nts assessments - rising stars
TRANSCRIPT
National Test-style Standardised Assessments: MathematicsThis document contains the mark schemes and teacher guidance for the NTS Spring Assessments [published September 2019].
The free teacher guidance provides what you need to administer and mark the Spring tests.
It contains the:
❯ curriculum maps of content covered in the tests
❯ mark schemes and marking guidance for the tests.
More extensive teacher guidance will be provided in the full NTS Manual, which will be published in
Spring 2020, together with the NTS tests for Summer. The NTS Manual will also include the following
information:
❯ raw score to standardised score conversion tables
❯ strand level performance information
❯ age-standardised scores, mathematics ages and the NTS Scale for predicting progress
❯ further information about interpreting and analysing results
❯ technical information about the standardisation
❯ answers and mark schemes for all NTS tests for all terms.
The final manual will take the form of an online PDF, which will be free to download for all
NTS customers.
To access your copy as soon as it publishes, go to risingstars-uk.com/ntsmarkschemes.
NTS Assessments
© Hodder and Stoughton Limited 2019
First published in 2019 by
RS Assessment from Hodder Education, part of the Hodder Education Group
An Hachette UK Company
Carmelite House
50 Victoria Embankment
London
EC4Y 0DZ
www.rsassessment.com
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Contents © Hodder & Stoughton Limited 2019
1 Introduction 3
Why use NTS Assessments? 3
NTS Mathematics: Spring curriculum maps 4
2 Administering NTS Assessments 18
When to test 18
Group size 18
Timing 18
Preparation 18
Administering the test 20
3 Answers and mark schemes 21
Marking the answers 21
Profiling performance by strand 21
Transcripts for Key Stage 1 21
Answers and mark schemes: NTS Year 1 Spring 24
Answers and mark schemes: NTS Year 2 Spring 35
Answers and mark schemes: NTS Year 3 Spring 49
Answers and mark schemes: NTS Year 4 Spring 70
Answers and mark schemes: NTS Year 5 Spring 96
Answers and mark schemes: NTS Year 6 Spring 124
Contents
NTS Assessments
3© Hodder & Stoughton Limited 2019 1 Introduction
NTS Assessments (National Test-style Standardised Assessments) have been written to enable schools
to monitor progress in Mathematics and Reading from Years 1 to 6. The tests are intended to be
used termly, around November, March and June – although each individual school will decide how the
assessments best fit into their assessment plans. The tests will provide reliable predictive and diagnostic
information and outcomes, and are designed for whole-class use, with pupils who will be entered for the
National Tests.
The tests have been written by SATs authors, and follow the National Test framework. Autumn and
Spring tests are shorter than the full SATs tests, as schools told us that they don’t necessarily have time
to administer a full SATs paper every term. The shorter papers in the earlier terms allow children to build
familiarity with the test content, format and demand, ready for a full-length paper in the Summer. The
Summer test mirrors the test framework for that key stage exactly, meaning that teachers quickly gain
an idea of how their children will manage the demands of questions on curriculum content for their year
group under challenging timings.
Tests increase in demand every term, reflecting the progress children will be making in class. Teachers
may use the curriculum maps (see page 4) to quickly understand what content is covered in each
test, checking before a teaching period begins that the relevant content will be covered before the
assessment is administered and ensuring a valid test.
NTS Assessments were all standardised on a sample of over 1000 children per paper; close to 7000
children have been involved in the trial altogether, which took place during the 2018-19 academic year.
Our sample schools were carefully chosen to ensure that we standardised the tests on a nationally
representative selection of schools. We looked carefully at geographical representation, and also at
attainment and disadvantage, to ensure that the results would not be skewed in any way and that our
scoring takes all kinds of schools and backgrounds into account.
The tests are simple to administer and straightforward to mark.
See page 18 for a breakdown of the tests and the times we suggest allocating for each.
Why use NTS Assessments?
Using NTS Assessments provides many benefits.
❯ NTS tests are written to the National Test framework, meaning that you are able to monitor progress
and familiarise children with SATs papers in a single termly test.
❯ NTS provides three carefully designed tests for each year. This enables you to follow the progress of
your pupils from term-to-term, as well as from year-to-year throughout Key Stages 1 and 2.
❯ Scores have been calibrated onto the NTS Scale to allow you to see small increments of progress
from term-to-term and to compare progress against national norms. The NTS Scale was originally
developed as the Hodder Scale for our PiRA, PUMA and GAPS tests to provide a decimal scale that
has proved to be an extremely useful measure to monitor and predict small increments of progress
from term-to-term. The NTS Scale is now an independent progress measure.
❯ NTS test scores help you to set appropriate and meaningful targets for your pupils and to monitor
pupils’ progress.
1 Introduction
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1 Introduction © Hodder & Stoughton Limited 2019
❯ NTS tests can provide you with an external reference for end-of-terms and end-of-years, so that you
may report your value-added term-by-term, as well as monitoring to ensure pupils are on target.
❯ NTS Assessments provide diagnostic information both about the individual pupil’s performance in
particular areas and through the use of data management software (MARK: My Assessment and
Reporting Kit), about groups of pupils such as class groups. This allows teachers to provide tailored
support so that all pupils can achieve the target results.
❯ NTS’s diagnostic capability allows you to investigate the strengths and weaknesses in your pupils’
mathematics skills. To enable you to use the information gained in this formative way, total scores on
the tests can be broken down into strands, giving a useful profile that reflects the content domains of
the National Tests.
The strands used in NTS Mathematics are:
Content domain reference
Number (N)Calculations (C)Fractions, decimals and percentages (F)Measurement (M)Geometry – properties of shapes (G)Geometry – position and direction (P)Statistics (S)Ratio and proportion (R)Algebra (A)
The balance of the questions assessing these strands reflects the balance of content domains in the
National Tests, and remains fairly constant as the tests become more demanding, helping you to pinpoint
where pupils may be under-performing or making above average progress.
NTS Mathematics: Spring curriculum mapsCurriculum maps outline the content covered in every test, enabling you to ensure that relevant content
has been taught by the time the students take the tests.
These should be used as a quick guide at the beginning of a period of teaching and learning, to ensure
that lessons cover relevant content and therefore enable a valid test.
Year 1: Spring
Strand Content Assessed
Number (N) Prior Learning:n/a
From Year 1 curriculum:1N1a - count to and across 100, forward and backwards, beginning with 0 or 1, or from any given number1N1b - count in multiples of twos, fives and tens 1N2b - given a number, identify one more and one less 1N2c - read and write numbers from 1 to 20 in numerals and words 1N4 - identify and represent numbers using objects and pictorial representations including the number line, and use the language of: equal to, more than, less than (fewer), most and least
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5© Hodder & Stoughton Limited 2019 1 Introduction
Strand Content Assessed
Calculation (C) Prior Learning:n/a
From Year 1 curriculum:1C2a - add and subtract one–digit and two–digit numbers to 20, including zero.1C2b - read, write and interpret mathematical statements involving addition (+), subtraction (–) and equals (=) signs 1C4 - solve one–step problems that involve addition and subtraction, using concrete objects and pictorial representations, and missing number problems such as 7 = [ ] – 9
Fractions (F) -
Measurement (M)
Prior Learning:n/a
From Year 1 curriculum:1M1 - compare, describe and solve practical problems for:
lengths and heights [e.g. long / short, longer / shorter, tall / short, double / half] mass / weight [e.g. heavy / light, heavier than, lighter than] capacity and volume [e.g. full / empty, more than, less than, half, half full, quarter] time [e.g. quicker, slower, earlier, later]
1M2 - measure and begin to record the following: lengths and heights mass / weight capacity and volume time (hours, minutes, seconds)
Geometry – properties of
shapes (G)
Prior Learning:n/a
From Year 1 curriculum:1G1a - recognise and name common 2–D shapes [e.g. rectangles (including squares), circles and triangles]1G1b - recognise and name common 3–D shapes [e.g. cuboids (including cubes), pyramids and spheres]
Geometry – position and direction (P)
-
Statistics (S) -
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Year 2: Spring
Strand Content Assessed
Number (N) Prior Learning from Year 1 curriculum:1N1a - count to and across 100, forward and backwards, beginning with 0 or 1, or from any given number1N1b - count in multiples of twos, fives and tens1N2b - given a number, identify one more and one less
From Year 2 curriculum:2N2b - compare and order numbers from 0 up to 100; use <, > and = signs2N4 - identify, represent and estimate numbers using different representations, including the number line
Calculation (C) Prior Learning from Year 1 curriculum:1C2a - add and subtract one–digit and two–digit numbers to 20, including zero1C4 - solve one–step problems that involve addition and subtraction, using concrete objects and pictorial representations, and missing number problems such as 7 = [ ] – 9
From Year 2 curriculum:2C2a - add and subtract numbers mentally, including:
a two–digit number and ones a two–digit number and tens two two–digit numbers adding three one–digit numbers
2C4 - solve problems with addition and subtraction: using concrete objects and pictorial representations, including those involving numbers, quantities and measures applying their increasing knowledge of mental and written methods
2C6 - recall and use multiplication and division facts for the 2, 5 and 10 multiplication tables, including recognising odd and even numbers2C8 - solve problems involving multiplication and division, using materials, arrays, repeated addition, mental methods, and multiplication and division facts, including problems in contexts
Fractions (F) Prior Learning from Year 1 curriculum:1F1a - recognise, find and name a half as one of two equal parts of an object, shape or quantity 1F1b - recognise, find and name a quarter as one of four equal parts of an object, shape or quantity
From Year 2 curriculum:2F1a - recognise, find, name and write fractions 1/3, 1/4, 2/4 and 3/4 of a length, shape, set of objects or quantity 2F1b - write simple fractions [e.g. 1/2 of 6 = 3]
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Strand Content Assessed
Measurement (M)
Prior Learning from Year 1 curriculum:1M2 - measure and begin to record the following:
lengths and heights mass / weight capacity and volume time (hours, minutes, seconds)
1M3 - recognise and know the value of different denominations of coins and notes
From Year 2 curriculum:2M1 - compare and order lengths, mass, volume / capacity and record the results using >, < and = 2M2 - choose and use appropriate standard units to estimate and measure length / height in any direction (m / cm); mass (kg / g); temperature (°C); capacity (litres / ml) to the nearest appropriate unit using rulers, scales, thermometers and measuring vessels 2M3a - recognise and use symbols for pounds (£) and pence (p); combine amounts to make a particular value.2M9 - solve simple problems in a practical context involving addition and subtraction of money of the same unit, including giving change
Geometry – properties of
shapes (G)
Prior Learning:n/a
From Year 2 curriculum:2G2b - identify and describe the properties of 3–D shapes including the number of edges, vertices and faces
Geometry – position and direction (P)
-
Statistics (S) Prior Learning:n/a
From Year 2 curriculum:2S2b - ask and answer questions about totalling and comparing categorical data
Year 3: Spring
Strand Content Assessed
Number (N) Prior Learning from Years 1 and 2 curricula:1N2b - given a number, identify one more and one less 1N2c - read and write numbers from 1 to 20 in numerals and words 1N4 - identify and represent numbers using objects and pictorial representations including the number line, and use the language of: equal to, more than, less than (fewer), most and least 2N1 - count in steps of 2, 3 and 5, from 0, and in tens from any number, forward or backward 2N2b - compare and order numbers from 0 up to 100; use <, > and = signs 2N3 - recognise the place value of each digit in a two–digit number (tens and ones)
From Year 3 curriculum:3N2b - find 10 or 100 more or less than a given number
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Strand Content Assessed
Calculation (C) Prior Learning from Years 1 and 2 curricula:1C2a - add and subtract one–digit and two–digit numbers to 20, including zero1C4 - solve one–step problems that involve addition and subtraction, using concrete objects and pictorial representations, and missing number problems such as 7 = [ ] – 92C2a - add and subtract numbers mentally, including:
a two-digit number and onesa two-digit number and tenstwo two-digit numbersadding three one-digit numbers
2C6 - recall and use multiplication and division facts for the 2, 5 and 10 multiplication tables, including recognising odd and even numbers2C8 - solve problems involving multiplication and division, using materials, arrays, repeated addition, mental methods, and multiplication and division facts, including problems in contexts
From Year 3 curriculum:3C2 - add and subtract numbers with up to three digits, using formal written methods of columnar addition and subtraction3C6 - recall and use multiplication and division facts for the 3, 4 and 8 multiplication tables3C7 - write and calculate mathematical statements for multiplication and division using the multiplication tables that pupils know, including for two–digit numbers times one–digit numbers, using mental and progressing to formal written methods 3C8 - solve problems, including missing number problems, involving multiplication and division, including integer scaling problems and correspondence problems in which n objects are connected to m objects
Fractions, decimals and percentages
(FDP)
Prior Learning from Years 1 and 2 curricula:1F1a - recognise, find and name a half as one of two equal parts of an object, shape or quantity 1F1b - recognise, find and name a quarter as one of four equal parts of an object, shape or quantity 2F1a - recognise, find, name and write fractions 1/3, 1/4, 2/4 and 3/4 of a length, shape, set of objects or quantity 2F2 - recognise the equivalence of 2/4 and 1/2
From Year 3 curriculum:3F1a - count up and down in tenths; recognise that tenths arise from dividing an object into 10 equal parts and in dividing one–digit numbers or quantities by 103F1b - recognise, find and write fractions of a discrete set of objects: unit fractions and non–unit fractions with small denominators3F1c - recognise and use fractions as numbers: unit fractions and non–unit fractions with small denominators 3F2 - recognise and show, using diagrams, equivalent fractions with small denominators 3F3 - compare and order unit fractions and fractions with the same denominators
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© Hodder & Stoughton Limited 2019 1 Introduction
Strand Content Assessed
Measurement (M)
Prior Learning from Year 2 curriculum:2M1 - compare and order lengths, mass, volume / capacity and record the results using >, < and = 2M3a - recognise and use symbols for pounds (£) and pence (p); combine amounts to make a particular value
From Year 3 curriculum:3M2a - measure lengths (m / cm / mm)3M7 - measure the perimeter of simple 2–D shapes 3M9a - add and subtract amounts of money to give change, using both pounds (£) and pence (p) in practical contexts
Geometry – properties of
shapes (G)
Prior Learning from Years 1 and 2 curricula:1G1a - recognise and name common 2–D shapes [e.g. rectangles (including squares), circles and triangles] 1G1b - recognise and name common 3–D shapes [e.g. cuboids (including cubes), pyramids and spheres]2G3 - identify 2–D shapes on the surface of 3–D shapes, [e.g. a circle on a cylinder and a triangle on a pyramid]
From Year 3 curriculum:n/a
Geometry – position and direction (P)
Prior Learning from Year 1 curriculum:1P2 - describe position, directions and movement, including half, quarter and three–quarter turns
From Year 3 curriculum:n/a
Statistics (S) Prior Learning:n/a
From Year 3 curriculum:3S1 - interpret and present data using bar charts, pictograms and tables 3S2 - solve one–step and two–step questions [e.g. ‘How many more?’ and ‘How many fewer?’] using information presented in scaled bar charts, pictograms and tables
Year 4: Spring
Strand Content Assessed
Number (N) Prior Learning from Year 3 curriculum:3N1b - count from 0 in multiples of 4, 8, 50 and 100 3N2a - compare and order numbers up to 1000 / read and write numbers to 1000 in numerals and in words 3N2b - find 10 or 100 more or less than a given number
From Year 4 curriculum:4N1 - count in multiples of 6, 7, 9, 25 and 1,0004N2b - find 1,000 more or less than a given number
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Strand Content Assessed
Calculation (C) Prior Learning from Years 2 and 3 curricula:2C2a - add and subtract numbers mentally, including:
a two-digit number and onesa two-digit number and tenstwo two-digit numbersadding three one-digit numbers
2C4 - solve problems with addition and subtraction: using concrete objects and pictorial representations, including those involving numbers, quantities and measures 2C6 - recall and use multiplication and division facts for the 2, 5 and 10 multiplication tables, including recognising odd and even numbers3C2 - add and subtract numbers with up to three digits, using formal written methods of columnar addition and subtraction 3C4 - solve problems, including missing number problems, using number facts, place value, and more complex addition and subtraction 3C6 - recall and use multiplication and division facts for the 3, 4 and 8 multiplication tables 3C7 - write and calculate mathematical statements for multiplication and division using the multiplication tables that pupils know, including for two–digit numbers times one–digit numbers, using mental and progressing to formal written methods 3C8 - solve problems, including missing number problems, involving multiplication and division, including integer scaling problems and correspondence problems in which n objects are connected to m objects
From Year 4 curriculum:4C2 - add and subtract numbers with up to 4 digits using the formal written methods of columnar addition and subtraction where appropriate 4C6a - recall multiplication and division facts for multiplication tables up to 12 × 12 4C6b - use place value, known and derived facts to multiply and divide mentally, including: multiplying by 0 and 1; dividing by 1; multiplying together three numbers 4C6c - recognise and use factor pairs and commutativity in mental calculations4C7 - multiply two–digit and three–digit numbers by a one–digit number using formal written layout 4C8 - solve problems involving multiplying and adding, including using the distributive law to multiply two–digit numbers by one digit, integer scaling problems and harder correspondence problems such as n objects are connected to m objects
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© Hodder & Stoughton Limited 2019 1 Introduction
Strand Content Assessed
Fractions, decimals and percentages
(FDP)
Prior Learning from Years 2 and 3 curricula:2F1a - recognise, find, name and write fractions 1/3, 1/4, 2/4 and 3/4 of a length, shape, set of objects or quantity 2F2 - recognise the equivalence of 2/4 and 1/23F1b - recognise, find and write fractions of a discrete set of objects: unit fractions and non–unit fractions with small denominators3F2 - recognise and show, using diagrams, equivalent fractions with small denominators 3F4 - add and subtract fractions with the same denominator within one whole [e.g. 5/7 + 1/7 = 6/7]
From Year 4 Curriculum:4F1 - count up and down in hundredths; recognise that hundredths arise when dividing an object by a hundred and dividing tenths by ten 4F2 - recognise and show, using diagrams, families of common equivalent fractions4F4 - add and subtract fractions with the same denominator 4F9 - find the effect of dividing a one– or two–digit number by 10 and 100, identifying the value of the digits in the answer as ones, tenths and hundredths 4F10a - solve problems involving increasingly harder fractions to calculate quantities and fractions to divide quantities, including non–unit fractions where the answer is a whole number
Measurement (M)
Prior Learning from Years 2 and 3 curricula:2M3a - recognise and use symbols for pounds (£) and pence (p); combine amounts to make a particular value 3M1a - compare lengths (m / cm / mm) 3M4a - tell and write the time from an analogue clock; 12–hour3M9a - add and subtract amounts of money to give change, using both pounds (£) and pence (p) in practical contexts
From Year 4 Curriculum:4M5 - convert between different units of measurement [e.g. kilometre to metre; hour to minute]4M7a - measure and calculate the perimeter of a rectilinear figure (including squares) in centimetres and metres 4M7b - find the area of rectilinear shapes by counting squares
Geometry – properties of
shapes (G)
Prior Learning from Years 2 and 3 curricula:2G1b - compare and sort common 3–D shapes and everyday objects 2G3 - identify 2–D shapes on the surface of 3–D shapes, [e.g. a circle on a cylinder and a triangle on a pyramid] 3G2 - identify horizontal, vertical lines and pairs of perpendicular and parallel lines 3G3a - draw 2–D shapes
From Year 4 curriculum:n/a
Geometry – position and direction (P)
-
Statistics (S) Prior Learning from Year 2 curriculum:2S2a - ask and answer simple questions by counting the number of objects in each category and sorting the categories by quantity
From Year 4 curriculum:n/a
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Year 5: Spring
Strand Content Assessed
Number (N) Prior Learning from Years 3 and 4 curricula:3N2b - find 10 or 100 more or less than a given number 3N3 - recognise the place value of each digit in a three–digit number (hundreds, tens, ones) 4N1 - count in multiples of 6, 7, 9, 25 and 1,000 4N3b - read Roman numerals to 100 (I to C) and know that over time, the numeral system changed to include the concept of zero and place value 4N4b - round any number to the nearest 10, 100 or 1,000
From Year 5 curriculum:5N3b - read Roman numerals to 1,000 (M) and recognise years written in Roman numerals
Calculation (C) Prior Learning from Years 3 and 4 curricula:3C2 - add and subtract numbers with up to three digits, using formal written methods of columnar addition and subtraction 3C3 - estimate the answer to a calculation and use inverse operations to check answers 3C6 - recall and use multiplication and division facts for the 3, 4 and 8 multiplication tables 4C2 - add and subtract numbers with up to 4 digits using the formal written methods of columnar addition and subtraction where appropriate 4C4 - solve addition and subtraction two–step problems in contexts, deciding which operations and methods to use and why 4C6a - recall multiplication and division facts for multiplication tables up to 12 × 12 4C6b - use place value, known and derived facts to multiply and divide mentally, including: multiplying by 0 and 1; dividing by 1; multiplying together three numbers 4C7 - multiply two–digit and three–digit numbers by a one–digit number using formal written layout 4C8 - solve problems involving multiplying and adding, including using the distributive law to multiply two–digit numbers by one digit, integer scaling problems and harder correspondence problems such as n objects are connected to m objects
From Year 5 curriculum:5C2 - add and subtract whole numbers with more than 4 digits, including using formal written methods (columnar addition and subtraction)5C5d - recognise and use square numbers and cube numbers, and the notation for squared (2) and cubed (3)5C6b - multiply and divide whole numbers and those involving decimals by 10, 100 and 1,000 5C7a - multiply numbers up to 4 digits by a one–or two–digit number using a formal written method, including long multiplication for two–digit numbers 5C7b - divide numbers up to 4 digits by a one–digit number using the formal written method of short division and interpret remainders appropriately for the context 5C8a - solve problems involving multiplication and division including using their knowledge of factors and multiples, squares and cubes5C8b - solve problems involving addition, subtraction, multiplication and division and a combination of these, including understanding the meaning of the equals sign
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Strand Content Assessed
Fractions, decimals and percentages
(FDP)
Prior Learning from Years 3 and 4 curricula:3F2 - recognise and show, using diagrams, equivalent fractions with small denominators3F3 - compare and order unit fractions and fractions with the same denominators 3F4 - add and subtract fractions with the same denominator within one whole [e.g. 5/7 + 1/7 = 6/7] 4F1 - count up and down in hundredths; recognise that hundredths arise when dividing an object by a hundred and dividing tenths by ten 4F4 - add and subtract fractions with the same denominator 4F6b - recognise and write decimal equivalents of any number of tenths or hundredths4F7 - round decimals with one decimal place to the nearest whole number4F9 - find the effect of dividing a one– or two–digit number by 10 and 100, identifying the value of the digits in the answer as ones, tenths and hundredths 4F10a - solve problems involving increasingly harder fractions to calculate quantities and fractions to divide quantities, including non–unit fractions where the answer is a whole number
From Year 5 curriculum:5F2a - recognise mixed numbers and improper fractions and convert from one form to the other; write mathematical statements >1 as a mixed number [e.g. 2/5 + 4/5 = 6/5 = 1 1/5] 5F3 - compare and order fractions whose denominators are all multiples of the same number 5F4 - add and subtract fractions with the same denominator and denominators that are multiples of the same number 5F5 - multiply proper fractions and mixed numbers by whole numbers, supported by materials and diagrams 5F6a - read and write decimal numbers as fractions [e.g. 0.71 = 71/100] 5F7 - round decimals with two decimal places to the nearest whole number and to one decimal place 5F10 - solve problems involving numbers up to three decimal places 5F12 - solve problems that require knowing percentage and decimal equivalents of 1/2, 1/4, 1/5, 2/5, 4/5 and those fractions with a denominator of a multiple of 10 or 25
Measurement (M)
Prior Learning from Years 3 and 4 curricula:3M9a - add and subtract amounts of money to give change, using both pounds (£) and pence (p) in practical contexts 4M1 - compare different measures, including money in pounds and pence
From Year 5 curriculum:5M4 - solve problems involving converting between units of time 5M5 - convert between different units of metric measure [e.g. kilometre and metre; centimetre and metre; centimetre and millimetre; gram and kilogram; litre and millilitre]5M6 - understand and use approximate equivalences between metric units and common imperial units such as inches, pounds and pints
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Strand Content Assessed
Geometry – properties of
shapes (G)
Prior Learning from Year 3 curriculum:3G2 - identify horizontal, vertical lines and pairs of perpendicular and parallel lines 3G3b - make 3–D shapes using modelling materials; recognise 3–D shapes in different orientations and describe them
From Year 5 curriculum:5G2a - use the properties of rectangles to deduce related facts and find missing lengths and angles5G3b - identify 3–D shapes including cubes and other cuboids, from 2–D representations
Geometry – position and direction (P)
-
Statistics (S) Prior Learning from Years 3 and 4 curricula:3S1 - interpret and present data using bar charts, pictograms and tables 4S2 - solve comparison, sum and difference problems using information presented in bar charts, pictograms, tables and other graphs
From Year 5 curriculum:n/a
Year 6: Spring Strand Content Assessed
Number (N) Prior Learning from Years 3–5 curricula:3N3 - recognise the place value of each digit in a three–digit number (hundreds, tens, ones) 4N2a - order and compare numbers beyond 1,000 4N4b - round any number to the nearest 10, 100 or 1,000 5N5 - interpret negative numbers in context, count forwards and backwards with positive and negative whole numbers, including through zero 5N1 - count forwards or backwards in steps of powers of 10 for any given number up to 1,000,000
From Year 6 curriculum:n/a
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Strand Content Assessed
Calculation (C) Prior Learning from Years 3–5 curricula:3C2 - add and subtract numbers with up to three digits, using formal written methods of columnar addition and subtraction 3C4 - solve problems, including missing number problems, using number facts, place value, and more complex addition and subtraction 3C7 - write and calculate mathematical statements for multiplication and division using the multiplication tables that pupils know, including for two–digit numbers times one–digit numbers, using mental and progressing to formal written methods 4C2 - add and subtract numbers with up to 4 digits using the formal written methods of columnar addition and subtraction where appropriate 4C6a - recall multiplication and division facts for multiplication tables up to 12 × 12 4C7 - multiply two–digit and three–digit numbers by a one–digit number using formal written layout 5C2 - add and subtract whole numbers with more than 4 digits, including using formal written methods (columnar addition and subtraction)5C5a - identify multiples and factors, including finding all factor pairs of a number and common factors of two numbers 5C5b - know and use the vocabulary of prime numbers, prime factors and composite (non–prime) numbers5C6b - multiply and divide whole numbers and those involving decimals by 10, 100 and 1,000 5C7b - divide numbers up to 4 digits by a one–digit number using the formal written method of short division and interpret remainders appropriately for the context
From Year 6 curriculum:6C7a - multiply multi–digit numbers up to 4 digits by a two–digit whole number using the formal written method of long multiplication6C7b - divide numbers up to 4 digits by a two–digit whole number using the formal written method of long division, and interpret remainders as whole number remainders, fractions, or by rounding, as appropriate for the context 6C8 - solve problems involving addition, subtraction, multiplication and division6C9 - use their knowledge of the order of operations to carry out calculations involving the four operations
Ratio and proportion (R)
Prior Learning:n/a
From Year 6 curriculum:6R4 - solve problems involving unequal sharing and grouping using knowledge of fractions and multiples
Algebra (A) Prior Learning:n/a
From Year 6 curriculum:6A1 - express missing number problems algebraically6A2 - use simple formulae 6A3 - generate and describe linear number sequences 6A4 - find pairs of numbers that satisfy an equation with two unknowns
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Strand Content Assessed
Fractions, decimals and percentages
(FDP)
Prior Learning from Years 3–5 curricula:3F1b - recognise, find and write fractions of a discrete set of objects: unit fractions and non–unit fractions with small denominators3F1c - recognise and use fractions as numbers: unit fractions and non–unit fractions with small denominators 3F4 - add and subtract fractions with the same denominator within one whole [e.g. 5/7 + 1/7 = 6/7] 3F10 - solve problems that involve 3F1–3F4 4F4 - add and subtract fractions with the same denominator 5F2a - recognise mixed numbers and improper fractions and convert from one form to the other; write mathematical statements >1 as a mixed number [e.g. 2/5 + 4/5 = 6/5 = 1 1/5] 5F4 - add and subtract fractions with the same denominator and denominators that are multiples of the same number5F7 - round decimals with two decimal places to the nearest whole number and to one decimal place 5F10 - solve problems involving numbers up to three decimal places
From Year 6 curriculum:6F3 - compare and order fractions, including fractions >16F4 - add and subtract fractions with different denominators and mixed numbers, using the concept of equivalent fractions6F5a - multiply simple pairs of proper fractions, writing the answer in its simplest form [e.g. 1/4 × 1/2 = 18] 6F5b - divide proper fractions by whole numbers [e.g. 1/3 ÷ 2 = 1/6] 6F6 - associate a fraction with division to calculate decimal fraction equivalents (e.g. 0.375) for a simple fraction [e.g. 3/8] 6F9b - multiply one–digit numbers with up to two–decimal places by whole numbers 6F9c - use written division methods in cases where the answer has up to two–decimal places
Measurement (M)
Prior Learning from Year 4 curriculum:4M4a - read, write and convert time between analogue and digital 12–hour clocks 4M7a - measure and calculate the perimeter of a rectilinear figure (including squares) in centimetres and metres 4M7b - find the area of rectilinear shapes by counting squares
From Year 6 curriculum:6M9 - solve problems involving the calculation and conversion of units of measure, using decimal notation up to three decimal places where appropriate
Geometry – properties of
shapes (G)
Prior Learning from Year 5 curriculum:5G4b - identify: • angles at a point and one whole turn (total 360°) • angles at a point on a straight line and 12 a turn (total 180°) • other multiples of 90°
From Year 6 curriculum:6G2a - compare and classify geometric shapes based on their properties and sizes6G2b - describe simple 3–D shapes
17
NTS Assessments
© Hodder & Stoughton Limited 2019 1 Introduction
Strand Content Assessed
Geometry – position and direction (P)
-
Statistics (S) Prior Learning from Year 4 curriculum:4S2 - solve comparison, sum and difference problems using information presented in bar charts, pictograms, tables and other graphs
From Year 6 curriculum:n/a
18
NTS Assessments
2 Administering NTS Assessments © Hodder & Stoughton Limited 2019
When to test
The NTS Assessments should ideally be used just before the end of term, as they have been designed to
assess the content presented in the curriculum map for that term.
Since the standardisation with our trial schools took place in November, March and June, similar timings
will produce the most dependable data; but, if the subject content has been taught, the timing is not
critical.
Group size
You can administer the tests to whole classes or large groups if you feel comfortable doing so. If you
wish to give assistance to smaller groups outside the classroom setting this can be done at your
discretion; we suggest that children who require assistance receive it, but guidance should not be given
around the content itself or answers to test questions.
Timing
The table below shows the suggested time for each individual booklet. At KS1 in particular, this is just a
suggestion – we expect teachers to adjust as they see fit depending on the children in their class.
Year Paper Time allowed Total for year
Year 1Year 1
Spring Paper 1Spring Paper 2
Approx 15 minsApprox 25 mins
40 minutes
Year 2Year 2
Spring Paper 1Spring Paper 2
Approx 15 minsApprox 25 mins
40 minutes
KS2 (all identical)KS2 (all identical)KS2 (all identical)
Spring Paper 1Spring Paper 2Spring Paper 3
25 minutes30 minutes30 minutes
85 minutes
Table 1: Spring tests
Preparation
Each pupil will need the appropriate test booklet. Explain the following:
❯ Start off by making the pupils feel at ease. Explain what the test consists of and how long they have to
complete the booklet they have in front of them.
❯ The answer booklet consists of a range of questions: pupils should attempt them all.
❯ If pupils find a question too hard, they should have a go and then move on to the next one: they
should not spend too long on questions they cannot answer.
❯ If pupils have problems, they should ask for help by raising their hand.
2 Administering NTS Assessments
19
NTS Assessments
© Hodder & Stoughton Limited 2019 2 Administering NTS Assessments
❯ Review the timings of the papers using the table provided on page 18. Explain to children how long
they have to complete the test.
❯ Ensure appropriate breaks are taken between papers.
Teachers may choose to separate the class into smaller groups, based on ability. A more advanced
group may be able to complete the test in one sitting, whereas a less advanced group may need to
do so in smaller chunks. You should use your knowledge of pupils’ abilities to inform this decision, and
reflect this when completing the teacher questionnaire at the end of the test.
❯ The teacher-administrator should allow pupils with Special Educational Needs the same support as
would be allowed during National Tests. Pupils may sit tests designed for children in the years below
but please be aware that the outcomes will not be valid, with the exception of the NTS Scale, which
can be used to track small increments of progress.
❯ It is important that any supporting persons who may be reading questions to pupils read the text only
and not any symbols or operations, or give any other advice, explanations or definitions of words or
terms to pupils.
❯ In Years 1 and 2, the questions may be read to the pupils. This applies to groups of pupils requiring
this assistance in other years, if this is how you would usually administer a non-statutory assessment,
but under test conditions (i.e. no help or guidance should be given in finding answers).
Paper Resource list
Maths Year 1, Paper 1 Pencil/blue or black penEraser
Maths Year 1, Paper 2 Pencil/blue or black penEraserRuler (showing mm and cm)
Maths Year 2, Paper 1 Pencil/blue or black penEraser
Maths Year 2, Paper 2 Pencil/blue or black penA sharp, dark pencil for mathematical drawingEraserRuler (mm and cm)
Maths KS2, Paper 1 Pencil/blue or black penEraser
Maths KS2, Paper 2 and Paper 3
Pencil/blue or black penA sharp, dark pencil for mathematical drawingEraserRuler (mm and cm)Angle measurer/protractorMirror
Table 2: Equipment allowed for each test
20
NTS Assessments
2 Administering NTS Assessments © Hodder & Stoughton Limited 2019
Administering the test
Give each pupil a test booklet. Ask them to write their name, gender, date of birth and the date of the
test on the front cover.
If any pupils are uncertain about what they have to do, you may give some additional explanation to help
them understand the requirements of the test, but do not help with the content of the question.
If the results are to be reliable, it is important that the pupils work alone, without copying from each other
or discussing their answers. Remind pupils of this if necessary.
Once the pupils have completed the test, their answers may be marked using the answers and mark
schemes found in this guidance.
21
NTS Assessments
© Hodder & Stoughton Limited 2019 3 Answers and mark schemes
Marking the answers
❯ The mark boxes in the right-hand margins of each test booklet indicate where a mark can be gained.
❯ Some questions have more than one part, or attract more than one mark, so you should follow the
mark scheme carefully, using your professional judgement if necessary.
❯ If more answers than required have been circled or ticked, the mark should not be awarded except if
it is clearly indicated that an incorrect response was initially made and then corrected.
❯ For scores to be valid, you should not award half marks.
Profiling performance by strand
The code letters shown above each mark box may be used to profile the pupil’s performance by strand
(which equate to the National Test content domains). Total the number of correct answers the pupil has
obtained in each coded strand and make a note of these strand scores in the boxes on the front cover of
the test booklet.
Transcripts for Key Stage 1
The transcripts below should be used with the appropriate tests.
Year 1 Maths Transcript – Spring
Paper 1 arithmetic: teacher’s script for practice questions
Question number Script to read to pupils
Practice question a Practice question aAdd four and one.Write the number in the answer box.
Practice question b Practice question bFive take away which number equals two?Write the number in the answer box.
3 Answers and mark schemes
22
NTS Assessments
3 Answers and mark schemes © Hodder & Stoughton Limited 2019
Paper 2 reasoning: teacher’s script for practice and aural questions
Question number Script to read to pupils
Practice question a Practice question aLook at the picture in the practice question.Polly has six coins. She spends one coin.Write the number of coins she has left in the answer box.
Practice question b Practice question bHere are some shapes.Tick the rectangle.
Question 1 Question 1Here are some numbers.Three, four, a missing number, six, seven, eight.Write the missing number in the answer box.
Question 2 Question 2Here are some numbers in digits and some numbers in words.Draw a line to join the number in words to the same number in digits.The first one has been done for you.
Question 3 Question 3 Nishi’s shirt has six buttons.Two buttons drop off.How many buttons are left?Write the number in the box.
Question 4 Question 4 Here are seven pens.Jack takes three of the pens.How many pens are left?Write the number in the box.
Question 5 Question 5 Here are some glasses.Each glass has some water in it.Tick the glass that is nearly full.Write a tick in the tick box below one of the glasses.
23
NTS Assessments
© Hodder & Stoughton Limited 2019 3 Answers and mark schemes
Year 2 Maths Transcript – Spring
Year 2 Paper 2 reasoning: teacher’s script for practice and aural questions
Question number Script to read to pupils
Practice question a Practice question aHere are some numbers in order.Write the number that comes next.26, 25, 24, 23, 22, a missing number. Write the number in the box.
Practice question b Practice question bCircle the £1 coin.
Question 1 Question 1This jug holds some water.How much water is in the jug?
Question 2 Question 2Nia has a pizza.Nia eats ½ of the pizza.Tick the drawing that shows what is left.
Question 3 Question 3 Nia has four sweets. She eats one of the sweets. What fraction of the sweets has Nia eaten? Write your answer in the box.
Question 4 Question 4 What number is shown by this abacus?
Question 5 Question 5 Max has twenty counters. He divides them into five groups.How many counters are in each group?
Answers and mark schemes Year 1 © Hodder & Stoughton Limited 201924
An
swer
s an
d m
ark
sch
emes
Yea
r 1
Qu
esti
on
nu
mb
er
& c
on
ten
t d
om
ain
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
Prac
tice
qu
esti
on
a1N
2b4
+ 1
= 5
n/a
Prac
tice
qu
esti
on
b1C
45
– 3
= 2
n/a
1 1N2b
9 +
1 =
10
1
2 1N2b
15 –
1 =
14
1
3 1C2a
8 +
4 =
12
1
4 1C2a
11 –
5 =
61
5 1C2a
13 –
5 =
81
6 1C2a
20 –
13
= 7
1
7 1C4
6 +
6 =
12
1
8 1C4
10 =
10
– 0
1
9 1C4
19 =
9 +
10
1
10 1C4
17
– 4
= 1
31
Pap
er 1
ari
thm
etic
: an
swer
s an
d m
ark
sch
eme
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 1 25
Pap
er 2
rea
son
ing
: an
swer
s an
d m
ark
sch
eme
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
Prac
tice
q
ues
tio
n a
1N2b
Look
at
the
pict
ure
in t
he p
ract
ice
ques
tion.
Polly
has
six
coi
ns.
She
spen
ds o
ne c
oin.
Writ
e th
e nu
mbe
r of
coi
ns s
he h
as le
ft in
the
ans
wer
box
.
n/a
Prac
tice
q
ues
tio
n b
1G1a
Her
e ar
e so
me
shap
es.
Tick
the
rec
tang
le.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns, e
.g. c
ircle
d or
cro
ssed
.n/
a
5
coin
s
Answers and mark schemes Year 1 © Hodder & Stoughton Limited 201926
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 1N1a
Her
e ar
e so
me
num
bers
.
Thre
e, f
our,
a m
issi
ng n
umbe
r, si
x, s
even
, eig
ht.
Writ
e th
e m
issi
ng n
umbe
r in
the
ans
wer
box
.
3 4
5
6
7
8
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 1 27
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
2 1N2c
Her
e ar
e so
me
num
bers
in d
igits
and
som
e nu
mbe
rs in
wor
ds.
Dra
w a
line
to
join
the
num
ber
in w
ords
to
the
sam
e nu
mbe
r in
dig
its.
The
first
one
has
bee
n do
ne f
or y
ou.
Dra
w a
line
bet
wee
n ea
ch n
umbe
r an
d its
nam
e.
All
thre
e lin
es c
orre
ct f
or o
ne
mar
k.1
six
12
twel
ve6
sixt
een
20
twen
ty16
Answers and mark schemes Year 1 © Hodder & Stoughton Limited 201928
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
3 1C4
Nis
hi’s
shirt
has
six
but
tons
.
Two
but
tons
dro
p of
f.
How
man
y bu
tton
s ar
e le
ft?
1
4 1C4
Her
e ar
e se
ven
pen
s.
Jack
tak
es t
hre
e of
the
pen
s.
How
man
y pe
ns a
re le
ft?
1
4 p
ens
4
butt
ons
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 1 29
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
5 1M1
Her
e ar
e so
me
glas
ses.
Each
gla
ss h
as s
ome
wat
er in
it.
Tick
the
gla
ss t
hat
is n
earl
y fu
ll.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns, e
.g. c
ircle
d or
cro
ssed
.1
Answers and mark schemes Year 1 © Hodder & Stoughton Limited 201930
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
6 1C4
Jack
has
the
se c
ount
ers.
He
give
s 1
blac
k co
unte
r an
d 1
whi
te c
ount
er t
o Sa
m.
How
man
y co
unte
rs d
oes
Jack
hav
e le
ft?
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.
Aw
ard
one
mar
k fo
r a c
orre
ct m
etho
d, e
.g.
6 –
1 =
5
5 –
1 =
4
5 +
4 =
Acc
ept
one
coun
ter
cros
sed
from
eac
h ro
w a
s an
indi
catio
n of
a c
orre
ct m
etho
d.
2
7 1M2
How
long
is t
his
line?
1
cm
9
coun
ters
9
cm
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 1 31
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
8 1G1a
Circ
le t
he n
ame
of t
his
shap
e.
tr
iang
le
sq
uare
circ
le
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns, e
.g. t
icke
d or
cro
ssed
.1
9 1G1b
Dra
w li
nes
from
the
sha
pes
to t
heir
nam
es.
All
thre
e lin
es c
orre
ct f
or o
ne
mar
k.1
pyra
mid
cube
cubo
id
Answers and mark schemes Year 1 © Hodder & Stoughton Limited 201932
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
10 1C2b
Her
e ar
e so
me
card
s w
ith s
ymbo
ls.
Writ
e a
sym
bol i
n th
e em
pty
box
to m
ake
this
num
ber
sent
ence
cor
rect
.
1
11 1C4
Nis
hi h
as 8
cou
nter
s.
Polly
has
3 c
ount
ers.
Nis
hi g
ives
Pol
ly 2
cou
nter
s.
Com
plet
e th
is s
ente
nce.
N
ishi
now
has
6
cou
nter
s
an
d Po
lly n
ow h
as
5 c
ount
ers.
Aw
ard
on
e m
ark
for
each
cor
rect
nu
mbe
r.2
+−
=
17−
=12
5
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 1 33
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
12 1N1b
Her
e ar
e tw
o se
ts o
f nu
mbe
rs.
Writ
e th
e m
issi
ng n
umbe
rs in
the
circ
les.
Bo
th n
umbe
rs c
orre
ct f
or o
ne
mar
k.1
10 20
24
68
155
12
Answers and mark schemes Year 1 © Hodder & Stoughton Limited 201934
24 64
28 68
46
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
13 1N4
This
is p
art
of a
hun
dred
squ
are.
Mos
t of
the
num
bers
are
mis
sing
.
Writ
e th
e nu
mbe
r in
the
mid
dle
squa
re.
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 2 35
An
swer
s an
d m
ark
sch
emes
Yea
r 2
Qu
esti
on
nu
mb
er
& c
on
ten
t d
om
ain
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
Prac
tice
qu
esti
on
a1C
2a3
+ 2
= 5
n/a
Prac
tice
qu
esti
on
b1C
414
= 1
0 +
4n/
a
1 1N2b
15
– 1
= 1
41
2 1N2b
39
+ 1
= 4
01
3 1C2a
13 –
6 =
71
4 2C2a
18 +
7 =
25
1
5 2C2a
2 +
9 +
8 =
19
1
6 2C2a
33
= 2
1 +
12
1
7 2C2a
7
+ 9
+ 7
= 2
31
8 2C2a
63
– 4
= 5
91
9 2C2a
76
– 5
5 =
21
1
10 1C4
4 =
15
– 11
1
Pap
er 1
ari
thm
etic
: an
swer
s an
d m
ark
sch
eme
Answers and mark schemes Year 2 © Hodder & Stoughton Limited 201936
Qu
esti
on
nu
mb
er
& c
on
ten
t d
om
ain
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
11 2C4
56 +
22
= 7
81
12 2C4
41 =
65
– 24
1
13 2C6
8 ×
5 =
40
1
14 2C6
7 ×
10
= 7
01
15 2C6
16 ÷
2 =
81
16 2C6
45 ÷
5 =
91
17 2F1a
1 3
of 1
5 =
51
18 2F1a
1 4
of
40 =
10
1
19 2F1a
3 4
of
4 =
31
20 2F1a
1 4
of
20 =
51
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 2 37
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
Prac
tice
q
ues
tio
n a
1N1a
Her
e ar
e so
me
num
bers
in o
rder
.
Writ
e th
e nu
mbe
r th
at c
omes
nex
t.
26
25
24
23
22
21
n/a
Prac
tice
q
ues
tio
n b
1M3
Circ
le t
he £
1 co
in.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns, e
.g. u
nder
lined
or
ticke
d.n/
a
Pap
er 2
rea
son
ing
: an
swer
s an
d m
ark
sch
eme
Answers and mark schemes Year 2 © Hodder & Stoughton Limited 201938
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 1M2
This
jug
hold
s so
me
wat
er.
How
muc
h w
ater
is in
the
jug?
litr
es 5 4 3 2 1
3
litr
es
1
2 1F1a
N
ia h
as a
piz
za.
Nia
eat
s 1 2
of
the
pizz
a.
Tick
the
dra
win
g th
at s
how
s w
hat
is le
ft.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns, e
.g. u
nder
lined
or
circ
led.
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 2 39
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
3 1F1b
Nia
has
fou
r sw
eets
.
She
eats
one
of
the
swee
ts.
Wha
t fr
actio
n of
the
sw
eets
has
Nia
eat
en?
Writ
e yo
ur a
nsw
er in
the
box
.
Acc
ept
equi
vale
nt f
ract
ions
.1
4 2N4
TO
Wha
t nu
mbe
r is
sho
wn
by t
his
abac
us?
65
1
1 4
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esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
5 2C8
Max
has
tw
enty
cou
nter
s.
He
divi
des
them
into
five
gro
ups.
How
man
y co
unte
rs a
re in
eac
h gr
oup?
Acc
ept
a gr
oup
of f
our
coun
ters
or
four
in
divi
dual
cou
nter
s in
dica
ted.
1
4
coun
ters
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 2 41
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esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
6 2M2
2M2
2M1
Com
plet
e th
e m
issi
ng n
umbe
rs a
nd le
tter
s.
0kg
1kg
2kg
3kg
4kg5
kg0
kg1
kg10
kg
2kg
9kg
3kg
4kg
5kg
6kg
7kg
8kg
Parc
el A
Parc
el B
(a)
Parc
el A
wei
ghs
3
kg
(b)
Parc
el B
wei
ghs
4
kg
(c)
Parc
el
B is
hea
vier
tha
n Pa
rcel
A
(c
) A
ccep
t 4
and
3 w
ritte
n in
the
box
es
in p
lace
of
B an
d A
.
(a)
1
(b)
1
(c)
1
Answers and mark schemes Year 2 © Hodder & Stoughton Limited 201942
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esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
7 1N1b
Writ
e th
e m
issi
ng n
umbe
rs in
the
se s
eque
nces
.
(a)
35
40
45
50
55
60
(b)
28
30
32
34
36
38
(a) B
oth
num
bers
nee
ded
for
awar
d of
th
e m
ark.
(b) A
ll th
ree
num
bers
nee
ded
for
awar
d of
the
mar
k.
(a)
1
(b)
1
8 2C6
Her
e ar
e so
me
num
bers
.
5 8
12
17
20W
rite
each
num
ber
in t
he c
orre
ct s
et.
Even
num
bers
Od
d n
umbe
rs
Aw
ard
two
mar
ks f
or fi
ve c
orre
ctly
pl
aced
num
bers
.
Aw
ard
on
e m
ark
for
two
, th
ree
or f
ou
r co
rrec
tly p
lace
d nu
mbe
rs.
2
812
205
17
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 2 43
8
ver
tices
Qu
esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
9 2G2b
This
is a
cub
e.
How
man
y ve
rtic
es d
oes
it ha
ve?
1
Answers and mark schemes Year 2 © Hodder & Stoughton Limited 201944
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esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
10 2M9
2M3a
(a)
Nia
wan
ts t
o bu
y a
pen
for
75p
Sh
e ha
s th
ese
coin
s.
H
ow m
uch
mo
re m
oney
doe
s N
ia n
eed?
(b)
Max
wan
ts t
o bu
y a
penc
il fo
r 35
p
H
e us
es f
ou
r co
ins.
W
rite
the
valu
e of
the
coi
ns h
e us
es.
p p
p p
p p
p p
20 10
5 10
5 10
5 5
O
R
(b) A
ccep
t co
ins
in a
ny o
rder
.
(a)
1
(b)
1
15
p
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 2 45
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esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
11 2F1b
Writ
e th
e m
issi
ng n
umbe
rs in
the
se n
umbe
r se
nten
ces.
(a)
1 3 o
f 15
=
5
(b)
1 4 o
f 8
= 2
(a)
1
(b)
1
12 2C8
Max
pla
ys a
gam
e.
He
gets
5 p
oint
s fo
r co
llect
ing
a sq
uare
.
5po
ints
He
gets
10
poin
ts f
or c
olle
ctin
g a
circ
le.
10po
ints
How
man
y po
ints
doe
s M
ax g
et f
or
colle
ctin
g 10
squ
ares
and
4 c
ircle
s?
90
poi
nts
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.
Aw
ard
on
e m
ark
for
a co
rrec
t m
etho
d,
e.g.
(5 ×
10)
+ (1
0 ×
4) =
2
Answers and mark schemes Year 2 © Hodder & Stoughton Limited 201946
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esti
on
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ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
13 2N2b
(a)
Use
the
sig
ns <
, > a
nd =
to
com
pare
the
se n
umbe
rs.
73
>
37
43
=
4 te
ns a
nd 3
one
s
51
<
6 te
ns
(b)
Inse
rt a
num
ber
in t
his
num
ber
sent
ence
to
mak
e it
corr
ect.
40
>
>
3
0
(a) A
war
d tw
o m
arks
for
th
ree
corr
ect
sym
bols
.
A
war
d o
ne
mar
k fo
r tw
o c
orre
ct
sym
bols
.
(b) A
ccep
t an
y nu
mbe
r >
30 b
ut <
40
(a)
2
(b)
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 2 47
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esti
on
n
um
ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
14 2S2b
This
blo
ck d
iagr
am s
how
s th
e nu
mbe
r of
boy
s an
d gi
rls
in C
lass
2A
.
How
man
y ch
ildre
n a
re in
Cla
ss 2
A?
1
27 c
hild
ren
Answers and mark schemes Year 2 © Hodder & Stoughton Limited 201948
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esti
on
n
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ber
&
con
ten
t
do
mai
n
Qu
esti
on
an
d a
nsw
erM
arki
ng
gu
idan
ceM
ark
15 2C4
Her
e is
a s
ubtr
actio
n.
It ha
s m
issi
ng d
igits
.
Writ
e th
e m
issi
ng d
igits
to
mak
e th
e su
btra
ctio
n co
rrec
t.
Giv
e tw
o p
ossi
ble
answ
ers.
5
9 –
3
3 =
26
5
8 –
3
2 =
26
Aw
ard
on
e m
ark
for
each
cor
rect
nu
mbe
r se
nten
ce.
Als
o ac
cept
57
– 31
or
56 –
30
2
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 3 49
An
swer
s an
d m
ark
sch
emes
Yea
r 3
Pap
er 1
ari
thm
etic
: an
swer
s an
d m
ark
sch
eme
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 1C2a
3 +
5 =
81
2 1N2b
36 −
1 =
35
1
3 1N2b
29 +
1 =
30
1
4 1C4
15 −
8 =
71
5 1F1a
1 2
of 1
2 =
61
6 2C2a
4
+ 2
+ 5
= 1
11
7 2C6
5 ×
5 =
25
1
8 3N2b
60
7 =
507
+ 1
001
9 2C2a
12 +
23
= 3
51
10 3N2b
678
− 10
= 6
68
1
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ber
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nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
11 2C6
18 ÷
2 =
91
12 2C2a
48 −
33
= 1
51
13 2F1a
1 3 of
15
= 5
1
14 1F1b
1 4 of
20
= 5
1
15 3C2
428
+ 2
52 =
68
01
16 3C2
330
+ 3
3 +
3 =
36
61
17 3C2
724
+ 9
4 =
81
81
18 3F1b
1
0 =
1 5 o
f 50
1
19 3C6
96 ÷
8 =
12
1
20 3C7
21
0 =
70
× 3
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 3 51
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
21 3C2
832
− 37
1 =
46
11
22 3C7
42 ×
5 =
21
01
23 2F1a
3 4 of
8 =
61
24 3C7
72 ÷
3 =
24
1
25 3C7
37 ×
4 =
14
81
26 3F1b
2 3 of
12
= 8
1
27 3F1b
2 5 of
20
= 8
1
28 3F1b
5 5 of
10
= 1
01
29 3C2
824
− 7
56
= 6
81
30 3F1a
1 ÷
10 =
1 10
Acc
ept
0.1
1
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esti
on
n
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ber
&
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nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 1N2c
Dra
w a
line
fro
m t
he n
umbe
r in
wor
ds t
o th
e eq
uiva
lent
nu
mbe
r in
dig
its.
Aw
ard
two
mar
ks f
or fi
ve c
orre
ct li
nes.
Aw
ard
on
e m
ark
for
thre
e or
fo
ur
corr
ect
lines
.2
Pap
er 2
rea
son
ing
: an
swer
s an
d m
ark
sch
eme
six
nin
etee
n
sixt
een
fift
een
nin
e
15 9 6 19 16
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 3 53
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
2 3F3
Writ
e th
ese
in o
rder
, st
artin
g w
ith t
he s
mal
lest
.
5 7 1 7
2 7 2 7
1 7 4 7
4 7 5 7
6 7 6 7
smal
lest
la
rges
t
All
five
req
uire
d fo
r o
ne
mar
k.1
3 1G1a
1G1b
Mat
ch e
ach
shap
e to
its
nam
e.
cube
re
ctan
gle
sq
uare
cubo
id
All
fou
r lin
es n
eede
d fo
r o
ne
mar
k.1
Answers and mark schemes Year 3 © Hodder & Stoughton Limited 201954
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
4 1C4
Ben
eats
6 o
f 13
str
awbe
rrie
s.
How
man
y st
raw
berr
ies
are
left
?
7
str
awbe
rrie
s
1
5 2M3a
Tick
the
coi
ns n
eede
d to
mak
e 57
p.
The
follo
win
g co
ins
need
to
be in
dica
ted:
2 ×
20p
1 ×
10p
1 ×
5p1
× 2p
Cou
ld b
e ei
ther
10p
, 5p
or
2p b
ut m
ust
only
be
one
of e
ach.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d.
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 3 55
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
6 2N2b
2N
3
Writ
e >
, <
or =
in t
hese
num
ber
sent
ence
s to
mak
e
them
cor
rect
.
56
=
5
tens
and
6 o
nes
4
one
s an
d 6
tens
>
46
38
=
8
ones
and
3 t
ens
2
ten
s an
d 7
ones
<
72
Aw
ard
two
mar
ks f
or f
ou
r co
rrec
t an
swer
s.A
war
d o
ne
mar
k fo
r tw
o o
r th
ree
corr
ect
answ
ers.
2
7 2F1a
Sam
ir w
ante
d to
find
1 4 o
f 20
He
used
a d
iagr
am t
o he
lp.
Tick
the
dia
gram
Sam
ir us
ed.
Seco
nd d
iagr
am in
dica
ted
only.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d.
1
4 4
4 4
5 5
5 5
20 20
20 20
1 4 1 4
1 4 1 4
Answers and mark schemes Year 3 © Hodder & Stoughton Limited 201956
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esti
on
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um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
8 2C8
Find
the
mis
sing
num
ber.
2
+ 2
+ 2
+ 2
+ 2
+ 2
= 2
×
6
1
9 3M9a
K
ate
has
£30
She
buys
a b
ook
for
£8 a
nd a
set
of
pens
for
£4
How
muc
h m
oney
doe
s sh
e ha
ve le
ft?
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.8
+ 4
= 1
230
− 1
2 =
2
10 3C8
Sam
ir ha
s 5
pack
s of
6 p
ens.
Josh
wan
ts t
he s
ame
num
ber
of p
ens.
How
man
y p
acks
of
10 p
ens
will
Jos
h ne
ed
to b
uy t
o ha
ve t
he s
ame
num
ber
of p
ens
as
Sam
ir?
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.5
× 6
= 30
30 ÷
10
=
2
£ 1
8 3
p
acks
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 3 57
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esti
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um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
11 3C7
Writ
e th
e m
issi
ng n
umbe
rs.
2 ×
12
= 2
4 =
48
÷ 2
Aw
ard
on
e m
ark
for
each
cor
rect
mis
sing
num
ber.
2
Answers and mark schemes Year 3 © Hodder & Stoughton Limited 201958
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esti
on
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um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
12 3S1
3S2
Old
Far
m
= 5
ani
mal
s
Hen
s
Cow
s
Pigs
(a)
2
0 c
ows
(b)
10
pig
s
(c)
Car
l say
s th
ere
are
60 a
nim
als
alto
get
her
at
Old
Far
m.
Y
ES
N
O
H
ens
= 2
ë 5
= 1
0
+
Cow
s =
4 ë
5 =
20
+
Pig
s =
6 ë
5 =
30
=
60
anim
als
(c)
Nee
ds c
orre
ct e
xpla
natio
n to
ear
n th
e m
ark.
A
ccep
t 12
× 5
= 6
0D
o n
ot
awar
d an
y m
ark
for
an in
dica
tion
of Y
ES
or N
O.
The
mar
k sh
ould
be
awar
ded
for
the
expl
anat
ion
only.
(a)
1
(b)
1
(c)
1
How
man
y co
ws
are
ther
e at
Old
Far
m?
How
man
y m
ore
pig
s th
an c
ows
are
th
ere
at O
ld F
arm
?
Is h
e rig
ht?
Circ
le y
our
answ
er.
Expl
ain
how
you
kno
w.
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 3 59
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
13 3F2
Tina
sha
des
3 4 o
f th
is s
quar
e.
Shad
e th
e sa
me
frac
tion
of t
his
rect
angl
e.
Acc
ept
any
six
eigh
ths
shad
ed.
1
14 3F1b
M
ax h
as a
jar
of 1
0 m
arbl
es.
The
mar
bles
are
blu
e, r
ed a
nd y
ello
w.
1 2 o
f th
e m
arbl
es a
re b
lue.
1 5 o
f th
e m
arbl
es a
re r
ed.
How
man
y of
the
mar
bles
are
yel
low
?
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
. A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
. 1
0 ÷
2 =
5 1
0 ÷
5 =
2 5
+ 2
= 7
10
– 7
=
2
3
mar
bles
Answers and mark schemes Year 3 © Hodder & Stoughton Limited 201960
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
15 1P2
Her
e is
a s
hape
on
a gr
id.
Dra
w t
he s
hape
aft
er it
has
mad
e a
quar
ter
turn
clo
ckw
ise.
Acc
ept
the
corr
ect
shap
e dr
awn
anyw
here
on
the
grid
.1
16 3C8
A t
rain
has
5 c
arria
ges.
2 of
the
car
riage
s ca
n ea
ch h
old
37 p
asse
nger
s.
3 of
the
car
riage
s ca
n ea
ch h
old
79 p
asse
nger
s.
How
man
y pa
ssen
gers
can
the
tra
in h
old
alto
geth
er?
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.(3
7 ×
2) +
(79
× 3
) =
2
31
1 p
asse
nger
s
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 3 61
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nt
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esti
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erM
arki
ng
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idan
ceM
ark
1 2M1
Dan
Max
Tia
Writ
e th
e na
mes
of
the
child
ren,
sh
ort
est
first
.
Max
Tia
Dan
sho
rtes
t
Acc
ept
any
reco
gnis
able
spe
lling
, in
clud
ing
M,
T, D
.1
Pap
er 3
rea
son
ing
: an
swer
s an
d m
ark
sch
eme
Answers and mark schemes Year 3 © Hodder & Stoughton Limited 201962
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esti
on
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ber
&
co
nte
nt
do
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n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
2 2N1
Writ
e th
e ne
xt t
hre
e nu
mbe
rs in
eac
h se
quen
ce.
(a)
0 5
10
15
2
0
2
5
3
0
(b)
60
50
40
30
20
10
0
(a)
All
thre
e nu
mbe
rs n
eede
d fo
r o
ne
mar
k.
(b)
All
thre
e nu
mbe
rs n
eede
d fo
r o
ne
mar
k.
(a)
1
(b)
1
3 3F3
A b
ar o
f ch
ocol
ate
has
20 s
ectio
ns.
Four
frie
nds
each
ate
a p
art
of t
he b
ar.
Tick
the
nam
e of
the
frie
nd w
ho a
te t
he m
ost
.
Min
a at
e 3 20
of
the
bar.
Jill a
te
7 20 o
f th
e ba
r.
Har
ry a
te
4 20 o
f th
e ba
r.
Lenn
y at
e 6 20
of
the
bar.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d on
ly.1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 3 63
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esti
on
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um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
4 2F1a
Ti
ck t
he s
hape
tha
t ha
s 1 2
sha
ded.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d.1
5 1C4
Find
the
mis
sing
num
bers
.
(a)
17 =
9 +
8
(b)
3 +
1
0 +
7 =
20
(a)
1
(b)
1
6 3M2a
Mea
sure
thi
s lin
e in
cen
timet
res.
Acc
ept
an a
nsw
er b
etw
een
6.8
cm a
nd 7
.2 c
m
incl
usiv
e.1
7
cent
imet
res
Answers and mark schemes Year 3 © Hodder & Stoughton Limited 201964
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nte
nt
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esti
on
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erM
arki
ng
gu
idan
ceM
ark
7 1N4
Her
e is
a n
umbe
r lin
e.
50 40 30 20 10 0
A
(a)
45
(b)
(b)
Acc
ept
an a
rrow
dra
wn
>25
and
<30
(a)
1
(b)
1
Wha
t nu
mbe
r is
sho
wn
by t
he a
rrow
A?
Dra
w a
n ar
row
to
show
the
pos
ition
of
27
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 3 65
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on
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ber
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nte
nt
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n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
8 2G3
Sam
i is
mak
ing
a 3-
D s
hape
.
The
squa
re is
one
of
the
face
s of
Sam
i’s 3
-D s
hape
.
Circ
le t
he 3
-D s
hape
Sam
i cou
ld n
ot
be m
akin
g.
co
ne
cube
cu
boid
py
ram
id
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r tic
ked.
1
9 2C8
This
arr
ay s
how
s 5
× 2
= 10
Writ
e a
divi
sion
sen
tenc
e fo
r th
e sa
me
arra
y.
10
÷ 5
= 2
OR 1
0 ÷
2 =
5
1
Answers and mark schemes Year 3 © Hodder & Stoughton Limited 201966
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esti
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nte
nt
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n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
10 3S2
This
pic
togr
am s
how
s th
e nu
mbe
r of
boo
ks s
ome
child
ren
read
in c
lass
.
How
man
y m
ore
boo
ks d
id N
isha
rea
d th
an B
en?
1
Polly
repr
esen
ts 4
boo
ks
Ben
Max
Nis
ha
Dev
12
book
s
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 3 67
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nte
nt
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n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
11 3C6
Jo m
akes
a li
st o
f m
ultip
licat
ion
fact
s th
at e
qual
24
Circ
le a
ll th
e m
ultip
licat
ion
fact
s th
at J
o w
ill h
ave
on h
er li
st.
12 ×
2 =
4 ×
5 =
8
× 3
=
6 ×
4 =
7 ×
4 =
2
× 10
=
Aw
ard
two
mar
ks f
or t
hre
e co
rrec
ts f
acts
indi
cate
d on
ly.A
war
d o
ne
mar
k fo
r th
ree
corr
ect
fact
s an
d o
ne
inco
rrec
t fa
ct in
dica
ted
only.
OR
Aw
ard
on
e m
ark
for
two
cor
rect
fac
ts in
dica
ted
only.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r tic
ked.
2
12 3F1c
Yasm
in a
nd P
olly
hav
e 10
sim
ilar
mat
hs p
robl
ems
to s
olve
.
The
tabl
e sh
ows
how
muc
h of
the
ir ho
mew
ork
they
hav
e ea
ch
finis
hed.
Com
plet
e th
e m
issi
ng n
umbe
rs.
Num
ber
of
ques
tions
fini
shed
Frac
tion
of t
he
hom
ewor
k fin
ishe
d
Yasm
in5
out
of 1
0=
1 2
Polly
8 ou
t of
10
=4 5
Aw
ard
on
e m
ark
for
each
cor
rect
mis
sing
num
ber.
2
Answers and mark schemes Year 3 © Hodder & Stoughton Limited 201968
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nt
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esti
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erM
arki
ng
gu
idan
ceM
ark
13 3F1c
Ani
l eat
s 3 8
of
his
pizz
a.
Circ
le t
he f
ract
ion
of h
is p
izza
he
does
no
t ea
t.
4 8
3 5
5 8
8 3
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r tic
ked.
1
14 2F2
Hol
ly s
ays,
‘2 4 is
larg
er t
han
1 2 b
ecau
se 2
is la
rger
tha
n 1
and
4 is
larg
er
than
2’
Is H
olly
cor
rect
? Ex
plai
n yo
ur a
nsw
er.
No,
bec
ause
2 4 is
equal to
1 2
Acc
ept
draw
ings
or
num
eric
al a
nsw
ers
that
indi
cate
2 4
is e
qual
to
1 2
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 3 69
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nt
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esti
on
& a
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erM
arki
ng
gu
idan
ceM
ark
15 3M9a
Izzy
buy
s 2
met
res
of r
ibbo
n, w
hich
cos
ts 7
5p p
er m
etre
.
Wor
k ou
t ho
w m
uch
chan
ge s
he g
ets
from
£2
50
p
Aw
ard
two
mar
ks f
or t
he c
orre
ct a
nsw
er.
Aw
ard
on
e m
ark
for
a co
rrec
t m
etho
d, e
.g.
2 ×
100
= 20
020
0 −
(75
× 2)
=
2
16 3C8
In a
pac
k of
20
felt
tip p
ens,
4 a
re b
lack
fel
t tip
pen
s.
A t
each
er t
akes
eno
ugh
pack
s to
hav
e 20
bla
ck f
elt
tip p
ens.
How
man
y fe
lt tip
pen
s w
ill s
he h
ave
alto
geth
er?
Aw
ard
two
mar
ks f
or t
he c
orre
ct a
nsw
er.
Aw
ard
on
e m
ark
for
a co
rrec
t m
etho
d, e
.g.
20 ÷
4 =
520
× 5
=
2
17 3M7
Mea
sure
the
per
imet
er o
f th
is r
ecta
ngle
.
24
cm
Aw
ard
two
mar
ks f
or a
n an
swer
in t
he r
ange
23
.2 m
m t
o 24
.8 m
m in
clus
ive.
Aw
ard
on
e m
ark
for
evid
ence
of
wor
king
tha
t sh
ows
usin
g le
ngth
s in
the
ran
ge 7
.8 m
m t
o 8.
2 m
m
incl
usiv
e an
d w
idth
s of
3.8
to
4.2
mm
incl
usiv
e.
2
10
0 p
ens
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201970
An
swer
s an
d m
ark
sch
emes
Yea
r 4
Pap
er 1
ari
thm
etic
: an
swer
s an
d m
ark
sch
eme
Qu
esti
on
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ber
&
co
nte
nt
do
mai
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 2C6
8 ×
2 =
16
1
2 2C2a
62 −
5 =
57
1
3 2C2a
34 +
40
= 7
41
4 2C6
30 ÷
5 =
61
5 4N2b
6,98
7 −
1,00
0 =
5,9
87
*1
6 3N2b
17
4 =
184
− 1
01
7 3C2
251
+ 45
7 =
70
81
8 4C2
9,40
0 −
3,10
0 =
6,3
00
*1
9 4C6a
11 ÷
11
= 1
1
10 4N2b
1,86
4 =
86
4 +
1,0
001
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 71
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nt
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esti
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erM
arki
ng
gu
idan
ceM
ark
11 4F4
7 8 −
4 8 =
3 8
1
12 4F4
7 10 +
9 10 =
16
10
A
ccep
t ot
her
equi
vale
nt a
nsw
ers,
e.g
. 1 6 10
, 1 3 5
or 1
.61
13 4F4
4 5 + 4 5
+ 4 5 =
12 5
A
ccep
t ot
her
equi
vale
nt a
nsw
ers,
e.g
. 2 2 5 o
r 2.
41
14 2F1a
1 4 of
16 =
41
15 2F1a
1 3 of
21 =
71
16 3C2
777
− 58
= 7
19
1
17 3C6
8 =
24 ÷
31
18 3F4
7 8 − 2 8
= 5 8
1
19 3C7
26 ×
6 =
15
61
20 4C2
6,37
7 +
2,68
5 =
9,0
62
*1
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201972
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
Qu
esti
on
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ber
&
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nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
21 4C2
6,33
8 −
708
= 5
,63
0*
1
22 4C7
38 ×
9 =
34
21
23 4C7
3,4
08
= 4
26 ×
8*
1
24 3F1b
4 5 of
20 =
16
1
25 4C7
803
× 7
= 5
,62
1*
1
26 4C7
395
× 6
= 2
,37
0*
1
27 4F9
8 ÷
10 =
0.8
Acc
ept
.8,
8 10 o
r ot
her
equi
vale
nt a
nsw
ers.
1
28 4F9
73 ÷
10
= 7
.3A
ccep
t 7 3 10
1
29 4F9
35 ÷
100
= 0
.35
Acc
ept
.35,
35 10
0 or
othe
r eq
uiva
lent
ans
wer
s.1
30 4F9
0.0
4 =
4 ÷
100
Acc
ept
.04,
4 100 o
r ot
her
equi
vale
nt a
nsw
ers.
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 73
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nte
nt
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esti
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erM
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ng
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idan
ceM
ark
1 2M3a
TWENTY
PE
N C E
2015
TWENTY
PE
N C E
2015
TWENTY
PE
N C E
2015
TWENTY
PE
N C E
2015
All
fou
r lin
es n
eede
d fo
r th
e aw
ard
of o
ne
mar
k.1
Pap
er 2
rea
son
ing
: an
swer
s an
d m
ark
sch
eme 65
p
67p
75p
76p
Dra
w li
nes
to jo
in t
he c
oins
to
thei
r va
lue.
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201974
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nte
nt
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esti
on
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erM
arki
ng
gu
idan
ceM
ark
2 3G3a
On
the
grid
bel
ow,
use
a ru
ler
to d
raw
a s
qu
are.
Acc
ept
any
squa
re d
raw
n on
the
grid
.1
3 4F1
Com
plet
e ea
ch n
umbe
r se
quen
ce.
(a)
8.72
8.7
1
8.7
0
8
.69
8.6
8
(b)
2.28
2.2
9
2.
3
2
.31
2.3
2
(a)
Bo
th n
umbe
rs n
eede
d fo
r o
ne
mar
k.
(b)
Bo
th n
umbe
rs n
eede
d fo
r o
ne
mar
k.
(a)
1
(b)
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 75
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nt
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esti
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ng
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idan
ceM
ark
4 4F4
Bess
ie a
nd T
om s
hare
a p
ack
of b
iscu
its a
nd a
pac
k
of s
traw
berr
ies.
(a)
Bes
sie
take
s 2 12
of
the
bisc
uits
and
Tom
tak
es
3 12 o
f th
e
bisc
uits
.
C
ircle
the
fra
ctio
n of
bis
cuits
tha
t th
ey h
ave
take
n al
tog
eth
er.
5 12
5 24
6 12
6 24
(b)
Bess
ie t
akes
8 15
of
the
stra
wbe
rrie
s an
d To
m t
akes
6 15
of
the
stra
wbe
rrie
s.
C
ircle
the
fra
ctio
n th
at is
the
dif
fere
nce
bet
wee
n th
e am
ount
of
stra
wbe
rrie
s ta
ken
by B
essi
e an
d To
m.
14 0
2 30
2 15
2 4
(a)
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r tic
ked.
(b)
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r tic
ked.
(a)
1
(b)
1
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201976
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nte
nt
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esti
on
& a
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erM
arki
ng
gu
idan
ceM
ark
5 2C4
This
is a
mag
ic s
quar
e.
Each
col
umn
and
each
row
add
s up
to
15
Fill
in t
he m
issi
ng n
umbe
rs.
61
8
75
3
29
4
Aw
ard
two
mar
ks f
or f
ou
r co
rrec
t nu
mbe
rs.
Aw
ard
on
e m
ark
for
two
or
thre
e co
rrec
t nu
mbe
rs.
2
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 77
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
6 2F1a
Shad
e 3 4
of
this
rec
tang
le.
Acc
ept
any
6 se
ctio
ns s
hade
d to
rep
rese
nt 3 4
1
7 2G3
Her
e ar
e so
me
3-D
sha
pes.
Writ
e th
e nu
mbe
r of
tri
ang
ula
r fa
ces
on e
ach
shap
e.
All
thre
e co
rrec
t nu
mbe
rs n
eede
d fo
r th
e aw
ard
of
on
e m
ark.
1
24
4
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201978
£ 4
(.0
0)
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
8 3C4
I am
thi
nkin
g of
a n
umbe
r.
I add
200
and
the
n su
btra
ct 5
0
I get
300
Wha
t w
as m
y nu
mbe
r?
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.
Aw
ard
on
e m
ark
for
a co
rrec
t m
etho
d, e
.g.
300
+ 50
− 2
00 =
2
9 3M4a
Wha
t tim
e in
the
mor
ning
doe
s th
is c
lock
sho
w?
Acc
ept
40 m
inut
es p
ast
ten
or 2
0 m
inut
es t
o el
even
.1
10 3C8
3 ap
ples
cos
t 80
p.
How
muc
h w
ill 1
5 ap
ples
cos
t?
Do
not
acce
pt £
400
or £
4(,0
0)p
or £
400p
1
10:4
0 a
.m.
15
0
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 79
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
11 3F2
Josi
e ha
s a
box
of e
ggs.
She
has
used
4 o
f th
e 12
egg
s.
Circ
le t
he f
ract
ion
of t
he e
ggs
Josi
e ha
s us
ed.
4 8
1 4
1 3
8 4
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r tic
ked.
1
12 4F10
aH
arry
pic
ks 2
0 ch
errie
s.
He
give
s 1 5 o
f hi
s ch
errie
s to
Nad
ia a
nd h
e gi
ves
2 5 of
his
cher
ries
to A
hmed
.
How
man
y ch
errie
s do
es H
arry
hav
e le
ft?
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.20
÷ 5
= 4
4 ×
2 =
84
+ 8
= 12
20 −
12
= O
R
1 5 + 2 5 =
3 5
1 −
3 5 = 2 5
20 ÷
5 =
44
× 2
=
2
8 c
herr
ies
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201980
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
13 4M7a
4M7b
This
sha
pe is
dra
wn
on a
cen
timet
re s
quar
e gr
id.
(a)
Wha
t is
the
per
imet
er o
f th
e
shad
ed s
hape
?
(b)
Wha
t is
the
are
a of
the
sha
ded
shap
e?
(a)
1
(b)
1
32
cm
42
cm
2
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 81
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
14 4C6b
Find
the
mis
sing
num
bers
.A
ccep
t an
y tw
o nu
mbe
rs t
hat
com
plet
e th
e m
ultip
licat
ion
corr
ectly
.1
15 4M5
Paul
is b
akin
g a
cake
.
The
reci
pe s
ays
he n
eeds
0.5
kg
of
flour
.
Circ
le t
he a
mou
nt o
f flo
ur h
e ne
eds
in g
ram
s.
0.
5 g
5
g
50 g
500
g
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r tic
ked.
1
××
=80
28
5
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201982
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
16 4N1
Sam
ir w
rites
a s
eque
nce
of n
umbe
rs.
49
57
63
70
77
Sam
ir sa
ys,
‘Thi
s is
a s
eque
nce
of m
ultip
les
of s
even
.’
Expl
ain
why
Sam
ir is
inco
rrec
t.
1
An e
xpla
nation t
hat
show
s ei
ther
57
should
be
56
OR
The
dif
fere
nce
bet
wee
n 4
9 a
nd 5
7 is
8
not
7
OR
The
dif
fere
nce
bet
wee
n 5
7 a
nd 6
3 is
6
not
7
OR
57
is
not
a m
ultip
le o
f 7
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 83
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
17 3M1a
Put
thes
e le
ngth
s in
ord
er.
Star
t w
ith t
he s
ho
rtes
t.
21 cm
2
cm
200
mm
2 m
22 cm
2 cm
2
00
mm
2
1 cm
2
2 cm
2
m
sho
rtes
t
All
five
req
uire
d fo
r o
ne
mar
k.1
18 4C8
A t
rain
leav
es f
or L
ondo
n.
Ther
e ar
e 3
coac
hes
with
108
sea
ts a
nd 6
coa
ches
with
12
6 se
ats.
How
man
y se
ats
are
ther
e al
tog
eth
er?
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.(1
08 ×
3)
+ (1
26 ×
6)
= Ig
nore
com
ma
in a
nsw
er if
not
pla
ced
or in
corr
ectly
pl
aced
.
2
1,0
80
sea
ts
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201984
Pap
er 3
rea
son
ing
: an
swer
s an
d m
ark
sch
eme
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 2F2
Tick
the
tw
o s
hape
s th
at h
ave
1 2 sha
ded.
Aw
ard
on
e m
ark
for
each
cor
rect
ans
wer
.If
answ
er is
inco
rrec
t:A
war
d o
ne
mar
k fo
r:•
two
cor
rect
and
on
e in
corr
ectly
iden
tified
sha
pes
OR
• o
ne
corr
ectly
iden
tified
sha
pe a
nd n
o in
corr
ectly
id
entifi
ed s
hape
s.D
o n
ot
awar
d an
y m
arks
if:
• tw
o c
orre
ct a
nd t
wo
or
mor
e in
corr
ectly
iden
tified
sh
apes
OR
• o
ne
corr
ect
and
on
e in
corr
ectly
iden
tified
sha
pe.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d.
2
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 85
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
2 3N1b
Her
e ar
e so
me
num
ber
sequ
ence
s.
Two
sequ
ence
s go
acr
oss
the
page
.
Two
sequ
ence
s go
dow
n th
e pa
ge.
Com
plet
e th
e m
issi
ng n
umbe
rs in
the
seq
uenc
es.
Aw
ard
two
mar
ks f
or f
ou
r co
rrec
t an
swer
s.A
war
d o
ne
mar
k fo
r th
ree
corr
ect
answ
ers.
2
100
500
150
550
300
700
250
650
100
300
400
500
250
450
550
650
20
0
35
0
60
0
75
0
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201986
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
3 4C6a
Dra
w li
nes
to m
atch
the
div
isio
n fa
ct t
o its
ans
wer
.
One
line
has
bee
n dr
awn
for y
ou.
48
÷ 8
=
4
36
÷ 9
=
5
60
÷ 1
2 =
6
56
÷ 7
=
7
63
÷ 9
=
8
Aw
ard
two
mar
ks fo
r fou
r co
rrec
t lin
es.
Aw
ard
one
mar
k fo
r tw
o or
thr
ee c
orre
ct li
nes.
2
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 87
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
4 4F2
Thes
e sh
apes
sho
w a
fam
ily o
f eq
uiva
lent
fra
ctio
ns.
==
Fill
in t
he m
issi
ng n
umbe
rs t
o co
mpl
ete
the
equi
vale
nt
frac
tions
.
=1
12=
482
3
Aw
ard
two
mar
ks f
or t
hre
e co
rrec
t fr
actio
ns.
Aw
ard
on
e m
ark
for
two
cor
rect
fra
ctio
ns.
2
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201988
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
5 2S2a
Nia
is fi
ndin
g ou
t ho
w c
hild
ren
trav
el t
o sc
hool
.
She
keep
s a
tally
on
a re
cord
she
et.
Bus
Bus
Taxi
Taxi
Car
Car
Wal
kW
alk
(a)
How
man
y ch
ildre
n di
d N
ia c
ount
?
7
5 c
hild
ren
(b)
How
man
y m
ore
chi
ldre
n tr
avel
led
by c
ar t
han
by b
us?
1
8 c
hild
ren
(a)
1
(b)
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 89
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
6 2G1b
This
is a
box
of
coun
ters
.
The
box
is a
3-D
sha
pe.
Circ
le t
he n
ame
of t
he 3
-D s
hape
.
co
ne
cu
be
cu
boid
cylin
der
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r tic
ked.
1
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201990
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
7 3G2
(a)
Dra
w a
cro
ss o
n an
y sid
e th
at is
par
alle
l to
the
side
in b
old.
(b)
Dra
w a
cro
ss o
n an
y sid
e th
at is
per
pend
icul
ar to
the
side
in
bo
ld.
(a)
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
tic
king
or
circ
ling.
(b)
Acc
ept
eith
er o
r bo
th c
ross
es.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
tic
king
or
circ
ling.
(a)
1
(b)
1
8 3M9a
Tara
has
£40
She
spen
ds £
23 a
nd 3
2p
Circ
le t
he a
mou
nt o
f m
oney
she
has
left
.
£1
7 an
d 78
p
£17
and
68p
£
16 a
nd 7
8p
£16
and
68p
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r tic
ked.
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 91
60 v
anill
a cu
pcak
es
56
67
57
6
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
9 3N2a
Her
e ar
e fo
ur d
igit
card
s.
Use
an
y th
ree
of t
he n
umbe
rs t
o m
ake
th
e nu
mbe
r cl
ose
st t
o 6
00
1
10 4C8
Tom
buy
s a
box
of m
ini-c
upca
kes
with
12
vani
lla c
upca
kes
an
d 8
choc
olat
e cu
pcak
es.
Tom
bou
ght
som
e m
ore
boxe
s of
min
i-cup
cake
s fo
r th
e
scho
ol f
air.
He
had
40 c
hoco
late
cup
cake
s.
How
man
y va
nilla
cup
cake
s di
d he
ha
ve a
ltoge
ther
?
Aw
ard
two
mar
ks f
or t
he c
orre
ct a
nsw
er.
Aw
ard
on
e m
ark
for
a co
rrec
t m
etho
d, e
.g.
40 ÷
8 =
512
× 5
=
2
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201992
11 4F10
a(a
) D
ev c
an c
hoos
e
2 5 of
£20
1 4 of
£20
1 2 of
£10
Dev
cho
oses
the
larg
est
amou
nt.
Whi
ch a
mou
nt d
id D
ev c
hoos
e?
Dev
chose
2 5 o
f £
20
(b)
Expl
ain
Dev
’s ch
oice
2 5 o
f £
20
= £
8,
but
1 4 o
f £
20
and 1 2
of
£1
0
both
= £
5
(a)
1
(b)
1
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 93
12 4C6c
(a)
Ola
list
s th
e fa
ctor
s of
36
Writ
e th
e tw
o m
issi
ng f
acto
rs.
(b)
Ola
list
s so
me
of t
he f
acto
rs o
f a
diff
eren
t nu
mbe
r.
Wha
t co
uld
Ola
’s nu
mbe
r be
?
(a)
Bo
th n
umbe
rs n
eede
d fo
r aw
ard
of o
ne
mar
k.
(b)
Acc
ept
any
mul
tiple
of
24
(a)
1
(b)
1
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 36
2 1
8
3
12
4 9
6 6
24
3
4
6
8
Answers and mark schemes Year 4 © Hodder & Stoughton Limited 201994
13 4F9
Ja
y di
vide
s 58
by
10
Com
plet
e th
e se
nten
ce.
Ja
y sa
ys,
‘A
fter
I di
vide
58
by 1
0, t
he 8
will
be
wor
th
.‘
Acc
ept
.8D
o n
ot
acce
pt 5
.8 o
r 8
1
14 4F9
Circ
le b
oth
cal
cula
tions
tha
t gi
ve a
n an
swer
whe
re t
he 3
ha
s th
e va
lue
of t
hree
ten
ths.
36
÷ 1
0 =
36
÷ 1
00 =
63
÷ 1
0 =
63
÷ 1
00 =
Bo
th in
dica
ted
for
the
mar
k.A
ccep
t al
tern
ativ
e un
ambi
guou
s po
sitiv
e in
dica
tions
, e.
g. u
nder
lined
or
ticke
d.
1
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
8 10
, eig
ht
tenth
s or
0.8
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 4 95
15 4M7a
4M7b
Oliv
ia d
raw
s a
rect
angl
e w
ith a
leng
th o
f 12
cm
and
a w
idth
of
8 c
m.
Oliv
ia d
raw
s a
seco
nd r
ecta
ngle
, bu
t th
e le
ngth
is t
wic
e as
lo
ng.
(a)
Wha
t is
the
per
imet
er o
f O
livia
's s
econ
d re
ctan
gle?
(b)
Wha
t is
the
are
a of
Oliv
ia's
sec
ond
rect
angl
e?
(a)
1
(b)
1
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
64
cm
19
2
cm
2
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 201996
An
swer
s an
d m
ark
sch
emes
Yea
r 5
Pap
er 1
ari
thm
etic
: an
swer
s an
d m
ark
sch
eme
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 3N2b
155
− 10
0 =
55
1
2 3C2
87 −
35
= 5
21
3 3C6
4 ×
8 =
32
1
4 3C2
274
+ 56
4 =
83
81
5 5C2
322,
456
− 30
2,45
6 =
20
,00
0*
1
6 3C6
72 ÷
8 =
91
7 3F4
3 8 +
4 8 =
7 81
8 4C2
8,06
3 +
5,80
9 =
13
,87
2*
1
9 4C2
6,70
0 −
3,80
0 =
2,9
00
*1
10 4C7
716
× 3
= 2
,14
8*
1
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 97
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
11 4C6a
7 ×
6 =
42
1
12 4C6b
5 ×
4 ×
7 =
14
01
13 4F4
4 5 +
4 5 =
8 5 =
1 3 5
Acc
ept
8 51
14 4F10
a2 3
of 3
6 = 24
1
15 5C2
24,7
00 −
17,
900
= 6
,80
0*
1
16 5C5d
32 = 9
1
17 5F12
100%
of 5
0 =
50
1
18 4F10
a 3 4
of 2
0 = 1
51
19 5F12
25%
of
160
= 4
0
1
20 5C7b
8,67
6 ÷
4 =
2,1
69
*1
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 201998
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
21 5C7b
5,83
8 ÷
7 =
83
41
22 5F10
68.0
54 −
34.
781
= 3
3.2
73
1
23 5F4
4 5 −
3 10 =
5 10
OR 1 2
Acc
ept
any
equi
vale
nt f
ract
ion
or d
ecim
al.
1
24 5F4
2 3 +
7 12 =
15
12
OR 1
3 12
OR 1
1 4
Acc
ept
any
equi
vale
nt f
ract
ion
or d
ecim
al.
1
25 5F5
11 3
× 4
= 5
1 31
26 5C7a
56 ×
34
= 1
,90
4Se
e ad
ditio
nal m
arki
ng g
uida
nce.
2
27 5C7a
157
× 46
= 7
,22
2Se
e ad
ditio
nal m
arki
ng g
uida
nce.
2
28 4F9
0.4
5 =
45
÷ 10
0A
ccep
t .4
51
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 99
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Ad
dit
ion
al m
arki
ng
gu
idan
ce
26 5C7a
Aw
ard
two
mar
ks f
or t
he c
orre
ct a
nsw
er o
f 1,
904*
If th
e an
swer
is in
corr
ect,
aw
ard
on
e m
ark
for
evid
ence
of
usin
g fo
rmal
mul
tiplic
atio
n, w
hich
con
tain
s no
mor
e th
an o
ne
arith
met
ical
err
or.
Wor
king
mus
t be
car
ried
thro
ugh
for
the
awar
d of
on
e m
ark.
In
all
case
s, a
ccep
t a
follo
w-t
hrou
gh o
f o
ne
erro
r in
wor
king
, e.
g.
56
×3
42
04
16
80
18
84
Do
no
t aw
ard
any
mar
ks if
:•
the
erro
r is
in t
he p
lace
val
ue,
e.g.
om
issi
on o
f a
zero
w
hen
mul
tiply
ing
by t
ens,
e.g
.
56
×3
42
24
16
83
92
• th
e fin
al a
nsw
er li
ne o
f di
gits
is m
issi
ng,
e.g.
56
×3
42
24
16
80
forg
ettin
g to
add
the
2 c
arrie
d te
ns f
rom
6 ×
4
Pap
er 1
ari
thm
etic
: ad
dit
ion
al m
arki
ng
gu
idan
ceQ
ues
tio
ns
26 a
nd
27
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 2019100
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Ad
dit
ion
al m
arki
ng
gu
idan
ce
27 5C7a
Aw
ard
two
mar
ks f
or t
he c
orre
ct a
nsw
er o
f 7,
222*
If th
e an
swer
is in
corr
ect,
aw
ard
on
e m
ark
for
evid
ence
of
usin
g fo
rmal
mul
tiplic
atio
n, w
hich
con
tain
s no
mor
e th
an o
ne
arith
met
ical
err
or.
Wor
king
mus
t be
car
ried
thro
ugh
for
the
awar
d of
on
e m
ark.
In
all
case
s, a
ccep
t a
follo
w-t
hrou
gh o
f o
ne
erro
r in
wor
king
, e.
g.
15
7×
46
94
4
7 ×
6 ≠
446
28
07
22
4
Do
no
t aw
ard
any
mar
ks if
:•
the
erro
r is
in t
he p
lace
val
ue,
e.g.
om
issi
on o
f a
zero
w
hen
mul
tiply
ing
by t
ens,
e.g
.
15
7×
46
94
26
28
15
70
• th
e fin
al a
nsw
er li
ne o
f di
gits
is m
issi
ng,
e.g.
15
7×
46
94
26
28
0
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 101
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 3F3
Writ
e th
ese
frac
tions
in o
rder
, la
rges
t fir
st.
4
7 10
3 9 10
3
5 10
4 1 10
5
3 10
Acc
ept
equi
vale
nt f
ract
ions
or
deci
mal
s, e
.g.
53 10,
47 10,
41 10,
39 10,
35 10
1
Pap
er 2
rea
son
ing
: an
swer
s an
d m
ark
sch
eme
5 3 1
04
7 10
4 1 1
03
9 10
3 5 1
0
larg
est
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 2019102
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esti
on
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nte
nt
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n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
2 3S1
Gita
goe
s ru
nnin
g m
ost
days
.
This
tab
le s
how
s ho
w f
ar G
ita r
uns
each
day
dur
ing
one
wee
k.
This
bar
cha
rt s
how
s so
me
of t
he in
form
atio
n.
Use
the
info
rmat
ion
from
the
tabl
e to
com
plet
e th
e ba
r cha
rt.
Aw
ard
two
mar
ks f
or b
oth
Thu
rsda
y an
d Sa
turd
ay
bars
dra
wn
corr
ectly
on
the
grap
h.A
war
d o
ne
mar
k fo
r o
ne
bar
draw
n co
rrec
tly.
The
heig
ht o
f th
e ba
r m
ust
be d
raw
n to
the
ap
prop
riate
line
.Ig
nore
the
wid
th o
f th
e ba
r.A
war
d o
ne
mar
k fo
r tw
o co
rrec
t ba
rs d
raw
n fo
r Th
ursd
ay a
nd S
atur
day
and
any
bar
draw
n fo
r Tu
esda
y.
2
Gita
’s r
unni
ng r
ecor
d(D
ista
nces
in k
ilom
etre
s)
Sun
Mon
Tue
Wed
Thu
Fri
Sat
43
07
84
5
8 6 4 2
Sun
Mon
Tue
Wed
Thu
Fri
Sat
Dis
tan
ce
(km
)
Da
y
Git
a’s
ru
nn
ing
re
co
rd
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 103
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esti
on
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ber
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nte
nt
do
mai
n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
3 3G2
Circ
le t
he p
air
of li
nes
that
is p
aral
lel.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r tic
ked.
1
4 4M1
Writ
e th
ese
amou
nts
in o
rder
, st
artin
g w
ith t
he s
mal
lest
.
80p
£
0.89
£
9
£8
.90
9p
Acc
ept
a co
rrec
t co
nver
sion
of
units
, e.
g.
9p 8
0p 8
9p 8
90p
900p
If fo
ur a
mou
nts
are
corr
ect,
allo
w t
rans
crip
tion
erro
r of
the
fift
h am
ount
, e.
g. 9
p, 8
0p,
£0.9
8, £
8.90
, £9
Do
no
t ac
cept
rev
ersa
l of
amou
nts,
e.g
. £9
£8.
90 £
0.89
80p
9p
1
smal
lest
9p
80
p
£0
.89
£
8.9
0
£9
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 2019104
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esti
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ber
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nte
nt
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
5 4C8
A t
each
er g
ets
the
clas
sroo
m r
eady
for
an
art
less
on.
She
puts
out
5 s
mal
l pai
nt
bru
shes
for
eve
ry 3
larg
e
pai
nt
bru
shes
.
(a)
If sh
e pu
ts o
ut 1
0 sm
all p
aint
bru
shes
, ho
w m
any
la
rge
pain
t br
ushe
s do
es s
he p
ut o
ut?
(b)
If
she
puts
out
9 la
rge
pain
t br
ushe
s, h
ow m
any
smal
l pa
int
brus
hes
does
she
put
out
?
(c)
The
teac
her
buys
som
e ne
w b
rush
es.
Br
ushe
s co
me
in p
acks
of
8
Th
e te
ache
r bu
ys 1
2 pa
cks
of b
rush
es.
H
ow m
any
new
bru
shes
did
she
buy
?
(a)
1
(b)
1
(c)
1
6 la
rge
brus
hes
15
sm
all b
rush
es
96
bru
shes
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 105
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ber
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nte
nt
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n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
6 4N4b
A n
ew c
ruis
e sh
ip c
an c
arry
4,9
05 p
asse
nger
s an
d ha
s a
crew
of
1,4
71
Roun
d ea
ch o
f th
ese
num
bers
to
the
nea
rest
hu
nd
red
.
Pass
enge
rs
Cre
w
Aw
ard
on
e m
ark
for
each
cor
rect
ans
wer
.Ig
nore
com
ma
in a
nsw
er if
not
pla
ced
or
inco
rrec
tly p
lace
d.
2
7 4F1
Writ
e th
e ne
xt w
ho
le n
um
ber
in t
his
sequ
ence
.D
o n
ot
acce
pt 1
00 100
1
4,9
00
1,5
00
197 10
098 10
099 10
0
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 2019106
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esti
on
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nte
nt
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
8 5C8b
A f
acto
ry m
akes
640
ted
dy b
ears
.
520
of t
he b
ears
are
bro
wn.
The
rest
are
pin
k an
d bl
ue in
equ
al n
umbe
rs.
How
man
y pi
nk t
eddy
bea
rs a
re t
here
?
Aw
ard
two
mar
ks f
or t
he c
orre
ct a
nsw
er.
Aw
ard
on
e m
ark
for
a co
rrec
t m
etho
d, e
.g.
640
− 52
0 =
120
120
÷ 2
=
2
9 5C6b
Find
the
mis
sing
num
bers
.
(a
)
8.1
÷
= 0
.081
(b
)
×
1,0
00 =
180
(b)
Acc
ept
.18
or 0
.180
(a)
1
(b)
1
60
pin
k te
dd
y b
ears
10
0
0.1
8
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 107
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ber
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nte
nt
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n
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esti
on
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nsw
erM
arki
ng
gu
idan
ceM
ark
10 5F12
Fay
and
Izzy
sit
the
sam
e m
athe
mat
ics
test
.
Fay
says
,
‘I
got
60%
.’
Izzy
say
s,
‘I
got
seve
n ou
t of
ten
.’
Expl
ain
who
got
the
hig
her
sco
re.
Aw
ard
on
e m
ark
for
a co
rrec
t ex
plan
atio
n.1
e.g.
lzzy
got
the
hig
her
sco
re b
ecause
:
eith
er s
even
out
of
ten
=
7 10
= 7
0%
and 7
0%
> 6
0%
OR 6
0%
=
6 10
(=
six
out
of
ten)
and
6 10
or
6 o
ut
of
10
<
7 10
or
7 o
ut
of
10
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 2019108
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esti
on
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ber
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nte
nt
do
mai
n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
11 5G3b
Tick
the
tw
o t
ypes
of
2-D
sha
pes
that
mak
e th
e fa
ces
of
this
tria
ngul
ar p
rism
.
Tria
ngle
s
Para
llelo
gram
s
Rhom
buse
s
Rect
angl
es
Bo
th s
hape
s in
dica
ted
and
no o
ther
s, f
or t
he a
war
d of
on
e m
ark.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d.
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 109
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ber
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nte
nt
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n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
12 5G2a
The
diag
onal
s of
a r
ecta
ngle
are
dra
wn.
64°
b
Wha
t is
the
siz
e of
ang
le b
?
6
4
°
1
13 3N3
This
is a
sor
ting
diag
ram
for
num
bers
with
3 t
ens
and
3 o
nes
.
Writ
e th
ese
num
bers
into
the
sor
ting
diag
ram
.
321
231
13
3 2
13
333
3 te
ns3
ones
2
31
1
33
2
13
3
33
3
21
Aw
ard
two
mar
ks f
or fi
ve c
orre
ctly
pla
ced
num
bers
.A
war
d o
ne
mar
k fo
r tw
o,
thre
e or
fo
ur
corr
ectly
pl
aced
num
bers
.
2
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 2019110
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nt
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n
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esti
on
& a
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erM
arki
ng
gu
idan
ceM
ark
14 5F6a
(a)
Cha
nge
0.89
to
a fr
acti
on
.
(b)
Cha
nge
89 1000
to
a d
ecim
al.
(b)
Acc
ept
.089
(a)
1
(b)
1
15 5F10
The
popu
latio
n of
Lon
don
in 2
001
was
7.1
72 m
illio
n.
The
popu
latio
n of
Lon
don
in 2
015
was
8.5
39 m
illio
n.
Wha
t w
as t
he in
crea
se in
the
pop
ulat
ion?
1.3
67
m
illio
n
Acc
ept
1,36
7,00
01
89
10
0
0.0
89
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 111
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ber
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nte
nt
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n
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esti
on
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nsw
erM
arki
ng
gu
idan
ceM
ark
16 5M6
Sam
ir sa
ys,
‘I am
five
fee
t ta
ll.’
Use
thi
s ta
ble
to w
ork
out
Sam
ir’s
heig
ht in
met
res.
Leng
th
1 fo
ot =
12
inch
es
1 in
ch =
2.5
cm
100
cm =
1 m
1.5
met
res
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.5
× 12 =
60
60 ×
2.5
= 15
015
0 ÷ 10
0 =
Acc
ept
1.5
(met
res)
or
150
cm
2
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 2019112
Pap
er 3
rea
son
ing
: an
swer
s an
d m
ark
sch
eme
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 4N1
In t
his
tabl
e, m
ultip
les
of 6
are
writ
ten
to t
he r
ight
and
m
ultip
les
of 7
are
writ
ten
dow
nwar
ds.
Ther
e ar
e fo
ur
mis
sing
num
bers
. W
rite
the
mis
sing
nu
mbe
rs in
the
box
es.
Mu
ltip
les
of
6
Mu
ltip
les
of
735 42
66
49 70
3660
48
56
63
54
Aw
ard
two
mar
ks f
or f
ou
r co
rrec
t nu
mbe
rs.
Aw
ard
on
e m
ark
for
thre
e co
rrec
t nu
mbe
rs.
2
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 113
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esti
on
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ber
&
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nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
2 3G3b
(a)
This
is a
dra
win
g of
a 3
-D s
hape
.
Tick
the
nam
e of
the
sha
pe.
C
ube
C
uboi
d
C
one
C
ylin
der
Re
ctan
gle
(b)
Com
plet
e th
is s
ente
nce
with
the
nam
e of
a 2
-D s
hape
.
A
tr
iangle
is t
he m
ost
com
mon
fac
e in
any
pyr
amid
.
(a)
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d.
(b)
Acc
ept
any
unam
bigu
ous
spel
ling.
(a)
1
(b)
1
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 2019114
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esti
on
n
um
ber
&
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nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
3 4C4
At
the
begi
nnin
g of
Mar
ch, a
sho
p ha
d 37
8 T-
shirt
s in
sto
ck.
It re
ceiv
ed a
del
iver
y of
475
mor
e T-
shirt
s
in M
arch
.
Dur
ing
Mar
ch, 6
17 T
-shi
rts
wer
e so
ld.
How
man
y T-
shirt
s w
ere
in s
tock
at
the
end
of M
arch
?
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.(3
78 +
475
) − 6
17 =
2
4 5F3
Four
chi
ldre
n ra
ise
mon
ey f
or a
cha
rity.
Tick
the
chi
ld w
ho r
aise
d th
e m
ost
mon
ey.
3 20 o
f th
e m
oney
was
rai
sed
by O
llie.
7 20 o
f th
e m
oney
was
rai
sed
by E
wan
.
3 10 o
f th
e m
oney
was
rai
sed
by M
ia.
1 5 of
the
mon
ey w
as r
aise
d by
Ola
.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d.1
23
6 T
-shi
rts
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 115
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
5 3C3
Dan
ny c
ompl
etes
335
÷ 5
He
wan
ts t
o ch
eck
his
answ
er.
Tick
the
cal
cula
tion
Dan
ny u
ses
to c
heck
his
ans
wer
.
33
5 ×
5 =
1,67
5
67
× 5
= 3
35
5
÷ 33
5 =
67
67
÷ 5
= 3
35
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d.
1
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 2019116
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
6 3F2
Circ
le t
he t
wo
sha
pes
that
sho
w 3 5 s
hade
d.
Bo
th s
hape
s, a
nd n
o ot
hers
, in
dica
ted
for
on
e m
ark.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r tic
ked.
1
7 3M9a
Ada
m b
uys
a pa
ck o
f fe
lt tip
pen
s fo
r £4
and
tw
o pe
ns f
or
£2 e
ach
.
How
muc
h ch
ange
will
he
get
from
£20
?
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.20
− (4
+ 2
× 2
) =
2
£1
2 /
£1
2.0
0
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 117
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
8 4S2
This
gra
ph s
how
s th
e nu
mbe
r of
ice
crea
ms
sold
in o
ne w
eek.
How
man
y ic
e cr
eam
s w
ere
sold
on
Satu
rday
and
Sun
day
alto
get
her
?
27
0
ice
crea
ms
1
150
125
100 75 50 25 0
Mon
Tue
Wed
Thu
Fri
Sat
Sun
Nu
mb
er o
f ic
e cr
eam
s so
ld
Day
s o
f th
e w
eek
Ice
crea
m s
ales
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 2019118
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esti
on
n
um
ber
&
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nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
9 4N3b
5N
3b
Dra
w li
nes
betw
een
the
Rom
an n
umer
als
and
thei
r eq
uiva
lent
in n
umbe
rs.
Aw
ard
two
mar
ks f
or fi
ve c
orre
ct li
nes.
Aw
ard
on
e m
ark
for
fou
r co
rrec
t lin
es.
2
10 5F7
4F7
Roun
d ea
ch n
umbe
r in
thi
s ta
ble
to t
he n
eare
st
wh
ole
nu
mb
er.
Aw
ard
two
mar
ks f
or t
hre
e co
rrec
t an
swer
s.A
war
d o
ne
mar
k fo
r tw
o c
orre
ct a
nsw
ers.
For
5 ac
cept
5.0
or
5.00
For
52 a
ccep
t 52
.0 o
r 52
.00
For
516
acce
pt 5
16.0
or
516.
00
2
CM
10
1
CI
900
LV
6
DX
51
0
VI
55
Roun
ded
to t
he n
eare
st
who
le n
umbe
r
5
.
1 6
5
1
.
6 2
5
1 6
.
2
5 52
51
6
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 119
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esti
on
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ber
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nte
nt
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n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
11 5C7b
A s
choo
l org
anis
es a
vis
it to
the
the
atre
for
368
peo
ple.
8 bu
ses
are
orga
nise
d.
An
equa
l num
ber
of p
eopl
e si
t on
eac
h bu
s.
How
man
y pe
ople
are
on
each
bus
?
1
12 4F6b
This
dra
win
g re
pres
ents
1
Wha
t de
cim
al n
umbe
r do
es t
he d
raw
ing
belo
w r
epre
sent
?
1
46
p
eopl
e
2.3
9
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esti
on
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ber
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nte
nt
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n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
13 5F2a
Noa
h bu
ys s
ome
pizz
as f
or a
par
ty.
He
cuts
the
piz
zas
into
pie
ces.
Each
pie
ce is
1 8 of
a pi
zza.
He
has
32 8
How
man
y pi
zzas
did
Noa
h bu
y?
1
14 5F5
Nis
hi h
as 6
jugs
.
Each
jug
is fi
lled
with
11 4 li
tres
of
wat
er.
How
man
y lit
res
has
Nis
hi a
lto
get
her
?
Acc
ept
7.5
litre
s.1
4 p
izza
s
1 li
tre
1 li
tre
1 li
tre
1 li
tre
1 li
tre
1 li
tre
1 27
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 121
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
15 5C8a
Dev
say
s,
‘I kn
ow 1
0, 2
0, 3
0 an
d al
l mul
tiple
s of
10
are
also
mul
tiple
s of
5.’
Max
the
n sa
ys,
‘So
all m
ultip
les
of 5
will
hav
e a
fact
or o
f 10
.’
Expl
ain
why
Max
is n
ot
corr
ect.
Aw
ard
on
e m
ark
for
a co
unte
r ex
ampl
e, e
.g.
5 is
a f
acto
r of
15,
but
10
is n
ot.
1
16 5M4
Kat
ie a
nd M
anis
ha r
an a
rac
e.
Kat
ie t
ook
3 m
inu
tes
53 s
eco
nd
s.
Man
isha
too
k 4
min
ute
s 8
seco
nd
s.
How
man
y se
con
ds
qu
icke
r w
as K
atie
tha
n M
anis
ha?
15
se
cond
s
1
Acc
ept
an
expla
natio
n sh
owin
g
som
e m
ultip
les
of 5
have
5 o
nes
and
num
ber
s w
ith 5
one
s ca
nnot
ha
ve 1
0 a
s a f
act
or.
Answers and mark schemes Year 5 © Hodder & Stoughton Limited 2019122
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esti
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ber
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nte
nt
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mai
n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
17 5F4
Ned
add
s tw
o fr
actio
ns t
o m
ake
a to
tal o
f 7 10
Ther
e ar
e di
ffer
ent
frac
tions
he
coul
d ha
ve u
sed.
Writ
e tw
o p
ossi
ble
num
erat
ors
for
Ned
’s ad
ditio
n.
Acc
ept
any
of
the
follo
win
g:
• • •
Do
no
t ac
cept
num
bers
in t
he r
ever
se o
rder
.1
510
+= = =
510
107 107107
+
510
+
1 2 3
5 3 1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 5 123
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esti
on
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ber
&
co
nte
nt
do
mai
n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
18 5M5
Jug
A a
nd ju
g B
both
con
tain
a li
quid
.
2 l
itre
s
1 l
itre
500m
l
Ju
g A
Ju
g B
How
muc
h m
ore
liq
uid
is t
here
in ju
g A
tha
n in
jug
B?
1.1
(00
) li
tres
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.
Aw
ard
on
e m
ark
for
sigh
t of
eith
er 1
.5 (l
itres
) /
1,50
0 (m
l) or
0.4
(litr
es) /
400
(ml)
as a
cor
rect
re
adin
g of
eith
er s
cale
.
Acc
ept
1.1(
00) (
litre
s) o
r 1,
100
(ml)
2
Answers and mark schemes Year 6 © Hodder & Stoughton Limited 2019124
An
swer
s an
d m
ark
sch
emes
Yea
r 6
Pap
er 1
ari
thm
etic
: an
swer
s an
d m
ark
sch
eme
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 3C2
89 +
876
+ 9
4 =
1,0
59
*1
2 3F1b
1 2 of
900
= 4
50
1
3 4C2
8,36
0 –
3,77
0 =
4,5
90
*1
4 4C2
4,70
0 +
3,9
00 =
8,6
00
*1
5 4C6a
12
× 4
= 6
× 8
1
6 4C6a
63
÷ 7
= 9
1
7 4C7
562
× 3
= 1
,68
6*
1
8 4C7
746
× 6
= 4
,47
6*
1
9 3F4
11 12 –
4 12
= 7 12
1
10 4F4
7 8 +
4 8 =
13 8
Acc
ept
11 81
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 6 125
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
11 5C2
61,7
00 –
33,
000
= 2
8,7
00
*1
12 5F10
12
9.1
6 =
46.
32 +
82.
841
13 4C7
720
× 4
= 2
,88
0*
1
14 5C7b
865
÷ 5
= 1
73
1
15 5F4
2 3 4
– 1 4
= 2
1 2A
ccep
t 2 2 4
or
equi
vale
nt.
1
16 6F9b
0.8
× 4
= 3
.21
17 6F9b
0.07
× 7
= 0
.49
1
18 6C9
90 +
6 ×
5 =
12
01
19 6C7a
687
× 4
7 =
32
,28
9Se
e ad
ditio
nal m
arki
ng g
uida
nce.
2
20 6C7a
7,69
3 ×
86
= 6
61
,59
8Se
e ad
ditio
nal m
arki
ng g
uida
nce.
2
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
Answers and mark schemes Year 6 © Hodder & Stoughton Limited 2019126
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
21 6F4
5 4 5
+ 2 3
= 6
7 15
Acc
ept
any
equi
vale
nt f
ract
ion.
1
22 6C7b
1,97
6 ÷
38
= 5
2Se
e ad
ditio
nal m
arki
ng g
uida
nce.
2
23 6C7b
6,86
2 ÷
73
= 9
4Se
e ad
ditio
nal m
arki
ng g
uida
nce.
2
24 6F5b
3 5 ÷
9 =
3 45
Acc
ept
any
equi
vale
nt f
ract
ion
or e
xact
dec
imal
i.e
. 0.
061
25 6F5b
3 4 ÷
7 =
3 28
Acc
ept
any
equi
vale
nt f
ract
ion
or e
xact
dec
imal
,
i.e.
0.75
1
26 6C8
500,
000
– 50
0.05
= 4
99
,49
9.9
5*
1
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 6 127
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Ad
dit
ion
al m
arki
ng
gu
idan
ce
19 6C7a
Aw
ard
two
mar
ks f
or t
he c
orre
ct a
nsw
er o
f 32
,289
*
If th
e an
swer
is in
corr
ect,
aw
ard
on
e m
ark
for
evid
ence
of
usin
g a
form
al m
etho
d of
mul
tiplic
atio
n, w
hich
con
tain
s no
m
ore
than
on
e ar
ithm
etic
err
or.
Wor
king
mus
t be
car
ried
thro
ugh
for
the
awar
d of
on
e m
ark.
In
all
case
s, a
ccep
t a
follo
w-t
hrou
gh o
f on
e er
ror
in w
orki
ng, e
.g.
68
7×
47
49
89
8 ×
7 ≠
54
and
6 ×
7 ≠
44
27
48
03
24
69
Do
no
t aw
ard
any
mar
ks if
:•
the
erro
r is
in t
he p
lace
val
ue,
e.g.
68
7×
47
48
09
27
48
75
57
• th
e fin
al a
nsw
er li
ne o
f di
gits
is m
issi
ng,
e.g.
68
7×
47
48
09
27
48
0
Pap
er 1
ari
thm
etic
: ad
dit
ion
al m
arki
ng
gu
idan
ceQ
ues
tio
ns
19, 2
0, 2
2 an
d 2
3
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
Answers and mark schemes Year 6 © Hodder & Stoughton Limited 2019128
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Ad
dit
ion
al m
arki
ng
gu
idan
ce
20 6C7a
Aw
ard
two
mar
ks f
or t
he c
orre
ct a
nsw
er o
f 66
1,59
8*
If th
e an
swer
is in
corr
ect,
aw
ard
on
e m
ark
for
evid
ence
of
usin
g a
form
al m
etho
d of
mul
tiplic
atio
n, w
hich
con
tain
s no
m
ore
than
on
e ar
ithm
etic
err
or.
Wor
king
mus
t be
car
ried
thro
ugh
for
the
awar
d of
on
e m
ark.
In
all
case
s, a
ccep
t a
follo
w-t
hrou
gh o
f o
ne
erro
r in
wor
king
, e.
g.
76
93
×8
64
61
58
61
54
40
65
15
98
46,1
58 +
615
,440
≠ 6
51,5
98
Do
no
t aw
ard
any
mar
ks if
:•
the
erro
r is
in t
he p
lace
val
ue,
e.g.
76
93
×8
64
61
58
61
54
41
07
70
2
• th
e fin
al a
nsw
er li
ne o
f di
gits
is m
issi
ng,
e.g.
76
93
×8
64
61
58
61
54
40
*Ign
ore
com
ma
in a
nsw
er if
not
pla
ced
or in
corre
ctly
pla
ced.
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 6 129
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Ad
dit
ion
al m
arki
ng
gu
idan
ce
22 6C7b
Aw
ard
two
mar
ks fo
r the
cor
rect
ans
wer
of 5
2
If th
e an
swer
is in
corr
ect,
aw
ard
on
e m
ark
for
evid
ence
of
usin
g a
form
al m
etho
d, w
hich
con
tain
s no
mor
e th
an o
ne
arith
met
ic e
rror
.
Wor
king
mus
t be
car
ried
thro
ugh
for
the
awar
d of
on
e m
ark.
In
all c
ases
, acc
ept
a fo
llow
-thr
ough
of
on
e er
ror
in w
orki
ng, e
.g.
54
r24
381
97
61
80
197
÷ 3
8 ≠
5 r 1
71
76
15
22
4O
R
52
r30
381
97
61
90
(50
× 3
8)1
06
197
– 19
0 ≠
107
6(2
× 2
8)3
0O
R
46
r28
25
381
97
619
7 ÷
38
≠ 4
r 25
Do
no
t aw
ard
any
mar
ks if
:•
the
final
ans
wer
line
is m
issi
ng,
e.g.
381
97
61
90 7
67
6 0
• an
info
rmal
met
hod
is u
sed,
e.g
. us
ing
repe
ated
su
btra
ctio
n of
equ
al g
roup
s:
53
r22
381
97
67
60
(20
× 3
8)1
21
67
60
(20
× 3
8)4
56
38
0(1
0 ×
38)
13
645
6 –
380
≠ 13
67
6(2
× 3
8)6
03
8(1
× 3
8)2
2
Answers and mark schemes Year 6 © Hodder & Stoughton Limited 2019130
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Ad
dit
ion
al m
arki
ng
gu
idan
ce
23 6C7b
Aw
ard
two
mar
ks fo
r the
cor
rect
ans
wer
of 9
4
If th
e an
swer
is in
corr
ect,
aw
ard
on
e m
ark
for
evid
ence
of
usin
g a
form
al m
etho
d, w
hich
con
tain
s no
mor
e th
an o
ne
arith
met
ic e
rror
.
Wor
king
mus
t be
car
ried
thro
ugh
for
the
awar
d of
one
mar
k.
In a
ll ca
ses,
acc
ept
a fo
llow
-thr
ough
of
one
erro
r in
wor
king
, e.g
.
94
r20
736
86
26
57
31
268
6 ÷
73
≠ 9
r 31
29
22
0O
R
95
r27
736
86
26
47
090
× 7
3 ≠
6470
39
23
65
27
OR
95 29
736
86
229
2 ÷
73
≠ 5
Do
no
t aw
ard
any
mar
ks if
:•
the
final
ans
wer
line
is m
issi
ng,
e.g.
736
86
26
57
29
22
92 0
• an
info
rmal
met
hod
is u
sed,
e.g
. us
ing
repe
ated
su
btra
ctio
n of
equ
al g
roup
s:
94
r 2
736
86
26
57
0(9
0 ×
73)
29
21
46
(2 ×
73)
14
8(2
92 –
146
≠ 1
48)
14
6(2
× 7
3)2
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 6 131
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 4N2a
Writ
e th
e nu
mbe
rs in
ord
er,
smal
lest
firs
t.
4,28
02,
804
4,82
02,
408
2,4
08
2,8
04
4,2
80
4,8
20
smal
lest
Igno
re c
omm
a in
ans
wer
s if
not
plac
ed o
r
inco
rrec
tly p
lace
d.1
2 5N5
This
tab
le s
how
s th
e te
mpe
ratu
res
in d
iffer
ent
citie
s on
e da
y.
City
Lond
onBi
rmin
gham
Car
diff
Man
ches
ter
Gla
sgow
Tem
pera
ture
0°C
2°C
–1°C
–2°C
1°C
Tick
the
city
tha
t ha
s th
e co
ldes
t te
mpe
ratu
re.
Lond
on
Birm
ingh
am
Car
diff
Man
ches
ter
Gla
sgow
Acc
ept
alte
rnat
ive
unam
bigu
ous
indi
catio
ns,
e.g.
un
derli
ned
or c
ircle
d, in
clud
ing
in t
he t
able
. 1
Pap
er 2
rea
son
ing
: an
swer
s an
d m
ark
sch
eme
Answers and mark schemes Year 6 © Hodder & Stoughton Limited 2019132
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
3 4M4a
Dra
w li
nes
to m
atch
the
equ
ival
ent
times
.
te
n pa
st fi
ve
3:50
te
n to
fou
r
5:
10
fiv
e pa
st t
en
4:55
fiv
e to
five
10
:05
Aw
ard
two
mar
ks f
or f
ou
r co
rrec
t lin
es.
Aw
ard
on
e m
ark
for
two
or
thre
e co
rrec
t lin
es.
2
4 3N3
7
8
9H
ere
are
thre
e di
gits
.
Arr
ange
the
dig
its t
o m
ake
a th
ree-
digi
t nu
mbe
r w
ith
seve
n t
ens.
87
9 O
R 9
78
1
5 3F1c
Har
ry h
as £
32
He
spen
ds 3 4
of
his
mon
ey.
How
muc
h m
oney
has
he
spen
t?
£
2
4
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 6 133
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esti
on
n
um
ber
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co
nte
nt
do
mai
n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
6 3C7
Her
e ar
e th
ree
digi
t ca
rds.
36
9
Use
the
thr
ee d
igit
card
s to
mak
e th
is m
ultip
licat
ion
corr
ect.
3
9
×
6
2
3
4
All
thre
e nu
mbe
rs c
orre
ct f
or t
he a
war
d of
o
ne
mar
k.1
Answers and mark schemes Year 6 © Hodder & Stoughton Limited 2019134
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esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
7 4S2
This
bar
cha
rt s
how
s th
e go
als
scor
ed b
y an
d ag
ains
t a
foot
ball
team
.
01
23
45
6
2468101214
Foo
tbal
l tea
m r
esu
lts
Wee
k
Go
als
sco
red
Go
als
sco
red
by
the
team
Go
als
sco
red
agai
nst
th
e te
am
(a)
How
man
y go
als
wer
e sc
ored
ag
ain
st t
he t
eam
in
the
gam
es?
18
goa
ls
(b)
How
man
y m
ore
goa
ls d
id t
he t
eam
sco
re
in W
eek
5 th
an in
Wee
k 2?
7 g
oals
(a)
1
(b)
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 6 135
Qu
esti
on
n
um
ber
&
co
nte
nt
do
mai
n
Qu
esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
8 5C6b
Writ
e th
e m
issi
ng n
umbe
rs in
the
box
es.
Aw
ard
two
mar
ks f
or t
hre
e co
rrec
t an
swer
s.A
war
d o
ne
mar
k fo
r tw
o c
orre
ct a
nsw
ers.
2
9 5F7
Com
plet
e th
is t
able
by
rou
nd
ing
the
num
bers
.
Roun
ded
to o
ne
deci
mal
pla
ceRo
unde
d to
the
ne
ares
t w
hole
nu
mbe
r
48.2
74
8.3
48
559.
725
59
.75
60
Aw
ard
two
mar
ks f
or f
ou
r co
rrec
t an
swer
s.A
war
d o
ne
mar
k fo
r th
ree
corr
ect
answ
ers.
For
•48
.3
acce
pt 4
8.30
•48
acce
pt 4
8.0
or 4
8.00
•55
9.7
acce
pt 5
59.7
0•
560
acce
pt 5
60.0
or
560.
00
2
50
6÷
10
= 5
0.6
50
.6×
100
= 5
,060
50
6÷
100
= 5
.06
Answers and mark schemes Year 6 © Hodder & Stoughton Limited 2019136
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esti
on
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um
ber
&
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nte
nt
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n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
10 6G2b
Each
3-D
sha
pe is
nam
ed.
Tria
ng
ula
r-b
ased
Tr
ian
gu
lar
pri
sm
Squ
are-
bas
ed
p
yram
id
p
yram
id
Com
plet
e th
is t
able
of
info
rmat
ion
abou
t th
e th
ree
shap
es.
Som
e nu
mbe
rs h
ave
been
writ
ten
in f
or y
ou.
Tria
ngul
ar-b
ased
py
ram
idTr
iang
ular
pr
ism
Squa
re-b
ased
py
ram
id
Vert
ices
46
5
Edge
s6
98
Face
s4
55
Aw
ard
two
mar
ks f
or s
ix c
orre
ct a
nsw
ers.
Aw
ard
on
e m
ark
for
fou
r or
five
cor
rect
ans
wer
s.2
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 6 137
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esti
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ber
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nte
nt
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n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
11 6F9c
Four
frie
nds
have
a m
eal i
n a
rest
aura
nt.
Ali’
s m
eal c
osts
£18
.85
Ben’
s m
eal c
osts
£17
.65
Cal
lum
’s m
eal c
osts
£17
.15
Dev
’s m
eal c
osts
£17
.35
They
dec
ide
to s
hare
the
cos
t eq
ual
ly.
How
muc
h do
the
y ea
ch p
ay?
£
1
7.7
5
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.
(18.
85 +
17.
65 +
17.
15 +
17.
35)
÷ 4
=
2
Answers and mark schemes Year 6 © Hodder & Stoughton Limited 2019138
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esti
on
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um
ber
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nte
nt
do
mai
n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
12 6A2
Max
kno
ws
ther
e ar
e di
ffer
ent
form
ulae
to
find
the
perim
eter
of
a r
ecta
ngle
.
In t
he f
orm
ulae
, l =
leng
th a
nd w
= w
idth
.
Tick
the
for
mul
a th
at M
ax c
ould
no
t us
e to
find
the
pe
rimet
er o
f a
rect
angl
e.
4(
l + w
)
2(l +
w)
2l
+ 2
w
l +
l +
w +
w
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d.
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 6 139
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esti
on
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um
ber
&
co
nte
nt
do
mai
n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
13 6M9
Josh
nee
ds s
ome
new
kitc
hen
units
.
He
is g
oing
to
fit t
he u
nits
alo
ng a
wal
l tha
t is
3.8
25 m
etre
s lo
ng.
Each
uni
t is
600
mill
imet
res
wid
e.
How
man
y un
its w
ill J
osh
be a
ble
to fi
t al
ong
the
wal
l?
6
u
nit
s
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.3.
825
× 1
,000
= 3
,825
3,82
5 ÷
600
=
OR
Aw
ard
on
e m
ark
for
sigh
t of
3,8
25 O
R 0.
6 O
R 3.
6
2
Answers and mark schemes Year 6 © Hodder & Stoughton Limited 2019140
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ber
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nte
nt
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n
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esti
on
& a
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erM
arki
ng
gu
idan
ceM
ark
14 6A4
Nis
ha t
akes
4 p
acka
ges
to t
he p
ost
offic
e.
She
has
1 he
avie
r pa
ckag
e an
d 3
iden
tical
ligh
ter
pack
ages
. The
pa
ckag
es w
eigh
15
kilo
gram
s in
tot
al.
Each
pac
kage
wei
ghs
a w
hole
num
ber
of k
ilogr
ams.
Wha
t co
uld
the
pack
ages
wei
gh?
Hea
vier
pac
kage
=
12
k
g
Ligh
ter
pack
age
=
1
kg
Acc
ept:
• he
avie
r pa
ckag
e =
9 (
kg)
and
light
er p
acka
ge =
2 (
kg)
OR
• he
avie
r pa
ckag
e =
6 (
kg)
and
light
er p
acka
ge =
3 (
kg)
Do
no
t ac
cept
hea
vier
pac
kage
= 3
(kg
) an
d lig
hter
pa
ckag
e =
4 (
kg)
1
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 6 141
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nte
nt
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n
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esti
on
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nsw
erM
arki
ng
gu
idan
ceM
ark
15 6F5a
6F
5b
A t
each
er h
as a
jar
of c
ount
ers.
The
coun
ters
are
diff
eren
t co
lour
s an
d so
me
are
larg
e an
d so
me
are
smal
l.
1 4 o
f th
e co
unte
rs a
re r
ed a
nd 1 2
of
the
red
coun
ters
are
larg
e.
Ben
and
Tom
sha
re t
he la
rge,
red
cou
nter
s eq
ually
.
Wha
t fr
acti
on
of
the
jar
of c
ount
ers
does
Ben
hav
e? 1 16
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.
1 4 ×
1 2 =
1 8
1 8 ÷
2 =
2
Answers and mark schemes Year 6 © Hodder & Stoughton Limited 2019142
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esti
on
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ber
&
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nte
nt
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esti
on
& a
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erM
arki
ng
gu
idan
ceM
ark
16 6R4
A r
ugby
gro
und
can
hold
9,5
68 s
pect
ator
s.
Ther
e ar
e se
ats
for
3 4 o
f th
e sp
ecta
tors
.
The
rest
sta
nd.
(a)
How
man
y se
ats
are
ther
e fo
r sp
ecta
tors
?
(b)
At
a m
atch
, 3 4
of
the
seat
s ar
e ta
ken.
How
man
y em
pty
sea
ts a
re t
here
?
(a)
Igno
re c
omm
a in
ans
wer
if n
ot p
lace
d or
in
corr
ectly
pla
ced.
(b)
Acc
ept
a co
rrec
t fo
llow
-thr
ough
fro
m t
he a
nsw
er
give
n in
16(
a),
incl
udin
g co
rrec
tly r
ound
ed
answ
ers.
Ig
nore
com
ma
in a
nsw
er if
not
pla
ced
or
inco
rrec
tly p
lace
d.
(a)
1
(b)
1
7,1
76
sea
ts
1,7
94
sea
ts
© Hodder & Stoughton Limited 2019 Answers and mark schemes Year 6 143
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esti
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ber
&
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nte
nt
do
mai
n
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esti
on
& a
nsw
erM
arki
ng
gu
idan
ceM
ark
1 5N1
Writ
e th
e nu
mbe
r th
at c
omes
nex
t in
thi
s se
quen
ce.
516,
245
51
7,24
5
518,
245
51
9,24
5 52
0,2
45
Igno
re c
omm
a in
ans
wer
if n
ot p
lace
d or
inco
rrec
tly
plac
ed.
1
2 4N4b
4,29
0 pe
ople
att
end
a co
ncer
t.
A n
ewsp
aper
hea
dlin
e ro
unds
thi
s nu
mbe
r to
the
n
eare
st h
un
dre
d.
Writ
e th
e nu
mbe
r in
the
hea
dlin
e.
4,3
00
Igno
re c
omm
a in
ans
wer
if n
ot p
lace
d or
inco
rrec
tly
plac
ed.
1
Pap
er 3
rea
son
ing
: an
swer
s an
d m
ark
sch
eme
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3 3C4
A s
hopk
eepe
r bu
ys 5
00 t
ins
of s
oup.
325
of t
he t
ins
are
tom
ato
soup
and
the
res
t ar
e
vege
tabl
e so
up.
The
shop
keep
er s
ells
125
tin
s of
veg
etab
le s
oup.
How
man
y tin
s of
veg
etab
le s
oup
are
left
?
50
tin
s
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.
500
– 32
5 =
175
17
5 –
125
=
2
4 3F10
Sam
doe
s so
me
of h
is h
omew
ork
on F
riday
, so
me
on S
atur
day
and
finis
hes
it on
Sun
day.
He
com
plet
es
1 12 o
n Fr
iday
and
7 12
on
Satu
rday
.
Wha
t fr
actio
n of
his
hom
ewor
k m
ust
he c
ompl
ete
on
Sund
ay t
o fin
ish
his
hom
ewor
k?
Acc
ept
any
equi
vale
nt f
ract
ion.
1
4 12
1 3O
R
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5 5F2a
Dra
w a
line
to
join
eac
h m
ixed
num
ber
to it
s eq
uiv
alen
t
impr
oper
fra
ctio
n.
Aw
ard
two
mar
ks f
or fi
ve c
orre
ct li
nes.
Aw
ard
on
e m
ark
for
thre
e or
fo
ur
corr
ect
lines
.
2
3 533 5
5 825 8
5 813 8
1 821 8
3 518 5
3 2 1 3 6
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6
4M7a
4M7b
Layl
a’s
gard
en is
a r
ecta
ngul
ar s
hape
.
It is
20
met
res
long
and
12
met
res
wid
e.
(a)
Wha
t is
the
per
imet
er o
f La
yla’
s ga
rden
?
64
m
(b)
Wha
t is
the
are
a of
Lay
la’s
gard
en?
24
0
m2
(a)
1
(b)
1
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7 5C5a
5C
5b
Use
the
num
bers
in t
he b
oxes
to
com
plet
e th
e
sent
ence
s be
low
.
You
can
use
a nu
mbe
r m
ore
than
onc
e.
8
9
10
11
12
13
8 a
nd
12
are
bot
h fa
cto
rs o
f 24
11
and
1
3 a
re p
rim
e n
um
ber
s.
9 a
nd
12
are
mu
ltip
les
of 3
Acc
ept
answ
ers
in e
ither
ord
er.
1
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8 5G4b
Four
ang
les
mee
t at
a p
oint
.
68°
48°
a
Find
the
ang
le m
arke
d a.
15
4
°
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.36
0 –
(90
+ 6
8 +
48)
=
2
9 6A3
This
seq
uenc
e of
num
bers
fol
low
s th
is r
ule:
Mu
ltip
ly b
y 4
and
div
ide
by
2.
(a
) Fi
ll in
the
mis
sing
num
bers
.
4
8
16
32
(b)
Writ
e an
othe
r ru
le t
hat
give
s th
e sa
me
seq
uen
ce
of n
umbe
rs.
(b)
Acc
ept
othe
r eq
uiva
lent
rul
es.
A
ccep
t ‘a
dd e
ight
’ or
‘+
8’ if
0 a
nd 2
4 ar
e w
ritte
n in
the
box
es in
par
t (a
).
(a)
1
(b)
1
Multip
ly b
y 2
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10 6C9
Tick
bo
th c
alcu
latio
ns t
hat
have
an
answ
er o
f 50
30 –
5 ×
2 =
(60
+ 4
0) ÷
2 =
(10
+ 5
0) ÷
2 +
15
=
(60
– 30
– 5
) ×
2 =
10 +
15
× 2
=
Aw
ard
two
mar
ks f
or b
oth
cor
rect
box
es,
and
no
othe
rs,
indi
cate
d on
ly.A
war
d o
ne
mar
k fo
r:o
ne
corr
ect
box,
and
no
oth
ers,
indi
cate
d on
lyO
Rtw
o c
orre
ct b
oxes
and
on
e in
corr
ect
box
indi
cate
d on
ly.A
ccep
t al
tern
ativ
e un
ambi
guou
s po
sitiv
e in
dica
tions
, e.
g. u
nder
lined
or
circ
led.
2
11 6A1
Nis
ha t
hink
s of
a n
umbe
r, n.
She
do
ub
les
the
num
ber
and
div
ides
by
3
Tick
the
exp
ress
ion
that
sho
ws
Nis
ha’s
calc
ulat
ion.
3n 2
2n
÷ 3
n
2 ÷
3
2(
n ÷
3)
Seco
nd b
ox in
dica
ted
only.
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d.
1
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12 6G2a
Har
ry p
icks
five
diff
eren
t 3-
D s
hape
s.
Har
ry h
as c
hose
n on
e cu
be.
(a)
Tick
Har
ry’s
cube
.
(b)
Expl
ain
why
the
tic
ked
shap
e is
a c
ube.
Acc
ept
an e
xpla
nation t
hat
show
s th
e
dif
fere
nce
bet
wee
n a
cube
and a
cu
boid
, e.
g.
•
it h
as
6 f
ace
s th
at
are
square
s
OR
•
the
length
, w
idth
and h
eight
(or
all
the
le
ngth
s) a
re e
qual
(a)
Acc
ept
alte
rnat
ive
unam
bigu
ous
posi
tive
indi
catio
ns,
e.g.
und
erlin
ed o
r ci
rcle
d.
(b)
Do
no
t ac
cept
exp
lana
tions
tha
t al
so a
pply
to
all
cubo
ids,
e.g
.
• it
has
six
face
s
(a)
1
(b)
1
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13 6F9c
A
tea
cher
buy
s fiv
e bo
oks
for
£54
Each
boo
k co
sts
the
sam
e.
Wha
t is
the
cos
t of
eac
h bo
ok?
£
10
.80
1
14 6G2b
Ker
ry h
as t
wo
mys
tery
3-D
sha
pes.
She
desc
ribes
eac
h sh
ape.
(a)
‘My
first
sha
pe h
as 5
fac
es.
It
has
a sq
uare
bas
e.
Th
e ot
her
side
s ar
e is
osce
les
tria
ngle
s.’
Nam
e K
erry
’s fir
st s
hape
.
(b)
‘My
seco
nd s
hape
has
tw
o fa
ces
that
are
circ
les.
It
has
a cu
rved
sur
face
.’
Nam
e K
erry
’s se
cond
sha
pe.
(a)
Acc
ept
any
unam
bigu
ous
spel
ling.
(b)
Acc
ept
any
unam
bigu
ous
spel
ling.
(a)
1
(b)
1
(square
-base
d)
pyra
mid
cylin
der
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15 6C8
Nia
cha
nges
sev
enty
-eig
ht
£10
note
s an
d o
ne
hu
nd
red
an
d
thir
ty-s
ix £
5 no
tes
for
£20
note
s.
How
man
y £2
0 no
tes
does
Nia
get
?
73
n
otes
Aw
ard
two
mar
ks f
or a
cor
rect
ans
wer
.A
war
d o
ne
mar
k fo
r a
corr
ect
met
hod,
e.g
.(1
0 ×
78)
+ (
5 ×
136
) =
1,4
601,
460
÷ 2
0 =
2
16 6F3
Oliv
er h
as w
ritte
n th
ree
frac
tions
in o
rder
, st
artin
g w
ith
the
larg
est.
Writ
e th
e m
issi
ng n
umer
ator
.
7 84 5
20
17
Acc
ept
34
40
if t
he d
enom
inat
or o
f 20
is c
hang
ed
to 4
0
1