copyright © 2009 pearson education, inc. chapter 9 section 4 - slide 1 and
TRANSCRIPT
Copyright © 2009 Pearson Education, Inc. Chapter 9 Section 4 - Slide 1
AND
Chapter 9 Section 4 - Slide 2Copyright © 2009 Pearson Education, Inc.
Chapter 9
Geometry
Chapter 9 Section 4 - Slide 3Copyright © 2009 Pearson Education, Inc.
WHAT YOU WILL LEARN
• Points, lines, planes, and angles• Polygons, similar figures, and
congruent figures• Perimeter and area• Pythagorean theorem• Circles• Volume
Chapter 9 Section 4 - Slide 4Copyright © 2009 Pearson Education, Inc.
Section 4
Volume and Surface Area
Copyright © 2009 Pearson Education, Inc. Chapter 9 Section 4 - Slide 5
Volume
Volume is the measure of the capacity of a figure.
It is the amount of material you can put inside a three-dimensional figure.
Surface area is sum of the areas of the surfaces of a three-dimensional figure.
It refers to the total area that is on the outside surface of the figure.
Copyright © 2009 Pearson Education, Inc. Chapter 9 Section 4 - Slide 6
r
Volume Formulas
Sphere
Cone
V = r2hCylinder
V = s3Cube
V = lwhRectangular Solid
DiagramFormulaFigure
213V r h
343V r
l
h
w
s
s
s
h
h
r
Copyright © 2009 Pearson Education, Inc. Chapter 9 Section 4 - Slide 7
r
Surface Area Formulas
Sphere
Cone
SA = 2rh + 2r2Cylinder
SA= 6s2Cube
SA = 2lw + 2wh +2lhRectangular Solid
DiagramFormulaFigure
SA r2
r r2
h2
SA 4r 2
l
h
w
s
s
s
h
r
h
r
Copyright © 2009 Pearson Education, Inc. Chapter 9 Section 4 - Slide 8
Mr. Stoller needs to order potting soil for his horticulture class. The class is going to plant seeds in rectangular planters that are 12 inches long, 8 inches wide and 3 inches deep. If the class is going to fill 500 planters, how many cubic inches of soil are needed? How many cubic feet is this?
Example
12
3
8
Copyright © 2009 Pearson Education, Inc. Chapter 9 Section 4 - Slide 9
Example (continued)
We need to find the volume of one planter.
Soil for 500 planters would be
500(288) = 144,000 cubic inches The number of cube feet
V lwh
V 12(8)(3)
V 288 in.3
33 3 3
3
1 ft 144,000144,000 in ft 83.33 ft
1728 in 1728
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Copyright © 2009 Pearson Education, Inc. Chapter 9 Section 4 - Slide 10
Polyhedron
A polyhedron is a closed surface formed by the union of polygonal regions.
Copyright © 2009 Pearson Education, Inc. Chapter 9 Section 4 - Slide 11
Euler’s Polyhedron Formula
Number of vertices number of edges + number of faces = 2
Example: A certain polyhedron has 12 edges and 6 faces. Determine the number of vertices for this polyhedron.
# of vertices # of edges + # of faces = 2
There are 8 vertices.
12 6 2
6 2
8
x
x
x
Copyright © 2009 Pearson Education, Inc. Chapter 9 Section 4 - Slide 12
Volume of a Prism A prism is a polyhedron whose bases are
congruent and whose sides are parallelograms. V = Bh, where B is the area of the base and h is
the height. Example: Find the volume of the figure.
Area of one triangle. Find the volume.
8 m
6 m
4 m
12
12
2
(6)(4)
12 m
A bh
A
A
3
12(8)
96 m
V Bh
V
V
Copyright © 2009 Pearson Education, Inc. Chapter 9 Section 4 - Slide 13
Volume of a Pyramid
A pyramid is a polyhedron with one base, all of whose faces intersect at a common vertex.
where B is the area of the base and h is the height.
Example: Find the volume of the pyramid.Base area = 122 = 144
13V Bh
12 m
12 m
18 m
13
13
3
(144)(18)
864 m
V Bh
V
V