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Department of Physics and Applied Physics95.141, F2010, Lecture 20
Physics I95.141
LECTURE 2011/21/10
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Parallel Axis Theorem
• Moment of inertia for a sphere, rotating about an axis through its center, is:
• What is moment of inertia for this sphere about an axis going through the edge of the sphere?
• Through an axis a distance R from the center?
• As R>>ro?
R
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Rotational Kinetic Energy
• We now know the rotational equivalent of mass is the moment of inertia I.
• If I told you there was such a thing as rotational kinetic energy, you could probably make a good guess as to what form it would take…
2
2
1mvKEtrans
2
2
1 IKErot
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Rotational Kinetic Energy
• Prove it!
2
2
1mvKE trans Rv
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Rolling without slipping
• If the CM of the wheel is moving with speed v
• Place yourself at the axis, you will see road moving by at –v beneath you.
• So if the road is moving at –v, and the wheel isn’t slipping, you know the angular velocity of the wheel!
Rv
Rv
/
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Instantaneous Axis
• What is the axis of rotation for the rolling wheel?• The point on the ground is fixed, the wheel is
then rotating around this point.
2MRII CM
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Total KE of Rolling Body
• The total kinetic energy of the rolling body will then be:
22
2
1 MRIKE CM
RvCM
Department of Physics and Applied Physics95.141, F2010, Lecture 20
• What is speed of rock at end of incline?• Use conservation of Energy
Rolling Body Example
2
53
5
2
5
1076.13
4
5.2
MRI
my
kgRMrock
mR
sphere
ROCK
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Outline• Angular Momentum
• Vector Cross Products
• What do we know?
– Units
– Kinematic equations
– Freely falling objects
– Vectors
– Kinematics + Vectors = Vector Kinematics
– Relative motion
– Projectile motion
– Uniform circular motion
– Newton’s Laws
– Force of Gravity/Normal Force
– Free Body Diagrams
– Problem solving
– Uniform Circular Motion
– Newton’s Law of Universal Gravitation
– Weightlessness– Kepler’s Laws– Work by Constant Force– Scalar Product of Vectors– Work done by varying Force– Work-Energy Theorem– Conservative, non-conservative Forces– Potential Energy– Mechanical Energy – Conservation of Energy– Dissipative Forces– Gravitational Potential Revisited– Power– Momentum and Force– Conservation of Momentum– Collisions– Impulse– Conservation of Momentum and Energy– Elastic and Inelastic Collisions2D, 3D Collisions– Center of Mass and translational motion– Angular quantities– Vector nature of angular quantities– Constant angular acceleration – Torque– Rotational Inertia– Moments of Inertia
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Review of Lecture 19
• Introduced concept of Torque– “Rotational Force”
• Comes from Force exerted on a rotating body• Depends on distance from axis of rotation• Equal to radius x perpendicular component of Force• Does not have same units as Force
• Rotational equivalent of mass is moment of inertia…how hard it is to accelerate (angularly) an object for a given Torque.– For a point mass: – For a collection of point masses:– For solid object rotating around CM: use table in book, or– use integral:
][ mNRF
2MRI ...2
33222
211 RMRMRMI
dmrI 2
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Lecture 19 Review
• Parallel axis theorem– Can be used to determine I around an axis other than one
through center of mass
• Discussed equivalent of Newton’s 2nd Law for Angular Motion– Torque is what gives angular acceleration:
• Angular Kinetic Energy
• Rolling without slipping
IRF
2
2
1 IKEangular
22
2
1 MRIKE CM RvCM
Department of Physics and Applied Physics95.141, F2010, Lecture 20
What are we missing?
• We have discussed angular acceleration, velocity, Force (torque) and kinetic energy
• All have equivalents in linear motion• There is one other translational quantity we have
spent a lot of time with…momentum, does this have an angular equivalent?
• Again, if we had to guess….
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Angular Momentum
• Angular momentum is defined as the product angular velocity of an object and the object’s moment of inertia.
• Can write the equivalent of Newton’s second law for angular momentum, just like we did for translational momentum
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Conservation of Angular Momentum
• Just like translational momentum, angular momentum is a conserved quantity in certain circumstances.
• Because a torque leads to angular acceleration (a change in angular velocity), if a torque is applied to a rotating body, angular momentum is not conserved.
• But if no external torques act on a body, and I is constant, then angular momentum is conserved!
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Conservation of Angular Momentum
• Law of conservation of angular momentum:• The total angular momentum of a rotating object
remains constant if the net external torque acting on the object is zero
• Import conservation law in Physics, along with conservation of linear momentum and energy!!
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Example Problem
• Lets take the rotating rod system we looked at earlier.• If the rod is rotating at ω=5rad/s, what is the system’s angular
momentum?
• If I remove block 2, what is the new angular velocity of the system?
m2=3kg m1=2kg2m2m
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Directional Nature of L
• For translational momentum, the momentum vector points in the same direction as the velocity vector, because mass is a scalar.
• In the same way, because the moment of inertia is a scalar, the angular velocity vector determines the direction of the angular momentum vector.
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Vector Cross Product
• We have discussed, so far, two types of vector products:– Multiplication by a scalar:
– Dot-product of two vectors ( )
kjiAc ˆ2ˆ4ˆ3,2
Ac
dF
kjiBkjiA ˆ4ˆ5ˆ2,ˆ2ˆ4ˆ3
BA
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Vector Cross-Product
• There is yet a third type of vector product, known as the vector cross product
• Product of two vector, that results in a vector
• Resulting vector has a magnitude
• And points in the direction perpendicular to the plane created by• Direction determined by right hand rule
BAC
sinABBAC
BA,
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Vector Cross Product, Mathematically
zyx
zyx
zyx
zyx
BBB
AAA
kji
BA
kBjBiBB
kAjAiAA
ˆˆˆ
ˆˆˆ
ˆˆˆ
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Vector Cross Product
• What is the vector cross product of a vector and itself?
zyx
zyx
zyx
AAA
AAA
kji
AA
kAjAiAA
ˆˆˆ
ˆˆˆ
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Does Order Matter?
zyx
zyx
zyx
zyx
zyx
zyx
AAA
BBB
kji
AB
BBB
AAA
kji
BA
kBjBiBB
kAjAiAA
ˆˆˆ
ˆˆˆ
ˆˆˆ
ˆˆˆ
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Example
• What are the vector cross products
ji ˆˆ kj ˆˆ ii ˆˆ
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Example
• What is the vector dot product of the two vectors:
kjiB
kjiA
ˆ1ˆ2ˆ1
ˆ4ˆ3ˆ2
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Torque and the Cross Product
• Technically, when we first introduced torque as the product of the radius and the perpendicular component of the Force, we were taking a cross product!
FR
Department of Physics and Applied Physics95.141, F2010, Lecture 20
Angular Momentum of a particle
• Imagine a particle of mass m moving in a circular path of radius R with angular velocity ω.