copyright © 2015, 2008, 2011 pearson education, inc. section 6.2, slide 1 chapter 6 polynomial...
TRANSCRIPT
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 1
Chapter 6Polynomial Functions
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 2
6.2 Multiplying Polynomial Expressions and Functions
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 3
Monomials, Binomials, and Trinomials
A polynomial is a monomial, binomial, or trinomial, depending on the number of terms.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 4
Example: Finding the Product of Two Monomials
Find the product 3 2 64 2 .x y xy
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 5
Solution
6 63 2 234 2 4( 2)x x xy y yx y 4 88 yx
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 6
Equivalent Expressions
Warning
3 2 6 3 2 64 2 4 2x y xy x y xy
The left expression is a product, whereas the right expression is a difference.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 7
Multiplying Two Polynomials
To multiply two polynomials, multiply each term in the first polynomial by each term in the second polynomial. Then combine like terms if possible.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 8
Example: Finding the Products of Two Polynomials
Find the product.
1. (2x + y)(5x2 – 3xy + 4y2)
2. (x2 – 3x + 2)(x2 + x – 5)
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 9
Solution
1. Multiply each term in the first polynomial by each term in the second polynomial:
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 10
Solution
2.2 2( )( 5)23 x xx x
2 2 22 2 3 535 3x x x x xx xx xx 22 2 2 5x x
4 3 2 3 2 25 3 3 15 2 2 10x x x x x x x x 2 24 23 3 15 5 2 13 3 02x x xx x x xx
234 2 17 016xx xx
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 11
Solution
2. Use a graphing calculator table to verify our work.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 12
Squaring a Binomial
(A + B)2 = A2 + 2AB + B2
(A – B)2 = A2 – 2AB + B2
In words, the square of a binomial equals the first term squared, plus (or minus) twice the product of the two terms, plus the second term squared.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 13
Example: Simplifying Squares of Binomials
Simplify.
1. (x + 7)2 2. (5t – 4w)2 3. (3r2 + 2y2)2
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 14
Solution
1. Substitute x for A and 7 for B:
Or, 2( 7) ( 7)( 7)x x x 2 7 97 4x x x 2 14 49x x
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 15
Solution
2. Substitute 5t for A and 4w for B:
Or, 2(5 4 ) (5 4 )(5 4 )t w t w t w 2 220 2025 16twt tw w 2 225 40 16t tw w
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 16
Solution
3.
2 22 22222 23 232 22 3y r r yr y
4 2 2 49 12 4r r y y
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 17
Perfect-Square Trinomial
A perfect-square trinomial is a trinomial equivalent to the square of a binomial.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 18
Product of Binomial Conjugates
(A + B)(A – B) = A2 – B2
In words, the product of two binomial conjugates is the difference of the square of the first term and the square of the second term.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 19
Example: Multiplying Binomial Conjugates
Find the product.
1. (x + 6)(x + 6)
2. (3p – 8q)(3p + 8q)
3. (4m2 – 7rt)(4m2 + 7rt)
4. (x + 3)(x – 3)(x2 + 9)
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 20
Solution
1. Substitute x for A and 6 for B:
2. Substitute 3p for A and 8q for B:
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 21
Solution
3.
4.
2 2 22 2( )( ) (7 74 4 4 7 )rt rm m t rtm
4 2 216 49m r t
2 2 2( 3)( 3)( 9) ( 9) )9 (xx x xx
2 22 9x 4 81x
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 22
Product Function
Definition
If f and g are functions and x is in the domain of both functions, then we can form the product function f ∙ g:
(f ∙ g)(x) = f(x) ∙ g(x)
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 23
Example: Using a Product Function to Model a Situation
The annual cost of state corrections (prisons and related costs) per person in the United States can be modeled by the function C(t) = 3.3t + 89, where C(t) is the annual cost (in dollars per person at t years since 1990. The U.S. population can be modeled by the function P(t) = 2.8t + 254, where P(t) is the population (in millions) at t years since 1990. Data is shown in the table on the next slide.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 24
Example: Using a Product Function to Model a Situation
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 25
Example: Using a Product Function to Model a Situation
1. Check that the models fit the data well.2. Find an equation of the product function C ∙ P.3. Perform a unit analysis of the expression C(t) ∙ P(t).4. Find (C ∙ P)(28). What does it mean in this
situation?5. Use a graphing calculator graph to determine
whether the function C ∙ P is increasing, decreasing, or neither for values of t between 0 and 30. What does your result mean in this situation?
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 26
Solution
1. Check the fit of the cost model on the left and the fit of the population model on the right. The models appear to fit the data fairly well.
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 27
Solution
2.
3.
The units of the expressions are millions of dollars.
( ( )))( () CC t tP P t (3.3 89) (2.8 254)t t
2 838.2 249.24 9.2 22,606tt t 2 1087.49.24 22,606tt
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 28
Solution
4.
This means the total cost of state corrections will be about $60,297 million ($60.297 billion) in 2018, according to the model.
2( )( ) 9.24 1087.4 22,6028 28 28 6C P
60,297
Copyright © 2015, 2008, 2011 Pearson Education, Inc. Section 6.2, Slide 29
Solution
5. To graph the model, set the window as shown. For values of t between 0 and 30, the model is increasing. This means the total cost of state corrections has been increasing since 1990 and will continue to increase until 2020.