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Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide Chapter 6 Polynomial Functions

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Page 1: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1

Chapter 6Polynomial Functions

Page 2: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 2

6.2 Multiplying Polynomial Expressions and Functions

Page 3: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 3

Monomials, Binomials, and Trinomials

A polynomial is a monomial, binomial, or trinomial, depending on the number of terms.

Page 4: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 4

Example: Finding the Product of Two Monomials

Find the product 3 2 64 2 .x y xy

Page 5: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 5

Solution

6 63 2 234 2 4( 2)x x xy y yx y 4 88 yx

Page 6: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 6

Equivalent Expressions

Warning

3 2 6 3 2 64 2 4 2x y xy x y xy

The left expression is a product, whereas the right expression is a difference.

Page 7: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 7

Multiplying Two Polynomials

To multiply two polynomials, multiply each term in the first polynomial by each term in the second polynomial. Then combine like terms if possible.

Page 8: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 8

Example: Finding the Products of Two Polynomials

Find the product.

1. (2x + y)(5x2 – 3xy + 4y2)

2. (x2 – 3x + 2)(x2 + x – 5)

Page 9: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 9

Solution

1. Multiply each term in the first polynomial by each term in the second polynomial:

Page 10: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 10

Solution

2.2 2( )( 5)23 x xx x

2 2 22 2 3 535 3x x x x xx xx xx 22 2 2 5x x

4 3 2 3 2 25 3 3 15 2 2 10x x x x x x x x 2 24 23 3 15 5 2 13 3 02x x xx x x xx

234 2 17 016xx xx

Page 11: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 11

Solution

2. Use a graphing calculator table to verify our work.

Page 12: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 12

Squaring a Binomial

(A + B)2 = A2 + 2AB + B2

(A – B)2 = A2 – 2AB + B2

In words, the square of a binomial equals the first term squared, plus (or minus) twice the product of the two terms, plus the second term squared.

Page 13: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 13

Example: Simplifying Squares of Binomials

Simplify.

1. (x + 7)2 2. (5t – 4w)2 3. (3r2 + 2y2)2

Page 14: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 14

Solution

1. Substitute x for A and 7 for B:

Or, 2( 7) ( 7)( 7)x x x 2 7 97 4x x x 2 14 49x x

Page 15: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 15

Solution

2. Substitute 5t for A and 4w for B:

Or, 2(5 4 ) (5 4 )(5 4 )t w t w t w 2 220 2025 16twt tw w 2 225 40 16t tw w

Page 16: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 16

Solution

3.

2 22 22222 23 232 22 3y r r yr y

4 2 2 49 12 4r r y y

Page 17: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 17

Perfect-Square Trinomial

A perfect-square trinomial is a trinomial equivalent to the square of a binomial.

Page 18: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 18

Product of Binomial Conjugates

(A + B)(A – B) = A2 – B2

In words, the product of two binomial conjugates is the difference of the square of the first term and the square of the second term.

Page 19: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 19

Example: Multiplying Binomial Conjugates

Find the product.

1. (x + 6)(x + 6)

2. (3p – 8q)(3p + 8q)

3. (4m2 – 7rt)(4m2 + 7rt)

4. (x + 3)(x – 3)(x2 + 9)

Page 20: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 20

Solution

1. Substitute x for A and 6 for B:

2. Substitute 3p for A and 8q for B:

Page 21: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 21

Solution

3.

4.

2 2 22 2( )( ) (7 74 4 4 7 )rt rm m t rtm

4 2 216 49m r t

2 2 2( 3)( 3)( 9) ( 9) )9 (xx x xx

2 22 9x 4 81x

Page 22: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 22

Product Function

Definition

If f and g are functions and x is in the domain of both functions, then we can form the product function f ∙ g:

(f ∙ g)(x) = f(x) ∙ g(x)

Page 23: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 23

Example: Using a Product Function to Model a Situation

The annual cost of state corrections (prisons and related costs) per person in the United States can be modeled by the function C(t) = 3.3t + 89, where C(t) is the annual cost (in dollars per person at t years since 1990. The U.S. population can be modeled by the function P(t) = 2.8t + 254, where P(t) is the population (in millions) at t years since 1990. Data is shown in the table on the next slide.

Page 24: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 24

Example: Using a Product Function to Model a Situation

Page 25: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 25

Example: Using a Product Function to Model a Situation

1. Check that the models fit the data well.2. Find an equation of the product function C ∙ P.3. Perform a unit analysis of the expression C(t) ∙ P(t).4. Find (C ∙ P)(28). What does it mean in this

situation?5. Use a graphing calculator graph to determine

whether the function C ∙ P is increasing, decreasing, or neither for values of t between 0 and 30. What does your result mean in this situation?

Page 26: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 26

Solution

1. Check the fit of the cost model on the left and the fit of the population model on the right. The models appear to fit the data fairly well.

Page 27: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 27

Solution

2.

3.

The units of the expressions are millions of dollars.

( ( )))( () CC t tP P t (3.3 89) (2.8 254)t t

2 838.2 249.24 9.2 22,606tt t 2 1087.49.24 22,606tt

Page 28: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 28

Solution

4.

This means the total cost of state corrections will be about $60,297 million ($60.297 billion) in 2018, according to the model.

2( )( ) 9.24 1087.4 22,6028 28 28 6C P

60,297

Page 29: Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1 Chapter 6 Polynomial Functions

Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 29

Solution

5. To graph the model, set the window as shown. For values of t between 0 and 30, the model is increasing. This means the total cost of state corrections has been increasing since 1990 and will continue to increase until 2020.