code part test-3 (pt-3) 0 - · pdf fileplease read the instructions carefully. you are...

Please read the instructions carefully. You are allotted 5 minutes specifically for this purpose.

Duration : 3 Hours Max. Marks : 243

PAPER - 2

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INSTRUCTIONSA. General :

1. This Question Paper contains 63 questions.

2. The question paper CODE is printed on the right hand top corner on this sheet of this booklet.

3. No additional sheets will be provided for rough work.

4. Blank paper, clipboard, log tables, slide rules, calculators, cellular phones, pagers and electronic gadgets

in any form are not allowed.

5. The answer sheet, a machine-gradable Objective Response Sheet (ORS), is provided separately.

6. Do not Tamper / mutilate the ORS or this booklet.

7. Do not break the seals of the question-paper booklet before instructed to do so by the invigilators.

8. Write your Name, Roll No. and Sign in the space provide on the back page of this booklet.

B. Filling the bottom-half of the ORS :

9. The ORS has CODE printed on its lower and upper Parts.

10. Make sure the CODE on the ORS is the same as that on this booklet. If the Codes do not match, ask for a

change of the Booklet.

11. Write your Roll No., Name and Name of centre and sign with pen in appropriate boxes. Do not write these

anywhere else.

12. Darken the appropriate bubbles below your registration number with HB Pencil.

13. Fill the test cities code in ORS Sheet and for details of cities code see last page this test paper booklet.

C. Question paper format and Marking scheme :

14. The question paper consists of 3 parts (Chemistry, Mathematics & Physics). Each part consists of four Sections.

15. For each question in Section�I , you will be awarded 3 marks if you darken the bubble corresponding to the

correct answer and zero marks if no bubble is darkened. In case of bubbling of incorrect answer, minus

one (�1) mark will be awarded.

16. For each question in Section�II , you will be awarded 4 marks if you darken the bubble(s) corresponding

to the correct choice(s) for the answer and zero mark if no bubbled is darkened. There is no negative

marking for incorrect answer for this this section.

17. For each question in Section�III, you will be awarded 4 marks if you darken the bubble corresponding to

the correct answer, and zero mark if no bubble is darkened. In case of bubbling of incorrect answer, minus

one (�1) mark will be awarded.

18. For each question in Section�IV, you will be awarded 2 marks for each row in which you have darkened the

bubble(s) corresponding to the correct answer. Thus, each question in this section carries a maximum of

8 marks. There is no negative marking for incorrect answer(s) for this this section.

CODE

0PART TEST-3 (PT-3)TARGET : IIT-JEE 2011

(A Unit of Resonance Eduventures Pvt. Ltd.)Distance Learning Programmes Division

CLASS-XII/XIII COURSE : ALL INDIA TEST SERIES (VIKALP)

(SPACE FOR ROUGH WORK)

RESONANCE VIKALP_XII-XIII - 2 _ C� 0 - 1

PART-I

Atomic masses : [H = 1, D = 2, Li = 7, C = 12, N = 14, O = 16, F = 19, Na = 23, Mg = 24, Al = 27, Si = 28,

P = 31, S = 32, Cl = 35.5, K = 39, Ca = 40, Cr = 52, Mn = 55, Fe = 56, Cu = 63.5, Zn = 65, As = 75, Br =

80, Ag = 108, I = 127, Ba = 137, Hg = 200, Pb = 207]

SECTION - I

Straight Objective Type

This section contains 11 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its

answer, out of which ONLY ONE is correct.

1. The variation of equilibrium constant K with temperature is given by Vant-Hoff equation as : K = A e�H°/RT.

Find the value of pre-exponential factor A if it is given that as T , nK = 69.09.

(A) 1030 (B) 69.09 (C) 30 (D) 10�30

2. The equilibrium constant Kp for the reaction N

2O

4 (g) 2NO

2 (g) at 497ºC is found to be 640 mm of Hg.

At what pressure will N2O

4 (g) be half dissociated ?

(A) 320 mm of Hg (B) 480 mm of Hg (C) 360 mm of Hg (D) 1920 mm of Hg

3. The initial rate of zero order reaction of the gaseous equation A (g) 2B (g) is 10�2 M min�1. If the initial

concentration of A is 0.1 M, what would be concentration of B after 60 sec.

(A) 0.09 M (B) 0.01 M (C) 0.02 M (D) 0.03 M



4. For a given reaction A Product, rate is 1 × 10�4 M s�1 when [A] = 0.01 M and rate is 1.414 × 10�4 M s�1 when

[A] = 0.02 M. Hence, rate law is :

(A) dt

]A[d = k [A]2 (B)

dt]A[d

= k[A] (C) ]A[4k

dt]A[d (D)

dt]A[d

= k[A]1/2

5. The gaseous decomposition of Cl2O7 (gas) takes place according to following reaction

Cl2O7 (g) Cl2(g) + 7/2 O2(g)

When decomposition is carried out in a closed container, pressure measured after 15 minute and after a very

long time were found to be 375 of Hg and 900 mm of Hg respectively, the ratio of partial pressure of Cl2 gas

after a very long time and after 15 minute is :

(A) 2 (B) 1 (C) 3 (D) 4

6.

The rate constant 'Ktotal

' is given by Ktotal

= 2/1

2

31K

K.K

. The activation energy of Ist path, IInd path, and IIIrd path

is given by 100, 80 and 50 KJ mol�1 respectively. The activation energy of overall reaction would be

(A) 60 KJ mol�1 (B) 35 KJ mol�1 (C) 80 KJ mol�1 (D) 100 KJ mol�1

7. 3A K

Products. Rate law is, rate = K [A]°, then (Here Ct = Concentration of reactant at time t,

C0 = concentration of reactant at time t = 0)

(A) Slope of graph of Ct vs t is � K (B) Slope of graph of C

t vs t is � 3K

(C) Slope of graph of (C0�C

t) vs t is K. (D) Slope of graph of (C

0 � C

t) vs t is �K



8. COONaCHofMole1 3

The products will be :

(A) + CH3COOH (B) + CH3COOH

(C) + CH3COOH (D) Reaction is not feasible

9. Which of the following will not show tautomerism ?

(A) (B)

(C) (D)



10. Identify most stable enol form of terric acid

(A) (B) (C) (D)

11. Give the stability order of the following compounds.

H

OCH3

+y

( )I H

OCH3

+

y

( )IIH

NH2

+

y( )IIIH

NH2

+y

( )IV

(A) I > II > III > IV (B) IV > I > II > III (C) IV > I > III > II (D) IV > II > I > III

SECTION - II

Multiple Correct Answer Type

This section contains 5 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for its

answer, out of which ONE OR MORE is/are correct.



12. Which is the correct statement about S2 (g) molecule which forms above 1000ºC ? Molecular orbital theory

of S2 is found to be similar to that of O

2 molecule.

(A) It is paramagnetic molecule having 2 unpaired electron.(B) Its bond order is two but both should be bonds.(C) The HOMO level in S

2 (g) should be *3p.

(D) Bond order is exactly same with O2, so bond strength should also be exactly same.

13. Correct order of boiling point is/are :

(A) CH3 � O � CH

3 < CH

3 � CH

2 � OH (B) O

2 < Cl

2 < Br

2 < IBr

(C) HCl < HBr < HF > HI (D) SbH3 > NH

3 > PH

3 > AsH

3

14. Rate of a chemical reaction 2A (g) B (g) is defined as

�rB� =

V1

dtdnB

Where nB = number of moles of B formed and C

B = concentration of B then which of the following relation is

correct.

(A) rB =

dtdCB +

VCB

dtdV

(If volume V is not constant)

(B) rB =

dtdCB (If volume V is constant)

(C) rB =

dtdCB

� V

CB

dtdV


(D) rB = �

dtdCB +

VCB

dtdV




15. Which of the following compound will racemize on keeping in aquous solution.

(A) (B)

(C) (D)

16. Tautomerism is exhibited by

(A) (B)

(C) (D)

SECTION - IIIReasoning Type

This section contains 3 reasoning type questions. Each question has 4 choices (A), (B), (C) and (D),out of which ONLY ONE is correct.



17. Statement-1 : For the reaction PCl5(g) PCl

3(g) + Cl

2 (g) at equilibrium, if volume of the reaction vessel

is suddenly decreased to half, then new equilibrium partial pressure of Cl2 will be lesser than that at initial

equilibrium. (at same temperature)

Statement-2 : For the reaction PCl5(g) PCl

3(g) + Cl

2 (g) at equilibrium, if volume of reaction vessel is

halved then reaction shifts in backward direaction.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.(C) Statement-1 is True, Statement-2 is False.(D) Statement-1 is False, Statement-2 is True.

18. Statement-1 : For zero order reaction, degree of dissociation () increases with progress of reaction.

Statement-2 : Degree of dissociation () for zero order reaction can be given as oC

Kt so depends on time.

Where C0 = initial concentration of reactant.

(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.(C) Statement-1 is True, Statement-2 is False.(D) Statement-1 is False, Statement-2 is True.

19. Statement-1 : Salicylic acid is much stronger acid than its m-, p-isomers and benzoic acid itself.Statement-2 : It is due to ortho effect of OH group in which formed anion is stabilised by intramolecularH-bonding.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1.(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1.(C) Statement-1 is True, Statement-2 is False.(D) Statement-1 is False, Statement-2 is True.



SECTION - IV

Matrix - Match TypeThis section contains 2 questions. Each question contains statements given in two

columns, which have to be matched. The statements in Column-I are labelled

A, B, C and D, while the statements in Column-II are labelled p, q, r, s and t. Any

given statement in Column-I can have correct matching with ONE OR MORE

statement(s) in Column-II. The appropriate bubbles corresponding to the answers

to these questions have to be drakened as illustrated in the following example.

If the correct matches are A-p, s and t ; B-q and r; C-p and q; and D-s and t; then the correct darkening of

bubbles will look like the following :

20. Column � I Column � II

(A) 2SO2 (g) + O

2 (g) 2SO

3 (g) (p) Heterogeneous equilibrium

(B) CaCO3(s) CaO(s) +CO

2(g) (q) Addition of inert gas at equilibrium at constant pressure favours

backward shift.

(C) H2(g) + I

2(g) 2HI (g) (r) Increase in pressure shifts equilibrium in backward direction

(D) CO2(g) CO

2 (aq) (s) Decreases in pressure shifts equilibrium in backward direction

(t) On addition of reactant at same volume shifts equilibrium in

forward direction.



21. Match the Ka values :


RESONANCE VIKALP_PT-3_XII/XIII_2_C0_10(A Unit of Resonance Eduventures Pvt. Ltd.)Distance Learning Programmes Division


PART- II

SECTION - IStraight Objective Type

This section contains 11 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for itsanswer, out of which ONLY ONE is correct.

22. The value of sin�1

31

+ sin�1 113

1+ sin�1

11

3 is equal to

(A) 2

(B) 0 (C) 4

(D) 6

23. If the function f(x) defined as f(x) = 1�x

1�x

,

,

b2xax

bax3

is differentiable for all x, then

(A) a = � 21

, b = 41

(B) a = �21

, b = 0 (C) a = � 21

, b = 1 (D) a = 23

, b = 1

24. The differential coefficient of f(cosx) with respect to g(sinx) at x = 3

, if f

21

= g

23

= �2, is

(A) 32 (B) 3

1(C) � 3 (D) 3

25. With usual notation in a ABC, if a

Acos =

bBcos

= c

Ccos, then

r

rrr 321 is equal to

(A) 16 (B) 27 (C) 3 (D) 9




26. If f(x) =

0x,1

0x,}x2{]x[2e

x|x|]x[

, ( where [.] and {.} denote greatest integer and fractional part functions

respectively ) then(A) f(x) is differentiable everywhere. (B) f(x) is continuous and differentiable at x = 0.(C) f(x) is continuous everywhere. (D) f(x) is not differentiable at x = 0.

27. Let f(x) =

0x,k

0x,x

3

xsinx

xcos243 . If f(x) is continuous at x = 0, then k is equal to

(A) 601

(B) 201

(C) 41

(D) 301

28. If y = ....yxyx , then dxdy

is equal to

(A) 1xy2y2

yx3

2

(B)

1xyy2

x2y3

2

(C)

1xy2y

x2y3

2

(D)

1xy2y2

xy3

2

29. Number of solutions of the equation sin�1x = sgn{x}, where sgn(.) and { . } represent signum andfractional part functions respectively, are(A) 0 (B) 1 (C) 2 (D) 3




30. Let g(x) be a function that is differentiable through out an open interval containing the origin. Supposeg(x) has the following properties

(i) g(x + y) = )y(g).x(g�1)y(g)x(g

for all real x, y and x + y in the domain of g(x).

(ii) 0)h(glim0h

(iii) 1h

)h(glim

0h

. Then which of the following is INCORRECT ?

(A) g(0) = 0 (B) g (x) = 1 + (g(x))2

(C) g(x) is an odd function (D) 1)x(g

))x(gsin(lim

1x

31.n

lim

n

1r

21�

125

�r3cot is equal to

(A) cot�1 23

(B) cot�1 23

(C) cot�1 25

(D) tan�1 23

32. The sides BC, CA, AB of a ABC are a, b, c respectively, satisfy the relation a4 + b4 + c4 = 2c2 (a2 + b2).Sum of possible values of the angle C is

(A) 4

5(B) (C)

43

(D) 6

5




SECTION - IIMultiple Correct Answer Type

This section contains 5 multiple choice questions. Each question has 4 choices (A), (B), (C) and (D) for itsanswer, out of which ONE OR MORE is/are correct.

33. Let f(x) = x3 � x2 + x + 1 and g(x) =

2x1,x�3

1x0,}xt0:)t(f{max, then

(A) g

21

= 811

(B) g(x) is continuous for all x [0, 2](C) g(x) is differentiable at all points in [0, 2](D) g(x) is discontinuous at only one point in [0, 2]

34. Let f(x) =

21

x +

21

x + 2 [�x], f : R R

(Where [ . ] denotes the greatest integer function), is(A) periodic (B) non-periodic (C) one-one (D) many-one

35. A function is defined as, f(x) = cot�1(sgnx) + sin�1(x � {x}), f : D R where sgn(.) and {.} representssignum and fractional part functions respectively. Which of the following is/are TRUE?(A) Domain of f(x) is [�1, 2). (B) Range of f(x) consist of only two elements.(C) f(x) is many one function. (D) f(x) is into function.




36. If f(x) =

0x,x

2x

sin

0x,b

0x,x

ax1e2

x

, then

(A) f(x) is continuous at x = 0 if a = �1, b = 21

.

(B) f(x) is discontinuous at x = 0 if b 21

.

(C) f(x) has non-removable discontinuity at x = 0 if a �1.

(D) f(x) has removable discontinuity at x = 0 if a = �1, b 21

.

37. Which of the following statement is/are TRUE ?

(A) tan�1 x + tan�1 y = + tan�1

xy�1yx

, x > 0, y > 0, xy > 1.

(B) Domain of the function

x1

xlogx is (1, ).

(C) If f(x) = sin�1

2x�1x2 , then f

2

1 = 2 2 .

(D) sin(sin�1x) is non-periodic.




SECTION - IIIReasoning Type

This section contains 3 reasoning type questions. Each question has 4 choices (A), (B), (C) and (D),out of which ONLY ONE is correct.

38. Statement- 1 : f(x) = en x can be expressed as a sum of even and odd function.

Statement- 2 : If f(x) can be expressed as a sum of even function g(x) and odd function h(x), then

g(x) = 2

)x(f)x(f and h(x) =

2)x(f)x(f

.

(A) Statement -1 is True, Statement -2 is True ; Statement -2 is a correct explanation for Statement -1

(B) Statement-1 is True, Statement-2 is True ; Statement-2 is NOT a correct explanation for Statement-1

(C) Statement -1 is True, Statement -2 is False

(D) Statement -1 is False, Statement -2 is True

39. Statement- 1 : x

lim x1

x

nx

has the indeterminancy of the form 0.

Statement- 2 : There are seven indeterminate forms : 00

,

, 0º, º, 1, � , 0 × .

(A) Statement -1 is True, Statement -2 is True ; Statement -2 is a correct explanation for Statement -1.

(B) Statement-1 is True, Statement-2 is True ; Statement-2 is NOT a correct explanation for Statement-1.

(C) Statement -1 is True, Statement -2 is False.

(D) Statement -1 is False, Statement -2 is True.




40. Statement- 1 : If f(x) = sgn(x) and g(x) = x(1 � x2) then fog(x) is neither odd nor even. (where sgn (.)represents signum function)

Statement- 2 : The graph of even function is symmetrical about the y-axis and the graph of odd function issymmetrical about the origin.(A) Statement -1 is True, Statement -2 is True ; Statement -2 is a correct explanation for Statement -1.

(B) Statement-1 is True, Statement-2 is True ; Statement-2 is NOT a correct explanation for Statement-1.

(C) Statement -1 is True, Statement -2 is False.

(D) Statement -1 is False, Statement -2 is True.

SECTION - IV

Matrix - Match TypeThis section contains 2 questions. Each question contains statements given in two

columns, which have to be matched. The statements in Column-I are labelled

A, B, C and D, while the statements in Column-II are labelled p, q, r, s and t. Any

given statement in Column-I can have correct matching with ONE OR MORE

statement(s) in Column-II. The appropriate bubbles corresponding to the answers

to these questions have to be drakened as illustrated in the following example.

If the correct matches are A-p, s and t ; B-q and r; C-p and q; and D-s and t; then the correct darkening of

bubbles will look like the following :




41. Column � I Column � II

(A) f(x) =

0x,}1x,x2{min

0x,}x,xmin{2

2

is non-differentiable at (p) one point

(B) f(x) = max {x2 � 1, 4, x2 + 1} is non-differentiable at (q) two points

(C) f(x) = max. {sin x, sin�1 (cos x)} is non-differentiable (r) no pointin [0, ] at

(D) f(x) = max. {1, cos x, 1 � sin x} is non-differentiable (s) three pointsin [�, ] at

(t) four points

42. Column- I Column- II

(A) If f(9) = 9, f (9) = 4, then 9x

lim 3�x

3�)x(fis equal to (p) �2

(B)

2x

lim

[sin�1(sinx)] is equal to (q) 1

(where [.] denotes the greatest integer function)

(C) �x

lim [cot�1x] is equal to (r) 3

(where [.] denotes the greatest integer function)

(D)

45

x

lim

[sinx + cosx] is equal to (s) does not exist

(where [.] denotes the greatest integer function)(t) 4



PART - IIISECTION - I

Straight Objective TypeThis section contains 11 multiple choice questions. Each question has choices (A), (B), (C) and (D),out of which ONLY ONE is correct.

43. A particle of mass m begins to slide down a fixed smooth sphere from the top. What is its rate of change ofspeed when it breaks off the sphere ?

(A) 3g2

(B) 3

g5(C) g (D)

3g

44. Consider a hypothetical condition in which resultant force in vertical direction is directly proportional tospeed of the particle and there is no horizontal force. A particle is projected horizontally from the topof a tower with a speed v0. If v be its speed at any instant, then the radius of curvature of the path of theparticle at that instant is directly proportional to:(A) v3 (B) v2 (C) v (D) 1/v

45. As shown in the figure a particle of mass m moving horizontally with speed 3 m/s hits a fixed smoothwedge and goes up with a velocity v

f in the vertical direction. If of wedge is 60º, the velocity v

f will be:

(A) 3 m/s (B) 3 m/s (C) 1 m/s (D) this is not possible



46. In the balance machine, shown in the Figure which arm of the rod will move downward after the systemis released? Mass of the rod is m.

(A) left (B) right (C) none (D) cannot be said

47. A rod pivoted at one end is shown in diagram, it is given that rod is in equilibrium then the direction of forceacting at the hinged end of the rod will be :

(A) horizontal (B) vertical(C) perpendicular to length of rod (D) along the length of rod

48. Two particles A and B having equal mass are interconnected by a light inextensiblestring that passes over a smooth pulley. One of the mass is pulled downward by aconstant force �F� as shown in diagram, then the acceleration of the centre of mass of

the system (A + B) is :

(A) zero (B) M2F

downwards

(C) M2F

upwards (D) none of these



49. Two rods are moving with constant velocity v in perpendicular direction totheir length as shown in figure. The velocity of point of intersection of tworods will be :

(A) v cosec (B) v cos

(C) v sin (D) 2vsin

50. A uniform rod of mass 'm' and length is hinged at one end and attached to a particle ofmass 'm' at other end. It is free to rotate in vertical plane about hinge as shown in figure.Particle is given minimum speed so that it can complete circle in vertical plane then workdoneby the rod on the particle during half of complete revolution starting from bottom.

(A) zero (B) � mg 4

(C) �mg 8

(D) 4

mg

51. Situation is shown in figure it is given that all surfaces are smooth. Find the minimum value of initial velocityof wedge v so that block just reaches heighest point of the wedge. Neglect any collision

(A) zero (B) gh2 (C) gh4 (D) gh4 � gh2



52. A uniform vertical ring of mass m and radius R is rotating (about a horizontal axis) with angular velocity ona smooth horizontal surface. Then the normal force acting on the ring will be :(A) mg (B) mR (C) mg � mR (D) mg + mR

53. A rocket is moving along a circle of radius r with constant speed v in free space away from all objects. Massof rocket is decreasing at constant rate. Relative speed of gases ejected is u then which of the followingstatement is true :(A) u will be constant in magnitude (B) u will increase at constant rate(C) u will decrease at constant rate (D) u will decrease but rate of change of u will be variable

SECTION - IIMultiple Correct Answers Type

This section contains 5 multiple correct answer(s) type questions. Each question has 4 choices (A),(B), (C) and (D), out of which ONE OR MORE is/are correct.

54. Which of the following results in perfectly elastic collision is/are possible for two particles of same mass.

1u

=velocity of particle 1 before collision.

2u

= velocity of particle 2 before collision.

1v

= velocity of particle 1 after collision.

2v

= velocity of particle 2 after collision.

(A) i�5u1

; i�3v1

(B) i�5u1

; j�4i�3v1

0u2

; i�2v2

0u2

; i�2j�4v2

(C) i�5u1

; j�4.2i�8.1v1

(D) None of these

0u2

; j�4.2i�2.3v2



55. In oblique elastic collision of two smooth bodies of equal masses:(A) the velocities are interchanged (B) the speeds are interchanged(C) kinetic energies are interchanged (D) None of these

56. In which of the following cases y coordinate of centre of mass is at 3h2

(A) (B)

(C) (D)




57. A strip of wood of mass M and length is placed on a smooth horizontal surface. An insect of massm starts at one end of the strip and walks to the other end in time t, moving with a constant speed.

(A) the speed of insect as seen from the ground is < t

(B) the speed of the strip as seen from the ground is t

mMM

(C) the speed of the insect as seen from the ground is t

mMM

(D) Sum of speed of insect and strip is t

58. The figure shows the velocity as a function of the time for an objectwith mass 10 kg being pushed along a frictionless horizontal surfaceby external horizontal force. At t = 3 s, the force stops pushing and theobject moves freely. It then collides head on and sticks to anotherobject of mass 25 kg.(A) External force acting on the system is 50 N from t = 0 to t = 3 sec.(B) Speed of the 2nd particle just before the collision is 1 m/s.(C) before collision both bodies are moving in the same direction.(D) before collision, bodies are moving in opposite direction.

SECTION - III

Reasoning TypeThis section contains 3 reasoning type questions. Each question has 4 choices (A), (B), (C) and(D), out of which ONLY ONE is correct.

59. STATEMENT-1 : A thin uniform rod is undergoing rotation about a fixed axis passing through one of its endswith variable angular acceleration. Then acceleration vector of any two moving points on the rod will beparallel at an instant of time.STATEMENT-2 : For a rod undergoing rotation about a fixed axis, the velocity of any two moving points on therod at different distances from centre of rotation are different.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1(C) Statement-1 is True, Statement-2 is False(D) Statement-1 is False, Statement-2 is True.





60. STATEMENT-1: A uniform rod is kept on a smooth horizontal surface, two equal and opposite horizontalforces are applied on the rod as shown, B is mid point of AC and C is mid point of AD. The rod wil have purerotation about a vertical axis passing through B.

STATEMENT-2 : When velocity of centre of mass is zero and acceleration of centre of mass is zero thencentre of mass remains fixed with respect to ground.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1(C) Statement-1 is True, Statement-2 is False(D) Statement-1 is False, Statement-2 is True.

61. STATEMENT-1 : If the net force acting on an object is zero then net torque on the object will be zero aboutany point.

STATEMENT-2 : Torque of a force about a point is given by formula Fr

if F

is zero then 0

.(A) Statement-1 is True, Statement-2 is True; Statement-2 is a correct explanation for Statement-1(B) Statement-1 is True, Statement-2 is True; Statement-2 is NOT a correct explanation for Statement-1(C) Statement-1 is True, Statement-2 is False(D) Statement-1 is False, Statement-2 is True.

SECTION - IVMatrix - Match Type

This section contains 2 questions. Each question contains statements given in twocolumns, which have to be matched. The statements in Column-I are labelledA, B, C and D, while the statements in Column-II are labelled p, q, r, s and t. Anygiven statement in Column-I can have correct matching with ONE OR MOREstatement(s) in Column-II. The appropriate bubbles corresponding to the answersto these questions have to be darkened as illustrated in the following example. If the correct matches are A-p, s and t ; B-q and r; C-p and q; and D-s and t; then the correct darkening ofbubbles will look like the following :




62. In each situation of column-I, a uniform disc of mass m and radius R rolls on a rough fixed horizontal surfaceas shown in the figure. At t=0 ( initially) the angular velocity of disc is

and velocity of centre of mass of

disc is v(in horizontal direction). The relation between v

and

for each situation and also initial sense of

rotation is given for each situation in column-I . Then match the statements in column-I with the correspondingresults in column-II .

Column-I Column-II

(A) (v > R

) (p) The angular momentum of disc about point A

(as shown in figure) remains conserved.

(B) (v > R

) (q) The kinetic energy of disc after it starts rolling

without slipping is less than its initial kinetic energy.

(C) (v < R

) (r) In the duration disc rolls with slipping, the

friction acts on disc towards left.

(D) (v < R

) (s) Final momentum of disc is greater then initial momentum

(t) Acceleration of centre of mass remains constant duringthe time disc rolls with slipping.



63. In each situation of column-I, a system involving two bodies is given. All strings and pulleys are lightand friction is absent everywhere. Initially each body of every system is at rest. Consider the system inall situation of column I from rest till any collision occurs. Then match the statements in column-I withthe corresponding results in column-II

Column-I Column-II(A) The block plus wedge system is placed (p) Shifts towards right

over smooth horizontal surface. Afterthe system is released from rest, thecentre of mass of system.

(B) The string connecting both the blocks of (q) Shifts downwardsmass m is horizontal. Left block is placedover smooth horizontal table as shown.After the two block system is releasedfrom rest, the centre of mass of system

(C) The block and monkey have same mass. (r) Shifts upwardsThe monkey starts climbing up the rope.After the monkey starts climbing up, the centre of mass of monkey + block system.

(D) Both block of mass m are initially at rest. (s) Does not shiftThe left block is given initial velocity udownwards. Then, the centre of mass oftwo block system afterwards.

(t) Shifts towards left.


Name of the Candidate Roll Number

I have read all the instructions andshall abide by them.

-------------------------------- Signature of the Invigilator

I have verified all the informationfilled in by the Candidate.

-------------------------------- Signature of the Candidate

(Space for rough work)

Example for Filling Test Cities Code in ORS :If your Test centre is Bhatinda and test code is 06 then fill in ORS :

(a)

(b)

Test Code Test Centre Test Code Test Centre Test Code Test Centre01 Ahamedabad 02 Agra 03 Bengluru04 Bikaner 05 Bhopal 06 Bhatinda07 Bhubneshwar 08 Bokaro 09 Chandigarh10 Dhanbad 11 Dehradun 12 Guwahati13 Hyderabad 14 Indore 15 Jaipur16 Kanpur 17 Kolkata 18 Kota19 Lucknow 20 Mumbai-Andheri 21 Mumbai-Thane22 Mumbai-Nerul 23 Mumbai- Dadar 24 Mangluru25 Muzaffarpur 26 Nagpur 27 New Delhi- East28 New Delhi-West 29 New Dehi- North West 30 New Delhi- South31 Patna 32 Raipur 33 Ranchi34 Sri Ganganagar 35 Shakti Nagar (NTPC) 36 Udaipur37 Udupi 38 Varanasi

code part test-3 (pt-3) 0 - · pdf fileplease read the instructions carefully. you are...

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