design procudere for flat belt drive based onprepared by p.gopi ap-ii mech c.guhan ap-i mech design...
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Prepared by
P.Gopi AP-II Mech
C.Guhan AP-I Mech
ANAND INSTITUTE OF HIGHER TECHNOLLOGY –
KAZHIPATTUR 603 103
DEPARTMENT OF MECHANICAL ENGINEERING
SUB.CODE/SUB.NAME:ME6601/DESIGN OF TRANSMISSION SYSTEMS
UNIT 1 DESIGN OF FLEXIBLE DRIVES
DESIGN PROCUDERE FOR FLAT BELT DRIVE BASED ON
MANUFACTURE’S DATA
1.SELECTION OF PULLEY DIAMETERS:
Select the pulley diameters and angle of contact(ie wrap angle) by using the
given belt speed, and assuming number of plies, minimum pulley diameter is
chosen
Use table from PSG DDB Pg.No:7.52 to select diameter of smaller pulley
2.CALCULATION OF DESIGN POWER IN KW
Design KW = Rated KW X Load concentration factor(KS )
Arc of contact (K∞) X small pulley factor (Kd)
Load concentration factor(KS ) : Assuming load conditions PSG DDB Pg.No:7.53
Arc of contact (K∞): arc of contact formula available in DDB PSG DDB Pg.No:7.54
small pulley factor (Kd): this value not available in DDB
Smaller pulley diameter
(d)
Kd
Upto 100mm 0.5
101 – 200mm 0.6
201 – 300mm 0.7
301 – 400mm 0.8
401 – 750mm 0.9
Over 751 above 1.0
3. SELECTION OF BELTING : PSG DDB Pg.No:7.54
4.LOAD RATING CORRECTION: Correct the load rating to the actual load
PSG DDB Pg.No:7.54
Prepared by
P.Gopi AP-II Mech
C.Guhan AP-I Mech
5.DETERMINATION OF BELT WIDTH
Belt Width = design power
Load rating X No.of Plies
Knowing the smaller pulley diameter and velocity of the belt, the no.of plies can be
found from PSG DDB Pg.No:7.52
The calculated belt width should be rounded of to the std. belt width. PSG DDB
Pg.No:7.52
6.DETERMINATION OF PULLEY WIDTH: PSG DDB Pg.No:7.54
7.CALCULATION OF BELT WIDTH: from PSG DDB Pg.No:7.53
DESIGN OF FLAT BELT PULLEYS
1.DIMENSION OF PULLEY:
σc = ρV2
ρ = 7200Kg/m3 for cast iron
V = DN
60 D = dia of Pulley; N = Speed of Pulley
(i) Select the diameter of the pulley (D) from PSG DDB Pg.No:7.54
(ii) Select the width of the pulley (D) from PSG DDB Pg.No:7.54
(iii) Select thickness of the pulley (D) from PSG DDB Pg.No:7.54
2.DIMESIONS OF ARM:
(i) No.of arm : PSG DDB Pg.No:7.56
(ii) Cross section of arms [ b&b/2] : PSG DDB Pg.No:7.56
(iii) Arms Taper : PSG DDB Pg.No:7.56
(iv) Radius of the cross section of arms : r = ¾ X b
3.DIMENSIONS OF HUB:
(i) Dia.of the hub(d1): d1 = [1.7 to 2.0d2] PSG DDB Pg.No:7.56
(ii) length of the hub(l): PSG DDB Pg.No:7.56
4.CROWNING OF PULLEY RIM: select the crown height PSG DDB
Pg.No:7.55
Prepared by
P.Gopi AP-II Mech
C.Guhan AP-I Mech
DESIGN PROCUDERE FOR V BELT DRIVE BASED ON
MANUFACTURE’S DATA
1.SELECTION OF BELT SECTION: select the belt section based on power
transmitted PSG DDB Pg.No:7.58
2.SELECTION OF PULLEY DIAMETERS [d & D]: select the small pulley
diameter from PSG DDB Pg.No:7.58, then using the speed ratio, calculate the
large pulley diameter[D].
These pulleys diameters should be rounded of to the a Std.diameters from PSG
DDB Pg.No:7.54
3.SELECTION OF CENTRE DISTANCE[C]: from PSG DDB Pg.No:7.61
4.DETERMINATION OF NOMINAL PITCH LENGTH: from PSG DDB
Pg.No:7.61
5.SELECTION OF VARIOUS MODIFICATION FACTORS:
(i) Length correction factor [FC]: PSG DDB Pg.No:7.60
(ii) Correction factor for arc of contact [Fd]: PSG DDB Pg.No:7.68
(iii) Service factor [Fa]: PSG DDB Pg.No:7.69
6.CALCULATION OF MAXIMUM POWER CAPACITY: PSG DDB
Pg.No:7.62
7.DETERMINATION OF NO.OF.BELTS (nb) : PSG DDB Pg.No:7.70
8.CALCULATION OF ACTUAL CENTRE DISTANCE: PSG DDB
Pg.No:7.61
Prepared by
P.Gopi AP-II Mech
C.Guhan AP-I Mech
DESIGN PROCUDERE FOR WIRE ROPE
1.SELECTION OF SUITABLE WIRE ROPE: select the rope as per
requirement
2.CALCULATION OF DESIGN LOAD: By assuming the Larger FOS ie 15,
find the Design load PSG DDB Pg.No:9.1
3.SELECTION OF WIRE ROPE: select the wire rope diameter(d) PSG DDB
Pg.No:9.5 -9.6
4.CALCULATION OF SHEAVE DIAMETER(D): PSG DDB Pg.No:9.1
always select the larger dia is preferred
5.SELECTION OF THE AREA OF THE USEFUL CROSS SECTION OF
THE ROPE[A]
Types of construction Metallic area of the Rope(mm2)
6x7 0.38d2
6x19 0.4d2
6x37 0.4d2
8x19 0.35d2
6.CALCULATION OF WIRE DIAMETER(dw)
dw = d
1.5
d = wire rope dia(mm); i = No. of. Strands X No. of wires in each strand
7.SELECTION WEIGHT OF ROPE[Wr]: PSG DDB Pg.No:9.5 -9.6
8.CALCULATION OF VARIOUS LOADS
(i) Direct load Wd = W+Wr
(ii) Bending Load Wb = σb x A = Er.dw/D.A
(iii)Acceleration load due to change in the speed of hoisting
Wa = X a
a = V2 – V1
t
(iv) Starting (or) Stopping load
(a) When there is no slack in the rope:
Starting Load Wst = 2.Wd
(b) When there is slack in the rope:
Starting Load Wst = σst x A
Prepared by
P.Gopi AP-II Mech
C.Guhan AP-I Mech
9.CALCULATION OF EFFECTIVE LOADS
(i) Effective load on the rope during normal working Wen =Wd+Wb
(ii) Effective load on the rope during Acceleration of the load
Wea = Wd+Wb+Wa
(iii) Effective load on the rope during starting Wst = Wb+ Wst
10.CALCULATION OF FACTOR OF SAFETY[Fsw]
Fsw = Breaking load from PSG DDB Pg.No:9.5 -9.6 for selected rope
Effective load during acceleration [Wea]
11.CHECK FOR SAFE DESIGN
If working FOS is greater than the Recommended FOS from PSG DDB Pg.No:9.1
the design is safe and satisfactory
12.CALCULATION OF NO.OF ROPES
No.of.Ropes = Recommended FOS n
Working FOS Fsw
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P.Gopi AP-II Mech
C.Guhan AP-I Mech
DESIGN PROCUDERE FOR ROLLER CHAIN
1.SELECTION OF THE TRANSMISSION RATIO:
Select the transmission ratio from PSG DDB Pg.No:7.74
i = Z2/Z1 = n1/n2
Z1 = No of teeth on Sprocket pinion
Z2 = no.of Teeth on Sprocket wheel
n1= Speed of the rotation of pinion (RPM)
n2= Speed of the rotation of wheel(RPM)
2.SELECTION OF NO OF TEETH ON THE DRIVER: select Z1 from PSG
DDB Pg.No:7.74
3.DETERMINATION OF NO.OF TEETH ON THE DRIVEN
SPROCKET(Z2): Z2 = iZ1
4.SELECTION OF STANDARD PITCH: a = [30 to 50] P and obtain
std.pitch(P) from PSG DDB Pg.No:7.74
5.SELECT THE CHAIN TYPE: from PSG DDB Pg.No:7.71 – 7.73
6.CALCULATION OF THE TOTAL LOAD ON THE DRIVING SIDE OF
THE CHAIN(PT):
Total load on the driving side (PT) =
+
+
(i)Tangential force : Pt = 1020N/V
N = Transmitted power in KW
V = Chain Velocity = Z1XPXN1 Or Z2XPXN2
60X1000 60X1000
P=Std.Pitch(mm)
(ii) Centrifugal Tension Pc: m.V2
m = mass of the chain/meter from PSG DDB Pg.No:7.71
(iii) Tension due to sagging (Ps):
Ps = K.W.a
Prepared by
P.Gopi AP-II Mech
C.Guhan AP-I Mech
K = Co efficient of sag from PSG DDB Pg.No:7.78
W = weight of chain / meter = m.g
a = centre distance in meter
7.CALCULATION OF SERVICE FACTOR(KS): from PSG DDB Pg.No:7.76
8.CALCULATION OF DESIGN LOAD:
Design Load = [Total load on the driving side] X service factor
9.CALCULATION OF WORKING FOS(Fsw)
FOS = Breaking load for selected belt from PSG DDB Pg.No:7.71 – 7.73
Design load
= Q/PT X Ks
10.CHECK FOS: compare the working FOS with Recommended FOS from PSG
DDB Pg.No:7.77
11.CHECK FOR THE BEARING STRESS IN THE ROLLER:
σ = Tangential load/ bearing Area = Pt X Ks
A
Now compare the calculated bearing stress value with allowable bearing stress
value from PSG DDB Pg.No:7.77
12.CALCULATION OF ACTUAL LENGTH OF THE CHAIN[L]: from PSG
DDB Pg.No:7.75
13.CALCULATION OF THE EXACT CENTRE DISTANCE: from PSG DDB
Pg.No:7.75
14.CALCULATION OF PITCH CIRCLE DIAMETERS(Pcd):
Pcd of smaller sprocket d1 = P/sin(180/Z1)
Pcd of larger sprocket d2 = P/sin(180/Z2)
Smaller sprocket outside dia: do1 = d1+0.8dr
larger sprocket outside dia: do2 = d2+0.8dr
dr = Dia.of roller from PSG DDB Pg.No:7.71 – 7.73
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P.Gopi AP-II Mech
C.Guhan AP-I Mech
UNIT 2 SPUR GEARS & PARALLEL AXIS HELICAL GEARS
DESIGN PROCUDERE FOR SPUR GEAR BASED ON LIFE
1.CALCULATION OF GEAR RATIO (i):
i = Z2/Z1 = N1/N2
2.SELECTION OF MATERIALS: from PSG DDB Pg.No:8.4
3.ASSUME GEAR LIFE: if not give assume 20,000hrs
4.CALCULATION OF DESIGN TORQUE:
[Mt] = Mt.K.Kd.Ko from PSG DDB Pg.No:8.15
Ko = 1 normal load; 1.25 moderate load; 1.5Heavy load
Mt = PX60 [pinion torque]
2 N1
Initially assume K.Kd = 1.3 from PSG DDB Pg.No:8.15
5.CALCULATION OF E,[σb], [σc ]: from PSG DDB Pg.No:8.14
[σb] from PSG DDB Pg.No:8.5
[σc] = CBHBKcl Kgf/m2 OR CRHRCKcl from PSG DDB Pg.No:8.16
6.CALCULATION OF CENTRE DISTANCE[a] from PSG DDB Pg.No:8.13
TABLE 8 = 0.1 to 0.2
7.NO.OF TEETH ON PINION
Z1 for 20º full depth system to avoid interfernce
Z1 for 20º stub depth
Z1 for 14 1/2 º full depth
8.CALCULATION OF MODULE:
m = 2a/(Z1+Z2) Z2 = iXZ1
9.REVISE “a” USING STD.MODULE:
Face width b =
Pitch dia d1 = m.Z1
Value of = b/d1
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P.Gopi AP-II Mech
C.Guhan AP-I Mech
10.ASSUME SUITABLE QUALITY OF GEAR: from PSG DDB Pg.No:8.3
TABLE 2
11.REVISE THE DESIGN TORQUE[MT]: Obtain new value for K and Kd
from PSG DDB Pg.No:8.15 and PSG DDB Pg.No:8.16 Table 15
12.CHECK FOR BENDING σb : from PSG DDB Pg.No:8.13A Table 8
Now compare the σb with design bending stress [σb], σb<[σb] design is safe
Check for wear σc from PSG DDB Pg.No:8.13 Table 8; σc<[σc] design is safe
13.CALCULATION OF BASIC DIMENSIONS: from PSG DDB Pg.No:8.22
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DESIGN PROCUDERE FOR HELICAL GEAR BASED ON LIFE
1.SELECTION OF MATERIALS: For corresponding i value and required
hardness select the material from PSG DDB Pg.No:8.4
2.ASSUME LIFE OF GEAR: if not given 20,000hrs
3.CALCULATION OF E,[σb], [σc ]: from PSG DDB Pg.No:8.14,8.16,8.18
4.CALCULATION OF DESIGN TORQUE:
[Mt] = Mt.K.Kd.Ko from PSG DDB Pg.No:8.15
Ko = 1 normal load; 1.25 moderate load; 1.5Heavy load
Mt= PX60 [pinion torque]
2 N1
Initially assume K.Kd = 1.3 from PSG DDB Pg.No:8.15
5.CALCULATION OF CENTRE DISTANCE[a] from PSG DDB Pg.No:8.13
TABLE 8 = 0.5
6.ASSUME Z1
Z1 ; Z2=iZ1
7.CALCULATION OF NORMAL MODULE[mn]:
mn=2acos /Z1+Z2 then revise mn from PSG DDB Pg.No:8.2
8.REVISE CENTRE DISTANCE(a):
d1=mnZ1/cos ; d2= id1
a= mn/cos [Z1+Z2 / 2] from PSG DDB Pg.No:8.22
9.calculate b,Pa,[Mt]
Pa=Pt/ tan = / tan ( not available in DDB)
b= b>Pa
based on these values Revise[Mt]
10.ASSUME SUITABLE QUALITY OF GEARS: based on the velocity select
quality of gears from PSG DDB Pg.No:8.3
11.CALCULATE INDUCED BENDING & COMPRESSIVE STRENGTH:
from PSG DDB Pg.No:8.13 & 8.13A
Then check for Safe design
σb<[σb] design is safe; σc<[σc] design is safe
12.CALCULATION OF BASIC DIMENSIONS: from PSG DDB Pg.No:8.22
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UNIT 3 BEVEL WORM AND CROSS HELICAL GEAR
DESIGN PROCUDERE FOR BEVEL GEAR BASED ON LIFE
1.CALCULATION OF GEAR RATIO (i) & PITCH ANGLES:
i = Z2/Z1 = N1/N2, & tan ; tan
2.SELECTION OF MATERIALS: from PSG DDB Pg.No:8.4
3.ASSUME GEAR LIFE: if not give assume 20,000hrs
4.CALCULATION OF DESIGN TORQUE:
[Mt] = Mt.K.Kd.Ko from PSG DDB Pg.No:8.15
Ko = 1 normal load; 1.25 moderate load; 1.5Heavy load
Mt = PX60 [pinion torque]
2 N1
Initially assume K.Kd = 1.3 from PSG DDB Pg.No:8.15
5.CALCULATION OF E,[σb], [σc ]: from PSG DDB Pg.No:8.14
[σb] from PSG DDB Pg.No:8.18
[σc] = CBHBKcl Kgf/m2 OR CRHRCKcl from PSG DDB Pg.No:8.16
6.CALCULATION OF CONE DISTANCE[R] from PSG DDB Pg.No:8.13
TABLE 8 Y= 3 for initial calculations
7.NO.OF TEETH ON PINION
Z1 for 20º full depth system to avoid interfernce
ZV1=Z1/cos ; ZV2=Z2/cos ; from PSG DDB Pg.No:8.39
8.CALCULATION OF TRANSVERSE MODULE[mt]: from PSG DDB
Pg.No:8.38 TABLE 31
R=0.5mt Z12+Z2
2 ; Choose nearest higher std. module value from
PSG DDB Pg.No:8.2 TABLE 01
9.REVISE “R” USING STD.MODULE:
R=0.5mt Z12+Z2
2 from PSG DDB Pg.No:8.38 TABLE 31
10.CALCULATION OF B,mav,d1av,V and Y
(i)Face width b = R/ Y
(ii) Avg.Module mav = mt - bsin /Z1
(iii)Avg.Pcd d1av= mav.Z1
(iv)Pitch Line velocity V = d1avXZ1 (m/s)
60
(v) Calculate Y =b/d1av
Prepared by
P.Gopi AP-II Mech
C.Guhan AP-I Mech
11.ASSUME SUITABLE QUALITY OF GEAR: from PSG DDB Pg.No:8.3
TABLE 2
12.REVISE THE DESIGN TORQUE[MT]: Obtain new value for K and Kd
from PSG DDB Pg.No:8.15 Table 14 and PSG DDB Pg.No:8.16 Table 15
12.CHECK FOR BENDING σb : from PSG DDB Pg.No:8.13A Table 8
Now compare the σb with design bending stress [σb], σb<[σb] design is safe
Check for wear σc from PSG DDB Pg.No:8.13 Table 8; σc<[σc] design is safe
13.CALCULATION OF BASIC DIMENSIONS: from PSG DDB Pg.No:8.38
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DESIGN PROCUDERE FOR WORM GEAR BASED ON LIFE
1.SELECT THE MATERIALS: from PSG DDB Pg.No:8.45 Table 33
2.CALCULATE THE INITIAL DESIGN TORQUE[Mt]
[Mt] = KKd.Mt
KKd=1 (initially assume)
Mt = PX60 [pinion torque]
2 N2
3.SELECT Z1&Z2: as per efficiency from PSG DDB Pg.No:8.46 Table 37
4.SELECT [σb], [σc]: from PSG DDB Pg.No:8.45 Table 32,33 initially assume
V=3m/s
5.CALCULATE CENTRE DISTANCE(a): q=11 from PSG DDB Pg.No:8.44
6.CALCULATE THE AXIAL MODULE[mx]: from PSG DDB Pg.No:8.43
Table35
mx=2a/(q+Z2+2X) X=0 Assume ; then std.these value from PSGDDB
Pg.No:8.2
7.REVISE THE CENTER DISTANCE “a” : from PSG DDB Pg.No:8.43
Table35
8.CALCULATE d,V, ,Vs
Pitch Dia d1= qXmx; d2=Z2Xmx
Pitch line velocity V = d1N1/60; V2 = d2N2/60;
Lead angle tan = Z1/q
Sliding Velocity Vs = V1/Cos
9.RECALCULATE THE DESIGN CONTACT STRESS [σc]: for
corresponding value of Vs Recalculate [σc] from PSG DDB Pg.No:8.45 Table 32
10.REVISE K,Kd,[Mt]: from PSG DDB Pg.No:8.44
11.CHECK FOR BENDING σb : from PSG DDB Pg.No:8.44
Now compare the σb with design bending stress [σb], σb<[σb] design is safe
Check for wear σc from PSG DDB Pg.No:8.44; σc<[σc] design is safe
Prepared by
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C.Guhan AP-I Mech
12.CHECK FOR EFFICIENCY:
Mt = 71620 hP/n i*n from PSG DDB Pg.No:8.44
ncal ndes design is safe (if not increase the lead angle )
n from PSG DDB Pg.No:8.49 from graph
14.CALCULATE THE POWER LOSS AND THE AREA REQUIRED TO
DISSIPIATE HEAT:
(1-n)* IP = Kt*A*(to-ta)
15.CALCULATE THE BASIC DIMENSIONS: from PSG DDB Pg.No:8.43
Table 35
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UNIT -4 GEAR BOXES
DESIGN PROCUDERE FOR BEVEL GEAR BASED ON LIFE
1.SELECTION OF SPINDLE SPEEDS
Nmax = n-1
Nmin
n= No.of. Speeds Required; = Step Ratio
Select the Std. Step Ratio from PSG DDB Pg.No:7.20
2.STUCTURAL FORMULA Stage1 Stage2 Stage3 Stage4 n=P1(X1) * P2(X2) * P3(X3) * P4(X4)
X1=1; X2=P1; X3=P1.P2; X4=P1.P2.P3
3.CONSTRUCT THE RAY DIAGRAM:
Draw the Horizontal Lines as per the No.Of. Speeds Required, and Split this
line in to Column as per the No.Of. Satges needed
4.CHECK THE CONDITIONS:
nmin 1/4 nmax 2
ni/p ni/p
But never keep
nmax > nmax
ni/p ni/p
5.KINEMATIC ARRANGEMENT
Mark horizontal lines = No.Of.Satges + 1
Total Gears= (P1+P2)*2
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UNIT – 5 CAM,CLUTCH, BRAKES
FORMULA FOR CLUTCH
1.Frictional Torque:
T = n*µ*W*R If single plate clutch n=2(both sides being effective)
If multi plate clutch n = n1+n2 – 1
n1 = No.of Discs on the Driving Shaft
n2 = No.of Discs on the Driven Shaft
µ = Co-efficient of friction
R = 2/3*(r13 –r2
3/ r1
2 – r2
2 ) - Uniform Pressure
R = r1+r2 / 2 – Uniform Wear
r1,r2 = Outer & Inner diameter Rply
2.POWER
P = 2 NT/60
3.INTENSITY OF PRESSURE
Pmin.r1 = Pmax.r2 = C
AXIAL THRUST W = 2 C[r1-r2]
4.TOTAL NO.OF PLATES REQUIRED
no.of plates required = no.of pair of contact + 1 = Ttotal/Tsurface
CONICAL CLUTCH
T=2/3* µ*W* Cosec (r13 –r2
3/ r1
2 – r2
2 ) - Uniform Pressure
T=µ*W* Cosec (r1+r2/ 2 ) - Uniform Pressure
Brake
T1/T2 = e µº
T1= Tension on tight side
T2= Tension on Slack side
µ = Co-efficient of friction
º = Angle of Lap
BRAKE POWER (TB) = (T1-T2)*r
r= Radius of the drum