ch07 thermochemistry

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Slide 1 of 57 Copyright © 2011 Pearson Canada Inc. General Chemistry: Chapter 7 Slide 1 of 57 TENTH EDITION GENERAL CHEMISTRY Principles and Modern Applications PETRUCCI HERRING MADURA BISSONNETTE Thermochemistry 7

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Slide 1 of 57 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7Slide 1 of 57

TENTH EDITION

GENERAL CHEMISTRYPrinciples and Modern Applications

PETRUCCI HERRING MADURA BISSONNETTE

Thermochemistry 7

Slide 2 of 57

Thermochemistry

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7Slide 2 of 57

Slide 3 of 57

6-1 Getting Started: Some Terminology

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

FIGURE 7-1Systems and their surroundings

Slide 4 of 57 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Energy, UThe capacity to do work.

Work, wForce acting through a distance.

Kinetic Energy, eK

The energy of motion.

Potential Energy, VThe stored energy has potential to do work.

Slide 5 of 57 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Kinetic Energy

ek = 12 mv2 [ek ] = m

s = Jkg 2

w = F x d

= m x a x d [w ] = ms2 = Jm

Work

kg

Slide 6 of 57 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Potential EnergyEnergy due to condition, position, or composition.Associated with forces of attraction or repulsion between objects.

Energy can change from potential to kinetic.

Slide 7 of 57 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

7-2 Heat

Thermal EnergyKinetic energy associated with random molecular motion.

In general proportional to temperature.

An intensive property.

Heat and Workq and w.Energy changes.

Slide 8 of 57

Internal energy is transferred between a system and its surroundings as a result of a temperature difference.

Heat “flows” from hotter to colder.Temperature may change.Phase may change (an isothermal process).

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Slide 9 of 57 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Calorie (cal)The quantity of heat required to change the

temperature of one gram of water by one degree Celsius.

Joule (J)SI unit for heat

1 cal = 4.184 J

Slide 10 of 57

Heat Capacity

The quantity of heat required to change the temperature of a system by one degree.

Molar heat capacity.System is one mole of substance.

Specific heat capacity, c.System is one gram of substance

Heat capacity(Mass of system) x specific heat.

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

q = mcT

q = CT

Slide 11 of 57

Law of conservation of energy

In interactions between a system and its surroundings the total energy remains constant— energy is neither created nor destroyed.

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

qsystem + qsurroundings = 0

qsystem = -qsurroundings

Slide 12 of 57

TABLE 7.1 Some Specific Heat Values, J g-1 °C-1

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7Slide 12 of 57

Slide 13 of 57

7-3 Heats of Reaction and Calorimetry

Chemical energy. Contributes to the internal energy of a system.

Heat of reaction, qrxn.

The quantity of heat exchanged between a system and its surroundings when a chemical reaction occurs within the system, at constant temperature.

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Slide 14 of 57 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

KEEP IN MINDthat the temperature of areaction mixture usuallychanges during a reaction, sothe mixture must be returnedto the initial temperature(actually or hypothetically)before we assess how muchheat is exchanged with thesurroundings.

Slide 15 of 57

Conceptualizing a heat of reaction at constant temperatureFIGURE 7-4

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Slide 16 of 57

Bomb Calorimetry

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

FIGURE 7-5A bomb calorimeter assembly

qrxn = -qcal

qcal = q bomb + q water + q wires +…

Define the heat capacity of the calorimeter: qcal = miciT = CcalT

all i

heat

Slide 17 of 57

The “Coffee-Cup” Calorimeter

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

FIGURE 7-6 A Styrofoam “coffee-cup” calorimeter

A simple calorimeter.Well insulated and therefore isolated.Measure temperature change.

qrxn = -qcal

Slide 18 of 57

7-4 Work

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

FIGURE 7-7 Illustrating work (expansion) during the chemical reaction 2 KClO3(s) 2 KCl(s) + 3 O2(g)

In addition to heat effects chemical reactions may also do work.

Gas formed pushes against the atmosphere.The volume changes.

Pressure-volume work.

Slide 19 of 57

Pressure-volume workFIGURE 7-8

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

(m x g)

= PV

w = -PextV

A h= x A

x hw = F x d

= (m x g)

Slide 20 of 57

7-5 The First Law of Thermodynamics

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

FIGURE 7-9Some contributions to the internal energy of a system

Internal Energy, U.Total energy (potential and

kinetic) in a system.

•Translational kinetic energy.•Molecular rotation.•Bond vibration.•Intermolecular attractions.•Chemical bonds.•Electrons.

Slide 21 of 57

The First Law of Thermodynamics

A system contains only internal energy.A system does not contain heat or work.These only occur during a change in the system.

Law of Conservation of EnergyThe energy of an isolated system is constant

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

U = q + w

Slide 22 of 57

The First Law of Thermodynamics

An isolated system is unable to exchange either heat or work with its surroundings, so that Uisolated system = 0, and we can say:

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

The energy of an isolated system is constant.

Slide 23 of 57

Illustration of sign conventions used in thermodynamicsFIGURE 7-10

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Slide 24 of 57

Functions of State

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Any property that has a unique value for a specified state of a system is said to be a function of state or a state function.

Water at 293.15 K and 1.00 atm is in a specified state. d = 0.99820 g/mLThis density is a unique function of the state.It does not matter how the state was established.

Slide 25 of 57

Functions of State

U is a function of state.Not easily measured.

U has a unique value between two states.Is easily measured.

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Slide 26 of 57

7-6 Heats of Reaction: U and H

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Reactants → Products

Ui Uf

U = Uf - Ui

U = qrxn + w

In a system at constant volume (bomb calorimeter):

U = qrxn + 0 = qrxn = qv

Slide 27 of 57

Two different paths leading to the same internal energy change in a systemFIGURE 7-13

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Slide 28 of 57

Heats of Reaction

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

qV = qP + w

We know that w = - PV and U = qv, therefore:

U = qP - PV

qP = U + PV

These are all state functions, so define a new function.

Let enthalpy be H = U + PV

Then H = Hf – Hi = U + PV

If we work at constant pressure and temperature:

H = U + PV = qP

Slide 29 of 57

Comparing Heats of Reaction

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

FIGURE 7-14Comparing heats of reaction at constant volume and constant pressure for the reaction 2 CO(g) + 2 O2(g) 2 CO2(g)

qV = U = H - PV

= -563.5 kJ/mol

w = PV = P(Vf – Vi)

= RT(nf – ni)

= -2.5 kJ

qP = H

= -566 kJ/mol

Slide 30 of 57

Enthalpy Change () Accompanying a Change in State of Matter

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

H2O (l) → H2O(g) H = 44.0 kJ at 298 K

Molar enthalpy of vaporization:

Molar enthalpy of fusion:

H2O (s) → H2O(l) H = 6.01 kJ at 273.15 K

Slide 31 of 57

Standard States and Standard Enthalpy Changes

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Define a particular state as a standard state.

Standard enthalpy of reaction, H°

The enthalpy change of a reaction in which all reactants and products are in their standard states.

Standard StateThe pure element or compound at a pressure of 1 bar and at the temperature of interest.

Slide 32 of 57

Enthalpy DiagramsFIGURE 7-15

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Slide 33 of 57

7-7 Indirect Determination of H:Hess’s Law

H is an extensive property.Enthalpy change is directly proportional to the amount of substance in a system.

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

N2(g) + O2(g) → 2 NO(g) H° = +180.50 kJ

½N2(g) + ½O2(g) → NO(g) H° = +90.25 kJ

• H changes sign when a process is reversed

NO(g) → ½N2(g) + ½O2(g) H° = -90.25 kJ

Slide 34 of 57

Hess’s Law Schematically

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Slide 35 of 57

• Hess’s law of constant heat summation

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

If a process occurs in stages or steps (even hypothetically), the enthalpy change for the overall process is the sum of the enthalpy changes for the individual steps.

½N2(g) + O2(g) → NO2(g) H° = +33.18 kJ

½N2(g) + O2(g) → NO(g) + ½ O2 (g) H° = +90.25 kJ

NO(g) + ½O2(g) → NO2(g) H° = -57.07 kJ

Slide 36 of 57

7-8 Standard Enthalpies of Formation

The enthalpy change that occurs in the formation of one mole of a substance in the standard state from the reference forms of the elements in their standard states.

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Hf°

The standard enthalpy of formation of a pure element in its reference state is 0.

Slide 37 of 57 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Slide 38 of 57

Standard Enthalpy of Formation

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Slide 39 of 57 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Slide 40 of 57

Standard Enthalpies of Reaction

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

FIGURE 7-20 Computing heats of reaction from standard enthalpies of formation

Hoverall = -2Hf°NaHCO3

+ Hf°Na2CO3

+ Hf

°CO2

+ Hf°H2O

Slide 41 of 57

Diagramatic representation of equation (7.21)FIGURE 7-21

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

∆H° = ∑p∆Hf°(products) - ∑r∆Hf°(reactants) (7.21)

Slide 42 of 57

Ionic Reactions in Solutions

Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7

Slide 43 of 57 Copyright © 2011 Pearson Canada Inc.General Chemistry: Chapter 7