Determining “Apparent Weight”

The Elevator Problem

Elevator Problem FormulasRemember:

1. F(net) = m x a

2. Fg = mass x acc. due to gravity

3. On a scale, there are two forces acting on you (Fg & Fn)

4. Fn = Fscale

5. Therefore… Fnet = Fscale – Fg

Elevator Demo

Set Up and Apparent Weight Outcomes to Know

When an elevator is at rest or in constant motion Fnet = zero, so…

Fscale = Fg

(Apparent weight is equal to actual weight)

When an elevator is accelerating upward…

Fnet = Fscale – Fg

(Apparent weight will be greater than actual weight)

Set Up and Apparent Weight Outcomes to Know (cont.)

When an elevator is accelerating downward…

Fnet = Fscale – Fg

(Apparent weight is less than actual weight)

When in an elevator and the cable breaks!!!

“Help Me!!! I Don’t Want To Die!!!” Fnet = Fscale – Fg (equal but opposite directions)

You will feel weightless