Já os cercamentos serviram para disponibilizar mão-de-obra barata para as indústrias.

Alternativa A

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Resolução:

A questão não cobrou raciocino do candidato, ficou presa a simples "decoreba" de fatos históricos. Tipo de questão pedagogicamente questionável no atual desenvolvimento dos cursos de história de ensino médio, que devem enfatizar o raciocínio e não a memorização de datas, nomes e fatos.

Alternativa D

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Resolução:

O candidato que observou os fatores motivadores da colonização do interior da colônia portuguesa na América acertou a questão, em especial os que se recordaram de que a ocupação das regiões sudeste e centro-oeste se deu por causa do Bandeirismo e da Mineração. Também acertou aquele que recordou que as regiões mineradoras eram Minas Gerais, Goiás e Mato Grosso.

Alternativa C

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5$7; 4A;44A;444A;4@;3;@6Resolução:

Acertou o aluno que lembrou-se de que a Revolução Farroupilha foi a revolução mais elitista de todas as Revoluções do período Regencial, ou o que se recordou do período de duração da rebelião (1835-1845), ou mesmo de que o evento envolveu as províncias do Rio Grande do Sul e de Santa Catarina.

Alternativa B

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RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

2

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Resolução:

A resposta da questão se encontra presa a explicações de caráter estruturalista, focando apenas os aspectos sócio-econômicos da imigração para o Brasil do Séc. XIX. Deixou de observar as questões ideológicas que envolvem o projeto de imigração, como o preconceito contra as populações negras no Brasil e o "darwinismo social", que serviu de base para a formulação da idéia de "branqueamento" da população por meio da imigração.

Alternativa E

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Resolução:

Questão capciosa quando se refere ao federalismo da Constituição de 1891, pois o candidato poderia ter confundido o federalismo brasileiro (cuja forma mais aceita é de uma República Federativa) com o proposto pela "Revolução Federalista" de 1895.Outro aspecto é o de que a questão afirma que a Constituição de 1934 "[...] trouxe como importante novidade a presença do voto secreto", mas diversos historiadores consideram que o voto secreto foi instituído no Brasil pelo código eleitoral de 1932. A VUNESP trabalhou com a noção de que a Constituição de 1934 trouxe como novidade o voto secreto dentro do Direito Constitucional, e não sob o ponto de vista eleitoral, o que pode ter sido uma armadilha para o candidato que sabia da instituição do voto secreto no código eleitoral de 1932.

Alternativa D

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Resolução:

A questão focou o processo de desenvolvimento econômico no Brasil, e o aluno que estudou o assunto, especialmente durante a Ditadura Militar e o governo Dutra, sabia sobre o aumentou a desigualdade social.

Alternativa B

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RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

3

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5MC9 N9I,@9/37/,939,9/37/,90,@A@9/K,923+@,/9SA39/[email protected],9.9/3A9/1671G10.F,;

5UC9 #A12,/9G1?\/,G,/9SA3/21,7.@9:1E\23/3/93ZE?10.21-./9F,9/37*/,90,@A@;

5$C9 N9I,@9/37/,9B9G+3SA3723@37239176]7A,<90+BFA?,939F,6@J210,;

!#

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5OC9 ,/9-.?,+3/9@,+.1/9E+3/0+12,/9E,+90+37R./9+3?161,/./9/3@E+39?3-.@93@90,7/1F3+.RK,9E+170LE1,/9B210,/93@963+.?;

5MC9 .9 F1/01E?17.9 e210.9 23@9 E,+9 ,IQ321-,9 0372+.?9 17-3/216.+9 ,/99./E302,/9+3?161,/,/9F.9@,+.?939/A./91@E?10.R^3/97.90,7FA2.;

5UC9 .9 @,+.?9 +3?161,/.9 B9 /17c71@,9 F39 2,?3+d701.9 39 0,@E.1ZK,<90,@,9/39F3E+337F39F./9E+J210./9GA7F.@372.?1/2./;

5$C9 ,9/3721F,90,@A@9F,923+@,9B210.&/39+3G3+39f/9I./3/9-.?,+.21*-./[email protected],7FA2.9:[email protected]@9/,013F.F3;

Resolução:

Necessita apenas ler o enunciado da questão com atenção para chegar a resposta correta. Sobre o senso comum para a filosofia.

Alternativa D

! "#$%&&'()''&*"+,-.$/0+12.*".+234

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D9E.+21+9F,9G+.6@372,<9B90,++32,90,7/1F3+.+H

5DC9 D930,7,@1.9I+./1?31+.90+3/03A9F39G,[email protected]/A/2372J-3?9.E37./97.9+361K,[email protected]/9E,I+39F,9E.L/<9,9M372+,*N3/23;

5OC9 N9F3/37-,?-1@372,9F.930,7,@1.9I+./1?31+.9F3/F39.9/[email protected],9/B0A?,9PP97K,963+,A9A@9E+,03//,9QA/2,9F39F1/2+1*IA1RK,9F.9+1SA3T.90+1.F.;

5MC9 N9E3SA37,9.A@372,9F./9+1SA3T./97.01,7.1/[email protected]@.1,+9E.+239F,/9I+./1?31+,/90,7SA1/2.//39.901F.F.71.9E?37.;

5UC9 UA+.7239,[email protected],+12J+1,<9,+1617J+1,9F,9V,?E39F39&WXY<9.9F1/2+1IA1RK,9F./9+1SA3T./9I+./1?31+./9G,[email protected]/9QA/2.9F,9SA397,/9E3+L,F,/9F3@,0+J210,/;

5$C9 ".+.F,Z.?@3723<9.9F3/16A.?F.F397.9F1/2+1IA1RK,9F39+37F.97,9O+./1?97./03A90,@9.9,ERK,9F39/AI/212A1+9.9.6+10A?2A+.9F393Z*E,+2.RK,9E3?.917F[/2+1.;

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D//17.?39.9.?23+7.21-.9SA393/2J9F39.0,+F,90,@9./90,?,0.R^3/9F,923Z2,;

5DC9 N9 /37/,9 0,@A@9 B9 0,7/1F3+.F,9 F,6@J210,9 E,+9 2,F,/9 ,/99G1?\/,G,/;

5OC9 N/9 013721/2./9 0,7/36A3@9 F3@,7/2+.+9 .9 2,2.?1F.F39 F39 /A./90+37R./;

5MC9 N9I,@9/37/,939,9/37/,90,@A@9/K,923+@,/9SA39/[email protected],9.9/3A9/1671G10.F,;

5UC9 #A12,/9G1?\/,G,/9SA3/21,7.@9:1E\23/3/93ZE?10.21-./9F,9/37*/,90,@A@;

5$C9 N9I,@9/37/,9B9G+3SA3723@37239176]7A,<90+BFA?,939F,6@J210,;

!#

",+92+J/9F,/9-BA/H96.+,2.9,?:.9372+39@A?:3+3/9.G36K/90,@9IA+0./;

5:22EH))-3Q.;.I+1?;0,@;I+)1F.F3)3Z0?A/1-,)1/?.@1/@,)0,723Z2,bF3I.23;:2@?C

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5OC9 ,/9-.?,+3/9@,+.1/9E+3/0+12,/9E,+90+37R./9+3?161,/./9/3@E+39?3-.@93@90,7/1F3+.RK,9E+170LE1,/9B210,/93@963+.?;

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5UC9 .9 @,+.?9 +3?161,/.9 B9 /17c71@,9 F39 2,?3+d701.9 39 0,@E.1ZK,<90,@,9/39F3E+337F39F./9E+J210./9GA7F.@372.?1/2./;

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! "#$%&&'()''&*"+,-.$/0+12.*".+234

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D9E.+21+9F,9G+.6@372,<9B90,++32,90,7/1F3+.+H

5DC9 D930,7,@1.9I+./1?31+.90+3/03A9F39G,[email protected]/A/2372J-3?9.E37./97.9+361K,[email protected]/9E,I+39F,9E.L/<9,9M372+,*N3/23;

5OC9 N9F3/37-,?-1@372,9F.930,7,@1.9I+./1?31+.9F3/F39.9/[email protected],9/B0A?,9PP97K,963+,A9A@9E+,03//,9QA/2,9F39F1/2+1*IA1RK,9F.9+1SA3T.90+1.F.;

5MC9 N9E3SA37,9.A@372,9F./9+1SA3T./97.01,7.1/[email protected]@.1,+9E.+239F,/9I+./1?31+,/90,7SA1/2.//39.901F.F.71.9E?37.;

5UC9 UA+.7239,[email protected],+12J+1,<9,+1617J+1,9F,9V,?E39F39&WXY<9.9F1/2+1IA1RK,9F./9+1SA3T./9I+./1?31+./9G,[email protected]/9QA/2.9F,9SA397,/9E3+L,F,/9F3@,0+J210,/;

5$C9 ".+.F,Z.?@3723<9.9F3/16A.?F.F397.9F1/2+1IA1RK,9F39+37F.97,9O+./1?97./03A90,@9.9,ERK,9F39/AI/212A1+9.9.6+10A?2A+.9F393Z*E,+2.RK,9E3?.917F[/2+1.;

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5$C9 N9I,@9/37/,9B9G+3SA3723@37239176]7A,<90+BFA?,939F,6@J210,;

!#

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5OC9 ,/9-.?,+3/9@,+.1/9E+3/0+12,/9E,+90+37R./9+3?161,/./9/3@E+39?3-.@93@90,7/1F3+.RK,9E+170LE1,/9B210,/93@963+.?;

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5UC9 .9 @,+.?9 +3?161,/.9 B9 /17c71@,9 F39 2,?3+d701.9 39 0,@E.1ZK,<90,@,9/39F3E+337F39F./9E+J210./9GA7F.@372.?1/2./;

5$C9 ,9/3721F,90,@A@9F,923+@,9B210.&/39+3G3+39f/9I./3/9-.?,+.21*-./[email protected],7FA2.9:[email protected]@9/,013F.F3;

Resolução:

A questão aborda as diferenças entre ética e moral; o próprio enunciado já apresentara as definições conceituais dessas duas áreas da filosofia. Coube ao candidato apenas a interpretação do texto.

Alternativa E

!"#$%&&'()''&*"+,-.$/0+12.*".+234

!"

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23.2+,;:H182G+.;:382+3:,G2+./;: /I,:EG12,:.821J./<:KE.: 1EH,+2.823:

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RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

4

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Resolução:

A questão apresenta uma pergunta que está relacionada com duas áreas da filosofia: a filosofia da arte e a estética, que apesar de estarem próximas ou até serem consideradas iguais possuem análises distintas sobre o universo das artes.

Alternativa B

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Resolução:

Na leitura, verifica-se identifica-se o conceito de cidadania no próprio enunciado: “a cidadania é naturalizada pelas práticas cotidianas”...

Alternativa A

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Resolução:

A questão não demandava conhecimentos prévios, o aluno deveria fazer uma leitura do trecho do texto do Rousseau, e a partir da análise do respectivo texto conseguiria acertar a questão. Portanto questão envolvendo compreensão de texto.

Alternativa C

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Resolução:

Nessa questão vemos um dos itens do edital, “ o que nos diferencia como humanos” no caso a socialização presente no enunciado da questão, portanto uma questão possível de

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

5

acertar com a junção de conhecimentos prévios e a compreensão do texto.

Alternativa E

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Resolução:

Típica questão na qual o aluno deve atentar as palavras das alternativas que são apostasias, como alternativa a “não podemos lutar”, alternativa c “ nada pode ser feito”, alternativa d “não devemos nos preocupar” e alternativa e “em nosso país não existem”.

Alternativa B

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Resolução:

A consigna não permite uma resposta, nessa questão era necessário o aluno saber a diferença entre gênero e sexo, assim como as palavras não tem sexo e sim gênero, para acertar a questão.

Alternativa C

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Resolução:

O examinador pede o conceito de cidadania, o enunciado da questão poderia levar ao aluno a uma conclusão errônea, pois ele trás o conceito inicial de cidadão que seria o burguês da cidade, entretanto ele pede a ampliação do conceito, que está ligado aos direitos fundamentais de qualquer morador da cidade ou do campo.

Alternativa E

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

6

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Resolução:

A temática da questão está ligada a passagem do absolutismo (poder concentrado no rei) para a democracia moderna com seus três poderes.

Alternativa B

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Resolução:

As pirâmides etárias são figuras constantes nos vestibulares, nessa questão a comparação foi entre países pobres e ricos em várias temporalidades, sabendo que na base estão as crianças e no ápice estão os idosos, pelo exame visual era possível responder a questão.

Alternativa A

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

7

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Resolução:

A localização dos países e fenômenos geográficos ainda é muito cobrada nas provas, por isso a necessidade de uma prévia leitura no Atlas. Com relação a essa questão envolvendo localização de clima é necessário ter como guia as cinco latitudes que determinam os anéis climáticos da Terra: Linha do Equador, Trópico de Capricórnio, Trópico de Câncer, Círculo Polar Ártico, Círculo Polar Antártico.

Alternativa B

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C$G8 M,-,8SU?1<,8bK+.71/2.B

Resolução:

A figura da questão indicava elementos da aridez como os uedis (rios temporários), duna, oásis, facilitando a resposta eólica e árida.

Alternativa C

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C$G8 M,-,8SU?1<,8bK+.71/2.B

Resolução:

Uma das poucas questões envolvendo atualidades, todavia para quem acompanhou o noticiário facilmente acertaria colocando o Novo Código Florestal.

Alternativa B

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

8

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6-62.).262;Resolução:

Novamente uma questão envolvendo localização, no caso das regiões brasileiras, era só lembrar quais estados compõem as regiões brasileiras.

Alternativa E

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Resolução:

A questão mais confusa em termos de enunciado da parte de Geografia, pois faz com que o aluno vá numa direção quando se lê: “Aeroporto de Guarulhos, obra crucial para o sucesso do torneio” e como resposta para a questão tem que todos os doze aeroportos das cidades-sede devem receber maior atenção, porém se o texto fala que o aeroporto de São Paulo é crucial para o torneio o aluno é induzido a marcar a alternativa na qual fala que SP, RJ e PE devem receber maior atenção.

Alternativa D

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RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

9

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Resolução:

A cartografia temática norteou essa questão, nela o aluno deveria perceber que a tonalidade da cor mais forte é a que representa os maiores valores, portanto o agrupamento de estados com maiores expectativas de vida foi feito utilizando a tonalidade de cor mais forte (em direção ao preto).

Alternativa D

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Resolução:

Nessa questão era exigida que o candidato tivesse um bom conhecimento sobre o tema, pois muitos autores não fazem distinção dos tigres asiáticos (Coréia do Sul, Taiwan, Hong Kong) e novos tigres asiáticos (Indonésia, Malásia, Cingapura, Tailândia) e na alternativa A tínhamos tigres asiáticos e na alternativa B tigres asiáticos e novos tigres asiáticos.

Alternativa B

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82.8+.7,-6+*2.:

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C-.796-/-.712/1^50/-.:

Resolução:

Questão envolvendo a diferenciação entre a crosta oceânica e a crosta continental, na qual se pede a localização da formação do tsunami que é na crosta oceânica.

Alternativa C

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

10

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Resolução:

Nessa última questão também envolve a composição das regiões brasileiras, Sudeste e Sul, só que na com a presença do mapa como na questão 27 e sim com um gráfico. Para o aluno acertar a questão era só saber quais estados fazem parte da Região Sul e Região Sudeste.

Alternativa D

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<FC7 &IA2.12727&I67B+..I2G7-61+73FH;

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!#

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Resolução:Temos:

6 h ─ 150 lx h ─ 500 lx = 6 . 500 / 150x = 20 hDe 12 h de 10.05 até 24 h de 10.05 passaram 12 h. Portanto, ficou com a metade de sua capacidade às 8 h do dia 11.05.

Alternativa E

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<FC7 &IA2.12727&I67B+..I2G7-61+73FH;

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!#

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Resolução:

Adotando x como a quantia de Augusto antes das compras, temos:

x - x/2 - x/4 - x/8 - x/16 - x/32 - 2 = 2032x - 16x - 8x - 4x - 2x - x - 64 = 640x = 704 ∴ R$ 704,00

Alternativa E

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

11

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<FC7 &IA2.12727&I67B+..I2G7-61+73FH;

<%C7 &I6727N251*+)O2.127B+..I2G7GJA0+7D-0P+73FH;

!#

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!$

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<%C7 2.1-,-7-/0G-7A27^_7b''?'';7

!!

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<4C7 4;

<=C7 =;

<NC7 F;

<FC7 c;

<%C7 H;

Resolução:

Notamos que a aranha sai do fio H e para voltar ao fio H, percorre 8 números.Assim, dividindo-se 409 por 8, obtemos 51 voltas completas (quociente) mais um espaço (resto).

Alternativa A

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!"

56.78,9.7:37/.;,<323/7+3.81=.7>6.7?+,6,@A,7BC,6?+37>67/.;,*

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8,9.7?,:37H.=3+7,H3+303<:,7,763/6,7:3/0,<2,7?3+03<2>.87IJ

KLM7 BN3-37:,1/737?.O>37>6DE

KPM7 BN3-372+Q/737?.O>37:,1/DE

KCM7 BN3-37G>.2+,737?.O>372+Q/DE

KRM7 BN3-372+Q/737?.O>37>6DE

K%M7 BN3-3701<0,737?.O>37G>.2+,DE

!#

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?+1631+,7-3<03:,+E7L<2S<1,7-3<037<.7?+1631+.7-3=7G>37/.V+367(7

0.+./7/3O>1:./T7U,A,7-3<037<.7?+1631+.7-3=7G>37/.V+367(70,+,./7

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0,+,.E7L/7?+,;.;181:.:3/7:37L<2S<1,T7 U,A,7 37C.+8,/7O.<W.+367

/A,T7+3/?3021-.63<23T

KLM7 E

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!$

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!&

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Resolução:

Considerando x o preço do sabonete em “compre um sabonete e leve outro pela metade do preço”, temos: 2x ─ 100%1,5x ─ y%y = 100 . 1,5 / 2 y = 75 ∴ 75% de quatro sabonetes = 3 sabonetes

Alternativa C

!" #$%&!!'()''!*#+,-.%/0+12.*#.+234

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KPM7 BN3-372+Q/737?.O>37:,1/DE

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KRM7 BN3-372+Q/737?.O>37>6DE

K%M7 BN3-3701<0,737?.O>37G>.2+,DE

!#

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0.+./7/3O>1:./T7U,A,7-3<037<.7?+1631+.7-3=7G>37/.V+367(70,+,./7

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0,+,.E7L/7?+,;.;181:.:3/7:37L<2S<1,T7 U,A,7 37C.+8,/7O.<W.+367

/A,T7+3/?3021-.63<23T

KLM7 E

KPM7 E

KCM7 E

KRM7 E

K%M7 E

!$

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KLM7 E

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KCM7 E

KRM7 E

K%M7 E

!&

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Resolução:

Estabelecendo os casos favoráveis entre os casos possíveis, vem:cara, cara, cara → Antônio ganhacara, cara, coroa → Antônio ganhacara, coroa, cara → Carlos ganhacara, coroa, coroa → Carlos ganhacoroa, cara, cara → Antônio ganhacoroa, coroa, cara → João ganhacoroa, cara, coroa → Carlos ganhacoroa, coroa, coroa → João ganhaLogo, as chances de Antônio, João e Carlos ganharem são, respectivamente:3/8, 1/4 e 3/8.

Alternativa D

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56.78,9.7:37/.;,<323/7+3.81=.7>6.7?+,6,@A,7BC,6?+37>67/.;,*

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8,9.7?,:37H.=3+7,H3+303<:,7,763/6,7:3/0,<2,7?3+03<2>.87IJ

KLM7 BN3-37:,1/737?.O>37>6DE

KPM7 BN3-372+Q/737?.O>37:,1/DE

KCM7 BN3-37G>.2+,737?.O>372+Q/DE

KRM7 BN3-372+Q/737?.O>37>6DE

K%M7 BN3-3701<0,737?.O>37G>.2+,DE

!#

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?+1631+,7-3<03:,+E7L<2S<1,7-3<037<.7?+1631+.7-3=7G>37/.V+367(7

0.+./7/3O>1:./T7U,A,7-3<037<.7?+1631+.7-3=7G>37/.V+367(70,+,./7

/3O>1:./737C.+8,/7-3<037G>.<:,7/.1+7>6.70.+.7/3O>1:.7:37>6.7

0,+,.E7L/7?+,;.;181:.:3/7:37L<2S<1,T7 U,A,7 37C.+8,/7O.<W.+367

/A,T7+3/?3021-.63<23T

KLM7 E

KPM7 E

KCM7 E

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!$

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63+01.<237:3-370,;+.+7?,+73//37?+,:>2,T7 /37,7?.O.63<2,7 H,+7a7

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RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

12

Resolução:

1ª parcela = R$ 100,002ª parcela = R$ 100,00 . 0,9524 = R$ 95, 243ª parcela = R$ 100,00 . 0,9070 = R$ 90,70Total = R$ 100,00 + R$ 95,24 + R$ 90,70 = R$ 285,94

Alternativa E

!" #$%&!!'()''!*#+,-.%/0+12.*#.+234

!"

56.78,9.7:37/.;,<323/7+3.81=.7>6.7?+,6,@A,7BC,6?+37>67/.;,*

<32373783-37,>2+,7?38.7632.:37:,7?+3@,DE7F>2+.7?+,6,@A,7G>37.7

8,9.7?,:37H.=3+7,H3+303<:,7,763/6,7:3/0,<2,7?3+03<2>.87IJ

KLM7 BN3-37:,1/737?.O>37>6DE

KPM7 BN3-372+Q/737?.O>37:,1/DE

KCM7 BN3-37G>.2+,737?.O>372+Q/DE

KRM7 BN3-372+Q/737?.O>37>6DE

K%M7 BN3-3701<0,737?.O>37G>.2+,DE

!#

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?+1631+,7-3<03:,+E7L<2S<1,7-3<037<.7?+1631+.7-3=7G>37/.V+367(7

0.+./7/3O>1:./T7U,A,7-3<037<.7?+1631+.7-3=7G>37/.V+367(70,+,./7

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0,+,.E7L/7?+,;.;181:.:3/7:37L<2S<1,T7 U,A,7 37C.+8,/7O.<W.+367

/A,T7+3/?3021-.63<23T

KLM7 E

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KRM7 E

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!$

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!&

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Resolução:

E

E

6 - t

6

S

2S D • C

A • B

3

P(x) x – 3 ! P(x) = (x – 3). Q1(x) + 11

Q1(x)

P(x) x +1 ! P(x) = (x + 1). Q2(x) + 4

4 Q2(x)

P(x) = (x – 3).(x + 1).Q3(x) + ax + b

P(3) = 1 ! 0 + a.3 + b = 1 ! 3a + b = 1

P(– 1) = 4 ! 0 + a. (– 1) + b = 4 ! –a + b = 4 (x3)

3a + b = 1 Substituindo o valor de b obtemos:

–3a + 3b = 12

0 + 4b = 13 ! b = – a + b = 4

Substituindo o valor de b obtemos: – a + b = 4

a = b – 4

O ponto assintótico é o limite da soma:

Logo é a soma dos termos de uma PG decrescente e infinita.

Gráfico de f(x):

y

x 0

O gráfico de g(x) = f( |x|) é simétrico com relação ao eixo

das ordenadas, pois | x| " 0, # x $ R . Logo o gráfico da

função g(x) é:

y

x

0

E

E

6 - t

6

S

2S D • C

A • B

3

P(x) x – 3 ! P(x) = (x – 3). Q1(x) + 11

Q1(x)

P(x) x +1 ! P(x) = (x + 1). Q2(x) + 4

4 Q2(x)

P(x) = (x – 3).(x + 1).Q3(x) + ax + b

P(3) = 1 ! 0 + a.3 + b = 1 ! 3a + b = 1

P(– 1) = 4 ! 0 + a. (– 1) + b = 4 ! –a + b = 4 (x3)

3a + b = 1 Substituindo o valor de b obtemos:

–3a + 3b = 12

0 + 4b = 13 ! b = – a + b = 4

Substituindo o valor de b obtemos: – a + b = 4

a = b – 4

O ponto assintótico é o limite da soma:

Logo é a soma dos termos de uma PG decrescente e infinita.

Gráfico de f(x):

y

x 0

O gráfico de g(x) = f( |x|) é simétrico com relação ao eixo

das ordenadas, pois | x| " 0, # x $ R . Logo o gráfico da

função g(x) é:

y

x

0

E

E

6 - t

6

S

2S D • C

A • B

3

P(x) x – 3 ! P(x) = (x – 3). Q1(x) + 11

Q1(x)

P(x) x +1 ! P(x) = (x + 1). Q2(x) + 4

4 Q2(x)

P(x) = (x – 3).(x + 1).Q3(x) + ax + b

P(3) = 1 ! 0 + a.3 + b = 1 ! 3a + b = 1

P(– 1) = 4 ! 0 + a. (– 1) + b = 4 ! –a + b = 4 (x3)

3a + b = 1 Substituindo o valor de b obtemos:

–3a + 3b = 12

0 + 4b = 13 ! b = – a + b = 4

Substituindo o valor de b obtemos: – a + b = 4

a = b – 4

O ponto assintótico é o limite da soma:

Logo é a soma dos termos de uma PG decrescente e infinita.

Gráfico de f(x):

y

x 0

O gráfico de g(x) = f( |x|) é simétrico com relação ao eixo

das ordenadas, pois | x| " 0, # x $ R . Logo o gráfico da

função g(x) é:

y

x

0

Alternativa C

!" #$%&!!'()''!*#+,-.%/0+12.*#.+234

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Resolução:

E

E

6 - t

6

S

2S D • C

A • B

3

P(x) x – 3 ! P(x) = (x – 3). Q1(x) + 11

Q1(x)

P(x) x +1 ! P(x) = (x + 1). Q2(x) + 4

4 Q2(x)

P(x) = (x – 3).(x + 1).Q3(x) + ax + b

P(3) = 1 ! 0 + a.3 + b = 1 ! 3a + b = 1

P(– 1) = 4 ! 0 + a. (– 1) + b = 4 ! –a + b = 4 (x3)

3a + b = 1 Substituindo o valor de b obtemos:

–3a + 3b = 12

0 + 4b = 13 ! b = – a + b = 4

Substituindo o valor de b obtemos: – a + b = 4

a = b – 4

O ponto assintótico é o limite da soma:

Logo é a soma dos termos de uma PG decrescente e infinita.

Gráfico de f(x):

y

x 0

O gráfico de g(x) = f( |x|) é simétrico com relação ao eixo

das ordenadas, pois | x| " 0, # x $ R . Logo o gráfico da

função g(x) é:

y

x

0

Alternativa A

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

13

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JEK6

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J%K6

Resolução:

E

E

6 - t

6

S

2S D • C

A • B

3

P(x) x – 3 ! P(x) = (x – 3). Q1(x) + 11

Q1(x)

P(x) x +1 ! P(x) = (x + 1). Q2(x) + 4

4 Q2(x)

P(x) = (x – 3).(x + 1).Q3(x) + ax + b

P(3) = 1 ! 0 + a.3 + b = 1 ! 3a + b = 1

P(– 1) = 4 ! 0 + a. (– 1) + b = 4 ! –a + b = 4 (x3)

3a + b = 1 Substituindo o valor de b obtemos:

–3a + 3b = 12

0 + 4b = 13 ! b = – a + b = 4

Substituindo o valor de b obtemos: – a + b = 4

a = b – 4

O ponto assintótico é o limite da soma:

Logo é a soma dos termos de uma PG decrescente e infinita.

Gráfico de f(x):

y

x 0

O gráfico de g(x) = f( |x|) é simétrico com relação ao eixo

das ordenadas, pois | x| " 0, # x $ R . Logo o gráfico da

função g(x) é:

y

x

0

Alternativa D

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JEK6 D

JLK6 D

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JNK6 D

J%K6 D

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JEK6

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RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

14

Resolução:

E

E

6 - t

6

S

2S D • C

A • B

3

P(x) x – 3 ! P(x) = (x – 3). Q1(x) + 11

Q1(x)

P(x) x +1 ! P(x) = (x + 1). Q2(x) + 4

4 Q2(x)

P(x) = (x – 3).(x + 1).Q3(x) + ax + b

P(3) = 1 ! 0 + a.3 + b = 1 ! 3a + b = 1

P(– 1) = 4 ! 0 + a. (– 1) + b = 4 ! –a + b = 4 (x3)

3a + b = 1 Substituindo o valor de b obtemos:

–3a + 3b = 12

0 + 4b = 13 ! b = – a + b = 4

Substituindo o valor de b obtemos: – a + b = 4

a = b – 4

O ponto assintótico é o limite da soma:

Logo é a soma dos termos de uma PG decrescente e infinita.

Gráfico de f(x):

y

x 0

O gráfico de g(x) = f( |x|) é simétrico com relação ao eixo

das ordenadas, pois | x| " 0, # x $ R . Logo o gráfico da

função g(x) é:

y

x

0

Alternativa B

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1:38,+^-3FB

6 44B6LFA3T.6.F0.:X.+6,6F1+1/A,60,:23A9F.21-,B

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%/2^60,++32,6.93:./6,6=>36/36.N1+A.63A

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I%M6 .6/,F1;.+13;.;36:,6A>:;,6;36[,T36Y61F>/S+1.6363/2^6N.;.;.6.,6

N+.0.//,B

Resolução:

Trata-se de sinonímia.

Alternativa C

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6 44B6LFA3T.6.F0.:X.+6,6F1+1/A,60,:23A9F.21-,B

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ILM6 .6 +3.F1;.;36 Y6 1:/.21/N.2S+1.J6 A./6 381/236 93+/93021-.6 ;366

A3F[,+.B

IUM6 ,6A>:;,63/2^60.;>0,J69,+61//,6Y61:@21F6;1/0,++3+6/,Z+363F3B

IEM6 .6A>F[3+6 36 .6 [1/2S+1.6 :Q,6 0,:/212>3A6 .//>:2,6 9.+.6 9,32./6

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I%M6 .6/,F1;.+13;.;36:,6A>:;,6;36[,T36Y61F>/S+1.6363/2^6N.;.;.6.,6

N+.0.//,B

Resolução:

No trecho citado, o advérbio sim é usado para introduzir uma ressalva à constatação do que uma nova e robusta geração de leitores vem surgindo no país. A ressalva rompe com o otimismo da constatação já que as obras citadas não representam obras da literatura nacional.

Alternativa B

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&=-+'.%'$,2)#,)2+'25.-'$&&-'$#$%'2-#,%#'%'1)$25#%'-9&-1)2%:'>-'?#%7

&$1'.%'($#%.%'.-'&4/51-'@@'6%#%'-'@@A+'-'(%2$/B,$-'%24'6%#)/$%'

#%*-"()1C'-'&$&2)3%'.)'),&$,-')3'D#%,/-'.)/1B,$-')'&5%'2#%.$<=-'

.)'D#%/%&&-',%'3$&&=-'.)'D-#3%#'1)$2-#)&+'-'6-5/-'%6#)<-'.%.-'

E'$,&2#5<=-'/-3-'(%1-#'D5,.%3),2%1')'%24'.%.-&'35$2-'6#"2$/-&+'

/-3-'%'D%12%')'%'6-9#)*%'.)'9$91$-2)/%&'6091$/%&')'-'%12-'6#)<-'

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,=-'D5J$#)$'6%#%'%&'$18%&',)3'&)#)$'#%62%.-'6-#'&)#%D$,&:

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A,6;30.;3:21/2.B

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IWM6 4J64446364aB

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A3F[,+.B

IUM6 ,6A>:;,63/2^60.;>0,J69,+61//,6Y61:@21F6;1/0,++3+6/,Z+363F3B

IEM6 .6A>F[3+6 36 .6 [1/2S+1.6 :Q,6 0,:/212>3A6 .//>:2,6 9.+.6 9,32./6

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23A.6;369,3/1.B

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N+.0.//,B

Resolução:

“Porém” é conjunção adversativa que liga termos que exprimem contraste, oposição.

Alternativa E

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

15

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Resolução:

A validade dos itens I e IV pode ser constatada pela leitura do texto: ao afirmar “Estou preso à vida e olho meus companheiros” e “Entre eles, considero a enorme realidade” o eu - lírico revela a impossibilidade de ignorar a realidade circundante e o último verso da primeira parte conclama os companheiros a enfrentarem a vida unidos. Já o item III exige a lembrança das características do romantismo e do simbolismo e a identificação da negação ao escapismo e ao decadentismo nos quatro primeiros versos da segunda parte do poema.

Alternativa D

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Resolução:

A expressão “mundo caduco” revela a insatisfação do eu lírico quanto à realidade, no entanto, ao conclamar seus companheiros a lutarem de mãos dadas, demonstra comparti lhar das “grandes esperanças” de seus companheiros.

Alternativa A

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?@A5 0,72+.612Z+1,<5,;,76,5%'$(#&&'5?73D.21-,A5.5(#&&'&$&R7)-9'&5

?;,/121-,AB

?CA5 371D9N210,<5>/.76,5>9.5:+./357,917.8<5,5O>35K5170,9>957.5

817D>.D395[,+7.8Q/210.B

?EA5 0+Q210,<5.;3/.+5635,523J2,50,723+5;38,5937,/56,1/538,D1,/5.,5

C+./18B

?IA5 0\910,<5=./3.6,57.50,9;.+.GH,5372+35.50.;12.85 19;3+1.8535

6>./5016.63/53>+,;31./B

?%A5 .9=QD>,<52376,5395-1/2.5,/5/37216,/5637,2.21-,5350,7,2.21-,5

6.53J;+3//H,5%'$(#&&'B

&'

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/395;+3[>QF,5;.+.5,5/37216,<5;38.53J;+3//H,

?@A5 73//350./,B

?CA5 7.O>38.5K;,0.B

?EA5 73//3/58>D.+3/B

?IA5 0,7/3O>372393723B

?%A5 +3.893723B

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C+./185:1F3//35:,15V,76+3/535^.9=>+D,B

?EA5 @5;+1931+.5016.635.517-3/21+5395/1/239.56350,832.56353/D,2,<5

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?%A5 @57Q-3856353/D,2,<50,7/212>15.176.5>9.5/,8>GH,5;.+.5918RX3/5

635;3//,./5./50R.9.6./5-.8./5.50K>5.=3+2,B

Resolução:

O poema é formado por versos que apresentam paralelismo sintático, como, por exemplo entre o 1º e o 2º versos e entre o 8º e 11º versos.

Alternativa D

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?CA5 ,539;+3D,5635+19./51723+7./B

?EA5 .5>2181F.GH,5635381;/3/5-3+=.1/B

?IA5 .5+3;321GH,56353/2+>2>+./B

?%A5 .517-3+/H,56,/523+9,/56.5,+.GH,B

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?@A5 0,72+.612Z+1,<5,;,76,5%'$(#&&'5?73D.21-,A5.5(#&&'&$&R7)-9'&5

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?CA5 371D9N210,<5>/.76,5>9.5:+./357,917.8<5,5O>35K5170,9>957.5

817D>.D395[,+7.8Q/210.B

?EA5 0+Q210,<5.;3/.+5635,523J2,50,723+5;38,5937,/56,1/538,D1,/5.,5

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?%A5 .9=QD>,<52376,5395-1/2.5,/5/37216,/5637,2.21-,5350,7,2.21-,5

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?@A5 73//350./,B

?CA5 7.O>38.5K;,0.B

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?IA5 0,7/3O>372393723B

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#36+,5,519;3+.6,+B

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?EA5 @5;+1931+.5016.635.517-3/21+5395/1/239.56350,832.56353/D,2,<5

63;,1/5635V,76+3/535^.9=>+D,<5:,15,5]1,5635_.731+,B

?IA5 @50,73JH,50,95,5/1/239.56353/D,2,/5 :,15 :312,<53959>12,/5

8.+3/<5.2+.-K/5635:,//./5/K;210./B

?%A5 @57Q-3856353/D,2,<50,7/212>15.176.5>9.5/,8>GH,5;.+.5918RX3/5

635;3//,./5./50R.9.6./5-.8./5.50K>5.=3+2,B

Resolução:

O imperativo negativo forma-se a partir do presente do subjuntivo, antepondo-se o advérbio não. (Que vós vos afasteis) = (Não vos afasteis). Já, o imperativo afirmativo possui formas próprias apenas para as segundas pessoas - tu e vós: que provêm do presente indicativo sem o “s”. “vós ides” (-s) = (Ide vós)

Alternativa C

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

16

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3/;301.8<

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?CA5 ,539;+3D,5635+19./51723+7./B

?EA5 .5>2181F.GH,5635381;/3/5-3+=.1/B

?IA5 .5+3;321GH,56353/2+>2>+./B

?%A5 .517-3+/H,56,/523+9,/56.5,+.GH,B

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Resolução:

O livro “Sentimento do mundo” de Carlos Drummond de Andrade faz parte da segunda geração do modernismo, situada entre 1930 e 1945. Essa geração caracterizou-se por aproveitar as conquistas formais da primeira geração, porém de forma mais madura e, portanto menos radical ou demolidora.

Alternativa D

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?@A5 0,72+.612Z+1,<5,;,76,5%'$(#&&'5?73D.21-,A5.5(#&&'&$&R7)-9'&5

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?CA5 371D9N210,<5>/.76,5>9.5:+./357,917.8<5,5O>35K5170,9>957.5

817D>.D395[,+7.8Q/210.B

?EA5 0+Q210,<5.;3/.+5635,523J2,50,723+5;38,5937,/56,1/538,D1,/5.,5

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6>./5016.63/53>+,;31./B

?%A5 .9=QD>,<52376,5395-1/2.5,/5/37216,/5637,2.21-,5350,7,2.21-,5

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?@A5 73//350./,B

?CA5 7.O>38.5K;,0.B

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635;3//,./5./50R.9.6./5-.8./5.50K>5.=3+2,B

Resolução:

A expressão “na fossa”, em sentido conotativo significa “em má situação ou condição” e, no texto, faz referência à falta de estruturas de saneamento básico em 45% dos domicílios brasileiros. A ambigüidade se dá pela relação entre esse sentido e o sentido denotativo que faz parte do assunto do texto.

Alternativa E

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?CA5 ,539;+3D,5635+19./51723+7./B

?EA5 .5>2181F.GH,5635381;/3/5-3+=.1/B

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?%A5 .517-3+/H,56,/523+9,/56.5,+.GH,B

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D+.9.210.89372350,++32.57.5/3D>17235:+./3L

?@A5 MH,5/35.:./23959>12,<5-.63/56359H,/56.6./B

?CA5 MH,5-,/5.:./23/59>12,<5-N/56359H,/56.6./B

?EA5 MH,5-,/5.:./231/59>12,<516356359H,/56.6./B

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63;,1/5635V,76+3/535^.9=>+D,<5:,15,5]1,5635_.731+,B

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635;3//,./5./50R.9.6./5-.8./5.50K>5.=3+2,B

Resolução:

Classificada como advérbio, a palavra “então” expressa noção temporal.

Alternativa B

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?EA5 .5>2181F.GH,5635381;/3/5-3+=.1/B

?IA5 .5+3;321GH,56353/2+>2>+./B

?%A5 .517-3+/H,56,/523+9,/56.5,+.GH,B

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D+.9.210.89372350,++32.57.5/3D>17235:+./3L

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?CA5 MH,5-,/5.:./23/59>12,<5-N/56359H,/56.6./B

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;,+K9<5635:,+9.5937,/5639,816,+.B

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635;3//,./5./50R.9.6./5-.8./5.50K>5.=3+2,B

Resolução:

Alternativa “A” - Corrigindo-se: A construção (...) de esgotos foi iniciada... Alternativa “B” – Corrigindo-se: As cidades que dispuseram de coleta de dejetos antes que o Brasil o fizesse foram Londres e Hamburgo.Alternativa “D” – Corrigindo-se: A conexão com o sistema de esgoto foi feitaAlternativa “E” – Corrigindo-se: Relativamente ...

Alternativa C

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

17

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CPD6!"#$%"&'(&)*$+,*-+,*C$"#$ ."$/"0*C$/*-$ .#,*$*$1#"$)2$,"$3+(4$4+5-+,*C$1#"$6*78$3"$"47-"6+$#3+$7+-.(&)+A

CSD$ D(3$,('"&,*C$7*3*$9$1#"$6*78$6+(E$F#"C$"#$&:*$4"(C$"#$+&,*$.:*$'+-+&'+$/*-$7+#4+$,*$."#$+%+&,*&*A

CUD$ G#$7)*-*$"$#3$,(+C$/"5*H$.*3*$#3$/*--"$,+&+,*$1#"$6*78$6+($6"-$"$+;C$&#&7+$3+(4C$3"43*$1#"$6*78$3"$1#"-A

CVD$ D+%"$*$1#"$"#$<+0*E$G#$6*#=3"$"3%*-+C$/+-+$4"3/-"$"$&#&=7+$3+(4C$6">*$"44"$-*4.*$?(&,*C$1#"$"#$+,*-*I

C%D$ J*78$9$ .*,+$+$3(&)+$6(,+$"$ "#C$ 4@$ "47-"6*$/*-$ .#+$7+#4+$(&5-+.+A

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K$/-+,*C$+4$<?*-"4$%-+&7+4$"$6"-3"?)+4

G4.2$4#+6"3"&."$+/-"4"&.+&,*L

B4$,*7"4$"$4*?;7(.+4$+%"?)+4C

M*3$#3$%-+&,*$4#44#--*$6:*$6*+&,*L

B4$3+&4+4$"$/+7;<(7+4$*6"?)+4C

N*$7*3"-$"41#"7(,+4C$(&7?(&+&,*

B4$7+%"0+4$"4.:*$+*$4*3$,(6(&*

F#"$<+'C$/+44+&,*C$*$O">*$7-(4.+?(&*A

C7>F/6E.X6;36U.A?3/B6K%-+$7*3/?".+G6!HIIBD

!!

P63/2+,N36383A9O1N10.6.6OF+10.60OZ//10.69,+2>R>3/.G6:.6=>.O

CPD6 ,6A>:;,6;./6+3.O1X.K?3/6Y>A.:./6W6:.++.;,63A6/>.6;1A3:*/L,61;3.O636R+.:;1,/.B

CSD6 .6 :.2>+3X.G6 93O,6 /3>6 3=>1OFT+1,G6 ;3-36 /3+-1+6 0,A,6A,;3O,69.+.6,6Y,A3AB

CUD6 ,6 3/9.K,6 :.2>+.O6 A1A321X.6 ,6 0,:NO12,6 .A,+,/,6 ;,6 9,32.G6.2+.-W/6;./60.:21R./B

CVD6 ,6382+.-./.A3:2,6;,/6/3:21A3:2,/6/>93+.G6;36A,;,638.03+*T.;,G6,6;,AF:1,6;.6+.XL,B

C%D6 .6;3/0+1KL,6;.6:.2>+3X.636;362>;,6=>36OY36;1X6+3/9312,6W6N312.6;36A,;,6,T[321-,B

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>A.69+3,0>9.KL,60,A6.693+N31KL,6N,+A.OB6444B6U,:2+1T>16;36A.:31+.6;301/1-.69.+.6/36.O0.:K.+6.69+323:;1;.6

+3R>O.+1;.;36+F2A10.B

%/2Z60,++32,6,6=>36/36.N1+A.63A

CPD6 4G6.93:./B

CSD6 444G6.93:./B

CUD6 463644G6.93:./B

CVD6 44636444G6.93:./B

C%D6 4G644636444B

!&

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CPD6 !B

CSD6 ^B

CUD6 _B

CVD6 "B

C%D6 IB

Resolução:

Vinícius de Moraes é um poeta da segunda geração do modernismo brasileiro, que tem como uma de suas características marcantes, a valorização da linguagem coloquial, como demonstrado pelo texto em questão que simula a espontaneidade e de alguém que faz uma declaração de amor, principalmente, pela ausência de pontuação que aproxima o texto escrito do ritmo da fala.

Alternativa A

!" #$%&!!'()''!*#+,-.%/0+12.*#.+234

!"#$%&'()56731.6,62382,69.+.6+3/9,:;3+6</6=>3/2?3/6;36:@A3+,/6!"6.6!#B

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7*3*$9$1#"$6*78$6+($1#"$"#$&:*$ 4"($ "#$+&,*$ .:*$ '+-+&'+$/*-$

7+#4+$,*$."#$+%+&,*&*$"#$7)*-*$"$#3$,(+$/"5*$.*3*$#3$/*--"$

,+&+,*$1#"$6*78$6+($6"-$"$+;$&#&7+$3+(4$3"43*$1#"$6*78$3"$

1#"-$"$4+%"$*$1#"$"#$<+0*$"#$6*#=3"$"3%*-+$/+-+$4"3/-"$"$&#&=

7+$3+(4$6">*$"44"$-*4.*$?(&,*$1#"$"#$+,*-*$/*-1#"$6*78$9$.*,+$

+$3(&)+$6(,+$"$"#$4@$"47-"6*$/*-$.#+$7+#4+$(&5-+.+$CBBBD$,*$."#$,"<(&(.(6*$"$4"3/-"$+3(5*AAA

CE1:F01>/6;36$,+.3/B6B&.*?*5(+$/*9.(7+G6!HI!BD

!"

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CPD6 /1A>O.+6,62,A63/9,:2Q:3,6;.6OF:R>.6N.O.;.G69.+.62,+:.+6A.1/6.>2M:210.6>A.6;30O.+.KL,6;36.A,+B

CSD6 1A12.+6,69,+2>R>M/6A.O63/0+12,G69.+.6389+3//.+6.6/>TA1//L,6;,63A1//,+6;1.:236;36/>.6.A.;.B

CUD6 0,:23/2.+G69,+6A31,6;36>A.6N.O/.60.+2.6;36.A,+G6./6:,+A./6R+.A.210.1/6;.6OF:R>.60>O2.B

CVD6 389+3//.+6 >A6 /3:21A3:2,6 =>36 W6 2L,6 /3A6 /3:21;,6 =>.:2,6 .6O1:R>.R3A6>21O1X.;.69.+.62+.;>X1*O,B

C%D6 1+,:1X.+6./693//,./6=>363/0+3-3A6;36A,;,61:0,A9+33:/F-3O69,+6;3/0,:Y301A3:2,6;.6R+.AZ210.B

!#

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CPD6 /"0*B

CSD6 7)*-*B

CUD6 /"5*B

CVD6 <+0*B

C%D6 6">*B

!$

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CPD6!"#$%"&'(&)*$+,*-+,*C$"#$ ."$/"0*C$/*-$ .#,*$*$1#"$)2$,"$3+(4$4+5-+,*C$1#"$6*78$3"$"47-"6+$#3+$7+-.(&)+A

CSD$ D(3$,('"&,*C$7*3*$9$1#"$6*78$6+(E$F#"C$"#$&:*$4"(C$"#$+&,*$.:*$'+-+&'+$/*-$7+#4+$,*$."#$+%+&,*&*A

CUD$ G#$7)*-*$"$#3$,(+C$/"5*H$.*3*$#3$/*--"$,+&+,*$1#"$6*78$6+($6"-$"$+;C$&#&7+$3+(4C$3"43*$1#"$6*78$3"$1#"-A

CVD$ D+%"$*$1#"$"#$<+0*E$G#$6*#=3"$"3%*-+C$/+-+$4"3/-"$"$&#&=7+$3+(4C$6">*$"44"$-*4.*$?(&,*C$1#"$"#$+,*-*I

C%D$ J*78$9$ .*,+$+$3(&)+$6(,+$"$ "#C$ 4@$ "47-"6*$/*-$ .#+$7+#4+$(&5-+.+A

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K$/-+,*C$+4$<?*-"4$%-+&7+4$"$6"-3"?)+4

G4.2$4#+6"3"&."$+/-"4"&.+&,*L

B4$,*7"4$"$4*?;7(.+4$+%"?)+4C

M*3$#3$%-+&,*$4#44#--*$6:*$6*+&,*L

B4$3+&4+4$"$/+7;<(7+4$*6"?)+4C

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F#"$<+'C$/+44+&,*C$*$O">*$7-(4.+?(&*A

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CPD6 ,6A>:;,6;./6+3.O1X.K?3/6Y>A.:./6W6:.++.;,63A6/>.6;1A3:*/L,61;3.O636R+.:;1,/.B

CSD6 .6 :.2>+3X.G6 93O,6 /3>6 3=>1OFT+1,G6 ;3-36 /3+-1+6 0,A,6A,;3O,69.+.6,6Y,A3AB

CUD6 ,6 3/9.K,6 :.2>+.O6 A1A321X.6 ,6 0,:NO12,6 .A,+,/,6 ;,6 9,32.G6.2+.-W/6;./60.:21R./B

CVD6 ,6382+.-./.A3:2,6;,/6/3:21A3:2,/6/>93+.G6;36A,;,638.03+*T.;,G6,6;,AF:1,6;.6+.XL,B

C%D6 .6;3/0+1KL,6;.6:.2>+3X.636;362>;,6=>36OY36;1X6+3/9312,6W6N312.6;36A,;,6,T[321-,B

!%

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>A.69+3,0>9.KL,60,A6.693+N31KL,6N,+A.OB6444B6U,:2+1T>16;36A.:31+.6;301/1-.69.+.6/36.O0.:K.+6.69+323:;1;.6

+3R>O.+1;.;36+F2A10.B

%/2Z60,++32,6,6=>36/36.N1+A.63A

CPD6 4G6.93:./B

CSD6 444G6.93:./B

CUD6 463644G6.93:./B

CVD6 44636444G6.93:./B

C%D6 4G644636444B

!&

]A60./,6;369,/9,/1KL,6;,6/>[312,63A6+3O.KL,6.,6-3+T,6,0,++36:,6-3+/,

CPD6 !B

CSD6 ^B

CUD6 _B

CVD6 "B

C%D6 IB

Resolução:

Trata-se de uso informal, coloquial.

Alternativa C

!" #$%&!!'()''!*#+,-.%/0+12.*#.+234

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7*3*$9$1#"$6*78$6+($1#"$"#$&:*$ 4"($ "#$+&,*$ .:*$ '+-+&'+$/*-$

7+#4+$,*$."#$+%+&,*&*$"#$7)*-*$"$#3$,(+$/"5*$.*3*$#3$/*--"$

,+&+,*$1#"$6*78$6+($6"-$"$+;$&#&7+$3+(4$3"43*$1#"$6*78$3"$

1#"-$"$4+%"$*$1#"$"#$<+0*$"#$6*#=3"$"3%*-+$/+-+$4"3/-"$"$&#&=

7+$3+(4$6">*$"44"$-*4.*$?(&,*$1#"$"#$+,*-*$/*-1#"$6*78$9$.*,+$

+$3(&)+$6(,+$"$"#$4@$"47-"6*$/*-$.#+$7+#4+$(&5-+.+$CBBBD$,*$."#$,"<(&(.(6*$"$4"3/-"$+3(5*AAA

CE1:F01>/6;36$,+.3/B6B&.*?*5(+$/*9.(7+G6!HI!BD

!"

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CPD6 /1A>O.+6,62,A63/9,:2Q:3,6;.6OF:R>.6N.O.;.G69.+.62,+:.+6A.1/6.>2M:210.6>A.6;30O.+.KL,6;36.A,+B

CSD6 1A12.+6,69,+2>R>M/6A.O63/0+12,G69.+.6389+3//.+6.6/>TA1//L,6;,63A1//,+6;1.:236;36/>.6.A.;.B

CUD6 0,:23/2.+G69,+6A31,6;36>A.6N.O/.60.+2.6;36.A,+G6./6:,+A./6R+.A.210.1/6;.6OF:R>.60>O2.B

CVD6 389+3//.+6 >A6 /3:21A3:2,6 =>36 W6 2L,6 /3A6 /3:21;,6 =>.:2,6 .6O1:R>.R3A6>21O1X.;.69.+.62+.;>X1*O,B

C%D6 1+,:1X.+6./693//,./6=>363/0+3-3A6;36A,;,61:0,A9+33:/F-3O69,+6;3/0,:Y301A3:2,6;.6R+.AZ210.B

!#

J6/>T/2.:21-,6/*--"693+23:036<6-.+1.:2369,9>O.+6;.6OF:R>.G6.//1A60,A,G623:;,63A6-1/2.6,60,:2382,G6.6N,+A.6-3+T.O

CPD6 /"0*B

CSD6 7)*-*B

CUD6 /"5*B

CVD6 <+0*B

C%D6 6">*B

!$

P60,++32.69,:2>.KL,6;36>A.6;./6N+./3/6;,62382,6W5

CPD6!"#$%"&'(&)*$+,*-+,*C$"#$ ."$/"0*C$/*-$ .#,*$*$1#"$)2$,"$3+(4$4+5-+,*C$1#"$6*78$3"$"47-"6+$#3+$7+-.(&)+A

CSD$ D(3$,('"&,*C$7*3*$9$1#"$6*78$6+(E$F#"C$"#$&:*$4"(C$"#$+&,*$.:*$'+-+&'+$/*-$7+#4+$,*$."#$+%+&,*&*A

CUD$ G#$7)*-*$"$#3$,(+C$/"5*H$.*3*$#3$/*--"$,+&+,*$1#"$6*78$6+($6"-$"$+;C$&#&7+$3+(4C$3"43*$1#"$6*78$3"$1#"-A

CVD$ D+%"$*$1#"$"#$<+0*E$G#$6*#=3"$"3%*-+C$/+-+$4"3/-"$"$&#&=7+$3+(4C$6">*$"44"$-*4.*$?(&,*C$1#"$"#$+,*-*I

C%D$ J*78$9$ .*,+$+$3(&)+$6(,+$"$ "#C$ 4@$ "47-"6*$/*-$ .#+$7+#4+$(&5-+.+A

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K$/-+,*C$+4$<?*-"4$%-+&7+4$"$6"-3"?)+4

G4.2$4#+6"3"&."$+/-"4"&.+&,*L

B4$,*7"4$"$4*?;7(.+4$+%"?)+4C

M*3$#3$%-+&,*$4#44#--*$6:*$6*+&,*L

B4$3+&4+4$"$/+7;<(7+4$*6"?)+4C

N*$7*3"-$"41#"7(,+4C$(&7?(&+&,*

B4$7+%"0+4$"4.:*$+*$4*3$,(6(&*

F#"$<+'C$/+44+&,*C$*$O">*$7-(4.+?(&*A

C7>F/6E.X6;36U.A?3/B6K%-+$7*3/?".+G6!HIIBD

!!

P63/2+,N36383A9O1N10.6.6OF+10.60OZ//10.69,+2>R>3/.G6:.6=>.O

CPD6 ,6A>:;,6;./6+3.O1X.K?3/6Y>A.:./6W6:.++.;,63A6/>.6;1A3:*/L,61;3.O636R+.:;1,/.B

CSD6 .6 :.2>+3X.G6 93O,6 /3>6 3=>1OFT+1,G6 ;3-36 /3+-1+6 0,A,6A,;3O,69.+.6,6Y,A3AB

CUD6 ,6 3/9.K,6 :.2>+.O6 A1A321X.6 ,6 0,:NO12,6 .A,+,/,6 ;,6 9,32.G6.2+.-W/6;./60.:21R./B

CVD6 ,6382+.-./.A3:2,6;,/6/3:21A3:2,/6/>93+.G6;36A,;,638.03+*T.;,G6,6;,AF:1,6;.6+.XL,B

C%D6 .6;3/0+1KL,6;.6:.2>+3X.636;362>;,6=>36OY36;1X6+3/9312,6W6N312.6;36A,;,6,T[321-,B

!%

U,:/1;3+36./6 /3R>1:23/6389O10.K?3/69.+.6,6 +30>+/,6;.6 1:-3+/L,6=>36,0,++36:,62382,56 4B6\6>A.60.+.023+F/210.6;,6UO.//101/A,6+3:./03:21/2.6=>36+3/>O2.6

;.623:2.21-.6;361A12.+6.6/1:2.836;,67.21A60OZ//10,B6 44B6#+3:;3*/36 <6 :303//1;.;36 ;36 9+3/3+-.+6 ./6 +1A./G6 +3-3O.:;,6

>A.69+3,0>9.KL,60,A6.693+N31KL,6N,+A.OB6444B6U,:2+1T>16;36A.:31+.6;301/1-.69.+.6/36.O0.:K.+6.69+323:;1;.6

+3R>O.+1;.;36+F2A10.B

%/2Z60,++32,6,6=>36/36.N1+A.63A

CPD6 4G6.93:./B

CSD6 444G6.93:./B

CUD6 463644G6.93:./B

CVD6 44636444G6.93:./B

C%D6 4G644636444B

!&

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CPD6 !B

CSD6 ^B

CUD6 _B

CVD6 "B

C%D6 IB

Resolução:

A alternativa “A” é a única que não contraria as regras gerais de pontuação.

Alternativa A

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7*3*$9$1#"$6*78$6+($1#"$"#$&:*$ 4"($ "#$+&,*$ .:*$ '+-+&'+$/*-$

7+#4+$,*$."#$+%+&,*&*$"#$7)*-*$"$#3$,(+$/"5*$.*3*$#3$/*--"$

,+&+,*$1#"$6*78$6+($6"-$"$+;$&#&7+$3+(4$3"43*$1#"$6*78$3"$

1#"-$"$4+%"$*$1#"$"#$<+0*$"#$6*#=3"$"3%*-+$/+-+$4"3/-"$"$&#&=

7+$3+(4$6">*$"44"$-*4.*$?(&,*$1#"$"#$+,*-*$/*-1#"$6*78$9$.*,+$

+$3(&)+$6(,+$"$"#$4@$"47-"6*$/*-$.#+$7+#4+$(&5-+.+$CBBBD$,*$."#$,"<(&(.(6*$"$4"3/-"$+3(5*AAA

CE1:F01>/6;36$,+.3/B6B&.*?*5(+$/*9.(7+G6!HI!BD

!"

J/69+,03;1A3:2,/6.;,2.;,/6:.60,:/2+>KL,6;3//36 2382,6 2MA69,+6N1:.O1;.;3

CPD6 /1A>O.+6,62,A63/9,:2Q:3,6;.6OF:R>.6N.O.;.G69.+.62,+:.+6A.1/6.>2M:210.6>A.6;30O.+.KL,6;36.A,+B

CSD6 1A12.+6,69,+2>R>M/6A.O63/0+12,G69.+.6389+3//.+6.6/>TA1//L,6;,63A1//,+6;1.:236;36/>.6.A.;.B

CUD6 0,:23/2.+G69,+6A31,6;36>A.6N.O/.60.+2.6;36.A,+G6./6:,+A./6R+.A.210.1/6;.6OF:R>.60>O2.B

CVD6 389+3//.+6 >A6 /3:21A3:2,6 =>36 W6 2L,6 /3A6 /3:21;,6 =>.:2,6 .6O1:R>.R3A6>21O1X.;.69.+.62+.;>X1*O,B

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CUD6 ,6 3/9.K,6 :.2>+.O6 A1A321X.6 ,6 0,:NO12,6 .A,+,/,6 ;,6 9,32.G6.2+.-W/6;./60.:21R./B

CVD6 ,6382+.-./.A3:2,6;,/6/3:21A3:2,/6/>93+.G6;36A,;,638.03+*T.;,G6,6;,AF:1,6;.6+.XL,B

C%D6 .6;3/0+1KL,6;.6:.2>+3X.636;362>;,6=>36OY36;1X6+3/9312,6W6N312.6;36A,;,6,T[321-,B

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+3R>O.+1;.;36+F2A10.B

%/2Z60,++32,6,6=>36/36.N1+A.63A

CPD6 4G6.93:./B

CSD6 444G6.93:./B

CUD6 463644G6.93:./B

CVD6 44636444G6.93:./B

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CPD6 !B

CSD6 ^B

CUD6 _B

CVD6 "B

C%D6 IB

Resolução:

O texto representa a literatura do Classicismo, concepção de arte que tem como princípio estético o conceito de mímesis, que impõe a imitação da natureza como virtude da obra de arte, já que na concepção clássica, a natureza é o modelo de equilíbrio ideal.

Alternativa B

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

18

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CSD6 1A12.+6,69,+2>R>M/6A.O63/0+12,G69.+.6389+3//.+6.6/>TA1//L,6;,63A1//,+6;1.:236;36/>.6.A.;.B

CUD6 0,:23/2.+G69,+6A31,6;36>A.6N.O/.60.+2.6;36.A,+G6./6:,+A./6R+.A.210.1/6;.6OF:R>.60>O2.B

CVD6 389+3//.+6 >A6 /3:21A3:2,6 =>36 W6 2L,6 /3A6 /3:21;,6 =>.:2,6 .6O1:R>.R3A6>21O1X.;.69.+.62+.;>X1*O,B

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+3R>O.+1;.;36+F2A10.B

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CPD6 4G6.93:./B

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CPD6 !B

CSD6 ^B

CUD6 _B

CVD6 "B

C%D6 IB

Resolução:

Durante o Classicismo, a língua e a cultura latina eram referências culturais para os escritores; como a sintaxe latina tem uma organização dos termos da oração diferente da língua portuguesa, os poetas buscavam adequar a linguagem de seus poemas a fim de imitar a organização sintática do latim e alcançar o ritmo do falar latino em seus versos. Além disso, a preocupação com a perfeição formal levava às inversões que preservavam as rimas e a regularidade métrica desejadas ao poema perfeito.

Alternativa E

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,+&+,*$1#"$6*78$6+($6"-$"$+;$&#&7+$3+(4$3"43*$1#"$6*78$3"$

1#"-$"$4+%"$*$1#"$"#$<+0*$"#$6*#=3"$"3%*-+$/+-+$4"3/-"$"$&#&=

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CUD6 0,:23/2.+G69,+6A31,6;36>A.6N.O/.60.+2.6;36.A,+G6./6:,+A./6R+.A.210.1/6;.6OF:R>.60>O2.B

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CPD6 !B

CSD6 ^B

CUD6 _B

CVD6 "B

C%D6 IB

Resolução:

Colocando-se na ordem direta: Som divino/que o Tejo cristalino faz.

Alternativa E

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Resolução:

A pergunta da entrevistadora é sobre o nascimento de um texto, e a palavra que se refere a esse aspecto é “gênese”, que significa formação, origem.

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Resolução:

A expressão “trapézio voador” é uma metáfora que remete à liberdade de criação que artista experimenta em relação à realidade.

Alternativa C

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

19

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Resolução:

No fragmento: “São perguntas que ouço com frequência”, o pronome relativo “que” substituindo o termo anterior “perguntas”; exerce, relativamente ao verbo (ouço), exerce a função sintática de objeto direto (“ouço perguntas”).

Alternativa A

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Resolução:

A protagonista do romance “Inocência” reza, buscando na religiosidade a solução para seu sofrimento amoroso. No exagero do desespero, conforme os ideais românticos, chega a desejar até mesmo a morte com fuga do sofrimento e, no terceiro parágrafo, refere-se ao pai como causador de medo o que justifica o item II.

Alternativa B

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Resolução:

Segundo o texto, a protagonista pretextou “queda de sezões”, que seria uma recaída de febre, ou seja, um problema de ordem física.

Alternativa D

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Resolução:

O pronome oblíquo lhe pode ser usado com sentido possessivo, principalmente quando se refere a partes do corpo de uma pessoa.No caso, temos: amargas lágrimas inundavam o seu rosto (ou o rosto dela).

Alternativa A

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

20

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Resolução:

O advérbio “mal” está com sentido de “quase não”. (“mal tocou no assunto”) = quase não tocou no assunto.

Alternativa B

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Resolução:

O uso da segunda pessoa do plural (vós) denota respeito e solenidade.

Alternativa E

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CIE6 +3B1J1,/.F

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CDE6 !"#$#%&#'"()&%*$#'"CFFFE"(+!"*,-,.#/#$"0"%0'10F

CGE6 20''#"3!,+0%#".#"4-*#"$!"'050%%#6

CIE" 7-!"#&0%#"1#,10"$!.0"$!"$!1!F

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CDE6 $.B60N3J,:6>.6-1.J3@6>36H?+1./Q623-36>362+.A.BN.+F

CGE6 I,@,6;=,69:3+1.67.+303+61;>1/0+32,[email protected],0,:6;,6.//:;2,F

CIE6 D6 7.B.-+.6 SB123+.B@3;23T6 0,/2:@.6 /[email protected] 3@7+3J.>.6 7,+6@:12.6J3;23F

CKE6 %/2=,60.@1;N.;>,[email protected]./6+3H,+@./67,BL210./6;,6G+./1BF

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CKE6 1;23+0.B,:63@6/:.6,+.R=,6HB38W3/6-3+A.1/62L710./6>.6B1;J:.*J3@6+3J1,;.BF

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CDE6 4Q6.73;./F

CGE6 44Q6.73;./F

CIE6 463644Q6.73;./F

CKE6 44636444Q6.73;./F

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Resolução:O pretérito mais-que-perfeito que, normalmente, indica ação passada anterior a outra ação também passada. Estilisticamente, pode também expressar desejo.

Alternativa C

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CDE6 !"#$#%&#'"()&%*$#'"CFFFE"(+!"*,-,.#/#$"0"%0'10F

CGE6 20''#"3!,+0%#".#"4-*#"$!"'050%%#6

CIE" 7-!"#&0%#"1#,10"$!.0"$!"$!1!F

CKE6 8!.*9(+!"7-!"1!,+#":!,#".!"$*$F

C%E6 !'10%5*#9'!".!".!'!':!%0F

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CDE6 $.B60N3J,:6>.6-1.J3@6>36H?+1./Q623-36>362+.A.BN.+F

CGE6 I,@,6;=,69:3+1.67.+303+61;>1/0+32,[email protected],0,:6;,6.//:;2,F

CIE6 D6 7.B.-+.6 SB123+.B@3;23T6 0,/2:@.6 /[email protected] 3@7+3J.>.6 7,+6@:12.6J3;23F

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CDE6 :/,:6-3+A,/69:36>3-3@6/3+60,;X:J.>,/6>36@,>,6>1H3+3;236>,6-3+A,63@7+3J.>,63@6/:.67+1@31+.6H.B.F

CGE6 3;0,;2+.-.*/36.J,;1.>.Q6>3-1>,6.,6@,@3;2,67,+69:363/2.-.67.//.;>,Q67,+61//,63@7+3J,:[email protected],/6-3+A,/F

CIE6 3/2.-.6+37321;>,6:@.6,+.R=,69:36>3-1.6/.A3+6>360,+Q6XY69:363+.6@:12,6+3B1J1,/.F

CKE6 1;23+0.B,:63@6/:.6,+.R=,6HB38W3/6-3+A.1/62L710./6>.6B1;J:.*J3@6+3J1,;.BF

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Resolução:

O uso recorrente de conjunções, pronomes (que, outro), advérbios (antes); além dos vocábulos “tecer”, “costurar”, “fios”, “teia”, “encorpar”, “tela”, “tecido” estabelecem a coesão textual, aliados à imagem dos galos que juntos em coro, cantam e “tecem” a manhã. A sonoridade das consoantes em “tece”, “grito”, “teia”, “tênue”, “galo”, “grito” e das nasais em “encorpando”, “entre”, “tenda”,

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

21

“entrem”, “entretendendo”, “manhã”, “plana”, “balão” constitui a aliteração a que se refere o item II e fortalecem a ligação entre as palavras. A sugestão da manhã que se constrói a partir de um galo tem seu ponto culminante no nascer do sol, representado pela metáfora da “luz balão” que emerge dos cantos dos galos em conjunto.

Alternativa E

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Resolução:

A forma nominal correspondente ao gerúndio apresenta o processo verbal em curso, de maneira progressiva.

Alternativa B

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Resolução:

A partir da definição colocada no enunciado da questão, chega-se à alternativa correta, pois é a única em que há associação entre visão (“fios de sol”) e audição (“gritos”).

Alternativa A

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Resolução:

A união dos gritos dos galos para se tecer uma manhã é uma interpretação poética do dito popular: “Uma andorinha não faz verão” ou “A união faz a força”.

Alternativa E

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RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

22

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Resolução:

A alternativa “D” da questão 71 pode ser depreendida da idéia do trecho: “police officers have developed professionalism in their approaches to solving and preventing crime and mantaining public order.” (os oficiais de polícia tem desenvolvido profissionalismo em suas abordagens para prevenir e resolver crimes, e manter a ordem pública – de onde se depreende que os oficiais fazem valer lei.) idéia que sintetiza o trecho do parágrafo, que por sua vez, acentua essa relação com a declaração da alternativa D.

Alternativa D

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Resolução:

A alternativa “A” da questão de número 72 pode ser justificada nas linhas 9 e 10 do texto tendo como chave a própria seqüência “When police respects...” (quando a polícia respeita) empregada na questão. O primeiro efeito apresentado como conseqüência desse respeito da polícia para como os direitos humanos é o aumento da confiança pública (public confidence).

Alternativa A

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Resolução:

A alternativa “E” da questão 73 pode ser justificada na idéia apresentada logo no primeiro parágrafo do texto, no trecho “In this sense, respect for human rights by police, in addition to being a moral, legal and ethical imperative, also a practical requirement for law enforcement” (Neste sentido, o respeito aos direitos humanos por parte da polícia é, além de um imperativo moral, legal e ético, um princípio para a aplicação da lei). Traduzindo a alternativa “E” temos afirmação de que a policia deveria: “evitar qualquer ação contra os direitos humanos”, afirmação que tem relação com o trecho destacado e que se confirma em outros momentos do texto também considerando sua idéia geral. As palavras que permitem essa associação estão em negrito a fim de esclarecer o raciocínio que sustenta essa conclusão, havendo outras possibilidades.

Alternativa E

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Resolução:

A questão 74, cuja alternativa é “C”, envolve o conhecimento do verbo to bend (curvar, entortar, dobrar etc.) e também do substantivo rule (regra, norma, preceito) que são palavras de um nível básico de vocabulário. No entanto, no contexto em que essas palavras formam a expressão “bend the rules” (transgredir as regras) é necessário que se compreenda que neste trecho o texto apresenta o conflito entre aqueles que defendem os direitos humanos, e a realidade da aplicação da lei que muitas vezes “transgride um pouco das regras”.

Alternativa C

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

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A%C8 ]82("%!".-9/#:8]Resolução:

A questão 75 apresenta um problema semântico em relação a uma conjunção bem conhecida, “in order to” que significa a fim de, no intuito de ou mesmo para, indica finalidade.

Alternativa B

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Resolução:

A alternativa “D” da questão 76 apresenta melhor possibilidade de paráfrase da idéia do trecho destacado. Traduzida ela diz: “Os outros (as pessoas) respeitam a lei na sociedade quando um exemplo é colocado”.

Alternativa D

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AFC8 T52.10+6-*8-.8*24*-.E

AHC8 1*-6.4*270*8-.8*24*-.E

AKC8 +L272/2*8V.8>20.E

A%C8 -=*+,201-*).287-.8>20.E

!&

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5;-

ABC8 /-5.-E

AFC8 <06->07-72E

AHC8 /+;=-*-JM+E

AKC8 /+670JM+E

A%C8 ->12*6-10,-E

!'

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ABC8 &+/021P8 *2.=2/1.8 +1D2*.8 -//+*70648 1+8 >-Q8 29-;=>2.8 1D-18

.D+5>78L28.21E

AFC8 B6829-;=>28+<81D28>-Q80.8.218<+*8+1D2*.81+8*2.=2/18.+/021PE

AHC8 Z-Q8068.+/021P8Q+*R.8-.8-6829-;=>28<+*8+1D2*.E

AKC8 X1D2*.8*2.=2/181D28>-Q80681D28.+/021P8QD268-6829-;=>280.8.21E

A%C8 [+8.218-6829-;=>28+<81D28>-Q8;-R2.8.+/021P8*2.=2/18+1D2*.E

!!

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ABC8 ;04D1E

AFC8 Q+5>7E

AHC8 +54D181+E

AKC8 Q0>>E

A%C8 7+2.E

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7-.86+8N>10;+8=2*?+7+87+81291+E

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ABC8 EEE%!38]

AFC8 ]8;-(8]

AHC8 ]82#$8]

AKC8 ]8-(8]

A%C8 ]8&-8]

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AFC8 ]%2+%"2+36

AHC8 ]8*"2+&%$/;;/.)*&E

AKC8 ]8$/;;"("#."6

A%C8 ]%9-("%$/;;/.)*&6

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ABC8 ]8="("%!".-9/#:8EEE

AFC8 ]8!".-9"+8]

AHC8 ]%!".29"8]

AKC8 ]8!".-9"8]

A%C8 ]82("%!".-9/#:8]

Resolução:

A questão trabalha com a típica substituição dos verbos modais e requer conhecimentos básicos sobre o assunto. No caso, a alternativa “C” ought to (dever) é a melhor opção de substituição para should. Esta questão foi extremamente básica.

Alternativa C

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!"

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ABC8 -,->0-*8+.870*201+.8D5;-6+.87+8/*0;06+.+E

AFC8 G5>4-*8+.8/+61*-,261+*2.8/+6<+*;28-8.5-8;+*->828@10/-E

AHC8 -12;+*0I-*8+.8=+..?,20.8/*0;06+.+.8=2>+85.+87-8<+*J-E

AKC8 2,01-*8-8/*0;06->07-72:8L2;8/+;+8<-I2*8,->2*8-8>20E

A%C8 ->06D-*).28/+;8-8G5.10J-:8-8+=060M+8=NL>0/-828-8;?70-E

!#

OD268=+>0/28*2.=2/1.8D5;-68*04D1.:

ABC8 =5L>0/8/+6<0726/280.826D-6/27E

AFC8 2<<2/10,28=*+.2/510+6.8-*28D-;=2*27E

AHC8 /0,0>856*2.18;-P8-*0.2E

AKC8 =*2,2610,28-678=*+-/10,28-/10+6.8-*28;-72870<<0/5>1E

A%C8 >24->870./5..0+6.8Q0>>8/+;285=E

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ABC8 5.28+,2*QD2>;0648<+*/281+8/+61*+>872;+6.1*-10+6.E

AFC8 5.28=DP.0/->8=*2..5*28.+;210;2.81+8+L1-068/+6<2..0+6.E

AHC8 L28*2-/10,28*-1D2*81D-68=*+-/10,28068/*0;28=*2,2610+6E

AKC8 L*2-R8.+;28>-Q.8068/-.281D28*2.5>180.8Q+*1DQD0>2E

A%C8 -,+078-6P8-/10+68-4-06.18D5;-68*04D1.E

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2;8=+*1545U.:8-

ABC8 *2<+*J-*8-.8*24*-.E

AFC8 T52.10+6-*8-.8*24*-.E

AHC8 1*-6.4*270*8-.8*24*-.E

AKC8 +L272/2*8V.8>20.E

A%C8 -=*+,201-*).287-.8>20.E

!&

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5;-

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AFC8 <06->07-72E

AHC8 /+;=-*-JM+E

AKC8 /+670JM+E

A%C8 ->12*6-10,-E

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ABC8 &+/021P8 *2.=2/1.8 +1D2*.8 -//+*70648 1+8 >-Q8 29-;=>2.8 1D-18

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AFC8 B6829-;=>28+<81D28>-Q80.8.218<+*8+1D2*.81+8*2.=2/18.+/021PE

AHC8 Z-Q8068.+/021P8Q+*R.8-.8-6829-;=>28<+*8+1D2*.E

AKC8 X1D2*.8*2.=2/181D28>-Q80681D28.+/021P8QD268-6829-;=>280.8.21E

A%C8 [+8.218-6829-;=>28+<81D28>-Q8;-R2.8.+/021P8*2.=2/18+1D2*.E

!!

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AFC8 Q+5>7E

AHC8 +54D181+E

AKC8 Q0>>E

A%C8 7+2.E

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7-.86+8N>10;+8=2*?+7+87+81291+E

!(

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AKC8 ]8$/;;"("#."6

A%C8 ]%9-("%$/;;/.)*&6

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AKC8 ]8!".-9"8]

A%C8 ]82("%!".-9/#:8]!" #$%&""'!(''")#*+,-%./*01-)#-*123

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AFC8 G5>4-*8+.8/+61*-,261+*2.8/+6<+*;28-8.5-8;+*->828@10/-E

AHC8 -12;+*0I-*8+.8=+..?,20.8/*0;06+.+.8=2>+85.+87-8<+*J-E

AKC8 2,01-*8-8/*0;06->07-72:8L2;8/+;+8<-I2*8,->2*8-8>20E

A%C8 ->06D-*).28/+;8-8G5.10J-:8-8+=060M+8=NL>0/-828-8;?70-E

!#

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ABC8 =5L>0/8/+6<0726/280.826D-6/27E

AFC8 2<<2/10,28=*+.2/510+6.8-*28D-;=2*27E

AHC8 /0,0>856*2.18;-P8-*0.2E

AKC8 =*2,2610,28-678=*+-/10,28-/10+6.8-*28;-72870<<0/5>1E

A%C8 >24->870./5..0+6.8Q0>>8/+;285=E

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AFC8 5.28=DP.0/->8=*2..5*28.+;210;2.81+8+L1-068/+6<2..0+6.E

AHC8 L28*2-/10,28*-1D2*81D-68=*+-/10,28068/*0;28=*2,2610+6E

AKC8 L*2-R8.+;28>-Q.8068/-.281D28*2.5>180.8Q+*1DQD0>2E

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2;8=+*1545U.:8-

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AFC8 T52.10+6-*8-.8*24*-.E

AHC8 1*-6.4*270*8-.8*24*-.E

AKC8 +L272/2*8V.8>20.E

A%C8 -=*+,201-*).287-.8>20.E

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ABC8 /-5.-E

AFC8 <06->07-72E

AHC8 /+;=-*-JM+E

AKC8 /+670JM+E

A%C8 ->12*6-10,-E

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ABC8 &+/021P8 *2.=2/1.8 +1D2*.8 -//+*70648 1+8 >-Q8 29-;=>2.8 1D-18

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AFC8 B6829-;=>28+<81D28>-Q80.8.218<+*8+1D2*.81+8*2.=2/18.+/021PE

AHC8 Z-Q8068.+/021P8Q+*R.8-.8-6829-;=>28<+*8+1D2*.E

AKC8 X1D2*.8*2.=2/181D28>-Q80681D28.+/021P8QD268-6829-;=>280.8.21E

A%C8 [+8.218-6829-;=>28+<81D28>-Q8;-R2.8.+/021P8*2.=2/18+1D2*.E

!!

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AFC8 Q+5>7E

AHC8 +54D181+E

AKC8 Q0>>E

A%C8 7+2.E

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7-.86+8N>10;+8=2*?+7+87+81291+E

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AKC8 ]8-(8]

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AHC8 ]8*"2+&%$/;;/.)*&E

AKC8 ]8$/;;"("#."6

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Resolução:

A preposição “by”, alternativa “A” é a opção correta. Essa questão também pode ser considerada simples, pois a aplicação da preposição by (por, pela ou pelo) é orientada pela própria compreensão da idéia principal do texto.

Alternativa A

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!"

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ABC8 -,->0-*8+.870*201+.8D5;-6+.87+8/*0;06+.+E

AFC8 G5>4-*8+.8/+61*-,261+*2.8/+6<+*;28-8.5-8;+*->828@10/-E

AHC8 -12;+*0I-*8+.8=+..?,20.8/*0;06+.+.8=2>+85.+87-8<+*J-E

AKC8 2,01-*8-8/*0;06->07-72:8L2;8/+;+8<-I2*8,->2*8-8>20E

A%C8 ->06D-*).28/+;8-8G5.10J-:8-8+=060M+8=NL>0/-828-8;?70-E

!#

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ABC8 =5L>0/8/+6<0726/280.826D-6/27E

AFC8 2<<2/10,28=*+.2/510+6.8-*28D-;=2*27E

AHC8 /0,0>856*2.18;-P8-*0.2E

AKC8 =*2,2610,28-678=*+-/10,28-/10+6.8-*28;-72870<<0/5>1E

A%C8 >24->870./5..0+6.8Q0>>8/+;285=E

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ABC8 5.28+,2*QD2>;0648<+*/281+8/+61*+>872;+6.1*-10+6.E

AFC8 5.28=DP.0/->8=*2..5*28.+;210;2.81+8+L1-068/+6<2..0+6.E

AHC8 L28*2-/10,28*-1D2*81D-68=*+-/10,28068/*0;28=*2,2610+6E

AKC8 L*2-R8.+;28>-Q.8068/-.281D28*2.5>180.8Q+*1DQD0>2E

A%C8 -,+078-6P8-/10+68-4-06.18D5;-68*04D1.E

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2;8=+*1545U.:8-

ABC8 *2<+*J-*8-.8*24*-.E

AFC8 T52.10+6-*8-.8*24*-.E

AHC8 1*-6.4*270*8-.8*24*-.E

AKC8 +L272/2*8V.8>20.E

A%C8 -=*+,201-*).287-.8>20.E

!&

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AHC8 Z-Q8068.+/021P8Q+*R.8-.8-6829-;=>28<+*8+1D2*.E

AKC8 X1D2*.8*2.=2/181D28>-Q80681D28.+/021P8QD268-6829-;=>280.8.21E

A%C8 [+8.218-6829-;=>28+<81D28>-Q8;-R2.8.+/021P8*2.=2/18+1D2*.E

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AKC8 Q0>>E

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7-.86+8N>10;+8=2*?+7+87+81291+E

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Resolução:

Na questão a compreensão da idéia central do texto também é imprescindível. A alternativa “E”, “more difficult” (mais difícil) é expressão conhecida e se destaca em relação às outras possibilidades.

Alternativa E

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!"

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ABC8 -,->0-*8+.870*201+.8D5;-6+.87+8/*0;06+.+E

AFC8 G5>4-*8+.8/+61*-,261+*2.8/+6<+*;28-8.5-8;+*->828@10/-E

AHC8 -12;+*0I-*8+.8=+..?,20.8/*0;06+.+.8=2>+85.+87-8<+*J-E

AKC8 2,01-*8-8/*0;06->07-72:8L2;8/+;+8<-I2*8,->2*8-8>20E

A%C8 ->06D-*).28/+;8-8G5.10J-:8-8+=060M+8=NL>0/-828-8;?70-E

!#

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AHC8 /0,0>856*2.18;-P8-*0.2E

AKC8 =*2,2610,28-678=*+-/10,28-/10+6.8-*28;-72870<<0/5>1E

A%C8 >24->870./5..0+6.8Q0>>8/+;285=E

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AFC8 5.28=DP.0/->8=*2..5*28.+;210;2.81+8+L1-068/+6<2..0+6.E

AHC8 L28*2-/10,28*-1D2*81D-68=*+-/10,28068/*0;28=*2,2610+6E

AKC8 L*2-R8.+;28>-Q.8068/-.281D28*2.5>180.8Q+*1DQD0>2E

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AFC8 T52.10+6-*8-.8*24*-.E

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AKC8 +L272/2*8V.8>20.E

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Resolução:

A questão 80 encerra o conjunto das três últimas questões com a alternativa “B”(becomes); o verbo become (tornar-se) a parece no trecho: “ When the law enforcer becomes the lawbreacker,...”(Quando a aplicação da lei se torna a quebra da lei) e o teste consiste no emprego do tempo correto do verbo, que nesse caso é a forma becomes, já que o sujeito está em 3º pessoa (the law, e por isso o s) e became corresponde ao pretérito de become.

Alternativa B

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

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Resolução:

A resposta dependia, apenas, da leitura do texto. No parágrafo em questão afirma que antigamente a emigração ocorria por necessidade e as pessoas partiam sem nada, sem formação, sem recursos, enquanto hoje, partem tendo formação, dominando idiomas, com cultura de viagem.

Alternativa D

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B$F5 8*09/M80+525/+9:0NO+A

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BEF5 :251*-,L.A

BRF5 8+*5@2:0+A

BSF5 :2D5*2,L.A

BGF5 -D5*2,L.A

B$F5 295@2:0+A

Resolução:

Questão tradicional, cobrando conhecimento de recursos coesivos em espanhol. “Pero” é conjunção adversativa e pode ser traduzida para o Português como “porém”.

Alternativa A

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+%("#&"# $.%&%#/0*1(%8'D1)/E$-' +%)()' 50"/#*%?(-'A#'F%#3#10'B'

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2"#$%&)@0-'I#"&0$'C4=%-')('!"#$%&%#8';Z)'1%30')('$4'1)$=#*A0'O4)'

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8-M.2.A

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J0@5:25-V.+*,2*5-5:2@-9:-52.8-9P+D-58+*58*+J0..0+9-0.A

BGF5 +5.0.12@-52:=/-10,+52.8-9P+D5L5=@5:+.5@2DP+*2.5:+5@=9:+5

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BEF5 :251*-,L.A

BRF5 8+*5@2:0+A

BSF5 :2D5*2,L.A

BGF5 -D5*2,L.A

B$F5 295@2:0+A

Resolução:

Outra questão que exige domínio de leitura e interpretação: o tecido industrial não absorve a quantidade de profissionais que se formam, por isso, é uma aspiração espanhola que o excedente emigre.

Alternativa E

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

25

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Resolução:

A resposta fornecida pelo gabarito oficial é única aceitável, já que as preposições fazem referência à extensão da América.

Alternativa C

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C#'1%")*+0"#'>)()"#&' ")*0(0*)'O4)')L%$+)')$#'1)/#(1#'1)'

="05)$%0(#&)$' *4#&%5%*#10$' )(' C#+%(0#/Q"%*#8' ;K(' K$=#@#-'

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(4)$+"0' $%$+)/#' )14*#+%F0-' O4)' )$' 1)' &0$' /)30")$' 1)&' /4(108'

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1#')('+01#'D/Q"%*#-''%2'%#I#(#1E'/02$0'+01#'C#+%(0#/Q"%*#G8

U%*A0')$+0-'030'%'O4)';1)$>"#*%#1#/)(+)'(0'$)')$+E('B)(10G8'

V(#'1)'&#$'+#")#$'1)'H%(')$'=0()"'&#$'*0$#$'5E*%&)$'#'&0$')$=#@0&)$'

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H#J$)$' O4)' #=#")(+)/)(+)' =")$)(+#(' >"#(1)$' 0=0"+4(%1#1)$-' )('

")#&%1#1'0*4&+#('1%5%*4&+#1)$'=#"#' &0$' )$=#@0&)$8'H0"')3)/=&0-' )('

!"#$%&W';X4'=0+)(*%#&' )$' )(0"/)'B'*0('(%$"2' %(/)1%#+0$-' *0/0')&'

/4(1%#&-'&0$'34)>0$'0&J/=%*0$-'&#'*02)"+4"#')()">Q+%*#-')&'+"#+#/%)(+0'

/)1%0#/2%)(+#&-')&'1)$=)>4)'1)&'+4"%$/0G8

K&' 1J#' :' 1)' /#"M0' $)' ")4(%?' *0(' )&' /%(%$+"0' 1)' Y"#2#30'

2"#$%&)@0-'I#"&0$'C4=%-')('!"#$%&%#8';Z)'1%30')('$4'1)$=#*A0'O4)'

!"#$%&'()*)$%+#',-.'/%&&0()$'1)'=)"$0(#$'1)'#&+#'*4#&%5%*#*%?('B'

O4)'K$=#@#' &#$' +)(J#G8'X%(' )/2#">0-' &0$' 3?F)()$'*0(')$+41%0$'

$4=)"%0")$' )$=#@0&)$' %&# +0("' (0' $)' F#(8' ;C#' &)>%$&#*%?(' 1)'

%/=&#(+#*%?('1)')/=")$#$')('!"#$%&')$'/4B'")$+"%*+%F#G-'#$)>4"#'

H%(8';C0$'+"#2#3#10")$'1)'4(#')/=")$#'O4)'$)'F#'#'!"#$%&'+%)()('

4('=)"/%$0'1)')$+#(*%#'=0"'02"#G-'&0'O4)'14"#'$4'*0(+"#+08'K('

*4#(+0'#')$+#2&)*)"$)'=0"'$4'*4)(+#-';)$'/4B'1%5J*%&-' &#$' &)B)$'

1%5%*4&+#('O4)'&#'>)(+)'+0/)')$#'0=*%?(G8

U)' &#'/%$/#'50"/#-'!"#$%&';=4)1)'O4)'()*)$%+)'4(0$':['777'

="05)$0")$'1)')$=#@0&'(#+%F0$G8'H)"0-'#4(O4)')('K$=#@#'$)'=4)1#('

)(*0(+"#"')$#$'=)"$0(#$-'(0'$)'%"E('*0('4(0$'26%,'"2'O4)'$0(';&#'

*4#"+#' =#"+)' O4)' )(' K$=#@#8' K$' 4(#' *0(+"#1%**%?(' 1)&' K$+#10'

2"#$%&)@0G'1)*&#"#"')&')$=#@0&'*0/0'="%0"%1#1')('&#')($)@#(M#'B'

1)/#(1#"'="05)$%0(#&)$'=)"0'(0')&)F#"' &#' ")/4()"#*%?(G-'0=%(#'

H%(A

BCCCA2D8-0.A/+@A5E:-81-:+AF

!"

G25-/+*:+5/+@5+58*0@20*+58-*HI*-J+K58+:2).25-J0*@-*5<=25L50@8+..M)

,2D5/+@8-*-*5-52@0I*-NO+52.8-9P+D-5:+58-..-:+5/+@5-5-1=-D58+*<=2

BEF5 +.52.8-9PQ0.52*-@[email protected]*28-*-:+.59-.5:L/-:-.5:251*091-525

<=-*291-A

BRF5 -912.5+.52.8-9PQ0.5:+@09-,-@[email protected]:[email protected]

BSF5 -912.5+.52.8-9PQ0.59O+58-..-,-@5J+@2A

BGF5 +.52.8-9PQ0.52*-@5@29+.58*28-*-:+.59-.5:L/-:-.5:251*091-525

<=-*291-A

B$F5 -912.5+.52.8-9PQ0.5109P-@[email protected]*2/=*.+.525@29+.592/2..0:-:2.A

!#

T5 /+92/1+*5 =)"05 9-5 J*-.25 <0' +)(1"E' )/=&)0-' =)"0' (0' +%)()'

A#/2")K5:2.1-/-:-59+58*0@20*+58-*HI*-J+K5278*2..-

BEF5 -:,2*.0:-:2A

BRF5 .0@=D1-920:-:2A

BSF5 /+9/+@01U9/0-A

BGF5 /++82*-NO+A

B$F5 /+9/+*:U9/0-A

!$

G25-/+*:+5/+@5+5.2I=9:+58-*HI*-J+K58+:2).25-J0*@-*5<=2

BEF5 -5 $.8-9P-5 0@82:25 <=25 .2=.5 P-V01-912.5 2@0I*2@5 -5 +=1*+.5

8-M.2.A

BRF5 -5:2@-9:-5:258*+J0..0+9-0.5:-5$.8-9P-58+:25.2*5-V.+*,0:-5

82D+512/0:+509:=.1*0-D52.8-9P+DA

BSF5 -5$.8-9P-5:2.2W-5<=25P-V01-912.5:25+=1*+.58-M.2.K5/+@+5+.5

:-5E@L*0/-56-109-K58+*5272@8D+K50@0I*2@58-*-5-5$=*+8-5-5

J0@5:25-V.+*,2*5-5:2@-9:-52.8-9P+D-58+*58*+J0..0+9-0.A

BGF5 +5.0.12@-52:=/-10,+52.8-9P+D5L5=@5:+.5@2DP+*2.5:+5@=9:+5

25I2*-58*+J0..0+9-0.5<=25.O+5-V.+*,0:+.59+58*Q8*0+58-M.A

B$F5 -5$.8-9P-5:2.2W-5<=25.2=.5P-V01-912.52@0I*2@5-5+=1*+.58-M)

.2.5<=258+..-@5-V.+*,2*5.=-5:2@-9:-5:258*+J0..0+9-0.A

!%

E.58*28+.0N>2.51)$1)%25A#$+#K%:2.1-/-:-.59+5.2I=9:+58-*HI*-J+K5

278*2..-@K5*2.82/10,-@2912

BEF5 +*0I2@525/+9109=0:-:2A

BRF5 +*0I2@525/+9:0NO+A

BSF5 8*09/M80+525J0@A

BGF5 8*09/M80+525/+9109=0:-:2A

B$F5 8*09/M80+525/+9:0NO+A

!&

T5/+92/1+*5#'+"#FQ$K%:2.1-/-:+59+512*/20*+58-*HI*-J+K58+:2*0-5.2*5

.=V.101=M:+58+*

BEF5 :251*-,L.A

BRF5 8+*5@2:0+A

BSF5 :2D5*2,L.A

BGF5 -D5*2,L.A

B$F5 295@2:0+A

Resolução:

“Através” significa em português, “por meio de” e é sinônimo, portanto, do item B.Questão voltada para o conhecimento sobre conectores.

Alternativa B

!" #$%&''(!)(('*#+,-.%/0+12.*#.+234

!"

56 7,+8.6 /19:;<.+6 =.6 7+./36!"#$ %&$ '#($ )#*&#($ %&$+,"$ &($ -."&*$

'#($ /.(#($ 01/,'&($#$ '.($ &(-#2.'&($34&$34,&*#"$ ,*(&$#$ )*#56($%&$

#/4&*%.($/."$'.($-#7(&($%&$%&(),".6>?

@5A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.<63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@IA6 B9.6 2.+3.6 =36 #196 3/6 C,93+6 <.6 0,/.6 7D01<6 .6 <,6 3/C.E,<6 F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@JA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@KA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@%A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.6<,63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

!!

L/623+8,/6#2#%&!36*&).(M6=3/2.0.=,/69,623+031+,6C.+D:+.7,M6C,=3*

+1.86/3+6/;N/212;G=,/M6+3/C3021-.83923M6C,+

@5A$ .E3O.636=.E,/H

@IA$ .E,+.636:./2,/H

@JA$ .:+3:.636=3/.7G,/H

@KA$ .92.E.636=3++,0P3/H

@%A$ .839.Q.636:./2,/H

!#

563RC+3//S,6&"$-#*.M6=3/2.0.=.69,6F;.+2,6C.+D:+.7,M6/1:91710.

@5A6 =3/38C+3:.=,/H

@IA6 .C,/392.=,/H

@JA6 C39/1,91/2./H

@KA6 =1C<,8.=,/H

@%A6 +38;93+.=,/H

!$

49=1F;36.6.71+8.TS,6F;363/2D6=36.0,+=,60,86,6F;192,6C.+D:+.7,6

=,623R2,H

@5A6 L/63/C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<M638*

N,+.6.63<3-.TS,6=,/6/.<D+1,/6=,/6C+,73//,+3/636,639/19,6=,6

3/C.9P,<6/3O.86C+1,+1=.=3/H

@IA6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=,6=3/38C+3:,H

@JA6 %8N,+.6,6I+./1<6 9303//1236=36!V6(((6C+,73//,+3/6=36 3/C.*

9P,<M6,639/19,6=,61=1,8.69S,6>60,9/1=3+.=,6;8.6C+1,+1=.=3H

@KA6 L/6 3/C.9PU1/6 9S,6 /36 1923+3//.86 C,+6 2+.N.<P.+6 9,6 I+./1<M6

83/8,6:.9P.9=,6F;.2+,6-3Q3/68.1/6=,6F;369.6%/C.9P.H

@%A6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=.6N.1R.6+38;93+.TS,6C+,71//1,9.<H

#%

W;.<6C.<.-+.6C+3/392369,623R2,6/3+-36=36/19X918,6C.+.6(4&'%.(M6

9,6F;192,6C.+D:+.7,Y

@5A6 Z,+8.01U9H

@IA6 [38;93+.01U9H

@JA6 %81:+.01U9H

@KA6 \3:1/<.01U9H

@%A6 J;.<1710.01U9H

Resolução:

Para responder, o candidato deveria dominar, principalmente o uso dos artigos em espanhol e o critério de número (singular/plural).

Alternativa D

!" #$%&''(!)(('*#+,-.%/0+12.*#.+234

!"

56 7,+8.6 /19:;<.+6 =.6 7+./36!"#$ %&$ '#($ )#*&#($ %&$+,"$ &($ -."&*$

'#($ /.(#($ 01/,'&($#$ '.($ &(-#2.'&($34&$34,&*#"$ ,*(&$#$ )*#56($%&$

#/4&*%.($/."$'.($-#7(&($%&$%&(),".6>?

@5A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.<63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@IA6 B9.6 2.+3.6 =36 #196 3/6 C,93+6 <.6 0,/.6 7D01<6 .6 <,6 3/C.E,<6 F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@JA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@KA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@%A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.6<,63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

!!

L/623+8,/6#2#%&!36*&).(M6=3/2.0.=,/69,623+031+,6C.+D:+.7,M6C,=3*

+1.86/3+6/;N/212;G=,/M6+3/C3021-.83923M6C,+

@5A$ .E3O.636=.E,/H

@IA$ .E,+.636:./2,/H

@JA$ .:+3:.636=3/.7G,/H

@KA$ .92.E.636=3++,0P3/H

@%A$ .839.Q.636:./2,/H

!#

563RC+3//S,6&"$-#*.M6=3/2.0.=.69,6F;.+2,6C.+D:+.7,M6/1:91710.

@5A6 =3/38C+3:.=,/H

@IA6 .C,/392.=,/H

@JA6 C39/1,91/2./H

@KA6 =1C<,8.=,/H

@%A6 +38;93+.=,/H

!$

49=1F;36.6.71+8.TS,6F;363/2D6=36.0,+=,60,86,6F;192,6C.+D:+.7,6

=,623R2,H

@5A6 L/63/C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<M638*

N,+.6.63<3-.TS,6=,/6/.<D+1,/6=,/6C+,73//,+3/636,639/19,6=,6

3/C.9P,<6/3O.86C+1,+1=.=3/H

@IA6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=,6=3/38C+3:,H

@JA6 %8N,+.6,6I+./1<6 9303//1236=36!V6(((6C+,73//,+3/6=36 3/C.*

9P,<M6,639/19,6=,61=1,8.69S,6>60,9/1=3+.=,6;8.6C+1,+1=.=3H

@KA6 L/6 3/C.9PU1/6 9S,6 /36 1923+3//.86 C,+6 2+.N.<P.+6 9,6 I+./1<M6

83/8,6:.9P.9=,6F;.2+,6-3Q3/68.1/6=,6F;369.6%/C.9P.H

@%A6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=.6N.1R.6+38;93+.TS,6C+,71//1,9.<H

#%

W;.<6C.<.-+.6C+3/392369,623R2,6/3+-36=36/19X918,6C.+.6(4&'%.(M6

9,6F;192,6C.+D:+.7,Y

@5A6 Z,+8.01U9H

@IA6 [38;93+.01U9H

@JA6 %81:+.01U9H

@KA6 \3:1/<.01U9H

@%A6 J;.<1710.01U9H!" #$%&''(!)(('*#+,-.%/0+12.*#.+234

!"

56 7,+8.6 /19:;<.+6 =.6 7+./36!"#$ %&$ '#($ )#*&#($ %&$+,"$ &($ -."&*$

'#($ /.(#($ 01/,'&($#$ '.($ &(-#2.'&($34&$34,&*#"$ ,*(&$#$ )*#56($%&$

#/4&*%.($/."$'.($-#7(&($%&$%&(),".6>?

@5A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.<63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@IA6 B9.6 2.+3.6 =36 #196 3/6 C,93+6 <.6 0,/.6 7D01<6 .6 <,6 3/C.E,<6 F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@JA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@KA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@%A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.6<,63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

!!

L/623+8,/6#2#%&!36*&).(M6=3/2.0.=,/69,623+031+,6C.+D:+.7,M6C,=3*

+1.86/3+6/;N/212;G=,/M6+3/C3021-.83923M6C,+

@5A$ .E3O.636=.E,/H

@IA$ .E,+.636:./2,/H

@JA$ .:+3:.636=3/.7G,/H

@KA$ .92.E.636=3++,0P3/H

@%A$ .839.Q.636:./2,/H

!#

563RC+3//S,6&"$-#*.M6=3/2.0.=.69,6F;.+2,6C.+D:+.7,M6/1:91710.

@5A6 =3/38C+3:.=,/H

@IA6 .C,/392.=,/H

@JA6 C39/1,91/2./H

@KA6 =1C<,8.=,/H

@%A6 +38;93+.=,/H

!$

49=1F;36.6.71+8.TS,6F;363/2D6=36.0,+=,60,86,6F;192,6C.+D:+.7,6

=,623R2,H

@5A6 L/63/C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<M638*

N,+.6.63<3-.TS,6=,/6/.<D+1,/6=,/6C+,73//,+3/636,639/19,6=,6

3/C.9P,<6/3O.86C+1,+1=.=3/H

@IA6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=,6=3/38C+3:,H

@JA6 %8N,+.6,6I+./1<6 9303//1236=36!V6(((6C+,73//,+3/6=36 3/C.*

9P,<M6,639/19,6=,61=1,8.69S,6>60,9/1=3+.=,6;8.6C+1,+1=.=3H

@KA6 L/6 3/C.9PU1/6 9S,6 /36 1923+3//.86 C,+6 2+.N.<P.+6 9,6 I+./1<M6

83/8,6:.9P.9=,6F;.2+,6-3Q3/68.1/6=,6F;369.6%/C.9P.H

@%A6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=.6N.1R.6+38;93+.TS,6C+,71//1,9.<H

#%

W;.<6C.<.-+.6C+3/392369,623R2,6/3+-36=36/19X918,6C.+.6(4&'%.(M6

9,6F;192,6C.+D:+.7,Y

@5A6 Z,+8.01U9H

@IA6 [38;93+.01U9H

@JA6 %81:+.01U9H

@KA6 \3:1/<.01U9H

@%A6 J;.<1710.01U9H

Resolução:

Questão voltada ao conhecimento de vocabulário em espanhol. Os vocábulos corretos são respectivamente sinônimos dos vocábulos do enunciado.

Alternativa C

!" #$%&''(!)(('*#+,-.%/0+12.*#.+234

!"

56 7,+8.6 /19:;<.+6 =.6 7+./36!"#$ %&$ '#($ )#*&#($ %&$+,"$ &($ -."&*$

'#($ /.(#($ 01/,'&($#$ '.($ &(-#2.'&($34&$34,&*#"$ ,*(&$#$ )*#56($%&$

#/4&*%.($/."$'.($-#7(&($%&$%&(),".6>?

@5A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.<63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@IA6 B9.6 2.+3.6 =36 #196 3/6 C,93+6 <.6 0,/.6 7D01<6 .6 <,6 3/C.E,<6 F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@JA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@KA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@%A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.6<,63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

!!

L/623+8,/6#2#%&!36*&).(M6=3/2.0.=,/69,623+031+,6C.+D:+.7,M6C,=3*

+1.86/3+6/;N/212;G=,/M6+3/C3021-.83923M6C,+

@5A$ .E3O.636=.E,/H

@IA$ .E,+.636:./2,/H

@JA$ .:+3:.636=3/.7G,/H

@KA$ .92.E.636=3++,0P3/H

@%A$ .839.Q.636:./2,/H

!#

563RC+3//S,6&"$-#*.M6=3/2.0.=.69,6F;.+2,6C.+D:+.7,M6/1:91710.

@5A6 =3/38C+3:.=,/H

@IA6 .C,/392.=,/H

@JA6 C39/1,91/2./H

@KA6 =1C<,8.=,/H

@%A6 +38;93+.=,/H

!$

49=1F;36.6.71+8.TS,6F;363/2D6=36.0,+=,60,86,6F;192,6C.+D:+.7,6

=,623R2,H

@5A6 L/63/C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<M638*

N,+.6.63<3-.TS,6=,/6/.<D+1,/6=,/6C+,73//,+3/636,639/19,6=,6

3/C.9P,<6/3O.86C+1,+1=.=3/H

@IA6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=,6=3/38C+3:,H

@JA6 %8N,+.6,6I+./1<6 9303//1236=36!V6(((6C+,73//,+3/6=36 3/C.*

9P,<M6,639/19,6=,61=1,8.69S,6>60,9/1=3+.=,6;8.6C+1,+1=.=3H

@KA6 L/6 3/C.9PU1/6 9S,6 /36 1923+3//.86 C,+6 2+.N.<P.+6 9,6 I+./1<M6

83/8,6:.9P.9=,6F;.2+,6-3Q3/68.1/6=,6F;369.6%/C.9P.H

@%A6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=.6N.1R.6+38;93+.TS,6C+,71//1,9.<H

#%

W;.<6C.<.-+.6C+3/392369,623R2,6/3+-36=36/19X918,6C.+.6(4&'%.(M6

9,6F;192,6C.+D:+.7,Y

@5A6 Z,+8.01U9H

@IA6 [38;93+.01U9H

@JA6 %81:+.01U9H

@KA6 \3:1/<.01U9H

@%A6 J;.<1710.01U9H

Resolução:

Questão de simples tradução, exigindo portanto, conhecimento de vocabulário.

Alternativa A

!" #$%&''(!)(('*#+,-.%/0+12.*#.+234

!"

56 7,+8.6 /19:;<.+6 =.6 7+./36!"#$ %&$ '#($ )#*&#($ %&$+,"$ &($ -."&*$

'#($ /.(#($ 01/,'&($#$ '.($ &(-#2.'&($34&$34,&*#"$ ,*(&$#$ )*#56($%&$

#/4&*%.($/."$'.($-#7(&($%&$%&(),".6>?

@5A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.<63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@IA6 B9.6 2.+3.6 =36 #196 3/6 C,93+6 <.6 0,/.6 7D01<6 .6 <,6 3/C.E,<6 F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@JA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@KA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@%A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.6<,63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

!!

L/623+8,/6#2#%&!36*&).(M6=3/2.0.=,/69,623+031+,6C.+D:+.7,M6C,=3*

+1.86/3+6/;N/212;G=,/M6+3/C3021-.83923M6C,+

@5A$ .E3O.636=.E,/H

@IA$ .E,+.636:./2,/H

@JA$ .:+3:.636=3/.7G,/H

@KA$ .92.E.636=3++,0P3/H

@%A$ .839.Q.636:./2,/H

!#

563RC+3//S,6&"$-#*.M6=3/2.0.=.69,6F;.+2,6C.+D:+.7,M6/1:91710.

@5A6 =3/38C+3:.=,/H

@IA6 .C,/392.=,/H

@JA6 C39/1,91/2./H

@KA6 =1C<,8.=,/H

@%A6 +38;93+.=,/H

!$

49=1F;36.6.71+8.TS,6F;363/2D6=36.0,+=,60,86,6F;192,6C.+D:+.7,6

=,623R2,H

@5A6 L/63/C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<M638*

N,+.6.63<3-.TS,6=,/6/.<D+1,/6=,/6C+,73//,+3/636,639/19,6=,6

3/C.9P,<6/3O.86C+1,+1=.=3/H

@IA6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=,6=3/38C+3:,H

@JA6 %8N,+.6,6I+./1<6 9303//1236=36!V6(((6C+,73//,+3/6=36 3/C.*

9P,<M6,639/19,6=,61=1,8.69S,6>60,9/1=3+.=,6;8.6C+1,+1=.=3H

@KA6 L/6 3/C.9PU1/6 9S,6 /36 1923+3//.86 C,+6 2+.N.<P.+6 9,6 I+./1<M6

83/8,6:.9P.9=,6F;.2+,6-3Q3/68.1/6=,6F;369.6%/C.9P.H

@%A6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=.6N.1R.6+38;93+.TS,6C+,71//1,9.<H

#%

W;.<6C.<.-+.6C+3/392369,623R2,6/3+-36=36/19X918,6C.+.6(4&'%.(M6

9,6F;192,6C.+D:+.7,Y

@5A6 Z,+8.01U9H

@IA6 [38;93+.01U9H

@JA6 %81:+.01U9H

@KA6 \3:1/<.01U9H

@%A6 J;.<1710.01U9H

Resolução

Questão de leitura e interpretação. A resposta depende apenas de domínio linguístico básicos.

Alternativa E

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

26

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Plac

a

Plac

a

Tote

m

!" #$%&''(!)(('*#+,-.%/0+12.*#.+234

!"

56 7,+8.6 /19:;<.+6 =.6 7+./36!"#$ %&$ '#($ )#*&#($ %&$+,"$ &($ -."&*$

'#($ /.(#($ 01/,'&($#$ '.($ &(-#2.'&($34&$34,&*#"$ ,*(&$#$ )*#56($%&$

#/4&*%.($/."$'.($-#7(&($%&$%&(),".6>?

@5A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.<63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@IA6 B9.6 2.+3.6 =36 #196 3/6 C,93+6 <.6 0,/.6 7D01<6 .6 <,6 3/C.E,<6 F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@JA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,96<,6C.G/6=36=3/219,H

@KA6 B9.62.+3.6=36#1963/6C,93+6<.60,/.67D01<6.<63/C.E,<6F;36F;13+.6

1+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

@%A6 B9.62.+3.6=36#1963/6C,93+6<./60,/./67D01<3/6.6<,63/C.E,<6F;36

F;13+.61+/36.62+.->/6=36.0;3+=,60,963<6C.G/6=36=3/219,H

!!

L/623+8,/6#2#%&!36*&).(M6=3/2.0.=,/69,623+031+,6C.+D:+.7,M6C,=3*

+1.86/3+6/;N/212;G=,/M6+3/C3021-.83923M6C,+

@5A$ .E3O.636=.E,/H

@IA$ .E,+.636:./2,/H

@JA$ .:+3:.636=3/.7G,/H

@KA$ .92.E.636=3++,0P3/H

@%A$ .839.Q.636:./2,/H

!#

563RC+3//S,6&"$-#*.M6=3/2.0.=.69,6F;.+2,6C.+D:+.7,M6/1:91710.

@5A6 =3/38C+3:.=,/H

@IA6 .C,/392.=,/H

@JA6 C39/1,91/2./H

@KA6 =1C<,8.=,/H

@%A6 +38;93+.=,/H

!$

49=1F;36.6.71+8.TS,6F;363/2D6=36.0,+=,60,86,6F;192,6C.+D:+.7,6

=,623R2,H

@5A6 L/63/C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<M638*

N,+.6.63<3-.TS,6=,/6/.<D+1,/6=,/6C+,73//,+3/636,639/19,6=,6

3/C.9P,<6/3O.86C+1,+1=.=3/H

@IA6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=,6=3/38C+3:,H

@JA6 %8N,+.6,6I+./1<6 9303//1236=36!V6(((6C+,73//,+3/6=36 3/C.*

9P,<M6,639/19,6=,61=1,8.69S,6>60,9/1=3+.=,6;8.6C+1,+1=.=3H

@KA6 L/6 3/C.9PU1/6 9S,6 /36 1923+3//.86 C,+6 2+.N.<P.+6 9,6 I+./1<M6

83/8,6:.9P.9=,6F;.2+,6-3Q3/68.1/6=,6F;369.6%/C.9P.H

@%A6 %8N,+.6,6I+./1<69303//1236=36C+,73//,+3/6=363/C.9P,<M6,/63/*

C.9PU1/69S,6/361923+3//.86C,+62+.N.<P.+69,6I+./1<63867;9TS,6

=.6N.1R.6+38;93+.TS,6C+,71//1,9.<H

#%

W;.<6C.<.-+.6C+3/392369,623R2,6/3+-36=36/19X918,6C.+.6(4&'%.(M6

9,6F;192,6C.+D:+.7,Y

@5A6 Z,+8.01U9H

@IA6 [38;93+.01U9H

@JA6 %81:+.01U9H

@KA6 \3:1/<.01U9H

@%A6 J;.<1710.01U9H

Resolução:

A resposta, óbvia, dependeu apenas do conhecimento léxico do candidato. A tradução da palavra em questão para o português é “salário”.

Alternativa B

RESOLUÇÃO COMENTADA DA PROVA ESCRITA (PARTE I) DO CONCURSO PÚBLICO PARA A ADMISSÃO AO BACHARELADO EM CIÊNCIAS POLICIAIS DE SEGURANÇA E ORDEM PÚBLICA

(CURSO DE FORMAÇÃO DE OFICIAIS DA POLÍCIA MILITAR DO ESTADO DE SÃO PAULO - CFO),REALIZADA EM 11 DE SETEMBRO DE 2011

27

EQUIPE RESPONSÁVEL PELA RESOLUÇÃO COMENTADA

CIÊNCIAS HUMANAS

HISTÓRIA

PROF. ALEXANDRE CLARO MENDESPROF. SAMUEL ROBES LOUREIRO

FILOSOFIA

PROF. ALEXANDRE CLARO MENDES

SOCIOLOGIA

PROF. EDUARDO COELHO MORGADO REZENDE

LINGUAGEM, CÓDIGOS E SUAS TECNOLOGIAS

LÍNGUA PORTUGUESA

PROF. ANDRÉ VALENTEPROF. ROMEU AGOSTINHO SANTOMAURO

LÍNGUA ESPANHOLA

PROF. ANDRÉ VALENTE

LÍNGUA INGLESA

PROF. MOACIR LUIZ DA SILVA PRUDÊNCIO

CIÊNCIAS DA NATUREZA E MATEMÁTICA

MATEMÁTICA

PROF. ARMÊNIO DOS ANJOS MARTINSPROF. AUGUSTO KUDOPROF. LEO GROSZ BARUFALDIPROF. PEDRO TADEU BATISTA

COORDENAÇÃO PEDAGÓGICA

PROF. LEO GROSZ BARUFALDI

DIREÇÃO

ANDERSON DURYNEK