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CBSE Class 11 Chemistry Important Questions Chapter 11 The p-Block Elements 1 Marks Questions 1.How many groups are there in p-block? Ans. There are six groups of p-block elements in the periodic table numbering from 13 to 18. 2.What is ‘inert pair effect’? Ans. The occurrence of oxidation states two unit less than the group oxidation states are sometimes attributed to the ‘inert pair effect’. 3.How does metallic and non-metallic character vary in a group? Ans. The non-metals and the metals exist only in the p-block of the periodic table. The non- metallic character of elements decreases down the group. In fact the heaviest element in each p-black group is the most metallic in nature. 4.Why do third – period elements expand their covalence above four? Ans. The third – period elements of p-groups included d-orbital, which can be utilized to form bond and expand octet. 5.Why do heaver elements form π – bonds? Ans. The heavier elements of p-block elements forms π – bonds because of the combined effect of size and availability of d-orbital’s considerably influences the ability of there elements to form π – bonds. 6.Where does metalloids and non – metals exist? 1

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CBSEClass11ChemistryImportantQuestions

Chapter11

Thep-BlockElements

1MarksQuestions

1.Howmanygroupsarethereinp-block?

Ans.Therearesixgroupsofp-blockelementsintheperiodictablenumberingfrom13to18.

2.Whatis‘inertpaireffect’?

Ans.Theoccurrenceofoxidationstatestwounitlessthanthegroupoxidationstatesare

sometimesattributedtothe‘inertpaireffect’.

3.Howdoesmetallicandnon-metalliccharactervaryinagroup?

Ans.Thenon-metalsandthemetalsexistonlyinthep-blockoftheperiodictable.Thenon-

metalliccharacterofelementsdecreasesdownthegroup.Infacttheheaviestelementin

eachp-blackgroupisthemostmetallicinnature.

4.Whydothird–periodelementsexpandtheircovalenceabovefour?

Ans.Thethird–periodelementsofp-groupsincludedd-orbital,whichcanbeutilizedto

formbondandexpandoctet.

5.Whydoheaverelementsformπ–bonds?

Ans.Theheavierelementsofp-blockelementsformsπ–bondsbecauseofthecombined

effectofsizeandavailabilityofd-orbital’sconsiderablyinfluencestheabilityofthere

elementstoformπ–bonds.

6.Wheredoesmetalloidsandnon–metalsexist?

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Ans.Itisinterestingtonotethatthenon-metalsandmetalloidsexistonlyinthep-blockof

theperiodiclabels.

7.Givethechemicalformulaofinorganicbenzene.

Ans.

8.Givetwoexamplesofelectrondeficientmolecules.

Ans.BF3,B2H6.

9.Arrangethefollowinghalidesofboronintheincreasingorderofacidiccharacter:

BF3,BCl3,BBr3,BI3.

Ans.BF3<BCl3<BBr3<BI3.

10.Whyisboricacidconsideredasaweakacid?

Ans.BoricacidisnotabletoreleaseH+ionsonitsown.ItreceiveOH-ionsfromwater

moleculestocompleteitsoctetandinturnreleaseH+ions.

11.Whyisboronmetalloid?

Ans.Because,boronresemblesbothwithmetalsandnon-metals,thereforeboronis

metalloid.

12.Whydoboronhaveunusualhighmeltingpoint?

Ans.Duetoverystrongcrystallinelattice,boronhasunusuallyhighmeltingpoint.

13.WhydoesBF3actasLewisacids?

Ans.Boroninitshalideshasonlysixelectronsinitsvalenceshell.Therefore,itcanaccepta

pairofelectronsfromanyelectron-richmolecule.Therefore,itactsasanelectron–acceptor

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andcalledLewisacid.

14.WhatistheelectronicconfigurationofGroup-14elements?

Ans.Theelectronicconfigurationisns2np2.

15.NamethemetalloidfoundinGroup14element?

Ans.Germaniumisametalloidfoundingroup–14.

16.Whichofthefollowingreactswithwaterandaqueoussolutionbecomesacidic:SiCl4

orCCl4?

Ans.SiCl4.

17.WhyCCl4behavesasanelectronprecisemolecule?

Ans.CarboninCCl4,thenumberofelectronsaroundthecentralatominamoleculeiseight

andthusiselectronprecisemolecule.

18.Whyisleadunaffectedbywater?

Ans.Leadisunaffectedbywater,probablebecauseofaprotectiveoxidefilmformation.

19.Whatisthecommonnameofrecentlydevelopedallotropeofcarboni.e.C60

molecule?s

Ans.Fullerene.

20.Howarefullerenesobtained?

Ans.Fullerenesaremadebytheheatingofgraphiteinanelectricarcinthepresenceofinert

gasessuchasheliumorargon.

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21.Diamondisthehardestsubstanceknown.Why?

Ans.Diamondisthehardestsubstanceontheearthbecauseitisverydifficulttobreak

extendedcovalentbonding.

22.Whatiswatergas?

Ans.ThemixtureofCOandH2isknownaswatergasorsynthesisgas.

23.Silicondioxideistreatedwithhydrogenfluoride.Explain?

Ans.

24.Whataresilicones?

Ans.Simplesiliconesconsistsof chainsinwhichalkalylorphenyl

groups

occupytheremainingbondingpositiononeachsilicon.Theyarehydrophobicinnature.

25.Whatisdryice?

Ans.SolidCO2isknownasdryice.

26.Whataresilicates?

Ans.ThestructuralunitofsilicatesisSiO44-inwhichsiliconatomisbondedtofouroxygen

atomsintetrahedronfashion.

27.Writetheresonancestructuresofcarbondioxide.

Ans.

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Resonancestructuresofcarbondioxide.

28.Whatissilica-gelusedas?

Ans.Silicagelisusedasadryingagentandasasupportforchromatographicmaterialsand

catalysts.

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CBSEClass12Chemistry

ImportantQuestions

Chapter11

Thep-BlockElements

2MarksQuestions

1.Whytheelementsofgroup13arecalledp-blockelements?

Ans.Group13elementsarecalledp-blockelementsbecausethelastelectronispresentinthe

p-orbital(np1).ThevalenceshellconfigurationsareB(2s22p1),Al(3s2,3p1),Ga(4s2,4p1),In

(5s25p1)Tl(6s26p1)

2.TheelementsB,Al,Ca,InandTlareplacedinthesamegroupoftheperiodictable.

Givereason.

Ans.TheelementsB,Al,Ga,InandTlareplacedinthesamegroupoftheperiodictable

becauseeachonehasthesamenumberofelectrons(ns2np1)initsvalanceshell.

3.Aluminiumforms innotformedwhy?

Ans.Duetopresenceofvacantd-orbital’s,Alcanexpanditsoctettoformbondswithsix

fluorideionswhereasBcannot.Borondoesnothaved-orbital’s.

4.TheatomicradiusofCaislessthanthatofAl.Why?

Ans.Thisisduetothevariationintheinnercoreoftheelectronicconfiguration.The

presenceofadditional10d-electronsofferonlypoorscreeningeffectfortheouterelectrons

fromtheincreasednuclearchargeingallium.

5.CandSarealwaystetravalentbutGe,SnAndPbshowdivalency.Why?

Ans.Inertpairismoreprominentaswemovedownthegroupinp–blockelements.Ge,Sn

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andPbshowdivalencyduetoinertpaireffect.

6.Somehalidesofgroup14elementsformcomplexesofthetype .Givereason.

Ans.Thehalidesoftheelementshavingvacantd-orbital’scanformcomplexeslike

becauseinsuchacasethecentralatomcanincreaseits

coordinationnumberfrom4to6duetoavailabilityofvacantd–orbital’s.

7. isleadknownwhereas not.Givereason.

Ans.Themainreasonsarethat

(i) SixlargechlorideionscannotbeaccommodatedaroundSi4+duetolimitationofitssize.

(ii) InteractionbetweenlonepairofchlorideionandSi4+isnotverystrong.

8.PbI4doesnotexist.Why?

Ans.PbI4doesnotexistbecausePb–Ibondinitiallyformedduringthereactiondoesnot

releaseenoughenergytounpair6s2electronsandexciteoneofthemtohigherorbitalto

havefourunpairedelectronsaroundleadatom.

9.Whyiscarbondifferentfromothermemberofthegroup?

Ans.Carbondiffersfromrestofthemembersofitsgroupduetoitssmallersize,higher

electronegativity,higherionizationenthalpyandunavailabilityofd-orbital’s.

10.Whydoesthecovalenceofcarbonnotexpandbeyondfour?

Ans.Incarbon,onlysandporbital’sareavailableforbondingandthereforeitcan

accommodateonlyfourpairsofelectronsaroundit.Thislimitthemaximumcovalenceto

fourwhereasothermemberscanexpandtheircovalenceduetothepresenceofd-orbital’s.

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11.Whydoescarbonshowdifferentallotropicforms?

Ans.Duetopropertyofcatenationandpπ-pπbondformationCarbonisabletoshow

differentallotropicforms.

12.Siliconhasnoallotropicformanalogoustographite.Why?

Ans.Duetolargesize.Sihaslittleornotendencyforpπ–pπbonding.Whereascarbonatom

formseasilypπ–pπbondsduetosmallersizeingraphitestructure.Hence,Sidoesnot

exhibitgraphitestructure.

13.Whydoesgraphiteconductelectricity?

Ans.Graphiteformshexagonalringandundergoessp2hybridization.Theelectronsare

delocalizedoverthewholesheet.Electronsaremobileandthereforegraphiteconducts

electricityoverthesheet.

14.Graphiteisusedaslubricant.Givereason.

Ans.Graphitehassp2hybridizedcarbonwithalayerstructureduetowideseparationand

weakinter–layerbondsthetwoadjacentlayerscaneasilyslideovereachother.Thismakes

graphiteactasalubricant.

15.Howaresiliconesmanufactured?

Ans.Theyaremanufacturedbyhydrolysisofchlorosilanes–

whereRisamethylorphenylgroup.

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16.WhydoesCO2havealinearshapewithnodipolemoment

Ans.InCO2moleculecarbonatomundergoessphybridization.Twosphybridizedorbitalof

carbonatomoverlapwithtwop-orbital’sofoxygenatomstomaketwosigmabondswhile

othertwoelectronsofcarbonatomareinvolvedinpπ–pπbondingwithoxygenatom.This

resultsinitslinearshape[withbothc-obondofequallength(115pm)]withnodipole

moment.

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CBSEClass12Chemistry

ImportantQuestions

Chapter11

Thep-BlockElements

3MarksQuestions

1.Whycarbondoesnotformioniccompounds?

Ans.Theelectronicconfigurationofcarbonatomis1s22s22px12py1andhasfourvalence

electrons.Inordertoformioniccompound,ithastoeitherlosefourelectronsorgainfour

electrons.Sinceveryhighenergyareinvolvedindoingso.Carbondoesnotformionic

compounds.Itcompletesitsoctetbysharingofelectronsandformscovalentcompounds.

2.Whydoestheheavierelementsdonotformpπ–pπmultiplebondascarbondo?

Ans.Carbonhastheuniqueabilitytoformpπ–pπmultiplebondwithitselfandwithother

atomsofsmallsizeandhighelectronegativitywhereasheavierelementsdonotfrompπ–

pπbondsbecausetheiratomicorbital’saretoolargeanddiffusetohaveeffective

overlapping.

3.WhyisCOconsideredpoisonous?

Ans.ThehighlypoisonousnatureofCOarisesbecauseofitsabilitytoformacomplexwith

haemoglobinwhichisabout300timesmorestablethantheoxygen–haemoglobincomplex.

Thispreventshaemoglobinintheredbloodcorpusclesfromcarryingoxygenroundthebody

andultimatelyresultingindeath.

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